Sum of all subarrays of an array efficiently

Here given code implementation process.

// C program for
// Sum of all subarrays of an array efficiently
#include <stdio.h>

void sumSubArray(int arr[], int n)
{
	if (n <= 0)
	{
		return;
	}
	// Sum of occurrence of first element
	int sum = arr[0] *n;
	// Calculate occurrence in remaining elements
	for (int i = 1; i < n; ++i)
	{
		// Here 
		// (n-i) Indicate number of element in current to last element
		// (i + 1) Indicate number of elements between start (0) to current 
		sum += (arr[i]) * ((n - i) * (i + 1));
	}
	// Display calculated result
	printf("\n Sum %d", sum);
}
int main(int argc, char
	const *argv[])
{
	int arr[] = {
		8 , 1 , 4 , 3 , 2 , 1
	};
	/*
	  arr = [8, 1, 4, 3, 2, 1]
	  ---------------------------
	  8
	  8 + 1
	  8 + 1 + 4
	  8 + 1 + 4 + 3
	  8 + 1 + 4 + 3 + 2
	  8 + 1 + 4 + 3 + 2 + 1
	  1
	  1 + 4
	  1 + 4 + 3
	  1 + 4 + 3 + 2
	  1 + 4 + 3 + 2 + 1
	  4
	  4 + 3
	  4 + 3 + 2
	  4 + 3 + 2 + 1
	  3
	  3 + 2
	  3 + 2 + 1
	  2
	  2 + 1
	  1
	  --------------------
	  Sum of all 168
	*/
	int n = sizeof(arr) / sizeof(arr[0]);
	sumSubArray(arr, n);
	return 0;
}

Output

 Sum 168
/*
    Java Program
    Sum of all subarrays of an array efficiently
*/
public class SubArray
{
	public void sumSubArray(int[] arr, int n)
	{
		if (n <= 0)
		{
			return;
		}
		// Sum of occurrence of first element
		int sum = arr[0] * n;
		// Calculate occurrence in remaining elements
		for (int i = 1; i < n; ++i)
		{
			// Here 
          	// -----------------------------------
			// (n-i) Indicate number of element in 
			// current to last element.
			// (i + 1) Indicate number of elements 
			// between start (0) to current.
			sum += (arr[i]) * ((n - i) * (i + 1));
		}
		// Display calculated result
		System.out.print("\n Sum " + sum);
	}
	public static void main(String[] args)
	{
		SubArray task = new SubArray();
		int[] arr = {
			8 , 1 , 4 , 3 , 2 , 1
		};
		/*
		  arr = [8, 1, 4, 3, 2, 1]
		  ---------------------------
		  8
		  8 + 1
		  8 + 1 + 4
		  8 + 1 + 4 + 3
		  8 + 1 + 4 + 3 + 2
		  8 + 1 + 4 + 3 + 2 + 1
		  1
		  1 + 4
		  1 + 4 + 3
		  1 + 4 + 3 + 2
		  1 + 4 + 3 + 2 + 1
		  4
		  4 + 3
		  4 + 3 + 2
		  4 + 3 + 2 + 1
		  3
		  3 + 2
		  3 + 2 + 1
		  2
		  2 + 1
		  1
		  --------------------
		  Sum of all 168
		*/
		int n = arr.length;
		task.sumSubArray(arr, n);
	}
}

Output

 Sum 168
// Include header file
#include <iostream>

using namespace std;
/*
    C++ Program
    Sum of all subarrays of an array efficiently
*/
class SubArray
{
	public: void sumSubArray(int arr[], int n)
	{
		if (n <= 0)
		{
			return;
		}
		// Sum of occurrence of first element
		int sum = arr[0] *n;
		// Calculate occurrence in remaining elements
		for (int i = 1; i < n; ++i)
		{
			// Here
			// -----------------------------------
			// (n-i) Indicate number of element in
			// current to last element.
			// (i + 1) Indicate number of elements
			// between start (0) to current.
			sum += (arr[i]) *((n - i) *(i + 1));
		}
		// Display calculated result
		cout << "\n Sum " << sum;
	}
};
int main()
{
	SubArray *task = new SubArray();
	int arr[] = {
		8 , 1 , 4 , 3 , 2 , 1
	};
	/*
	  arr = [8, 1, 4, 3, 2, 1]
	  ---------------------------
	  8
	  8 + 1
	  8 + 1 + 4
	  8 + 1 + 4 + 3
	  8 + 1 + 4 + 3 + 2
	  8 + 1 + 4 + 3 + 2 + 1
	  1
	  1 + 4
	  1 + 4 + 3
	  1 + 4 + 3 + 2
	  1 + 4 + 3 + 2 + 1
	  4
	  4 + 3
	  4 + 3 + 2
	  4 + 3 + 2 + 1
	  3
	  3 + 2
	  3 + 2 + 1
	  2
	  2 + 1
	  1
	  --------------------
	  Sum of all 168
	*/
	int n = sizeof(arr) / sizeof(arr[0]);
	task->sumSubArray(arr, n);
	return 0;
}

Output

 Sum 168
// Include namespace system
using System;
/*
    Csharp Program
    Sum of all subarrays of an array efficiently
*/
public class SubArray
{
	public void sumSubArray(int[] arr, int n)
	{
		if (n <= 0)
		{
			return;
		}
		// Sum of occurrence of first element
		int sum = arr[0] * n;
		// Calculate occurrence in remaining elements
		for (int i = 1; i < n; ++i)
		{
			// Here
			// -----------------------------------
			// (n-i) Indicate number of element in
			// current to last element.
			// (i + 1) Indicate number of elements
			// between start (0) to current.
			sum += (arr[i]) * ((n - i) * (i + 1));
		}
		// Display calculated result
		Console.Write("\n Sum " + sum);
	}
	public static void Main(String[] args)
	{
		SubArray task = new SubArray();
		int[] arr = {
			8 , 1 , 4 , 3 , 2 , 1
		};
		/*
		  arr = [8, 1, 4, 3, 2, 1]
		  ---------------------------
		  8
		  8 + 1
		  8 + 1 + 4
		  8 + 1 + 4 + 3
		  8 + 1 + 4 + 3 + 2
		  8 + 1 + 4 + 3 + 2 + 1
		  1
		  1 + 4
		  1 + 4 + 3
		  1 + 4 + 3 + 2
		  1 + 4 + 3 + 2 + 1
		  4
		  4 + 3
		  4 + 3 + 2
		  4 + 3 + 2 + 1
		  3
		  3 + 2
		  3 + 2 + 1
		  2
		  2 + 1
		  1
		  --------------------
		  Sum of all 168
		*/
		int n = arr.Length;
		task.sumSubArray(arr, n);
	}
}

Output

 Sum 168
package main
import "fmt"
/*
    Go Program
    Sum of all subarrays of an array efficiently
*/
type SubArray struct {}
func getSubArray() * SubArray {
	var me *SubArray = &SubArray {}
	return me
}
func(this SubArray) sumSubArray(arr[] int, n int) {
	if n <= 0 {
		return
	}
	// Sum of occurrence of first element
	var sum int = arr[0] * n
	// Calculate occurrence in remaining elements
	for i := 1 ; i < n ; i++ {
		// Here
		// -----------------------------------
		// (n-i) Indicate number of element in
		// current to last element.
		// (i + 1) Indicate number of elements
		// between start (0) to current.
		sum += (arr[i]) * ((n - i) * (i + 1))
	}
	// Display calculated result
	fmt.Print("\n Sum ", sum)
}
func main() {
	var task * SubArray = getSubArray()
	var arr = [] int {
		8,
		1,
		4,
		3,
		2,
		1,
	}
	/*
	  arr = [8, 1, 4, 3, 2, 1]
	  ---------------------------
	  8
	  8 + 1
	  8 + 1 + 4
	  8 + 1 + 4 + 3
	  8 + 1 + 4 + 3 + 2
	  8 + 1 + 4 + 3 + 2 + 1
	  1
	  1 + 4
	  1 + 4 + 3
	  1 + 4 + 3 + 2
	  1 + 4 + 3 + 2 + 1
	  4
	  4 + 3
	  4 + 3 + 2
	  4 + 3 + 2 + 1
	  3
	  3 + 2
	  3 + 2 + 1
	  2
	  2 + 1
	  1
	  --------------------
	  Sum of all 168
	*/
	var n int = len(arr)
	task.sumSubArray(arr, n)
}

Output

 Sum 168
<?php
/*
    Php Program
    Sum of all subarrays of an array efficiently
*/
class SubArray
{
	public	function sumSubArray($arr, $n)
	{
		if ($n <= 0)
		{
			return;
		}
		// Sum of occurrence of first element
		$sum = $arr[0] * $n;
		// Calculate occurrence in remaining elements
		for ($i = 1; $i < $n; ++$i)
		{
			// Here
			// -----------------------------------
			// (n-i) Indicate number of element in
			// current to last element.
			// (i + 1) Indicate number of elements
			// between start (0) to current.
			$sum += ($arr[$i]) * (($n - $i) * ($i + 1));
		}
		// Display calculated result
		echo("\n Sum ".$sum);
	}
}

function main()
{
	$task = new SubArray();
	$arr = array(8, 1, 4, 3, 2, 1);
	/*
	  arr = [8, 1, 4, 3, 2, 1]
	  ---------------------------
	  8
	  8 + 1
	  8 + 1 + 4
	  8 + 1 + 4 + 3
	  8 + 1 + 4 + 3 + 2
	  8 + 1 + 4 + 3 + 2 + 1
	  1
	  1 + 4
	  1 + 4 + 3
	  1 + 4 + 3 + 2
	  1 + 4 + 3 + 2 + 1
	  4
	  4 + 3
	  4 + 3 + 2
	  4 + 3 + 2 + 1
	  3
	  3 + 2
	  3 + 2 + 1
	  2
	  2 + 1
	  1
	  --------------------
	  Sum of all 168
	*/
	$n = count($arr);
	$task->sumSubArray($arr, $n);
}
main();

Output

 Sum 168
/*
    Node JS Program
    Sum of all subarrays of an array efficiently
*/
class SubArray
{
	sumSubArray(arr, n)
	{
		if (n <= 0)
		{
			return;
		}
		// Sum of occurrence of first element
		var sum = arr[0] * n;
		// Calculate occurrence in remaining elements
		for (var i = 1; i < n; ++i)
		{
			// Here
			// -----------------------------------
			// (n-i) Indicate number of element in
			// current to last element.
			// (i + 1) Indicate number of elements
			// between start (0) to current.
			sum += (arr[i]) * ((n - i) * (i + 1));
		}
		// Display calculated result
		process.stdout.write("\n Sum " + sum);
	}
}

function main()
{
	var task = new SubArray();
	var arr = [8, 1, 4, 3, 2, 1];
	/*
	  arr = [8, 1, 4, 3, 2, 1]
	  ---------------------------
	  8
	  8 + 1
	  8 + 1 + 4
	  8 + 1 + 4 + 3
	  8 + 1 + 4 + 3 + 2
	  8 + 1 + 4 + 3 + 2 + 1
	  1
	  1 + 4
	  1 + 4 + 3
	  1 + 4 + 3 + 2
	  1 + 4 + 3 + 2 + 1
	  4
	  4 + 3
	  4 + 3 + 2
	  4 + 3 + 2 + 1
	  3
	  3 + 2
	  3 + 2 + 1
	  2
	  2 + 1
	  1
	  --------------------
	  Sum of all 168
	*/
	var n = arr.length;
	task.sumSubArray(arr, n);
}
main();

Output

 Sum 168
#    Python 3 Program
#    Sum of all subarrays of an array efficiently
class SubArray :
	def sumSubArray(self, arr, n) :
		if (n <= 0) :
			return
		
		#  Sum of occurrence of first element
		sum = arr[0] * n
		i = 1
		#  Calculate occurrence in remaining elements
		while (i < n) :
			#  Here
			#  -----------------------------------
			#  (n-i) Indicate number of element in
			#  current to last element.
			#  (i + 1) Indicate number of elements
			#  between start (0) to current.
			sum += (arr[i]) * ((n - i) * (i + 1))
			i += 1
		
		#  Display calculated result
		print("\n Sum ", sum, end = "")
	

def main() :
	task = SubArray()
	arr = [8, 1, 4, 3, 2, 1]
	#  arr = [8, 1, 4, 3, 2, 1]
	#  ---------------------------
	#  8
	#  8 + 1
	#  8 + 1 + 4
	#  8 + 1 + 4 + 3
	#  8 + 1 + 4 + 3 + 2
	#  8 + 1 + 4 + 3 + 2 + 1
	#  1
	#  1 + 4
	#  1 + 4 + 3
	#  1 + 4 + 3 + 2
	#  1 + 4 + 3 + 2 + 1
	#  4
	#  4 + 3
	#  4 + 3 + 2
	#  4 + 3 + 2 + 1
	#  3
	#  3 + 2
	#  3 + 2 + 1
	#  2
	#  2 + 1
	#  1
	#  --------------------
	#  Sum of all 168
	n = len(arr)
	task.sumSubArray(arr, n)

if __name__ == "__main__": main()

Output

 Sum  168
#    Ruby Program
#    Sum of all subarrays of an array efficiently
class SubArray 
	def sumSubArray(arr, n) 
		if (n <= 0) 
			return
		end

		#  Sum of occurrence of first element
		sum = arr[0] * n
		i = 1
		#  Calculate occurrence in remaining elements
		while (i < n) 
			#  Here
			#  -----------------------------------
			#  (n-i) Indicate number of element in
			#  current to last element.
			#  (i + 1) Indicate number of elements
			#  between start (0) to current.
			sum += (arr[i]) * ((n - i) * (i + 1))
			i += 1
		end

		#  Display calculated result
		print("\n Sum ", sum)
	end

end

def main() 
	task = SubArray.new()
	arr = [8, 1, 4, 3, 2, 1]
	#  arr = [8, 1, 4, 3, 2, 1]
	#  ---------------------------
	#  8
	#  8 + 1
	#  8 + 1 + 4
	#  8 + 1 + 4 + 3
	#  8 + 1 + 4 + 3 + 2
	#  8 + 1 + 4 + 3 + 2 + 1
	#  1
	#  1 + 4
	#  1 + 4 + 3
	#  1 + 4 + 3 + 2
	#  1 + 4 + 3 + 2 + 1
	#  4
	#  4 + 3
	#  4 + 3 + 2
	#  4 + 3 + 2 + 1
	#  3
	#  3 + 2
	#  3 + 2 + 1
	#  2
	#  2 + 1
	#  1
	#  --------------------
	#  Sum of all 168
	n = arr.length
	task.sumSubArray(arr, n)
end

main()

Output

 Sum 168
/*
    Scala Program
    Sum of all subarrays of an array efficiently
*/
class SubArray()
{
	def sumSubArray(arr: Array[Int], n: Int): Unit = {
		if (n <= 0)
		{
			return;
		}
		// Sum of occurrence of first element
		var sum: Int = arr(0) * n;
		var i: Int = 1;
		// Calculate occurrence in remaining elements
		while (i < n)
		{
			// Here
			// -----------------------------------
			// (n-i) Indicate number of element in
			// current to last element.
			// (i + 1) Indicate number of elements
			// between start (0) to current.
			sum += (arr(i)) * ((n - i) * (i + 1));
			i += 1;
		}
		// Display calculated result
		print("\n Sum " + sum);
	}
}
object Main
{
	def main(args: Array[String]): Unit = {
		var task: SubArray = new SubArray();
		var arr: Array[Int] = Array(8, 1, 4, 3, 2, 1);
		/*
		  arr = [8, 1, 4, 3, 2, 1]
		  ---------------------------
		  8
		  8 + 1
		  8 + 1 + 4
		  8 + 1 + 4 + 3
		  8 + 1 + 4 + 3 + 2
		  8 + 1 + 4 + 3 + 2 + 1
		  1
		  1 + 4
		  1 + 4 + 3
		  1 + 4 + 3 + 2
		  1 + 4 + 3 + 2 + 1
		  4
		  4 + 3
		  4 + 3 + 2
		  4 + 3 + 2 + 1
		  3
		  3 + 2
		  3 + 2 + 1
		  2
		  2 + 1
		  1
		  --------------------
		  Sum of all 168
		*/
		var n: Int = arr.length;
		task.sumSubArray(arr, n);
	}
}

Output

 Sum 168
import Foundation;
/*
    Swift 4 Program
    Sum of all subarrays of an array efficiently
*/
class SubArray
{
	func sumSubArray(_ arr: [Int], _ n: Int)
	{
		if (n <= 0)
		{
			return;
		}
		// Sum of occurrence of first element
		var sum: Int = arr[0] * n;
		var i: Int = 1;
		// Calculate occurrence in remaining elements
		while (i < n)
		{
			// Here
			// -----------------------------------
			// (n-i) Indicate number of element in
			// current to last element.
			// (i + 1) Indicate number of elements
			// between start (0) to current.
			sum += (arr[i]) * ((n - i) * (i + 1));
			i += 1;
		}
		// Display calculated result
		print("\n Sum ", sum, terminator: "");
	}
}
func main()
{
	let task: SubArray = SubArray();
	let arr: [Int] = [8, 1, 4, 3, 2, 1];
	/*
	  arr = [8, 1, 4, 3, 2, 1]
	  ---------------------------
	  8
	  8 + 1
	  8 + 1 + 4
	  8 + 1 + 4 + 3
	  8 + 1 + 4 + 3 + 2
	  8 + 1 + 4 + 3 + 2 + 1
	  1
	  1 + 4
	  1 + 4 + 3
	  1 + 4 + 3 + 2
	  1 + 4 + 3 + 2 + 1
	  4
	  4 + 3
	  4 + 3 + 2
	  4 + 3 + 2 + 1
	  3
	  3 + 2
	  3 + 2 + 1
	  2
	  2 + 1
	  1
	  --------------------
	  Sum of all 168
	*/
	let n: Int = arr.count;
	task.sumSubArray(arr, n);
}
main();

Output

 Sum  168
/*
    Kotlin Program
    Sum of all subarrays of an array efficiently
*/
class SubArray
{
	fun sumSubArray(arr: Array < Int > , n: Int): Unit
	{
		if (n <= 0)
		{
			return;
		}
		// Sum of occurrence of first element
		var sum: Int = arr[0] * n;
		var i: Int = 1;
		// Calculate occurrence in remaining elements
		while (i < n)
		{
			// Here
			// -----------------------------------
			// (n-i) Indicate number of element in
			// current to last element.
			// (i + 1) Indicate number of elements
			// between start (0) to current.
			sum += (arr[i]) * ((n - i) * (i + 1));
			i += 1;
		}
		// Display calculated result
		print("\n Sum " + sum);
	}
}
fun main(args: Array < String > ): Unit
{
	val task: SubArray = SubArray();
	val arr: Array < Int > = arrayOf(8, 1, 4, 3, 2, 1);
	/*
	  arr = [8, 1, 4, 3, 2, 1]
	  ---------------------------
	  8
	  8 + 1
	  8 + 1 + 4
	  8 + 1 + 4 + 3
	  8 + 1 + 4 + 3 + 2
	  8 + 1 + 4 + 3 + 2 + 1
	  1
	  1 + 4
	  1 + 4 + 3
	  1 + 4 + 3 + 2
	  1 + 4 + 3 + 2 + 1
	  4
	  4 + 3
	  4 + 3 + 2
	  4 + 3 + 2 + 1
	  3
	  3 + 2
	  3 + 2 + 1
	  2
	  2 + 1
	  1
	  --------------------
	  Sum of all 168
	*/
	val n: Int = arr.count();
	task.sumSubArray(arr, n);
}

Output

 Sum 168



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