Sorted order insertion of linked list in kotlin

Kotlin program for Sorted order insertion of linked list. Here problem description and explanation.

/*
    Kotlin program for
    Add node in sorted order of linked list
*/
// Linked list node
class LinkNode
{
	var data: Int;
	var next: LinkNode ? ;
	constructor(data: Int)
	{
		this.data = data;
		this.next = null;
	}
}
class SingleLL
{
	var head: LinkNode ? ;
	constructor()
	{
		this.head = null;
	}
	// Add new node in sorted order
	fun sortedAdd(data: Int): Unit
	{
		// Create new node
		val node: LinkNode = LinkNode(data);
		if (this.head == null || 
            this.head!!.data >= data)
		{
			// When linked list empty
			// or new nodes are adding at beginning
			node.next = this.head;
			this.head = node;
		}
		else
		{
			var temp: LinkNode ? = this.head;
			// Find position to add new node
			while (temp?.next != null && 
              temp.next!!.data < data)
			{
				// Visit to next node
				temp = temp.next;
			}
			node.next = temp?.next;
			// Add new node
			temp?.next = node;
		}
	}
	// Display linked list element
	fun display(): Unit
	{
		if (this.head == null)
		{
			return;
		}
		var temp: LinkNode ? = this.head;
		// Iterating linked list elements
		while (temp != null)
		{
			print(""+ temp.data + " → ");
			// Visit to next node
			temp = temp.next;
		}
		println("NULL");
	}
}
fun main(args: Array < String > ): Unit
{
	val sll: SingleLL = SingleLL();
	// Add Linked list node
	sll.sortedAdd(1);
	sll.sortedAdd(-3);
	sll.sortedAdd(9);
	sll.sortedAdd(4);
	sll.sortedAdd(11);
	sll.sortedAdd(-7);
	println("Linked List");
	// -7 → -3 → 1 → 4 → 9 → 11 → NULL
	sll.display();
}

Output

Linked List
-7 → -3 → 1 → 4 → 9 → 11 → NULL


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