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Sum of even numbers at even position

Here given code implementation process.

// C Program
// Sum of even numbers at even position
#include <stdio.h>
// Display array elements
void printArr(int arr[], int n)
{
    for (int i = 0; i < n; ++i)
    {
        printf("  %d", arr[i]);
    }
    printf("\n");
}
void evenAtEvenLocation(int arr[], int n)
{
    int sum = 0;
    // This loop are visiting the array element from 0 to n-1.
    // And sum of elements which are exist in Even position.
    for (int i = 0; i < n; ++i)
    {
        if ((i % 2) == 0 && (arr[i] % 2) == 0)
        {
            sum += arr[i];
        }
    }
    printArr(arr, n);
    printf(" Result : %d \n", sum);
}
int main()
{
    // Sorted Arrays
    int a[] = {
        3 , 1 , 2 , 1 , 6
    };
    int b[] = {
        6 , 1 , 1 , -3 , -2 , 0 , 1 , 2
    };
    // Get the size
    int l1 = sizeof(a) / sizeof(a[0]);
    int l2 = sizeof(b) / sizeof(b[0]);
    // Test A
    // arr = [0, 1, 0,1]
    // --------------------------
    //  index  Value
    //    0     [3]  Index even but value not even
    //    ➀     [1]
    //    ➁     [2]  Index even and value is even  
    //    ➂     [1]
    //    ➃     [6]  Index even and value is even  [6]
    // ---------------
    //  Total :  [2] + [6] = 8                            
    evenAtEvenLocation(a, l1);
    // Test B
    // arr = [2, 1, 1, -2, 1, 0, 1, 2]
    // --------------------------
    //   Index    Value
    //    0       [6]     Index even and value is even  
    //    ➀       [1]
    //    ➁       [1]     Index even but value not even
    //    ➂       [-3]        
    //    ➃       [-2]    Index even and value is even       
    //    ➄       [0]             
    //    ➅       [1]     Index even but value not even   
    //    ➆       [2]           
    // ---------------
    //  Total : [6] + [-2]
    evenAtEvenLocation(b, l2);
    return 0;
}

Output

  3  1  2  1  6
 Result : 8
  6  1  1  -3  -2  0  1  2
 Result : 4
/*
    Java Program
    Sum of even numbers at even position
*/
public class EvenSum
{
	// Display array elements
	public void printArr(int[] arr, int n)
	{
		for (int i = 0; i < n; ++i)
		{
			System.out.print(" " + arr[i]);
		}
		System.out.print("\n");
	}
	public void evenAtEvenLocation(int[] arr, int n)
	{
		int sum = 0;
		// This loop are visiting the array element from 0 to n-1.
		// And sum of elements which are exist in Even position.
		for (int i = 0; i < n; ++i)
		{
			if ((i % 2) == 0 && (arr[i] % 2) == 0)
			{
				sum += arr[i];
			}
		}
		printArr(arr, n);
		System.out.print(" Result : " + sum + " \n");
	}
	public static void main(String[] args)
	{
		EvenSum task = new EvenSum();
		// Sorted Arrays
		int[] a =  {
			3 , 1 , 2 , 1 , 6
		};
		int[] b =  {
			6 , 1 , 1 , -3 , -2 , 0 , 1 , 2
		};
		// Get the size
		int l1 = a.length;
		int l2 = b.length;
		// Test A
		// arr = [0, 1, 0,1]
		// --------------------------
		//  index  Value
		//    0      [3]  Index even but value not even
		//    ➀     [1]
		//    ➁     [2]  Index even and value is even  
		//    ➂     [1]
		//    ➃     [6]  Index even and value is even  [6]
		// ---------------
		//  Total :  [2] + [6] = 8                            
		task.evenAtEvenLocation(a, l1);
		// Test B
		// arr = [2, 1, 1, -2, 1, 0, 1, 2]
		// --------------------------
		//   Index    Value
		//    0        [6]     Index even and value is even  
		//    ➀       [1]
		//    ➁       [1]     Index even but value not even
		//    ➂       [-3]        
		//    ➃       [-2]    Index even and value is even       
		//    ➄       [0]             
		//    ➅       [1]     Index even but value not even   
		//    ➆       [2]           
		// ---------------
		//  Total : [6] + [-2]
		task.evenAtEvenLocation(b, l2);
	}
}

Output

 3 1 2 1 6
 Result : 8
 6 1 1 -3 -2 0 1 2
 Result : 4
// Include header file
#include <iostream>
using namespace std;
/*
    C++ Program
    Sum of even numbers at even position
*/
class EvenSum
{
	public:
		// Display array elements
		void printArr(int arr[], int n)
		{
			for (int i = 0; i < n; ++i)
			{
				cout << " " << arr[i];
			}
			cout << "\n";
		}
	void evenAtEvenLocation(int arr[], int n)
	{
		int sum = 0;
		// This loop are visiting the array element from 0 to n-1.
		// And sum of elements which are exist in Even position.
		for (int i = 0; i < n; ++i)
		{
			if ((i % 2) == 0 && (arr[i] % 2) == 0)
			{
				sum += arr[i];
			}
		}
		this->printArr(arr, n);
		cout << " Result : " << sum << " \n";
	}
};
int main()
{
	EvenSum *task = new EvenSum();
	// Sorted Arrays
	int a[] = {
		3 , 1 , 2 , 1 , 6
	};
	int b[] = {
		6 , 1 , 1 , -3 , -2 , 0 , 1 , 2
	};
	// Get the size
	int l1 = sizeof(a) / sizeof(a[0]);
	int l2 = sizeof(b) / sizeof(b[0]);
	// Test A
	// arr = [0, 1, 0,1]
	// --------------------------
	//  index  Value
	//    0      [3]  Index even but value not even
	//    ➀     [1]
	//    ➁     [2]  Index even and value is even  
	//    ➂     [1]
	//    ➃     [6]  Index even and value is even  [6]
	// ---------------
	//  Total :  [2] + [6] = 8                            
	task->evenAtEvenLocation(a, l1);
	// Test B
	// arr = [2, 1, 1, -2, 1, 0, 1, 2]
	// --------------------------
	//   Index    Value
	//    0        [6]     Index even and value is even  
	//    ➀       [1]
	//    ➁       [1]     Index even but value not even
	//    ➂       [-3]        
	//    ➃       [-2]    Index even and value is even       
	//    ➄       [0]             
	//    ➅       [1]     Index even but value not even   
	//    ➆       [2]           
	// ---------------
	//  Total : [6] + [-2]
	task->evenAtEvenLocation(b, l2);
	return 0;
}

Output

 3 1 2 1 6
 Result : 8
 6 1 1 -3 -2 0 1 2
 Result : 4
// Include namespace system
using System;
/*
    Csharp Program
    Sum of even numbers at even position
*/
public class EvenSum
{
	// Display array elements
	public void printArr(int[] arr, int n)
	{
		for (int i = 0; i < n; ++i)
		{
			Console.Write(" " + arr[i]);
		}
		Console.Write("\n");
	}
	public void evenAtEvenLocation(int[] arr, int n)
	{
		int sum = 0;
		// This loop are visiting the array element from 0 to n-1.
		// And sum of elements which are exist in Even position.
		for (int i = 0; i < n; ++i)
		{
			if ((i % 2) == 0 && (arr[i] % 2) == 0)
			{
				sum += arr[i];
			}
		}
		this.printArr(arr, n);
		Console.Write(" Result : " + sum + " \n");
	}
	public static void Main(String[] args)
	{
		EvenSum task = new EvenSum();
		// Sorted Arrays
		int[] a = {
			3 , 1 , 2 , 1 , 6
		};
		int[] b = {
			6 , 1 , 1 , -3 , -2 , 0 , 1 , 2
		};
		// Get the size
		int l1 = a.Length;
		int l2 = b.Length;
		// Test A
		// arr = [0, 1, 0,1]
		// --------------------------
		//  index  Value
		//    0      [3]  Index even but value not even
		//    ➀     [1]
		//    ➁     [2]  Index even and value is even  
		//    ➂     [1]
		//    ➃     [6]  Index even and value is even  [6]
		// ---------------
		//  Total :  [2] + [6] = 8                            
		task.evenAtEvenLocation(a, l1);
		// Test B
		// arr = [2, 1, 1, -2, 1, 0, 1, 2]
		// --------------------------
		//   Index    Value
		//    0        [6]     Index even and value is even  
		//    ➀       [1]
		//    ➁       [1]     Index even but value not even
		//    ➂       [-3]        
		//    ➃       [-2]    Index even and value is even       
		//    ➄       [0]             
		//    ➅       [1]     Index even but value not even   
		//    ➆       [2]           
		// ---------------
		//  Total : [6] + [-2]
		task.evenAtEvenLocation(b, l2);
	}
}

Output

 3 1 2 1 6
 Result : 8
 6 1 1 -3 -2 0 1 2
 Result : 4
package main
import "fmt"
/*
    Go Program
    Sum of even numbers at even position
*/

// Display array elements
func printArr(arr[] int, n int) {
	for i := 0 ; i < n ; i++ {
		fmt.Print(" ", arr[i])
	}
	fmt.Print("\n")
}
func evenAtEvenLocation(arr[] int, n int) {
	var sum int = 0
	// This loop are visiting the array element from 0 to n-1.
	// And sum of elements which are exist in Even position.
	for i := 0 ; i < n ; i++ {
		if (i % 2) == 0 && (arr[i] % 2) == 0 {
			sum += arr[i]
		}
	}
	printArr(arr, n)
	fmt.Print(" Result : ", sum, " \n")
}
func main() {

	// Sorted Arrays
	var a = [] int { 3 , 1 , 2 , 1 , 6 }
	var b = [] int { 6 , 1 , 1 , -3 , -2 , 0 , 1 , 2 }
	// Get the size
	var l1 int = len(a)
	var l2 int = len(b)
	// Test A
	// arr = [0, 1, 0,1]
	// --------------------------
	//  index  Value
	//    0      [3]  Index even but value not even
	//    ➀     [1]
	//    ➁     [2]  Index even and value is even  
	//    ➂     [1]
	//    ➃     [6]  Index even and value is even  [6]
	// ---------------
	//  Total :  [2] + [6] = 8                            
	evenAtEvenLocation(a, l1)
	// Test B
	// arr = [2, 1, 1, -2, 1, 0, 1, 2]
	// --------------------------
	//   Index    Value
	//    0        [6]     Index even and value is even  
	//    ➀       [1]
	//    ➁       [1]     Index even but value not even
	//    ➂       [-3]        
	//    ➃       [-2]    Index even and value is even       
	//    ➄       [0]             
	//    ➅       [1]     Index even but value not even   
	//    ➆       [2]           
	// ---------------
	//  Total : [6] + [-2]
	evenAtEvenLocation(b, l2)
}

Output

 3 1 2 1 6
 Result : 8
 6 1 1 -3 -2 0 1 2
 Result : 4
<?php
/*
    Php Program
    Sum of even numbers at even position
*/
class EvenSum
{
	// Display array elements
	public	function printArr($arr, $n)
	{
		for ($i = 0; $i < $n; ++$i)
		{
			echo(" ".$arr[$i]);
		}
		echo("\n");
	}
	public	function evenAtEvenLocation($arr, $n)
	{
		$sum = 0;
		// This loop are visiting the array element from 0 to n-1.
		// And sum of elements which are exist in Even position.
		for ($i = 0; $i < $n; ++$i)
		{
			if (($i % 2) == 0 && ($arr[$i] % 2) == 0)
			{
				$sum += $arr[$i];
			}
		}
		$this->printArr($arr, $n);
		echo(" Result : ".$sum.
			" \n");
	}
}

function main()
{
	$task = new EvenSum();
	// Sorted Arrays
	$a = array(3, 1, 2, 1, 6);
	$b = array(6, 1, 1, -3, -2, 0, 1, 2);
	// Get the size
	$l1 = count($a);
	$l2 = count($b);
	// Test A
	// arr = [0, 1, 0,1]
	// --------------------------
	//  index  Value
	//    0      [3]  Index even but value not even
	//    ➀     [1]
	//    ➁     [2]  Index even and value is even  
	//    ➂     [1]
	//    ➃     [6]  Index even and value is even  [6]
	// ---------------
	//  Total :  [2] + [6] = 8                            
	$task->evenAtEvenLocation($a, $l1);
	// Test B
	// arr = [2, 1, 1, -2, 1, 0, 1, 2]
	// --------------------------
	//   Index    Value
	//    0        [6]     Index even and value is even  
	//    ➀       [1]
	//    ➁       [1]     Index even but value not even
	//    ➂       [-3]        
	//    ➃       [-2]    Index even and value is even       
	//    ➄       [0]             
	//    ➅       [1]     Index even but value not even   
	//    ➆       [2]           
	// ---------------
	//  Total : [6] + [-2]
	$task->evenAtEvenLocation($b, $l2);
}
main();

Output

 3 1 2 1 6
 Result : 8
 6 1 1 -3 -2 0 1 2
 Result : 4
/*
    Node JS Program
    Sum of even numbers at even position
*/
class EvenSum
{
	// Display array elements
	printArr(arr, n)
	{
		for (var i = 0; i < n; ++i)
		{
			process.stdout.write(" " + arr[i]);
		}
		process.stdout.write("\n");
	}
	evenAtEvenLocation(arr, n)
	{
		var sum = 0;
		// This loop are visiting the array element from 0 to n-1.
		// And sum of elements which are exist in Even position.
		for (var i = 0; i < n; ++i)
		{
			if ((i % 2) == 0 && (arr[i] % 2) == 0)
			{
				sum += arr[i];
			}
		}
		this.printArr(arr, n);
		process.stdout.write(" Result : " + sum + " \n");
	}
}

function main()
{
	var task = new EvenSum();
	// Sorted Arrays
	var a = [3, 1, 2, 1, 6];
	var b = [6, 1, 1, -3, -2, 0, 1, 2];
	// Get the size
	var l1 = a.length;
	var l2 = b.length;
	// Test A
	// arr = [0, 1, 0,1]
	// --------------------------
	//  index  Value
	//    0      [3]  Index even but value not even
	//    ➀     [1]
	//    ➁     [2]  Index even and value is even  
	//    ➂     [1]
	//    ➃     [6]  Index even and value is even  [6]
	// ---------------
	//  Total :  [2] + [6] = 8                            
	task.evenAtEvenLocation(a, l1);
	// Test B
	// arr = [2, 1, 1, -2, 1, 0, 1, 2]
	// --------------------------
	//   Index    Value
	//    0        [6]     Index even and value is even  
	//    ➀       [1]
	//    ➁       [1]     Index even but value not even
	//    ➂       [-3]        
	//    ➃       [-2]    Index even and value is even       
	//    ➄       [0]             
	//    ➅       [1]     Index even but value not even   
	//    ➆       [2]           
	// ---------------
	//  Total : [6] + [-2]
	task.evenAtEvenLocation(b, l2);
}
main();

Output

 3 1 2 1 6
 Result : 8
 6 1 1 -3 -2 0 1 2
 Result : 4
#    Python 3 Program
#    Sum of even numbers at even position
class EvenSum :
	#  Display list elements
	def printArr(self, arr, n) :
		i = 0
		while (i < n) :
			print(" ", arr[i], end = "")
			i += 1
		
		print(end = "\n")
	
	def evenAtEvenLocation(self, arr, n) :
		sum = 0
		i = 0
		#  This loop are visiting the list element from 0 to n-1.
		#  And sum of elements which are exist in Even position.
		while (i < n) :
			if ((i % 2) == 0 and(arr[i] % 2) == 0) :
				sum += arr[i]
			
			i += 1
		
		self.printArr(arr, n)
		print(" Result : ", sum ," ")
	

def main() :
	task = EvenSum()
	#  Sorted Arrays
	a = [3, 1, 2, 1, 6]
	b = [6, 1, 1, -3, -2, 0, 1, 2]
	#  Get the size
	l1 = len(a)
	l2 = len(b)
	#  Test A
	#  arr = [0, 1, 0,1]
	#  --------------------------
	#   index  Value
	#     0      [3]  Index even but value not even
	#     ➀     [1]
	#     ➁     [2]  Index even and value is even  
	#     ➂     [1]
	#     ➃     [6]  Index even and value is even  [6]
	#  ---------------
	#   Total :  [2] + [6] = 8                            
	task.evenAtEvenLocation(a, l1)
	#  Test B
	#  arr = [2, 1, 1, -2, 1, 0, 1, 2]
	#  --------------------------
	#    Index    Value
	#     0        [6]     Index even and value is even  
	#     ➀       [1]
	#     ➁       [1]     Index even but value not even
	#     ➂       [-3]        
	#     ➃       [-2]    Index even and value is even       
	#     ➄       [0]             
	#     ➅       [1]     Index even but value not even   
	#     ➆       [2]           
	#  ---------------
	#   Total : [6] + [-2]
	task.evenAtEvenLocation(b, l2)

if __name__ == "__main__": main()

Output

  3  1  2  1  6
 Result :  8
  6  1  1  -3  -2  0  1  2
 Result :  4
#    Ruby Program
#    Sum of even numbers at even position
class EvenSum 
	#  Display array elements
	def printArr(arr, n) 
		i = 0
		while (i < n) 
			print(" ", arr[i])
			i += 1
		end

		print("\n")
	end

	def evenAtEvenLocation(arr, n) 
		sum = 0
		i = 0
		#  This loop are visiting the array element from 0 to n-1.
		#  And sum of elements which are exist in Even position.
		while (i < n) 
			if ((i % 2) == 0 && (arr[i] % 2) == 0) 
				sum += arr[i]
			end

			i += 1
		end

		self.printArr(arr, n)
		print(" Result : ", sum ," \n")
	end

end

def main() 
	task = EvenSum.new()
	#  Sorted Arrays
	a = [3, 1, 2, 1, 6]
	b = [6, 1, 1, -3, -2, 0, 1, 2]
	#  Get the size
	l1 = a.length
	l2 = b.length
	#  Test A
	#  arr = [0, 1, 0,1]
	#  --------------------------
	#   index  Value
	#     0      [3]  Index even but value not even
	#     ➀     [1]
	#     ➁     [2]  Index even and value is even  
	#     ➂     [1]
	#     ➃     [6]  Index even and value is even  [6]
	#  ---------------
	#   Total :  [2] + [6] = 8                            
	task.evenAtEvenLocation(a, l1)
	#  Test B
	#  arr = [2, 1, 1, -2, 1, 0, 1, 2]
	#  --------------------------
	#    Index    Value
	#     0        [6]     Index even and value is even  
	#     ➀       [1]
	#     ➁       [1]     Index even but value not even
	#     ➂       [-3]        
	#     ➃       [-2]    Index even and value is even       
	#     ➄       [0]             
	#     ➅       [1]     Index even but value not even   
	#     ➆       [2]           
	#  ---------------
	#   Total : [6] + [-2]
	task.evenAtEvenLocation(b, l2)
end

main()

Output

 3 1 2 1 6
 Result : 8 
 6 1 1 -3 -2 0 1 2
 Result : 4 
/*
    Scala Program
    Sum of even numbers at even position
*/
class EvenSum()
{
	// Display array elements
	def printArr(arr: Array[Int], n: Int): Unit = {
		var i: Int = 0;
		while (i < n)
		{
			print(" " + arr(i));
			i += 1;
		}
		print("\n");
	}
	def evenAtEvenLocation(arr: Array[Int], n: Int): Unit = {
		var sum: Int = 0;
		var i: Int = 0;
		// This loop are visiting the array element from 0 to n-1.
		// And sum of elements which are exist in Even position.
		while (i < n)
		{
			if ((i % 2) == 0 && (arr(i) % 2) == 0)
			{
				sum += arr(i);
			}
			i += 1;
		}
		printArr(arr, n);
		print(" Result : " + sum + " \n");
	}
}
object Main
{
	def main(args: Array[String]): Unit = {
		var task: EvenSum = new EvenSum();
		// Sorted Arrays
		var a: Array[Int] = Array(3, 1, 2, 1, 6);
		var b: Array[Int] = Array(6, 1, 1, -3, -2, 0, 1, 2);
		// Get the size
		var l1: Int = a.length;
		var l2: Int = b.length;
		// Test A
		// arr = [0, 1, 0,1]
		// --------------------------
		//  index  Value
		//    0      [3]  Index even but value not even
		//    ➀     [1]
		//    ➁     [2]  Index even and value is even  
		//    ➂     [1]
		//    ➃     [6]  Index even and value is even  [6]
		// ---------------
		//  Total :  [2] + [6] = 8                            
		task.evenAtEvenLocation(a, l1);
		// Test B
		// arr = [2, 1, 1, -2, 1, 0, 1, 2]
		// --------------------------
		//   Index    Value
		//    0        [6]     Index even and value is even  
		//    ➀       [1]
		//    ➁       [1]     Index even but value not even
		//    ➂       [-3]        
		//    ➃       [-2]    Index even and value is even       
		//    ➄       [0]             
		//    ➅       [1]     Index even but value not even   
		//    ➆       [2]           
		// ---------------
		//  Total : [6] + [-2]
		task.evenAtEvenLocation(b, l2);
	}
}

Output

 3 1 2 1 6
 Result : 8
 6 1 1 -3 -2 0 1 2
 Result : 4
import Foundation;
/*
    Swift 4 Program
    Sum of even numbers at even position
*/
class EvenSum
{
	// Display array elements
	func printArr(_ arr: [Int], _ n: Int)
	{
		var i: Int = 0;
		while (i < n)
		{
			print(" ", arr[i], terminator: "");
			i += 1;
		}
		print(terminator: "\n");
	}
	func evenAtEvenLocation(_ arr: [Int], _ n: Int)
	{
		var sum: Int = 0;
		var i: Int = 0;
		// This loop are visiting the array element from 0 to n-1.
		// And sum of elements which are exist in Even position.
		while (i < n)
		{
			if ((i % 2) == 0 && (arr[i] % 2) == 0)
			{
				sum += arr[i];
			}
			i += 1;
		}
		self.printArr(arr, n);
		print(" Result : ", sum ," ");
	}
}
func main()
{
	let task: EvenSum = EvenSum();
	// Sorted Arrays
	let a: [Int] = [3, 1, 2, 1, 6];
	let b: [Int] = [6, 1, 1, -3, -2, 0, 1, 2];
	// Get the size
	let l1: Int = a.count;
	let l2: Int = b.count;
	// Test A
	// arr = [0, 1, 0,1]
	// --------------------------
	//  index  Value
	//    0      [3]  Index even but value not even
	//    ➀     [1]
	//    ➁     [2]  Index even and value is even  
	//    ➂     [1]
	//    ➃     [6]  Index even and value is even  [6]
	// ---------------
	//  Total :  [2] + [6] = 8                            
	task.evenAtEvenLocation(a, l1);
	// Test B
	// arr = [2, 1, 1, -2, 1, 0, 1, 2]
	// --------------------------
	//   Index    Value
	//    0        [6]     Index even and value is even  
	//    ➀       [1]
	//    ➁       [1]     Index even but value not even
	//    ➂       [-3]        
	//    ➃       [-2]    Index even and value is even       
	//    ➄       [0]             
	//    ➅       [1]     Index even but value not even   
	//    ➆       [2]           
	// ---------------
	//  Total : [6] + [-2]
	task.evenAtEvenLocation(b, l2);
}
main();

Output

  3  1  2  1  6
 Result :  8
  6  1  1  -3  -2  0  1  2
 Result :  4
/*
    Kotlin Program
    Sum of even numbers at even position
*/
class EvenSum
{
	// Display array elements
	fun printArr(arr: Array < Int > , n: Int): Unit
	{
		var i: Int = 0;
		while (i < n)
		{
			print(" " + arr[i]);
			i += 1;
		}
		print("\n");
	}
	fun evenAtEvenLocation(arr: Array < Int > , n: Int): Unit
	{
		var sum: Int = 0;
		var i: Int = 0;
		// This loop are visiting the array element from 0 to n-1.
		// And sum of elements which are exist in Even position.
		while (i < n)
		{
			if ((i % 2) == 0 && (arr[i] % 2) == 0)
			{
				sum += arr[i];
			}
			i += 1;
		}
		this.printArr(arr, n);
		print(" Result : " + sum + " \n");
	}
}
fun main(args: Array < String > ): Unit
{
	val task: EvenSum = EvenSum();
	// Sorted Arrays
	val a: Array < Int > = arrayOf(3, 1, 2, 1, 6);
	val b: Array < Int > = arrayOf(6, 1, 1, -3, -2, 0, 1, 2);
	// Get the size
	val l1: Int = a.count();
	val l2: Int = b.count();
	// Test A
	// arr = [0, 1, 0,1]
	// --------------------------
	//  index  Value
	//    0      [3]  Index even but value not even
	//    ➀     [1]
	//    ➁     [2]  Index even and value is even  
	//    ➂     [1]
	//    ➃     [6]  Index even and value is even  [6]
	// ---------------
	//  Total :  [2] + [6] = 8                            
	task.evenAtEvenLocation(a, l1);
	// Test B
	// arr = [2, 1, 1, -2, 1, 0, 1, 2]
	// --------------------------
	//   Index    Value
	//    0        [6]     Index even and value is even  
	//    ➀       [1]
	//    ➁       [1]     Index even but value not even
	//    ➂       [-3]        
	//    ➃       [-2]    Index even and value is even       
	//    ➄       [0]             
	//    ➅       [1]     Index even but value not even   
	//    ➆       [2]           
	// ---------------
	//  Total : [6] + [-2]
	task.evenAtEvenLocation(b, l2);
}

Output

 3 1 2 1 6
 Result : 8
 6 1 1 -3 -2 0 1 2
 Result : 4




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