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Code Circular Linked List

Sum of the nodes of a Circular Linked List

A circular linked list is a type of linked list where the last node points back to the first node, creating a circular structure. Each node in the list contains data and a reference (or "next" pointer) to the next node in the sequence. The problem at hand is to find the sum of all the node values within a given circular linked list.

Problem Statement

Given a circular linked list, we need to develop a program that calculates and outputs the sum of all the node values present in the list.


Let's consider a circular linked list with the following nodes: 1 -> 3 -> 5 -> 2 -> 6 -> 7 -> 1

In this example, the sum of all the node values is 25.

Idea to Solve the Problem

Sum of Circular Linked List

To find the sum of all node values in a circular linked list, we can traverse the list while keeping a running total of the sum. We start with the value of the first node, and then iterate through the rest of the nodes, adding their values to the running sum.


nodeSum(CircularLinkedList me):
    if me.head is null:
        return 0
    initialize sum =
    initialize temp =
    while temp is not equal to me.head:
        add to sum
        move temp to the next node
    return sum

Algorithm Explanation

  1. Check if the circular linked list is empty. If it is, return 0 as there are no nodes to sum.
  2. Initialize a variable sum with the data of the first node (
  3. Start traversing from the second node (temp =
  4. While the current node (temp) is not equal to the starting node (me.head), add the data of the current node ( to the sum.
  5. Move temp to the next node.
  6. After traversing the entire circular linked list, return the calculated sum.

Program List

Time Complexity

The time complexity of this algorithm is O(n), where n is the number of nodes in the circular linked list. We traverse the entire list once to calculate the sum.


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