Smallest subarray with k distinct numbers

Here given code implementation process.

import java.util.HashSet;
/*
    Java program for
    Smallest subarray with k distinct numbers
*/
public class SubArray
{
	public void printArray(int[] arr, int n)
	{
		for (int i = 0; i < n; ++i)
		{
			System.out.print(" " + arr[i]);
		}
	}
	public void kDistinctSmallArray(int[] arr, int n, int k)
	{
		if (k <= 0 || k > n)
		{
			return;
		}
		int sum = 0;
		HashSet < Integer > record = new HashSet < Integer > ();
		int result = Integer.MAX_VALUE;
		int startBy = -1;
		for (int i = 0; i < n; ++i)
		{
			if (record.contains(arr[i]))
			{
				// Remove all exist element in record
				record.clear();
				sum = 0;
			}
			if (record.size() < k)
			{
				record.add(arr[i]);
				sum += arr[i];
			}
			if (record.size() == k)
			{
				if (result > sum)
				{
					result = sum;
					startBy = (i + 1) - k;
				}
				// For next iteration
				record.remove(arr[(i + 1) - k]);
				sum -= arr[(i + 1) - k];
			}
		}
		System.out.print("\n Given Array element \n");
		this.printArray(arr, n);
		System.out.print("\n Smallest subarray of size k = " + k + " is \n");
		if (startBy == -1)
		{
			// Means no distinct subarray of given k size
			System.out.print("\nNone");
		}
		else
		{
			sum = k + startBy;
			// Display resultant subarray 
			while (startBy < sum)
			{
				System.out.print("  " + arr[startBy]);
				startBy++;
			}
		}
	}
	public static void main(String[] args)
	{
		SubArray task = new SubArray();
		int[] arr = {
			9 , 1 , 2 , 2 , -2 , 2 , -3 , -3 , 4 , -5 , 5
		};
		// Get the number of element in array
		int n = arr.length;
		int k = 3;
		task.kDistinctSmallArray(arr, n, k);
	}
}

Output

 Given Array element
 9 1 2 2 -2 2 -3 -3 4 -5 5
 Smallest subarray of size k = 3 is
  -3  4  -5
// Include header file
#include <iostream>
#include <set>
#include <limits.h>

using namespace std;
/*
    C++ program for
    Smallest subarray with k distinct numbers
*/
class SubArray
{
	public: void printArray(int arr[], int n)
	{
		for (int i = 0; i < n; ++i)
		{
			cout << " " << arr[i];
		}
	}
	void kDistinctSmallArray(int arr[], int n, int k)
	{
		if (k <= 0 || k > n)
		{
			return;
		}
		int sum = 0;
		set < int > record;
		int result = INT_MAX;
		int startBy = -1;
		for (int i = 0; i < n; ++i)
		{
			if (record.find(arr[i]) != record.end())
			{
				// Remove all exist element in record
				record.clear();
				sum = 0;
			}
			if (record.size() < k)
			{
				record.insert(arr[i]);
				sum += arr[i];
			}
			if (record.size() == k)
			{
				if (result > sum)
				{
					result = sum;
					startBy = (i + 1) - k;
				}
				// For next iteration
				record.erase(arr[(i + 1) - k]);
				sum -= arr[(i + 1) - k];
			}
		}
		cout << "\n Given Array element \n";
		this->printArray(arr, n);
		cout << "\n Smallest subarray of size k = " << k << " is \n";
		if (startBy == -1)
		{
			// Means no distinct subarray of given k size
			cout << "\nNone";
		}
		else
		{
			sum = k + startBy;
			// Display resultant subarray 
			while (startBy < sum)
			{
				cout << "  " << arr[startBy];
				startBy++;
			}
		}
	}
};
int main()
{
	SubArray *task = new SubArray();
	int arr[] = {
		9 , 1 , 2 , 2 , -2 , 2 , -3 , -3 , 4 , -5 , 5
	};
	// Get the number of element in array
	int n = sizeof(arr) / sizeof(arr[0]);
	int k = 3;
	task->kDistinctSmallArray(arr, n, k);
	return 0;
}

Output

 Given Array element
 9 1 2 2 -2 2 -3 -3 4 -5 5
 Smallest subarray of size k = 3 is
  -3  4  -5
// Include namespace system
using System;
using System.Collections.Generic;
/*
    Csharp program for
    Smallest subarray with k distinct numbers
*/
public class SubArray
{
	public void printArray(int[] arr, int n)
	{
		for (int i = 0; i < n; ++i)
		{
			Console.Write(" " + arr[i]);
		}
	}
	public void kDistinctSmallArray(int[] arr, int n, int k)
	{
		if (k <= 0 || k > n)
		{
			return;
		}
		int sum = 0;
		HashSet < int > record = new HashSet < int > ();
		int result = int.MaxValue;
		int startBy = -1;
		for (int i = 0; i < n; ++i)
		{
			if (record.Contains(arr[i]))
			{
				// Remove all exist element in record
				record.Clear();
				sum = 0;
			}
			if (record.Count < k)
			{
				record.Add(arr[i]);
				sum += arr[i];
			}
			if (record.Count == k)
			{
				if (result > sum)
				{
					result = sum;
					startBy = (i + 1) - k;
				}
				// For next iteration
				record.Remove(arr[(i + 1) - k]);
				sum -= arr[(i + 1) - k];
			}
		}
		Console.Write("\n Given Array element \n");
		this.printArray(arr, n);
		Console.Write("\n Smallest subarray of size k = " + k + " is \n");
		if (startBy == -1)
		{
			// Means no distinct subarray of given k size
			Console.Write("\nNone");
		}
		else
		{
			sum = k + startBy;
			// Display resultant subarray 
			while (startBy < sum)
			{
				Console.Write("  " + arr[startBy]);
				startBy++;
			}
		}
	}
	public static void Main(String[] args)
	{
		SubArray task = new SubArray();
		int[] arr = {
			9 , 1 , 2 , 2 , -2 , 2 , -3 , -3 , 4 , -5 , 5
		};
		// Get the number of element in array
		int n = arr.Length;
		int k = 3;
		task.kDistinctSmallArray(arr, n, k);
	}
}

Output

 Given Array element
 9 1 2 2 -2 2 -3 -3 4 -5 5
 Smallest subarray of size k = 3 is
  -3  4  -5
package main
import "math"
import "fmt"
/*
    Go program for
    Smallest subarray with k distinct numbers
*/

func printArray(arr[] int, n int) {
	for i := 0 ; i < n ; i++ {
		fmt.Print(" ", arr[i])
	}
}
func kDistinctSmallArray(arr[] int, n int, k int) {
	if k <= 0 || k > n {
		return
	}
	var sum int = 0
	var record = make(map[int] bool)
	var result int = math.MaxInt64
	var startBy int = -1
	for i := 0 ; i < n ; i++ {
		if _, found := record[arr[i]] ; found {
			// Remove all exist element in record
			for k := range record {
				delete(record, k)
			}
			sum = 0
		}
		if len(record) < k {
			record[arr[i]] = true
			sum += arr[i]
		}
		if len(record) == k {
			if result > sum {
				result = sum
				startBy = (i + 1) - k
			}
			// For next iteration
			delete(record,arr[(i + 1) - k])
			sum -= arr[(i + 1) - k]
		}
	}
	fmt.Print("\n Given Array element \n")
	printArray(arr, n)
	fmt.Print("\n Smallest subarray of size k = ", k, " is \n")
	if startBy == -1 {
		// Means no distinct subarray of given k size
		fmt.Print("\nNone")
	} else {
		sum = k + startBy
		// Display resultant subarray 
		for (startBy < sum) {
			fmt.Print("  ", arr[startBy])
			startBy++
		}
	}
}
func main() {
	
	var arr = [] int {9, 1, 2, 2,-2, 2, -3, -3, 4, -5, 5}
	// Get the number of element in array
	var n int = len(arr)
	var k int = 3
	kDistinctSmallArray(arr, n, k)
}

Output

 Given Array element
 9 1 2 2 -2 2 -3 -3 4 -5 5
 Smallest subarray of size k = 3 is
  -3  4  -5
<?php
/*
    Php program for
    Smallest subarray with k distinct numbers
*/
class SubArray
{
	public	function printArray($arr, $n)
	{
		for ($i = 0; $i < $n; ++$i)
		{
			echo(" ".$arr[$i]);
		}
	}
	public	function kDistinctSmallArray($arr, $n, $k)
	{
		if ($k <= 0 || $k > $n)
		{
			return;
		}
		$sum = 0;
		$record = array();
		$result = PHP_INT_MAX;
		$startBy = -1;
		for ($i = 0; $i < $n; ++$i)
		{
			if (in_array($arr[$i], $record, TRUE))
			{
				// Remove all exist element in record
				$sum = 0;
              	$record = array();
			}
			if (count($record) < $k)
			{
				
				$record[] = $arr[$i];
				$sum += $arr[$i];
			}
			if (count($record) == $k)
			{
				if ($result > $sum)
				{
					$result = $sum;
					$startBy = ($i + 1) - $k;
				}
				// For next iteration
				unset($record[$arr[($i + 1) - $k]]);
				$sum -= $arr[($i + 1) - $k];
			}
		}
		echo("\n Given Array element \n");
		$this->printArray($arr, $n);
		echo("\n Smallest subarray of size k = ".$k.
			" is \n");
		if ($startBy == -1)
		{
			// Means no distinct subarray of given k size
			echo("\nNone");
		}
		else
		{
			$sum = $k + $startBy;
			// Display resultant subarray 
			while ($startBy < $sum)
			{
				echo("  ".$arr[$startBy]);
				$startBy++;
			}
		}
	}
}

function main()
{
	$task = new SubArray();
	$arr = array(9, 1, 2, 2, -2, 2, -3, -3, 4, -5, 5);
	// Get the number of element in array
	$n = count($arr);
	$k = 3;
	$task->kDistinctSmallArray($arr, $n, $k);
}
main();

Output

 Given Array element
 9 1 2 2 -2 2 -3 -3 4 -5 5
 Smallest subarray of size k = 3 is
  -3  4  -5
/*
    Node JS program for
    Smallest subarray with k distinct numbers
*/
class SubArray
{
	printArray(arr, n)
	{
		for (var i = 0; i < n; ++i)
		{
			process.stdout.write(" " + arr[i]);
		}
	}
	kDistinctSmallArray(arr, n, k)
	{
		if (k <= 0 || k > n)
		{
			return;
		}
		var sum = 0;
		var record = new Set();
		var result = Number.MAX_VALUE;
		var startBy = -1;
		for (var i = 0; i < n; ++i)
		{
			if (record.has(arr[i]))
			{
				// Remove all exist element in record
				record.clear();
				sum = 0;
			}
			if (record.size < k)
			{
				record.add(arr[i]);
				sum += arr[i];
			}
			if (record.size == k)
			{
				if (result > sum)
				{
					result = sum;
					startBy = (i + 1) - k;
				}
				// For next iteration
				record.delete(arr[(i + 1) - k]);
				sum -= arr[(i + 1) - k];
			}
		}
		process.stdout.write("\n Given Array element \n");
		this.printArray(arr, n);
		process.stdout.write("\n Smallest subarray of size k = " + 
                             k + " is \n");
		if (startBy == -1)
		{
			// Means no distinct subarray of given k size
			process.stdout.write("\nNone");
		}
		else
		{
			sum = k + startBy;
			// Display resultant subarray 
			while (startBy < sum)
			{
				process.stdout.write("  " + arr[startBy]);
				startBy++;
			}
		}
	}
}

function main()
{
	var task = new SubArray();
	var arr = [9, 1, 2, 2, -2, 2, -3, -3, 4, -5, 5];
	// Get the number of element in array
	var n = arr.length;
	var k = 3;
	task.kDistinctSmallArray(arr, n, k);
}
main();

Output

 Given Array element
 9 1 2 2 -2 2 -3 -3 4 -5 5
 Smallest subarray of size k = 3 is
  -3  4  -5
import sys
#    Python 3 program for
#    Smallest subarray with k distinct numbers
class SubArray :
	def printArray(self, arr, n) :
		i = 0
		while (i < n) :
			print(" ", arr[i], end = "")
			i += 1
		
	
	def kDistinctSmallArray(self, arr, n, k) :
		if (k <= 0 or k > n) :
			return
		
		sum = 0
		record = set()
		result = sys.maxsize
		startBy = -1
		i = 0
		while (i < n) :
			if (arr[i] in record) :
				#  Remove all exist element in record
				record.clear()
				sum = 0
			
			if (len(record) < k) :
				record.add(arr[i])
				sum += arr[i]
			
			if (len(record) == k) :
				if (result > sum) :
					result = sum
					startBy = (i + 1) - k
				
				#  For next iteration
				record.remove(arr[(i + 1) - k])
				sum -= arr[(i + 1) - k]
			
			i += 1
		
		print("\n Given Array element ")
		self.printArray(arr, n)
		print("\n Smallest subarray of size k = ", k ," is ")
		if (startBy == -1) :
			#  Means no distinct sublist of given k size
			print("\nNone", end = "")
		else :
			sum = k + startBy
			#  Display resultant sublist 
			while (startBy < sum) :
				print("  ", arr[startBy], end = "")
				startBy += 1
			
		
	

def main() :
	task = SubArray()
	arr = [9, 1, 2, 2, -2, 2, -3, -3, 4, -5, 5]
	#  Get the number of element in list
	n = len(arr)
	k = 3
	task.kDistinctSmallArray(arr, n, k)

if __name__ == "__main__": main()

Output

 Given Array element
  9  1  2  2  -2  2  -3  -3  4  -5  5
 Smallest subarray of size k =  3  is
   -3   4   -5
require 'set'
#    Ruby program for
#    Smallest subarray with k distinct numbers
class SubArray 
	def printArray(arr, n) 
		i = 0
		while (i < n) 
			print(" ", arr[i])
			i += 1
		end

	end

	def kDistinctSmallArray(arr, n, k) 
		if (k <= 0 || k > n) 
			return
		end

		sum = 0
		record = SortedSet.new()
		result = (2 ** (0. size * 8 - 2))
		startBy = -1
		i = 0
		while (i < n) 
			if (record.include?(arr[i])) 
				#  Remove all exist element in record
				record.clear()
				sum = 0
			end

			if (record.size() < k) 
				record.add(arr[i])
				sum += arr[i]
			end

			if (record.size() == k) 
				if (result > sum) 
					result = sum
					startBy = (i + 1) - k
				end

				#  For next iteration
				record.delete(arr[(i + 1) - k])
				sum -= arr[(i + 1) - k]
			end

			i += 1
		end

		print("\n Given Array element \n")
		self.printArray(arr, n)
		print("\n Smallest subarray of size k = ", k ," is \n")
		if (startBy == -1) 
			#  Means no distinct subarray of given k size
			print("\nNone")
		else
 
			sum = k + startBy
			#  Display resultant subarray 
			while (startBy < sum) 
				print("  ", arr[startBy])
				startBy += 1
			end

		end

	end

end

def main() 
	task = SubArray.new()
	arr = [9, 1, 2, 2, -2, 2, -3, -3, 4, -5, 5]
	#  Get the number of element in array
	n = arr.length
	k = 3
	task.kDistinctSmallArray(arr, n, k)
end

main()

Output

 Given Array element 
 9 1 2 2 -2 2 -3 -3 4 -5 5
 Smallest subarray of size k = 3 is 
  -3  4  -5
import scala.collection.mutable._;
/*
    Scala program for
    Smallest subarray with k distinct numbers
*/
class SubArray()
{
	def printArray(arr: Array[Int], n: Int): Unit = {
		var i: Int = 0;
		while (i < n)
		{
			print(" " + arr(i));
			i += 1;
		}
	}
	def kDistinctSmallArray(
      	arr: Array[Int], 
      	n: Int, 
        k: Int): Unit = {
		if (k <= 0 || k > n)
		{
			return;
		}
		var sum: Int = 0;
		var record = Set[Int]();
		var result: Int = Int.MaxValue;
		var startBy: Int = -1;
		var i: Int = 0;
		while (i < n)
		{
			if (record.contains(arr(i)))
			{
				// Remove all exist element in record
				record.clear();
				sum = 0;
			}
			if (record.size < k)
			{
				record.add(arr(i));
				sum += arr(i);
			}
			if (record.size == k)
			{
				if (result > sum)
				{
					result = sum;
					startBy = (i + 1) - k;
				}
				// For next iteration
				record.remove(arr((i + 1) - k));
				sum -= arr((i + 1) - k);
			}
			i += 1;
		}
		print("\n Given Array element \n");
		this.printArray(arr, n);
		print("\n Smallest subarray of size k = " + k + " is \n");
		if (startBy == -1)
		{
			// Means no distinct subarray of given k size
			print("\nNone");
		}
		else
		{
			sum = k + startBy;
			// Display resultant subarray 
			while (startBy < sum)
			{
				print("  " + arr(startBy));
				startBy += 1;
			}
		}
	}
}
object Main
{
	def main(args: Array[String]): Unit = {
		var task: SubArray = new SubArray();
		var arr: Array[Int] = Array(9, 1, 2, 2, -2, 2, -3, -3, 4, -5, 5);
		// Get the number of element in array
		var n: Int = arr.length;
		var k: Int = 3;
		task.kDistinctSmallArray(arr, n, k);
	}
}

Output

 Given Array element
 9 1 2 2 -2 2 -3 -3 4 -5 5
 Smallest subarray of size k = 3 is
  -3  4  -5
import Foundation;
/*
    Swift 4 program for
    Smallest subarray with k distinct numbers
*/
class SubArray
{
	func printArray(_ arr: [Int], _ n: Int)
	{
		var i: Int = 0;
		while (i < n)
		{
			print(" ", arr[i], terminator: "");
			i += 1;
		}
	}
	func kDistinctSmallArray(_ arr: [Int], _ n: Int, _ k: Int)
	{
		if (k <= 0 || k > n)
		{
			return;
		}
		var sum: Int = 0;
		var record = Set<Int>();
		var result: Int = Int.max;
		var startBy: Int = -1;
		var i: Int = 0;
		while (i < n)
		{
			if (record.contains(arr[i]))
			{
				// Remove all exist element in record
				record.removeAll();
				sum = 0;
			}
			if (record.count < k)
			{
				record.insert(arr[i]);
				sum += arr[i];
			}
			if (record.count == k)
			{
				if (result > sum)
				{
					result = sum;
					startBy = (i + 1) - k;
				}
				// For next iteration
				record.remove(arr[(i + 1) - k]);
				sum -= arr[(i + 1) - k];
			}
			i += 1;
		}
		print("\n Given Array element ");
		self.printArray(arr, n);
		print("\n Smallest subarray of size k = ", k ," is ");
		if (startBy == -1)
		{
			// Means no distinct subarray of given k size
			print("\nNone", terminator: "");
		}
		else
		{
			sum = k + startBy;
			// Display resultant subarray 
			while (startBy < sum)
			{
				print("  ", arr[startBy], terminator: "");
				startBy += 1;
			}
		}
	}
}
func main()
{
	let task: SubArray = SubArray();
	let arr: [Int] = [9, 1, 2, 2, -2, 2, -3, -3, 4, -5, 5];
	// Get the number of element in array
	let n: Int = arr.count;
	let k: Int = 3;
	task.kDistinctSmallArray(arr, n, k);
}
main();

Output

 Given Array element
  9  1  2  2  -2  2  -3  -3  4  -5  5
 Smallest subarray of size k =  3  is
   -3   4   -5
/*
    Kotlin program for
    Smallest subarray with k distinct numbers
*/
class SubArray
{
	fun printArray(arr: Array < Int > , n: Int): Unit
	{
		var i: Int = 0;
		while (i < n)
		{
			print(" " + arr[i]);
			i += 1;
		}
	}
	fun kDistinctSmallArray(arr: Array < Int > , n: Int, k: Int): Unit
	{
		if (k <= 0 || k > n)
		{
			return;
		}
		var sum: Int = 0;
		var record: MutableSet <Int> = mutableSetOf <Int> ();
		var result: Int = Int.MAX_VALUE;
		var startBy: Int = -1;
		var i: Int = 0;
		while (i < n)
		{
			if (record.contains(arr[i]))
			{
				// Remove all exist element in record
				record.clear();
				sum = 0;
			}
			if (record.count() < k)
			{
				record.add(arr[i]);
				sum += arr[i];
			}
			if (record.count() == k)
			{
				if (result > sum)
				{
					result = sum;
					startBy = (i + 1) - k;
				}
				// For next iteration
				record.remove(arr[(i + 1) - k]);
				sum -= arr[(i + 1) - k];
			}
			i += 1;
		}
		print("\n Given Array element \n");
		this.printArray(arr, n);
		print("\n Smallest subarray of size k = " + k + " is \n");
		if (startBy == -1)
		{
			// Means no distinct subarray of given k size
			print("\nNone");
		}
		else
		{
			sum = k + startBy;
			// Display resultant subarray 
			while (startBy < sum)
			{
				print("  " + arr[startBy]);
				startBy += 1;
			}
		}
	}
}
fun main(args: Array < String > ): Unit
{
	val task: SubArray = SubArray();
	val arr: Array < Int > = arrayOf(9, 1, 2, 2, -2, 2, -3, -3, 4, -5, 5);
	// Get the number of element in array
	val n: Int = arr.count();
	val k: Int = 3;
	task.kDistinctSmallArray(arr, n, k);
}

Output

 Given Array element
 9 1 2 2 -2 2 -3 -3 4 -5 5
 Smallest subarray of size k = 3 is
  -3  4  -5


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