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Sum of digits of a number

Here given code implementation process.

//C Program
//Sum of digits of a number
#include <stdio.h>

// Method which are sum of given number 
// This method are add all digits and not take negative sign
void sum_digits(int number)
{
  int result = 0;
  if(number<0)
  {
    // Convert negative number to positive number
    number = - number;
  }
  while(number!=0)
  {
  
    // Adding last digit of a given number
    result+=number%10;
    
    // Remove last digit
    number/=10;
    
  }

  printf("%d\n",result );
}


int main()
{
  //Test Case
  sum_digits(123);
  sum_digits(562);

  //when passes negative number
  sum_digits(-562);

  return 0;
}

Output

6
13
13
/*
 C++ Program
 Sum of digits of a number
*/

#include<iostream>

using namespace std;

class MyNumber {
  public:

    // Method which are sum of given number 
    // This method are add all digits and not take negative sign
    void sum_digits(int number) {
      int result = 0;
      if (number < 0) {
        // Convert negative number to positive number
        number = -number;
      }
      while (number != 0) {
        // Adding last digit of a given number
        result += number % 10;
        // Remove last digit
        number /= 10;
      }
      cout << result << "\n";
    }
};
int main() {
  MyNumber obj ;
  //Test Case
  obj.sum_digits(123);
  obj.sum_digits(562);
  //When passes negative number
  obj.sum_digits(-562);
  return 0;
}

Output

6
13
13
/*
  Java Program
  Sum of digits of a number
*/

public class MyNumber {

  // Method which are sum of given number 
  // This method are add all digits and not take negative sign
  public void sum_digits(int number)
  {
    int result = 0;
   
    if(number<0)
    {
      // Convert negative number to positive number
      number = - number;
    }
    while(number!=0)
    {
    
      // Adding last digit of a given number
      result+=number%10;
      
      // Remove last digit
      number=number/10;
      
    }

    System.out.print(result+"\n" );
  }
  public static void main(String[] args) {
    
    MyNumber obj = new MyNumber();
    //Test Case
    obj.sum_digits(123);
    obj.sum_digits(562);

    //When passes negative number
    obj.sum_digits(-562);

  }


}

Output

6
13
13
/*
  C# Program
  Sum of digits of a number
*/
using System;
public class MyNumber {

	// Method which are sum of given number 
	// This method are add all digits and not take negative sign
	public void sum_digits(int number) {
		int result = 0;

		if (number < 0) {
			// Convert negative number to positive number
			number = -number;
		}
		while (number != 0) {

			// Adding last digit of a given number
			result += number % 10;

			// Remove last digit
			number = number / 10;

		}

		Console.Write(result + "\n");
	}
	public static void Main(String[] args) {

		MyNumber obj = new MyNumber();
		//Test Case
		obj.sum_digits(123);
		obj.sum_digits(562);

		//When passes negative number
		obj.sum_digits(-562);

	}


}

Output

6
13
13
# Python 3 Program
# Sum of digits of a number
class MyNumber :
  # This method are add all digits and not take negative sign

  # Method which are sum of given number 
  def sum_digits(self, number) :
    result = 0
    if (number < 0) :
      # Convert negative number to positive number
      number = -number
    
    while (number != 0) :
      # Adding last digit of a given number
      result += number % 10
      # Remove last digit
      number = int(number / 10)
    
    print(result)
  

def main() :
  obj = MyNumber()
  #Test Case
  obj.sum_digits(123)
  obj.sum_digits(562)
  #When passes negative number
  obj.sum_digits(-562)


if __name__ == "__main__":
  main()

Output

6
13
13
# Ruby Program 

# Sum of digits of a number
class MyNumber 
	# This method are add all digits and not take negative sign

	# Method which are sum of given number 
	def sum_digits(number) 
		result = 0
		if (number < 0) 
			# Convert negative number to positive number
			number = -number
		end
		while (number != 0) 
			# Adding last digit of a given number
			result += number % 10
			# Remove last digit
			number = number / 10
		end
		print(result ,"\n")
	end
end
def main() 
	obj = MyNumber.new()
	#Test Case
	obj.sum_digits(123)
	obj.sum_digits(562)
	#When passes negative number
	obj.sum_digits(-562)
end
main()

Output

6
13
13

/*
 Scala Program
 Sum of digits of a number
*/
class MyNumber {
	// Method which are sum of given number 
	// This method are add all digits and not take negative sign
	def sum_digits(value: Int): Unit = {
		var result: Int = 0;
        var number: Int = value;
		if (number < 0) {
			// Convert negative number to positive number
			number = -number;
		}
		while (number != 0) {
			// Adding last digit of a given number
			result += number % 10;
			// Remove last digit
			number = number / 10;
		}
		print(result);
        print("\n");
	}
}
object Main {
	def main(args: Array[String]): Unit = {
		var obj: MyNumber = new MyNumber();
		//Test Case
		obj.sum_digits(123);obj.sum_digits(562);
		//When passes negative number
		obj.sum_digits(-562);
	}
}

Output

6
13
13
/*
  Swift 4 Program
  Sum of digits of a number
*/
class MyNumber {
	// Method which are sum of given number 
	// This method are add all digits and not take negative sign
	func sum_digits(_ value: Int) {
		var result: Int = 0;
      	var number: Int = value;
		if (number < 0) {
			// Convert negative number to positive number
			number = -number;
		}
		while (number != 0) {
			// Adding last digit of a given number
			result += number % 10;
			// Remove last digit
			number = number / 10;
		}
		print(result);
	}
}
func main() {
	let obj: MyNumber = MyNumber();
	//Test Case
	obj.sum_digits(123);
	obj.sum_digits(562);
	//When passes negative number
	obj.sum_digits(-562);
}
main();

Output

6
13
13
<?php
/*
  Php Program
  Sum of digits of a number
*/
class MyNumber {
	// Method which are sum of given number 
	// This method are add all digits and not take negative sign

	public 	function sum_digits($number) {
		$result = 0;
		if ($number < 0) {
			// Convert negative number to positive number
			$number = -$number;
		}
		while ($number != 0) {
			// Adding last digit of a given number
			$result += $number % 10;
			// Remove last digit
			$number = intval($number / 10);
		}
		echo ($result."\n");
	}
}
function main() {
	$obj = new MyNumber();
	//Test Case

	$obj->sum_digits(123);
	$obj->sum_digits(562);
	//When passes negative number

	$obj->sum_digits(-562);
}
main();
?>

Output

6
13
13
/*
 Node Js Program
 Sum of digits of a number
*/
class MyNumber {
	// Method which are sum of given number 
	// This method are add all digits and not take negative sign
	sum_digits(number) {
		var result = 0;
		if (number < 0) {
			// Convert negative number to positive number
			number = -number;
		}
		while (number != 0) {
			// Adding last digit of a given number
			result += number % 10;
			// Remove last digit
			number = parseInt(number / 10);
		}
		process.stdout.write(result + "\n");
	}
}

function main(args) {
	var obj = new MyNumber();
	//Test Case
	obj.sum_digits(123);
	obj.sum_digits(562);
	//When passes negative number
	obj.sum_digits(-562)
}
main();

Output

6
13
13
Last updated on by Kalkicode




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