Spiral traversal of matrix in c#

Csharp program for Spiral traversal of matrix. Here more information.

// Include namespace system
using System;
// Csharp program for 
// Spiral form of matrix
public class SpiralView
{
	public void spiral(int[, ] data, int startRow, 
  	int startCol, int endRow, int endCol, int element)
	{
		// Left to right
		for (var i = startCol; i <= endCol && element > 0; ++i)
		{
			element--;
			Console.Write("  " + data[startRow, i].ToString());
		}
		// Top to down
		for (var i = startRow + 1; i <= endRow && element > 0; ++i)
		{
			element--;
			Console.Write("  " + data[i, endCol].ToString());
		}
		// Bottom right to bottom-left
		for (var i = endCol - 1; i >= startCol && element > 0; --i)
		{
			element--;
			Console.Write("  " + data[endRow, i].ToString());
		}
		// Bottom left to top
		for (var i = endRow - 1; i > startRow && element > 0; --i)
		{
			element--;
			Console.Write("  " + data[i, startRow].ToString());
		}
		if (startRow + 1 <= endRow - 1 && element > 0)
		{
			// Recursive call
			this.spiral(data, startRow + 1, 
                        startCol + 1, endRow - 1, 
                        endCol - 1, element);
		}
	}
	public static void Main(String[] args)
	{
		var task = new SpiralView();
		// Given matrix
		int[, ] matrix = {
          {1 ,  2 ,  3 ,  4 ,  5 ,  6} , 
          {22 , 23 , 24 , 25 , 26 , 7} , 
          {21 , 36 , 37 , 38 , 27 , 8} , 
          {20 , 35 , 42 , 39 , 28 , 9} , 
          {19 , 34 , 41 , 40 , 29 , 10} , 
          {18 , 33 , 32 , 31 , 30 , 11} , 
          {17 , 16 , 15 , 14 , 13 , 12}  
        }; 
		var row = matrix.GetLength(0);
		var col = matrix.GetLength(1);
		// Get the number of element
		var element = row * col;
		task.spiral(matrix, 0, 0, row - 1, col - 1, element);
	}
}

Output

  1  2  3  4  5  6  7  8  9  10  11  12  13  14  15  16  17  18  19  20  21  22  23  24  25  26  27  28  29  30  31  32  33  34  35  36  37  38  39  40  41  42


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