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Two elements whose sum is closest to zero

Here given code implementation process.

/*
    C program for
    Two elements whose sum is closest to zero
*/
#include <stdio.h>

int absValue(int num)
{
	if (num < 0)
	{
		return -num;
	}
	return num;
}
void closestZeroSum(int arr[], int n)
{
	if (n <= 1)
	{
		return;
	}
	// Get value of first element
	int x = arr[0];
	// Get value of second element
	int y = arr[1];
	int sum = x + y;
	// Execute the loop through by size of array
	for (int i = 0; i < n; ++i)
	{
		for (int j = i + 1; j < n; ++j)
		{
			if (absValue(sum) > absValue(arr[i] + arr[j]))
			{
				// Get pair of closest to zero
				x = arr[i];
				y = arr[j];
				// Change sum
				sum = x + y;
			}
		}
	}
	// Display resultant pair
	printf("\n (%d) + (%d) = %d", x, y, sum);
}
int main()
{
	int arr1[] = {
		4 , 7 , 8 , 2 , -6 , 12
	};
	int arr2[] = {
		2 , 6 , 8 , -2 , 5
	};
	// Test A
	int n = sizeof(arr1) / sizeof(arr1[0]);
	closestZeroSum(arr1, n);
	// Test B
	n = sizeof(arr2) / sizeof(arr2[0]);
	closestZeroSum(arr2, n);
	return 0;
}

Output

 (7) + (-6) = 1
 (2) + (-2) = 0
/*
    Java program for
    Two elements whose sum is closest to zero
*/
public class Test
{
	public int absValue(int num)
	{
		if (num < 0)
		{
			return -num;
		}
		return num;
	}
	public void closestZeroSum(int[] arr, int n)
	{
		if (n <= 1)
		{
			return;
		}
		// Get value of first element
		int x = arr[0];
		// Get value of second element
		int y = arr[1];
		int sum = x + y;
		// Execute the loop through by size of array
		for (int i = 0; i < n; ++i)
		{
			for (int j = i + 1; j < n; ++j)
			{
				if (absValue(sum) > absValue(arr[i] + arr[j]))
				{
					// Get pair of closest to zero
					x = arr[i];
					y = arr[j];
					// Change sum
					sum = x + y;
				}
			}
		}
		// Display resultant pair
		System.out.println(" (" + x + ") + (" + y + ") = " + sum);
	}
	public static void main(String[] args)
	{
		Test task = new Test();
		int[] arr1 = {
			4 , 7 , 8 , 2 , -6 , 12
		};
		int[] arr2 = {
			2 , 6 , 8 , -2 , 5
		};
		// Test A
		int n = arr1.length;
		task.closestZeroSum(arr1, n);
		// Test B
		n = arr2.length;
		task.closestZeroSum(arr2, n);
	}
}

Output

 (7) + (-6) = 1
 (2) + (-2) = 0
// Include header file
#include <iostream>
using namespace std;
/*
    C++ program for
    Two elements whose sum is closest to zero
*/
class Test
{
	public: int absValue(int num)
	{
		if (num < 0)
		{
			return -num;
		}
		return num;
	}
	void closestZeroSum(int arr[], int n)
	{
		if (n <= 1)
		{
			return;
		}
		// Get value of first element
		int x = arr[0];
		// Get value of second element
		int y = arr[1];
		int sum = x + y;
		// Execute the loop through by size of array
		for (int i = 0; i < n; ++i)
		{
			for (int j = i + 1; j < n; ++j)
			{
				if (this->absValue(sum) > this->absValue(arr[i] + arr[j]))
				{
					// Get pair of closest to zero
					x = arr[i];
					y = arr[j];
					// Change sum
					sum = x + y;
				}
			}
		}
		// Display resultant pair
		cout << " (" << x << ") + (" << y << ") = " << sum << endl;
	}
};
int main()
{
	Test *task = new Test();
	int arr1[] = {
		4 , 7 , 8 , 2 , -6 , 12
	};
	int arr2[] = {
		2 , 6 , 8 , -2 , 5
	};
	// Test A
	int n = sizeof(arr1) / sizeof(arr1[0]);
	task->closestZeroSum(arr1, n);
	// Test B
	n = sizeof(arr2) / sizeof(arr2[0]);
	task->closestZeroSum(arr2, n);
	return 0;
}

Output

 (7) + (-6) = 1
 (2) + (-2) = 0
// Include namespace system
using System;
/*
    Csharp program for
    Two elements whose sum is closest to zero
*/
public class Test
{
	public int absValue(int num)
	{
		if (num < 0)
		{
			return -num;
		}
		return num;
	}
	public void closestZeroSum(int[] arr, int n)
	{
		if (n <= 1)
		{
			return;
		}
		// Get value of first element
		int x = arr[0];
		// Get value of second element
		int y = arr[1];
		int sum = x + y;
		// Execute the loop through by size of array
		for (int i = 0; i < n; ++i)
		{
			for (int j = i + 1; j < n; ++j)
			{
				if (this.absValue(sum) > this.absValue(arr[i] + arr[j]))
				{
					// Get pair of closest to zero
					x = arr[i];
					y = arr[j];
					// Change sum
					sum = x + y;
				}
			}
		}
		// Display resultant pair
		Console.WriteLine(" (" + x + ") + (" + y + ") = " + sum);
	}
	public static void Main(String[] args)
	{
		Test task = new Test();
		int[] arr1 = {
			4 , 7 , 8 , 2 , -6 , 12
		};
		int[] arr2 = {
			2 , 6 , 8 , -2 , 5
		};
		// Test A
		int n = arr1.Length;
		task.closestZeroSum(arr1, n);
		// Test B
		n = arr2.Length;
		task.closestZeroSum(arr2, n);
	}
}

Output

 (7) + (-6) = 1
 (2) + (-2) = 0
package main
import "fmt"
/*
    Go program for
    Two elements whose sum is closest to zero
*/

func absValue(num int) int {
	if num < 0 {
		return -num
	}
	return num
}
func closestZeroSum(arr[] int, n int) {
	if n <= 1 {
		return
	}
	// Get value of first element
	var x int = arr[0]
	// Get value of second element
	var y int = arr[1]
	var sum int = x + y
	// Execute the loop through by size of array
	for i := 0 ; i < n ; i++ {
		for j := i + 1 ; j < n ; j++ {
			if absValue(sum) > absValue(arr[i] + arr[j]) {
				// Get pair of closest to zero
				x = arr[i]
				y = arr[j]
				// Change sum
				sum = x + y
			}
		}
	}
	// Display resultant pair
	fmt.Println(" (", x, ") + (", y, ") = ", sum)
}
func main() {

	var arr1 = [] int {4, 7, 8, 2, -6, 12}
	var arr2 = [] int {2, 6, 8, -2, 5}
	// Test A
	var n int = len(arr1)
	closestZeroSum(arr1, n)
	// Test B
	n = len(arr2)
	closestZeroSum(arr2, n)
}

Output

 (7) + (-6) = 1
 (2) + (-2) = 0
<?php
/*
    Php program for
    Two elements whose sum is closest to zero
*/
class Test
{
	public	function absValue($num)
	{
		if ($num < 0)
		{
			return -$num;
		}
		return $num;
	}
	public	function closestZeroSum($arr, $n)
	{
		if ($n <= 1)
		{
			return;
		}
		// Get value of first element
		$x = $arr[0];
		// Get value of second element
		$y = $arr[1];
		$sum = $x + $y;
		// Execute the loop through by size of array
		for ($i = 0; $i < $n; ++$i)
		{
			for ($j = $i + 1; $j < $n; ++$j)
			{
				if ($this->absValue($sum) > 
                    $this->absValue($arr[$i] + $arr[$j]))
				{
					// Get pair of closest to zero
					$x = $arr[$i];
					$y = $arr[$j];
					// Change sum
					$sum = $x + $y;
				}
			}
		}
		// Display resultant pair
		echo(" (".$x.
			") + (".$y.
			") = ".$sum.
			"\n");
	}
}

function main()
{
	$task = new Test();
	$arr1 = array(4, 7, 8, 2, -6, 12);
	$arr2 = array(2, 6, 8, -2, 5);
	// Test A
	$n = count($arr1);
	$task->closestZeroSum($arr1, $n);
	// Test B
	$n = count($arr2);
	$task->closestZeroSum($arr2, $n);
}
main();

Output

 (7) + (-6) = 1
 (2) + (-2) = 0
/*
    Node JS program for
    Two elements whose sum is closest to zero
*/
class Test
{
	absValue(num)
	{
		if (num < 0)
		{
			return -num;
		}
		return num;
	}
	closestZeroSum(arr, n)
	{
		if (n <= 1)
		{
			return;
		}
		// Get value of first element
		var x = arr[0];
		// Get value of second element
		var y = arr[1];
		var sum = x + y;
		// Execute the loop through by size of array
		for (var i = 0; i < n; ++i)
		{
			for (var j = i + 1; j < n; ++j)
			{
				if (this.absValue(sum) > this.absValue(arr[i] + arr[j]))
				{
					// Get pair of closest to zero
					x = arr[i];
					y = arr[j];
					// Change sum
					sum = x + y;
				}
			}
		}
		// Display resultant pair
		console.log(" (" + x + ") + (" + y + ") = " + sum);
	}
}

function main()
{
	var task = new Test();
	var arr1 = [4, 7, 8, 2, -6, 12];
	var arr2 = [2, 6, 8, -2, 5];
	// Test A
	var n = arr1.length;
	task.closestZeroSum(arr1, n);
	// Test B
	n = arr2.length;
	task.closestZeroSum(arr2, n);
}
main();

Output

 (7) + (-6) = 1
 (2) + (-2) = 0
#    Python 3 program for
#    Two elements whose sum is closest to zero
class Test :
	def absValue(self, num) :
		if (num < 0) :
			return -num
		
		return num
	
	def closestZeroSum(self, arr, n) :
		if (n <= 1) :
			return
		
		#  Get value of first element
		x = arr[0]
		#  Get value of second element
		y = arr[1]
		sum = x + y
		i = 0
		#  Execute the loop through by size of list
		while (i < n) :
			j = i + 1
			while (j < n) :
				if (self.absValue(sum) > self.absValue(arr[i] + arr[j])) :
					#  Get pair of closest to zero
					x = arr[i]
					y = arr[j]
					#  Change sum
					sum = x + y
				
				j += 1
			
			i += 1
		
		#  Display resultant pair
		print(" (", x ,") + (", y ,") = ", sum)
	

def main() :
	task = Test()
	arr1 = [4, 7, 8, 2, -6, 12]
	arr2 = [2, 6, 8, -2, 5]
	#  Test A
	n = len(arr1)
	task.closestZeroSum(arr1, n)
	#  Test B
	n = len(arr2)
	task.closestZeroSum(arr2, n)

if __name__ == "__main__": main()

Output

 ( 7 ) + ( -6 ) =  1
 ( 2 ) + ( -2 ) =  0
#    Ruby program for
#    Two elements whose sum is closest to zero
class Test 
	def absValue(num) 
		if (num < 0) 
			return -num
		end

		return num
	end

	def closestZeroSum(arr, n) 
		if (n <= 1) 
			return
		end

		#  Get value of first element
		x = arr[0]
		#  Get value of second element
		y = arr[1]
		sum = x + y
		i = 0
		#  Execute the loop through by size of array
		while (i < n) 
			j = i + 1
			while (j < n) 
				if (self.absValue(sum) > self.absValue(arr[i] + arr[j])) 
					#  Get pair of closest to zero
					x = arr[i]
					y = arr[j]
					#  Change sum
					sum = x + y
				end

				j += 1
			end

			i += 1
		end

		#  Display resultant pair
		print(" (", x ,") + (", y ,") = ", sum, "\n")
	end

end

def main() 
	task = Test.new()
	arr1 = [4, 7, 8, 2, -6, 12]
	arr2 = [2, 6, 8, -2, 5]
	#  Test A
	n = arr1.length
	task.closestZeroSum(arr1, n)
	#  Test B
	n = arr2.length
	task.closestZeroSum(arr2, n)
end

main()

Output

 (7) + (-6) = 1
 (2) + (-2) = 0

/*
    Scala program for
    Two elements whose sum is closest to zero
*/
class Test()
{
	def absValue(num: Int): Int = {
		if (num < 0)
		{
			return -num;
		}
		return num;
	}
	def closestZeroSum(arr: Array[Int], n: Int): Unit = {
		if (n <= 1)
		{
			return;
		}
		// Get value of first element
		var x: Int = arr(0);
		// Get value of second element
		var y: Int = arr(1);
		var sum: Int = x + y;
		var i: Int = 0;
		// Execute the loop through by size of array
		while (i < n)
		{
			var j: Int = i + 1;
			while (j < n)
			{
				if (absValue(sum) > absValue(arr(i) + arr(j)))
				{
					// Get pair of closest to zero
					x = arr(i);
					y = arr(j);
					// Change sum
					sum = x + y;
				}
				j += 1;
			}
			i += 1;
		}
		// Display resultant pair
		println(" (" + x + ") + (" + y + ") = " + sum);
	}
}
object Main
{
	def main(args: Array[String]): Unit = {
		var task: Test = new Test();
		var arr1: Array[Int] = Array(4, 7, 8, 2, -6, 12);
		var arr2: Array[Int] = Array(2, 6, 8, -2, 5);
		// Test A
		var n: Int = arr1.length;
		task.closestZeroSum(arr1, n);
		// Test B
		n = arr2.length;
		task.closestZeroSum(arr2, n);
	}
}

Output

 (7) + (-6) = 1
 (2) + (-2) = 0
import Foundation;
/*
    Swift 4 program for
    Two elements whose sum is closest to zero
*/
class Test
{
	func absValue(_ num: Int) -> Int
	{
		if (num < 0)
		{
			return -num;
		}
		return num;
	}
	func closestZeroSum(_ arr: [Int], _ n: Int)
	{
		if (n <= 1)
		{
			return;
		}
		// Get value of first element
		var x: Int = arr[0];
		// Get value of second element
		var y: Int = arr[1];
		var sum: Int = x + y;
		var i: Int = 0;
		// Execute the loop through by size of array
		while (i < n)
		{
			var j: Int = i + 1;
			while (j < n)
			{
				if (self.absValue(sum) > self.absValue(arr[i] + arr[j]))
				{
					// Get pair of closest to zero
					x = arr[i];
					y = arr[j];
					// Change sum
					sum = x + y;
				}
				j += 1;
			}
			i += 1;
		}
		// Display resultant pair
		print(" (", x ,") + (", y ,") = ", sum);
	}
}
func main()
{
	let task: Test = Test();
	let arr1: [Int] = [4, 7, 8, 2, -6, 12];
	let arr2: [Int] = [2, 6, 8, -2, 5];
	// Test A
	var n: Int = arr1.count;
	task.closestZeroSum(arr1, n);
	// Test B
	n = arr2.count;
	task.closestZeroSum(arr2, n);
}
main();

Output

 ( 7 ) + ( -6 ) =  1
 ( 2 ) + ( -2 ) =  0
/*
    Kotlin program for
    Two elements whose sum is closest to zero
*/
class Test
{
	fun absValue(num: Int): Int
	{
		if (num < 0)
		{
			return -num;
		}
		return num;
	}
	fun closestZeroSum(arr: Array < Int > , n: Int): Unit
	{
		if (n <= 1)
		{
			return;
		}
		// Get value of first element
		var x: Int = arr[0];
		// Get value of second element
		var y: Int = arr[1];
		var sum: Int = x + y;
		var i: Int = 0;
		// Execute the loop through by size of array
		while (i < n)
		{
			var j: Int = i + 1;
			while (j < n)
			{
				if (this.absValue(sum) > this.absValue(arr[i] + arr[j]))
				{
					// Get pair of closest to zero
					x = arr[i];
					y = arr[j];
					// Change sum
					sum = x + y;
				}
				j += 1;
			}
			i += 1;
		}
		// Display resultant pair
		println(" (" + x + ") + (" + y + ") = " + sum);
	}
}
fun main(args: Array < String > ): Unit
{
	val task: Test = Test();
	val arr1: Array < Int > = arrayOf(4, 7, 8, 2, -6, 12);
	val arr2: Array < Int > = arrayOf(2, 6, 8, -2, 5);
	// Test A
	var n: Int = arr1.count();
	task.closestZeroSum(arr1, n);
	// Test B
	n = arr2.count();
	task.closestZeroSum(arr2, n);
}

Output

 (7) + (-6) = 1
 (2) + (-2) = 0
Last updated on by Kalkicode




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