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# Sum of the nodes of a Circular Linked List

A circular linked list is a type of linked list where the last node points back to the first node, creating a circular structure. Each node in the list contains data and a reference (or "next" pointer) to the next node in the sequence. The problem at hand is to find the sum of all the node values within a given circular linked list.

## Problem Statement

Given a circular linked list, we need to develop a program that calculates and outputs the sum of all the node values present in the list.

## Example

Let's consider a circular linked list with the following nodes: 1 -> 3 -> 5 -> 2 -> 6 -> 7 -> 1

In this example, the sum of all the node values is 25.

## Idea to Solve the Problem

To find the sum of all node values in a circular linked list, we can traverse the list while keeping a running total of the sum. We start with the value of the first node, and then iterate through the rest of the nodes, adding their values to the running sum.

## Pseudocode

``````nodeSum(CircularLinkedList me):
return 0
while temp is not equal to me.head:
move temp to the next node
return sum``````

## Algorithm Explanation

1. Check if the circular linked list is empty. If it is, return 0 as there are no nodes to sum.
2. Initialize a variable `sum` with the data of the first node (`me.head.data`).
3. Start traversing from the second node (`temp = me.head.next`).
4. While the current node (`temp`) is not equal to the starting node (`me.head`), add the data of the current node (`temp.data`) to the `sum`.
5. Move `temp` to the next node.
6. After traversing the entire circular linked list, return the calculated `sum`.

## Time Complexity

The time complexity of this algorithm is O(n), where n is the number of nodes in the circular linked list. We traverse the entire list once to calculate the sum.

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