Sum of all minimum occurring elements in an Array

Here given code implementation process.

import java.util.HashMap;
/*
    Java program for
    Sum of all minimum occurring elements in an Array
*/
public class Occurrence
{
    public void minOccurrenceSum(int[] arr, int n)
    {
        int sum = 0;
        int min = n;
        HashMap < Integer, Integer > record = 
          new HashMap < Integer, Integer > ();
        // Count frequency of array elements
        for (int i = 0; i < n; ++i)
        {
            if (record.containsKey(arr[i]))
            {
              	// Increase the frequency
                record.put(arr[i], record.get(arr[i]) + 1);
            }
            else
            {
              	// Get most occuring element frequency
                record.put(arr[i], 1);
            }
        }
        // Find minimum frequency of array elements
        for (int v: record.keySet())
        {
            if (record.get(v) < min)
            {
                min = record.get(v);
            }
        }
        // Sum of elements which are appear minimum times
        for (int v: record.keySet())
        {
            if (record.get(v) == min)
            {	
                // Sum of minimum occurring element
                sum += (v * min);
            }
        }
        // Display sum
        System.out.println(" Result : " + sum);
    }
    public static void main(String[] args)
    {
        Occurrence task = new Occurrence();
        int[] arr = {
            6 , 2 , 4 , 6 , -1 , 6 , 8 , 8 , 8 , 6 , -1 , 2 , 4
        };
        int n = arr.length;
        /*
           [2+2]          =   4
           [4+4]          =   8 
           [-1+(-1)]      =  -2
           ------------------------------
            Result           10
            -----------------------------
            Note minimum occuring element frequency are 2                  
        */
        task.minOccurrenceSum(arr, n);
    }
}

Output

 Result : 10
// Include header file
#include <iostream>
#include <unordered_map>
using namespace std;
/*
    C++ program for
    Sum of all minimum occurring elements in an Array
*/
class Occurrence
{
	public: void minOccurrenceSum(int arr[], int n)
	{
		int sum = 0;
		int min = n;
		unordered_map < int, int > record;
		// Count frequency of array elements
		for (int i = 0; i < n; ++i)
		{
			if (record.find(arr[i]) != record.end())
			{
				// Increase the frequency
				record[arr[i]] = record[arr[i]] + 1;
			}
			else
			{
				// Get most occuring element frequency
				record[arr[i]] = 1;
			}
		}
		// Find minimum frequency of array elements
		for (auto &v: record)
		{
			if (record[v.first] < min)
			{
				min = record[v.first];
			}
		}
		// Sum of elements which are appear minimum times
		for (auto &v: record)
		{
			if (record[v.first] == min)
			{
				// Sum of minimum occurring element
				sum += (v.first *min);
			}
		}
		// Display sum
		cout << " Result : " << sum << endl;
	}
};
int main()
{
	Occurrence *task = new Occurrence();
	int arr[] = {
		6 , 2 , 4 , 6 , -1 , 6 , 8 , 8 , 8 , 6 , -1 , 2 , 4
	};
	int n = sizeof(arr) / sizeof(arr[0]);
	/*
	   [2+2]          =   4
	   [4+4]          =   8 
	   [-1+(-1)]      =  -2
	   ------------------------------
	    Result           10
	    -----------------------------
	    Note minimum occuring element frequency are 2                  
	*/
	task->minOccurrenceSum(arr, n);
	return 0;
}

Output

 Result : 10
// Include namespace system
using System;
using System.Collections.Generic;
/*
    Csharp program for
    Sum of all minimum occurring elements in an Array
*/
public class Occurrence
{
	public void minOccurrenceSum(int[] arr, int n)
	{
		int sum = 0;
		int min = n;
		Dictionary < int, int > record = 
          new Dictionary < int, int > ();
		// Count frequency of array elements
		for (int i = 0; i < n; ++i)
		{
			if (record.ContainsKey(arr[i]))
			{
				// Increase the frequency
				record[arr[i]] = record[arr[i]] + 1;
			}
			else
			{
				// Get most occuring element frequency
				record.Add(arr[i], 1);
			}
		}
		// Find minimum frequency of array elements
		foreach(KeyValuePair < int, int > v in record)
		{
			if (v.Value < min)
			{
				min = v.Value;
			}
		}
		// Sum of elements which are appear minimum times
		foreach(KeyValuePair < int, int > v in record)
		{
			if (v.Value == min)
			{
				// Sum of minimum occurring element
				sum += (v.Key * min);
			}
		}
		// Display sum
		Console.WriteLine(" Result : " + sum);
	}
	public static void Main(String[] args)
	{
		Occurrence task = new Occurrence();
		int[] arr = {
			6 , 2 , 4 , 6 , -1 , 6 , 8 , 
            8 , 8 , 6 , -1 , 2 , 4
		};
		int n = arr.Length;
		/*
		   [2+2]          =   4
		   [4+4]          =   8 
		   [-1+(-1)]      =  -2
		   ------------------------------
		    Result           10
		    -----------------------------
		    Note minimum occuring element frequency are 2                  
		*/
		task.minOccurrenceSum(arr, n);
	}
}

Output

 Result : 10
package main
import "fmt"
/*
    Go program for
    Sum of all minimum occurring elements in an Array
*/

func minOccurrenceSum(arr[] int, n int) {
	var sum int = 0
	var min int = n
	var record = make(map[int] int)
	// Count frequency of array elements
	for i := 0 ; i < n ; i++ {
		if _, found := record[arr[i]] ; found {
			// Increase the frequency
			record[arr[i]] = record[arr[i]] + 1
		} else {
			// Get most occuring element frequency
			record[arr[i]] = 1
		}
	}
	// Find minimum frequency of array elements
	for _, v := range record {
		if v < min {
			min = v
		}
	}
	// Sum of elements which are appear minimum times
	for k, v := range record {
		if v == min {
			// Sum of minimum occurring element
			sum += (k * min)
		}
	}
	// Display sum
	fmt.Println(" Result : ", sum)
}
func main() {

	var arr = [] int {6 , 2 , 4 , 6 , -1 , 6 , 
					  8 , 8 , 8 , 6 , -1 , 2 , 4}
	var n int = len(arr)
	/*
	   [2+2]          =   4
	   [4+4]          =   8 
	   [-1+(-1)]      =  -2
	   ------------------------------
	    Result           10
	    -----------------------------
	    Note minimum occuring element frequency are 2                  
	*/
	minOccurrenceSum(arr, n)
}

Output

 Result : 10
<?php
/*
    Php program for
    Sum of all minimum occurring elements in an Array
*/
class Occurrence
{
	public	function minOccurrenceSum($arr, $n)
	{
		$sum = 0;
		$min = $n;
		$record = array();
		// Count frequency of array elements
		for ($i = 0; $i < $n; ++$i)
		{
			if (array_key_exists($arr[$i], $record))
			{
				// Increase the frequency
				$record[$arr[$i]] = $record[$arr[$i]] + 1;
			}
			else
			{
				// Get most occuring element frequency
				$record[$arr[$i]] = 1;
			}
		}
		// Find minimum frequency of array elements
		foreach($record as $key => $value)
		{
			if ($value < $min)
			{
				$min = $value;
			}
		}
		// Sum of elements which are appear minimum times
		foreach($record as $key => $value)
		{
			if ($value == $min)
			{
				// Sum of minimum occurring element
				$sum += ($key * $min);
			}
		}
		// Display sum
		echo(" Result : ".$sum."\n");
	}
}

function main()
{
	$task = new Occurrence();
	$arr = array(6, 2, 4, 6, -1, 6, 8, 8, 8, 6, -1, 2, 4);
	$n = count($arr);
	/*
	   [2+2]          =   4
	   [4+4]          =   8 
	   [-1+(-1)]      =  -2
	   ------------------------------
	    Result           10
	    -----------------------------
	    Note minimum occuring element frequency are 2                  
	*/
	$task->minOccurrenceSum($arr, $n);
}
main();

Output

 Result : 10
/*
    Node JS program for
    Sum of all minimum occurring elements in an Array
*/
class Occurrence
{
	minOccurrenceSum(arr, n)
	{
		var sum = 0;
		var min = n;
		var record = new Map();
		// Count frequency of array elements
		for (var i = 0; i < n; ++i)
		{
			if (record.has(arr[i]))
			{
				// Increase the frequency
				record.set(arr[i], record.get(arr[i]) + 1);
			}
			else
			{
				// Get most occuring element frequency
				record.set(arr[i], 1);
			}
		}
		// Find minimum frequency of array elements
		for (let [key, value] of record)
		{
			if (value < min)
			{
				min = value;
			}
		}
		// Sum of elements which are appear minimum times
		for (let [key, value] of record)
		{
			if (value == min)
			{
				// Sum of minimum occurring element
				sum += (key * min);
			}
		}
		// Display sum
		console.log(" Result : " + sum);
	}
}

function main()
{
	var task = new Occurrence();
	var arr = [6, 2, 4, 6, -1, 6, 8, 8, 8, 6, -1, 2, 4];
	var n = arr.length;
	/*
	   [2+2]          =   4
	   [4+4]          =   8 
	   [-1+(-1)]      =  -2
	   ------------------------------
	    Result           10
	    -----------------------------
	    Note minimum occuring element frequency are 2                  
	*/
	task.minOccurrenceSum(arr, n);
}
main();

Output

 Result : 10
#    Python 3 program for
#    Sum of all minimum occurring elements in an Array
class Occurrence :
	def minOccurrenceSum(self, arr, n) :
		sum = 0
		min = n
		record = dict()
		i = 0
		#  Count frequency of list elements
		while (i < n) :
			if ((arr[i] in record.keys())) :
				#  Increase the frequency
				record[arr[i]] = record.get(arr[i]) + 1
			else :
				#  Get most occuring element frequency
				record[arr[i]] = 1
			
			i += 1
		
		for key, value in record.items() :
			if (value < min) :
				min = value
			
		
		for key, value in record.items() :
			if (value == min) :
				#  Sum of minimum occurring element
				sum += (key * min)
			
		
		#  Display sum
		print(" Result : ", sum)
	

def main() :
	task = Occurrence()
	arr = [6, 2, 4, 6, -1, 6, 8, 8, 8, 6, -1, 2, 4]
	n = len(arr)
	#   [2+2]          =   4
	#   [4+4]          =   8 
	#   [-1+(-1)]      =  -2
	#   ------------------------------
	#    Result           10
	#    -----------------------------
	#    Note minimum occuring element frequency are 2                  
	task.minOccurrenceSum(arr, n)

if __name__ == "__main__": main()

Output

 Result :  10
#    Ruby program for
#    Sum of all minimum occurring elements in an Array
class Occurrence 
	def minOccurrenceSum(arr, n) 
		sum = 0
		min = n
		record = Hash.new()
		i = 0
		#  Count frequency of array elements
		while (i < n) 
			if (record.key?(arr[i])) 
				#  Increase the frequency
				record[arr[i]] = record[arr[i]] + 1
			else
 
				#  Get most occuring element frequency
				record[arr[i]] = 1
			end

			i += 1
		end

		#  Find minimum frequency of array elements
		record.each { | key, value |
			if (value < min) 
				min = value
			end

		}
		#  Sum of elements which are appear minimum times
		record.each { | key, value |
			if (value == min) 
				#  Sum of minimum occurring element
				sum += (key * min)
			end

		}
		#  Display sum
		print(" Result : ", sum, "\n")
	end

end

def main() 
	task = Occurrence.new()
	arr = [6, 2, 4, 6, -1, 6, 8, 8, 8, 6, -1, 2, 4]
	n = arr.length
	#   [2+2]          =   4
	#   [4+4]          =   8 
	#   [-1+(-1)]      =  -2
	#   ------------------------------
	#    Result           10
	#    -----------------------------
	#    Note minimum occuring element frequency are 2                  
	task.minOccurrenceSum(arr, n)
end

main()

Output

 Result : 10
import scala.collection.mutable._;
/*
    Scala program for
    Sum of all minimum occurring elements in an Array
*/
class Occurrence()
{
	def minOccurrenceSum(arr: Array[Int], n: Int): Unit = {
		var sum: Int = 0;
		var min: Int = n;
		var record: HashMap[Int, Int] = new HashMap[Int, Int]();
		var i: Int = 0;
		// Count frequency of array elements
		while (i < n)
		{
			if (record.contains(arr(i)))
			{
				// Increase the frequency
				record.addOne(arr(i), record.get(arr(i)).get + 1);
			}
			else
			{
				// Get most occuring element frequency
				record.addOne(arr(i), 1);
			}
			i += 1;
		}
		// Find minimum frequency of array elements
		for ((key, value) <- record)
		{
			if (value < min)
			{
				min = value;
			}
		}
		// Sum of elements which are appear minimum times
		for ((key, value) <- record)
		{
			if (value == min)
			{
				// Sum of minimum occurring element
				sum += (key * min);
			}
		}
		// Display sum
		println(" Result : " + sum);
	}
}
object Main
{
	def main(args: Array[String]): Unit = {
		var task: Occurrence = new Occurrence();
		var arr: Array[Int] = 
          Array(6, 2, 4, 6, -1, 6, 8, 8, 8, 6, -1, 2, 4);
		var n: Int = arr.length;
		/*
		   [2+2]          =   4
		   [4+4]          =   8 
		   [-1+(-1)]      =  -2
		   ------------------------------
		    Result           10
		    -----------------------------
		    Note minimum occuring element frequency are 2                  
		*/
		task.minOccurrenceSum(arr, n);
	}
}

Output

 Result : 10
import Foundation;
/*
    Swift 4 program for
    Sum of all minimum occurring elements in an Array
*/
class Occurrence
{
	func minOccurrenceSum(_ arr: [Int], _ n: Int)
	{
		var sum: Int = 0;
		var min: Int = n;
		var record = [Int : Int]();
		var i: Int = 0;
		// Count frequency of array elements
		while (i < n)
		{
			if (record.keys.contains(arr[i]))
			{
				// Increase the frequency
				record[arr[i]] = record[arr[i]]! + 1;
			}
			else
			{
				// Get most occuring element frequency
				record[arr[i]] = 1;
			}
			i += 1;
		}
		// Find minimum frequency of array elements
		for (_, value) in record
		{
			if (value < min)
			{
				min = value;
			}
		}
		// Sum of elements which are appear minimum times
		for (key, value) in record
		{
			if (value == min)
			{
				// Sum of minimum occurring element
				sum += (key * min);
			}
		}
		// Display sum
		print(" Result : ", sum);
	}
}
func main()
{
	let task: Occurrence = Occurrence();
	let arr: [Int] = [6, 2, 4, 6, -1, 6, 8, 8, 8, 6, -1, 2, 4];
	let n: Int = arr.count;
	/*
	   [2+2]          =   4
	   [4+4]          =   8 
	   [-1+(-1)]      =  -2
	   ------------------------------
	    Result           10
	    -----------------------------
	    Note minimum occuring element frequency are 2                  
	*/
	task.minOccurrenceSum(arr, n);
}
main();

Output

 Result :  10
/*
    Kotlin program for
    Sum of all minimum occurring elements in an Array
*/
class Occurrence
{
	fun minOccurrenceSum(arr: Array < Int > , n: Int): Unit
	{
		var sum: Int = 0;
		var min: Int = n;
		val record = HashMap < Int, Int > ();
		var i: Int = 0;
		// Count frequency of array elements
		while (i < n)
		{
			if (record.containsKey(arr[i]))
			{
				// Increase the frequency
				record.put(arr[i], record.getValue(arr[i]) + 1);
			}
			else
			{
				// Get most occuring element frequency
				record.put(arr[i], 1);
			}
			i += 1;
		}
		// Find minimum frequency of array elements
		for ((_, value) in record)
		{
			if (value < min)
			{
				min = value;
			}
		}
		// Sum of elements which are appear minimum times
		for ((key, value) in record)
		{
			if (value == min)
			{
				// Sum of minimum occurring element
				sum += (key * min);
			}
		}
		// Display sum
		println(" Result : " + sum);
	}
}
fun main(args: Array < String > ): Unit
{
	val task: Occurrence = Occurrence();
	val arr: Array < Int > = arrayOf(
      6, 2, 4, 6, -1, 6, 8, 8, 8, 6, -1, 2, 4
    );
	val n: Int = arr.count();
	/*
	   [2+2]          =   4
	   [4+4]          =   8 
	   [-1+(-1)]      =  -2
	   ------------------------------
	    Result           10
	    -----------------------------
	    Note minimum occuring element frequency are 2                  
	*/
	task.minOccurrenceSum(arr, n);
}

Output

 Result : 10


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