Sorted insert for circular linked list
The Sorted Insert for Circular Linked List problem involves inserting a new node into a circular linked list while maintaining the sorted order of the list. A circular linked list is a data structure where the last node points back to the first node, creating a loop. The task is to insert a new node with a given value into the list in such a way that the sorted order of the list is preserved.
Problem Statement
Given a circular linked list in sorted order and a value to insert, the problem is to insert a new node with the given value into the circular linked list while keeping the list sorted.
Example
Consider a scenario where the initial circular linked list is: 3 > 5 > 8 > 14 > 17 > 25 > 26 > 34 > 62. Now, if we want to insert the value 20 into the list, the updated circular linked list should be: 3 > 5 > 8 > 14 > 17 > 20 > 25 > 26 > 34 > 62.
Idea to Solve the Problem
To solve the problem of inserting a new node in sorted order in a circular linked list, follow these steps:
 If the linked list is empty, create a new node and make it the head and tail of the list. Point the node's next to itself.
 If the new value is smaller than the value of the current head node, insert the new node at the beginning and adjust pointers accordingly.
 If the new value is larger than the value of the current tail node, insert the new node at the end and adjust pointers accordingly.
 For other cases, iterate through the linked list until a position is found where the new value is smaller than the next node's value. Insert the new node at that position and adjust pointers.
Pseudocode
function insert(value):
node = createLinkNode(value)
if head is null:
head = node
tail = node
node.next = node
else if head.data >= value:
node.next = head
head = node
tail.next = node
else if tail.data <= value:
tail.next = node
tail = node
node.next = head
else:
temp = head
while temp is not null and temp.next.data < value:
temp = temp.next
node.next = temp.next
temp.next = node
Algorithm Explanation
 If the list is empty, create a new node and set it as both the head and tail. Point its next to itself.
 If the new value is smaller than the head value, insert the new node at the beginning and update pointers accordingly.
 If the new value is larger than the tail value, insert the new node at the end and update pointers.
 If the new value falls between other nodes, iterate through the list until the correct position is found and insert the new node there.
Code Solution

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Time Complexity
The time complexity of the insertion operation in a circular linked list is O(n), where n is the number of nodes in the linked list. This is because, in the worst case, we may need to traverse the entire linked list to find the correct position for insertion.
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