Sort the biotonic doubly linked list
In this article, we will delve into the implementation of sorting a biotonic doubly linked list. A biotonic doubly linked list is a list that first increases up to a certain point and then decreases. The article will guide you through the process of sorting such a list while maintaining the biotonic property using Java code examples and detailed explanations.
Problem Statement
Given a biotonic doubly linked list, the task is to sort it while preserving its biotonic nature.
Example
Suppose we have the following biotonic doubly linked list:
3 <-> 5 <-> 7 <-> 12 <-> 10 <-> 6 <-> 4 <-> 1 <-> -1
After sorting, the list should become:
-1 <-> 1 <-> 3 <-> 4 <-> 5 <-> 6 <-> 7 <-> 10 <-> 12
Idea to Solve
The idea is to traverse the linked list and identify the point where the decreasing order begins. Then, we can sort the increasing and decreasing segments separately, and finally, merge them to obtain the sorted biotonic list.
Pseudocode
function sortBiotonicList():
if head is not null:
initialize front as head and last as null
if tail.data < front.data:
swap head and tail
adjust pointers
while front is not null and tail is not null and front is not tail:
if tail.data < front.data:
move last to the front of front node
adjust pointers
else:
move front to the next node
Algorithm Explanation
- Implement a
sortBiotonicList
function. - If the
head
is notnull
, initializefront
withhead
andlast
asnull
. - If
tail.data
is less thanfront.data
, swaphead
andtail
, and adjust the pointers to maintain the doubly linked list structure. - Traverse the list using a loop while
front
andtail
are notnull
, andfront
is not equal totail
. - If
tail.data
is less thanfront.data
, move thelast
node to the front of thefront
node. Adjust the pointers accordingly. - Otherwise, move
front
to the next node. - The list is now sorted in a biotonic manner.
Program Solution
-
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Time Complexity
The time complexity of sorting a biotonic doubly linked list is O(n), where n is the number of nodes in the list. The list is traversed only once to identify the transition point and then sorted segments are merged.
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