Shortest uncommon subsequence using dynamic programming
Here given code implementation process.
/*
Java program for
Shortest uncommon subsequence using dynamic programming
*/
public class Subsequence
{
public int minValue(int a, int b)
{
if (a < b)
{
return a;
}
return b;
}
// Find the length of shortest uncommon subsequence which is exist
// In str1 but not in str2.
public void uncommonSubsequence(
String str1,
String str2)
{
// Get the length
int m = str1.length();
int n = str2.length();
// Auxiliary space
int[][] dp = new int[m + 1][n + 1];
int result = 0;
int max = Integer.MAX_VALUE;
// Reduce size of max by length of longest substring
if (n > m)
{
max -= n;
}
else
{
max -= m;
}
for (int i = 0; i <= m; i++)
{
dp[i][0] = 1;
}
for (int i = 0; i <= n; i++)
{
dp[0][i] = max;
}
for (int i = 1; i <= m; i++)
{
for (int j = 1; j <= n; j++)
{
int k = j - 1;
while (k >= 0 && str2.charAt(k) != str1.charAt(i - 1))
{
k--;
}
if (k == -1)
{
dp[i][j] = 1;
}
else
{
dp[i][j] = minValue(dp[i - 1][j], dp[i - 1][k] + 1);
}
}
}
if (dp[m][n] != max)
{
result = dp[m][n];
}
// Display given strings
System.out.println(" String A : " + str1);
System.out.println(" String B : " + str2);
// Display calculated result
System.out.println(" " + result);
}
public static void main(String[] args)
{
Subsequence task = new Subsequence();
String str1 = "aecb";
String str2 = "bace";
// Case A
/*
Example 1
str1 = aecb
str2 = bace
------------
[ab,cb,eb,aecb,acb,ecb] Subsequences exists in
str1 but not str2
--------------------------------------------
Length of shortest subsequence is 2
Ans = 2
*/
task.uncommonSubsequence(str1, str2);
// Case B
str1 = "ABCCDBE";
str2 = "ABCCDBE";
/*
Example 2
str1 = ABCCDBE
str2 = ABCCDBE
------------
all subsequence str1 exist in str2
*/
task.uncommonSubsequence(str1, str2);
// Case C
str1 = "CCCCCB";
str2 = "CCB";
/*
Example 3
str1 = CCCCCB
str2 = CCB
------------
'CCC' Shortest subsequence which exist in str1 but not on str2.
Note ['CCCC',CCCCCB,CCCCB] is also uncommon subsequence
but its length more than 3.
--------------------------------------------------------
Ans = 3
*/
task.uncommonSubsequence(str1, str2);
// Case D
str1 = "fbi";
str2 = "ice";
/*
Example 4
str1 = fbi
str2 = ice
------------
[f,b,fb,fbi]
Subsequences which is exist in str1 but not on str2.
--------------------------------------------------------
Ans = 1 [length of f or b]
*/
task.uncommonSubsequence(str1, str2);
}
}
Output
String A : aecb
String B : bace
2
String A : ABCCDBE
String B : ABCCDBE
0
String A : CCCCCB
String B : CCB
3
String A : fbi
String B : ice
1
// Include header file
#include <iostream>
#include <string>
#include <limits.h>
using namespace std;
/*
C++ program for
Shortest uncommon subsequence using dynamic programming
*/
class Subsequence
{
public: int minValue(int a, int b)
{
if (a < b)
{
return a;
}
return b;
}
// Find the length of shortest uncommon subsequence which is exist
// In str1 but not in str2.
void uncommonSubsequence(string str1, string str2)
{
// Get the length
int m = str1.length();
int n = str2.length();
// Auxiliary space
int dp[m + 1][n + 1];
int result = 0;
int max = INT_MAX;
// Reduce size of max by length of longest substring
if (n > m)
{
max -= n;
}
else
{
max -= m;
}
for (int i = 0; i <= m; i++)
{
dp[i][0] = 1;
}
for (int i = 0; i <= n; i++)
{
dp[0][i] = max;
}
for (int i = 1; i <= m; i++)
{
for (int j = 1; j <= n; j++)
{
int k = j - 1;
while (k >= 0 && str2[k] != str1[i - 1])
{
k--;
}
if (k == -1)
{
dp[i][j] = 1;
}
else
{
dp[i][j] = this->minValue(dp[i - 1][j], dp[i - 1][k] + 1);
}
}
}
if (dp[m][n] != max)
{
result = dp[m][n];
}
// Display given strings
cout << " String A : " << str1 << endl;
cout << " String B : " << str2 << endl;
// Display calculated result
cout << " " << result << endl;
}
};
int main()
{
Subsequence *task = new Subsequence();
string str1 = "aecb";
string str2 = "bace";
// Case A
/*
Example 1
str1 = aecb
str2 = bace
------------
[ab,cb,eb,aecb,acb,ecb] Subsequences exists in
str1 but not str2
--------------------------------------------
Length of shortest subsequence is 2
Ans = 2
*/
task->uncommonSubsequence(str1, str2);
// Case B
str1 = "ABCCDBE";
str2 = "ABCCDBE";
/*
Example 2
str1 = ABCCDBE
str2 = ABCCDBE
------------
all subsequence str1 exist in str2
*/
task->uncommonSubsequence(str1, str2);
// Case C
str1 = "CCCCCB";
str2 = "CCB";
/*
Example 3
str1 = CCCCCB
str2 = CCB
------------
'CCC' Shortest subsequence which exist in str1 but not on str2.
Note ['CCCC',CCCCCB,CCCCB] is also uncommon subsequence
but its length more than 3.
--------------------------------------------------------
Ans = 3
*/
task->uncommonSubsequence(str1, str2);
// Case D
str1 = "fbi";
str2 = "ice";
/*
Example 4
str1 = fbi
str2 = ice
------------
[f,b,fb,fbi]
Subsequences which is exist in str1 but not on str2.
--------------------------------------------------------
Ans = 1 [length of f or b]
*/
task->uncommonSubsequence(str1, str2);
return 0;
}
Output
String A : aecb
String B : bace
2
String A : ABCCDBE
String B : ABCCDBE
0
String A : CCCCCB
String B : CCB
3
String A : fbi
String B : ice
1
// Include namespace system
using System;
/*
Csharp program for
Shortest uncommon subsequence using dynamic programming
*/
public class Subsequence
{
public int minValue(int a, int b)
{
if (a < b)
{
return a;
}
return b;
}
// Find the length of shortest uncommon subsequence which is exist
// In str1 but not in str2.
public void uncommonSubsequence(String str1, String str2)
{
// Get the length
int m = str1.Length;
int n = str2.Length;
// Auxiliary space
int[,] dp = new int[m + 1,n + 1];
int result = 0;
int max = int.MaxValue;
// Reduce size of max by length of longest substring
if (n > m)
{
max -= n;
}
else
{
max -= m;
}
for (int i = 0; i <= m; i++)
{
dp[i,0] = 1;
}
for (int i = 0; i <= n; i++)
{
dp[0,i] = max;
}
for (int i = 1; i <= m; i++)
{
for (int j = 1; j <= n; j++)
{
int k = j - 1;
while (k >= 0 && str2[k] != str1[i - 1])
{
k--;
}
if (k == -1)
{
dp[i,j] = 1;
}
else
{
dp[i,j] = this.minValue(dp[i - 1,j], dp[i - 1,k] + 1);
}
}
}
if (dp[m,n] != max)
{
result = dp[m,n];
}
// Display given strings
Console.WriteLine(" String A : " + str1);
Console.WriteLine(" String B : " + str2);
// Display calculated result
Console.WriteLine(" " + result);
}
public static void Main(String[] args)
{
Subsequence task = new Subsequence();
String str1 = "aecb";
String str2 = "bace";
// Case A
/*
Example 1
str1 = aecb
str2 = bace
------------
[ab,cb,eb,aecb,acb,ecb] Subsequences exists in
str1 but not str2
--------------------------------------------
Length of shortest subsequence is 2
Ans = 2
*/
task.uncommonSubsequence(str1, str2);
// Case B
str1 = "ABCCDBE";
str2 = "ABCCDBE";
/*
Example 2
str1 = ABCCDBE
str2 = ABCCDBE
------------
all subsequence str1 exist in str2
*/
task.uncommonSubsequence(str1, str2);
// Case C
str1 = "CCCCCB";
str2 = "CCB";
/*
Example 3
str1 = CCCCCB
str2 = CCB
------------
'CCC' Shortest subsequence which exist in str1 but not on str2.
Note ['CCCC',CCCCCB,CCCCB] is also uncommon subsequence
but its length more than 3.
--------------------------------------------------------
Ans = 3
*/
task.uncommonSubsequence(str1, str2);
// Case D
str1 = "fbi";
str2 = "ice";
/*
Example 4
str1 = fbi
str2 = ice
------------
[f,b,fb,fbi]
Subsequences which is exist in str1 but not on str2.
--------------------------------------------------------
Ans = 1 [length of f or b]
*/
task.uncommonSubsequence(str1, str2);
}
}
Output
String A : aecb
String B : bace
2
String A : ABCCDBE
String B : ABCCDBE
0
String A : CCCCCB
String B : CCB
3
String A : fbi
String B : ice
1
package main
import "math"
import "fmt"
/*
Go program for
Shortest uncommon subsequence using dynamic programming
*/
func minValue(a, b int) int {
if a < b {
return a
}
return b
}
// Find the length of shortest uncommon subsequence which is exist
// In str1 but not in str2.
func uncommonSubsequence(str1, str2 string) {
// Get the length
var m int = len(str1)
var n int = len(str2)
// Auxiliary space
var dp = make([][] int, m + 1)
for i:= 0;i < m + 1; i++ {
dp[i] = make([]int ,n + 1)
}
var result int = 0
var max int = math.MaxInt64
// Reduce size of max by length of longest substring
if n > m {
max -= n
} else {
max -= m
}
for i := 0 ; i <= m ; i++ {
dp[i][0] = 1
}
for i := 0 ; i <= n ; i++ {
dp[0][i] = max
}
for i := 1 ; i <= m ; i++ {
for j := 1 ; j <= n ; j++ {
var k int = j - 1
for (k >= 0 && str2[k] != str1[i - 1]) {
k--
}
if k == -1 {
dp[i][j] = 1
} else {
dp[i][j] = minValue(dp[i - 1][j], dp[i - 1][k] + 1)
}
}
}
if dp[m][n] != max {
result = dp[m][n]
}
// Display given strings
fmt.Println(" String A : ", str1)
fmt.Println(" String B : ", str2)
// Display calculated result
fmt.Println(" ", result)
}
func main() {
var str1 string = "aecb"
var str2 string = "bace"
// Case A
/*
Example 1
str1 = aecb
str2 = bace
------------
[ab,cb,eb,aecb,acb,ecb] Subsequences exists in
str1 but not str2
--------------------------------------------
Length of shortest subsequence is 2
Ans = 2
*/
uncommonSubsequence(str1, str2)
// Case B
str1 = "ABCCDBE"
str2 = "ABCCDBE"
/*
Example 2
str1 = ABCCDBE
str2 = ABCCDBE
------------
all subsequence str1 exist in str2
*/
uncommonSubsequence(str1, str2)
// Case C
str1 = "CCCCCB"
str2 = "CCB"
/*
Example 3
str1 = CCCCCB
str2 = CCB
------------
'CCC' Shortest subsequence which exist in str1 but not on str2.
Note ['CCCC',CCCCCB,CCCCB] is also uncommon subsequence
but its length more than 3.
--------------------------------------------------------
Ans = 3
*/
uncommonSubsequence(str1, str2)
// Case D
str1 = "fbi"
str2 = "ice"
/*
Example 4
str1 = fbi
str2 = ice
------------
[f,b,fb,fbi]
Subsequences which is exist in str1 but not on str2.
--------------------------------------------------------
Ans = 1 [length of f or b]
*/
uncommonSubsequence(str1, str2)
}
Output
String A : aecb
String B : bace
2
String A : ABCCDBE
String B : ABCCDBE
0
String A : CCCCCB
String B : CCB
3
String A : fbi
String B : ice
1
<?php
/*
Php program for
Shortest uncommon subsequence using dynamic programming
*/
class Subsequence
{
public function minValue($a, $b)
{
if ($a < $b)
{
return $a;
}
return $b;
}
// Find the length of shortest uncommon subsequence which is exist
// In str1 but not in str2.
public function uncommonSubsequence($str1, $str2)
{
// Get the length
$m = strlen($str1);
$n = strlen($str2);
// Auxiliary space
$dp = array_fill(0, $m + 1, array_fill(0, $n + 1, 0));
$result = 0;
$max = PHP_INT_MAX;
// Reduce size of max by length of longest substring
if ($n > $m)
{
$max -= $n;
}
else
{
$max -= $m;
}
for ($i = 0; $i <= $m; $i++)
{
$dp[$i][0] = 1;
}
for ($i = 0; $i <= $n; $i++)
{
$dp[0][$i] = $max;
}
for ($i = 1; $i <= $m; $i++)
{
for ($j = 1; $j <= $n; $j++)
{
$k = $j - 1;
while ($k >= 0 && $str2[$k] != $str1[$i - 1])
{
$k--;
}
if ($k == -1)
{
$dp[$i][$j] = 1;
}
else
{
$dp[$i][$j] = $this->minValue($dp[$i - 1][$j], $dp[$i - 1][$k] + 1);
}
}
}
if ($dp[$m][$n] != $max)
{
$result = $dp[$m][$n];
}
// Display given strings
echo(" String A : ".$str1.
"\n");
echo(" String B : ".$str2.
"\n");
// Display calculated result
echo(" ".$result.
"\n");
}
}
function main()
{
$task = new Subsequence();
$str1 = "aecb";
$str2 = "bace";
// Case A
/*
Example 1
str1 = aecb
str2 = bace
------------
[ab,cb,eb,aecb,acb,ecb] Subsequences exists in
str1 but not str2
--------------------------------------------
Length of shortest subsequence is 2
Ans = 2
*/
$task->uncommonSubsequence($str1, $str2);
// Case B
$str1 = "ABCCDBE";
$str2 = "ABCCDBE";
/*
Example 2
str1 = ABCCDBE
str2 = ABCCDBE
------------
all subsequence str1 exist in str2
*/
$task->uncommonSubsequence($str1, $str2);
// Case C
$str1 = "CCCCCB";
$str2 = "CCB";
/*
Example 3
str1 = CCCCCB
str2 = CCB
------------
'CCC' Shortest subsequence which exist in str1 but not on str2.
Note ['CCCC',CCCCCB,CCCCB] is also uncommon subsequence
but its length more than 3.
--------------------------------------------------------
Ans = 3
*/
$task->uncommonSubsequence($str1, $str2);
// Case D
$str1 = "fbi";
$str2 = "ice";
/*
Example 4
str1 = fbi
str2 = ice
------------
[f,b,fb,fbi]
Subsequences which is exist in str1 but not on str2.
--------------------------------------------------------
Ans = 1 [length of f or b]
*/
$task->uncommonSubsequence($str1, $str2);
}
main();
Output
String A : aecb
String B : bace
2
String A : ABCCDBE
String B : ABCCDBE
0
String A : CCCCCB
String B : CCB
3
String A : fbi
String B : ice
1
/*
Node JS program for
Shortest uncommon subsequence using dynamic programming
*/
class Subsequence
{
minValue(a, b)
{
if (a < b)
{
return a;
}
return b;
}
// Find the length of shortest uncommon subsequence which is exist
// In str1 but not in str2.
uncommonSubsequence(str1, str2)
{
// Get the length
var m = str1.length;
var n = str2.length;
// Auxiliary space
var dp = Array(m + 1).fill(0).map(() => new Array(n + 1).fill(0));
var result = 0;
var max = Number.MAX_VALUE;
// Reduce size of max by length of longest substring
if (n > m)
{
max -= n;
}
else
{
max -= m;
}
for (var i = 0; i <= m; i++)
{
dp[i][0] = 1;
}
for (var i = 0; i <= n; i++)
{
dp[0][i] = max;
}
for (var i = 1; i <= m; i++)
{
for (var j = 1; j <= n; j++)
{
var k = j - 1;
while (k >= 0 && str2.charAt(k) != str1.charAt(i - 1))
{
k--;
}
if (k == -1)
{
dp[i][j] = 1;
}
else
{
dp[i][j] = this.minValue(dp[i - 1][j], dp[i - 1][k] + 1);
}
}
}
if (dp[m][n] != max)
{
result = dp[m][n];
}
// Display given strings
console.log(" String A : " + str1);
console.log(" String B : " + str2);
// Display calculated result
console.log(" " + result);
}
}
function main()
{
var task = new Subsequence();
var str1 = "aecb";
var str2 = "bace";
// Case A
/*
Example 1
str1 = aecb
str2 = bace
------------
[ab,cb,eb,aecb,acb,ecb] Subsequences exists in
str1 but not str2
--------------------------------------------
Length of shortest subsequence is 2
Ans = 2
*/
task.uncommonSubsequence(str1, str2);
// Case B
str1 = "ABCCDBE";
str2 = "ABCCDBE";
/*
Example 2
str1 = ABCCDBE
str2 = ABCCDBE
------------
all subsequence str1 exist in str2
*/
task.uncommonSubsequence(str1, str2);
// Case C
str1 = "CCCCCB";
str2 = "CCB";
/*
Example 3
str1 = CCCCCB
str2 = CCB
------------
'CCC' Shortest subsequence which exist in str1 but not on str2.
Note ['CCCC',CCCCCB,CCCCB] is also uncommon subsequence
but its length more than 3.
--------------------------------------------------------
Ans = 3
*/
task.uncommonSubsequence(str1, str2);
// Case D
str1 = "fbi";
str2 = "ice";
/*
Example 4
str1 = fbi
str2 = ice
------------
[f,b,fb,fbi]
Subsequences which is exist in str1 but not on str2.
--------------------------------------------------------
Ans = 1 [length of f or b]
*/
task.uncommonSubsequence(str1, str2);
}
main();
Output
String A : aecb
String B : bace
2
String A : ABCCDBE
String B : ABCCDBE
0
String A : CCCCCB
String B : CCB
3
String A : fbi
String B : ice
1
import sys
# Python 3 program for
# Shortest uncommon subsequence using dynamic programming
class Subsequence :
def minValue(self, a, b) :
if (a < b) :
return a
return b
# Find the length of shortest uncommon subsequence which is exist
# In str1 but not in str2.
def uncommonSubsequence(self, str1, str2) :
# Get the length
m = len(str1)
n = len(str2)
# Auxiliary space
dp = [[0] * (n + 1) for _ in range(m + 1) ]
result = 0
max = sys.maxsize
# Reduce size of max by length of longest substring
if (n > m) :
max -= n
else :
max -= m
i = 0
while (i <= m) :
dp[i][0] = 1
i += 1
i = 0
while (i <= n) :
dp[0][i] = max
i += 1
i = 1
while (i <= m) :
j = 1
while (j <= n) :
k = j - 1
while (k >= 0 and str2[k] != str1[i - 1]) :
k -= 1
if (k == -1) :
dp[i][j] = 1
else :
dp[i][j] = self.minValue(dp[i - 1][j], dp[i - 1][k] + 1)
j += 1
i += 1
if (dp[m][n] != max) :
result = dp[m][n]
# Display given strings
print(" String A : ", str1)
print(" String B : ", str2)
# Display calculated result
print(" ", result)
def main() :
task = Subsequence()
str1 = "aecb"
str2 = "bace"
# Case A
# Example 1
# str1 = aecb
# str2 = bace
# ------------
# [ab,cb,eb,aecb,acb,ecb] Subsequences exists in
# str1 but not str2
# --------------------------------------------
# Length of shortest subsequence is 2
# Ans = 2
task.uncommonSubsequence(str1, str2)
# Case B
str1 = "ABCCDBE"
str2 = "ABCCDBE"
# Example 2
# str1 = ABCCDBE
# str2 = ABCCDBE
# ------------
# all subsequence str1 exist in str2
task.uncommonSubsequence(str1, str2)
# Case C
str1 = "CCCCCB"
str2 = "CCB"
# Example 3
# str1 = CCCCCB
# str2 = CCB
# ------------
# 'CCC' Shortest subsequence which exist in str1 but not on str2.
# Note ['CCCC',CCCCCB,CCCCB] is also uncommon subsequence
# but its length more than 3.
# --------------------------------------------------------
# Ans = 3
task.uncommonSubsequence(str1, str2)
# Case D
str1 = "fbi"
str2 = "ice"
# Example 4
# str1 = fbi
# str2 = ice
# ------------
# [f,b,fb,fbi]
# Subsequences which is exist in str1 but not on str2.
# --------------------------------------------------------
# Ans = 1 [length of f or b]
task.uncommonSubsequence(str1, str2)
if __name__ == "__main__": main()
Output
String A : aecb
String B : bace
2
String A : ABCCDBE
String B : ABCCDBE
0
String A : CCCCCB
String B : CCB
3
String A : fbi
String B : ice
1
# Ruby program for
# Shortest uncommon subsequence using dynamic programming
class Subsequence
def minValue(a, b)
if (a < b)
return a
end
return b
end
# Find the length of shortest uncommon subsequence which is exist
# In str1 but not in str2.
def uncommonSubsequence(str1, str2)
# Get the length
m = str1.length
n = str2.length
# Auxiliary space
dp = Array.new(m + 1) {Array.new(n + 1) {0}}
result = 0
max = (2 ** (0. size * 8 - 2))
# Reduce size of max by length of longest substring
if (n > m)
max -= n
else
max -= m
end
i = 0
while (i <= m)
dp[i][0] = 1
i += 1
end
i = 0
while (i <= n)
dp[0][i] = max
i += 1
end
i = 1
while (i <= m)
j = 1
while (j <= n)
k = j - 1
while (k >= 0 && str2[k] != str1[i - 1])
k -= 1
end
if (k == -1)
dp[i][j] = 1
else
dp[i][j] = self.minValue(
dp[i - 1][j], dp[i - 1][k] + 1
)
end
j += 1
end
i += 1
end
if (dp[m][n] != max)
result = dp[m][n]
end
# Display given strings
print(" String A : ", str1, "\n")
print(" String B : ", str2, "\n")
# Display calculated result
print(" ", result, "\n")
end
end
def main()
task = Subsequence.new()
str1 = "aecb"
str2 = "bace"
# Case A
# Example 1
# str1 = aecb
# str2 = bace
# ------------
# [ab,cb,eb,aecb,acb,ecb] Subsequences exists in
# str1 but not str2
# --------------------------------------------
# Length of shortest subsequence is 2
# Ans = 2
task.uncommonSubsequence(str1, str2)
# Case B
str1 = "ABCCDBE"
str2 = "ABCCDBE"
# Example 2
# str1 = ABCCDBE
# str2 = ABCCDBE
# ------------
# all subsequence str1 exist in str2
task.uncommonSubsequence(str1, str2)
# Case C
str1 = "CCCCCB"
str2 = "CCB"
# Example 3
# str1 = CCCCCB
# str2 = CCB
# ------------
# 'CCC' Shortest subsequence which exist in str1 but not on str2.
# Note ['CCCC',CCCCCB,CCCCB] is also uncommon subsequence
# but its length more than 3.
# --------------------------------------------------------
# Ans = 3
task.uncommonSubsequence(str1, str2)
# Case D
str1 = "fbi"
str2 = "ice"
# Example 4
# str1 = fbi
# str2 = ice
# ------------
# [f,b,fb,fbi]
# Subsequences which is exist in str1 but not on str2.
# --------------------------------------------------------
# Ans = 1 [length of f or b]
task.uncommonSubsequence(str1, str2)
end
main()
Output
String A : aecb
String B : bace
2
String A : ABCCDBE
String B : ABCCDBE
0
String A : CCCCCB
String B : CCB
3
String A : fbi
String B : ice
1
/*
Scala program for
Shortest uncommon subsequence using dynamic programming
*/
class Subsequence()
{
def minValue(a: Int, b: Int): Int = {
if (a < b)
{
return a;
}
return b;
}
// Find the length of shortest uncommon subsequence which is exist
// In str1 but not in str2.
def uncommonSubsequence(str1: String, str2: String): Unit = {
// Get the length
var m: Int = str1.length();
var n: Int = str2.length();
// Auxiliary space
var dp: Array[Array[Int]] = Array.fill[Int](m + 1, n + 1)(0);
var result: Int = 0;
var max: Int = Int.MaxValue;
// Reduce size of max by length of longest substring
if (n > m)
{
max -= n;
}
else
{
max -= m;
}
var i: Int = 0;
while (i <= m)
{
dp(i)(0) = 1;
i += 1;
}
i = 0;
while (i <= n)
{
dp(0)(i) = max;
i += 1;
}
i = 1;
while (i <= m)
{
var j: Int = 1;
while (j <= n)
{
var k: Int = j - 1;
while (k >= 0 && str2.charAt(k) != str1.charAt(i - 1))
{
k -= 1;
}
if (k == -1)
{
dp(i)(j) = 1;
}
else
{
dp(i)(j) = minValue(dp(i - 1)(j), dp(i - 1)(k) + 1);
}
j += 1;
}
i += 1;
}
if (dp(m)(n) != max)
{
result = dp(m)(n);
}
// Display given strings
println(" String A : " + str1);
println(" String B : " + str2);
// Display calculated result
println(" " + result);
}
}
object Main
{
def main(args: Array[String]): Unit = {
var task: Subsequence = new Subsequence();
var str1: String = "aecb";
var str2: String = "bace";
// Case A
/*
Example 1
str1 = aecb
str2 = bace
------------
[ab,cb,eb,aecb,acb,ecb] Subsequences exists in
str1 but not str2
--------------------------------------------
Length of shortest subsequence is 2
Ans = 2
*/
task.uncommonSubsequence(str1, str2);
// Case B
str1 = "ABCCDBE";
str2 = "ABCCDBE";
/*
Example 2
str1 = ABCCDBE
str2 = ABCCDBE
------------
all subsequence str1 exist in str2
*/
task.uncommonSubsequence(str1, str2);
// Case C
str1 = "CCCCCB";
str2 = "CCB";
/*
Example 3
str1 = CCCCCB
str2 = CCB
------------
'CCC' Shortest subsequence which exist in str1 but not on str2.
Note ['CCCC',CCCCCB,CCCCB] is also uncommon subsequence
but its length more than 3.
--------------------------------------------------------
Ans = 3
*/
task.uncommonSubsequence(str1, str2);
// Case D
str1 = "fbi";
str2 = "ice";
/*
Example 4
str1 = fbi
str2 = ice
------------
[f,b,fb,fbi]
Subsequences which is exist in str1 but not on str2.
--------------------------------------------------------
Ans = 1 [length of f or b]
*/
task.uncommonSubsequence(str1, str2);
}
}
Output
String A : aecb
String B : bace
2
String A : ABCCDBE
String B : ABCCDBE
0
String A : CCCCCB
String B : CCB
3
String A : fbi
String B : ice
1
import Foundation;
/*
Swift 4 program for
Shortest uncommon subsequence using dynamic programming
*/
class Subsequence
{
func minValue(_ a: Int, _ b: Int) -> Int
{
if (a < b)
{
return a;
}
return b;
}
// Find the length of shortest uncommon subsequence which is exist
// In str1 but not in str2.
func uncommonSubsequence(_ s1: String, _ s2: String)
{
let str1 = Array(s1);
let str2 = Array(s2);
// Get the length
let m: Int = str1.count;
let n: Int = str2.count;
// Auxiliary space
var dp: [
[Int]
] = Array(
repeating: Array(repeating: 0, count: n + 1), count: m + 1
);
var result: Int = 0;
var max: Int = Int.max;
// Reduce size of max by length of longest substring
if (n > m)
{
max -= n;
}
else
{
max -= m;
}
var i: Int = 0;
while (i <= m)
{
dp[i][0] = 1;
i += 1;
}
i = 0;
while (i <= n)
{
dp[0][i] = max;
i += 1;
}
i = 1;
while (i <= m)
{
var j: Int = 1;
while (j <= n)
{
var k: Int = j - 1;
while (k >= 0 && str2[k] != str1[i - 1])
{
k -= 1;
}
if (k == -1)
{
dp[i][j] = 1;
}
else
{
dp[i][j] = self.minValue(
dp[i - 1][j], dp[i - 1][k] + 1
);
}
j += 1;
}
i += 1;
}
if (dp[m][n] != max)
{
result = dp[m][n];
}
// Display given strings
print(" String A : ", s1);
print(" String B : ", s2);
// Display calculated result
print(" ", result);
}
}
func main()
{
let task: Subsequence = Subsequence();
var str1: String = "aecb";
var str2: String = "bace";
// Case A
/*
Example 1
str1 = aecb
str2 = bace
------------
[ab,cb,eb,aecb,acb,ecb] Subsequences exists in
str1 but not str2
--------------------------------------------
Length of shortest subsequence is 2
Ans = 2
*/
task.uncommonSubsequence(str1, str2);
// Case B
str1 = "ABCCDBE";
str2 = "ABCCDBE";
/*
Example 2
str1 = ABCCDBE
str2 = ABCCDBE
------------
all subsequence str1 exist in str2
*/
task.uncommonSubsequence(str1, str2);
// Case C
str1 = "CCCCCB";
str2 = "CCB";
/*
Example 3
str1 = CCCCCB
str2 = CCB
------------
'CCC' Shortest subsequence which exist in str1 but not on str2.
Note ['CCCC',CCCCCB,CCCCB] is also uncommon subsequence
but its length more than 3.
--------------------------------------------------------
Ans = 3
*/
task.uncommonSubsequence(str1, str2);
// Case D
str1 = "fbi";
str2 = "ice";
/*
Example 4
str1 = fbi
str2 = ice
------------
[f,b,fb,fbi]
Subsequences which is exist in str1 but not on str2.
--------------------------------------------------------
Ans = 1 [length of f or b]
*/
task.uncommonSubsequence(str1, str2);
}
main();
Output
String A : aecb
String B : bace
2
String A : ABCCDBE
String B : ABCCDBE
0
String A : CCCCCB
String B : CCB
3
String A : fbi
String B : ice
1
/*
Kotlin program for
Shortest uncommon subsequence using dynamic programming
*/
class Subsequence
{
fun minValue(a: Int, b: Int): Int
{
if (a < b)
{
return a;
}
return b;
}
// Find the length of shortest uncommon subsequence which is exist
// In str1 but not in str2.
fun uncommonSubsequence(str1: String, str2: String): Unit
{
// Get the length
val m: Int = str1.length;
val n: Int = str2.length;
// Auxiliary space
var dp: Array < Array < Int >> = Array(m + 1)
{
Array(n + 1)
{
0
}
};
var result: Int = 0;
var max: Int = Int.MAX_VALUE;
// Reduce size of max by length of longest substring
if (n > m)
{
max -= n;
}
else
{
max -= m;
}
var i: Int = 0;
while (i <= m)
{
dp[i][0] = 1;
i += 1;
}
i = 0;
while (i <= n)
{
dp[0][i] = max;
i += 1;
}
i = 1;
while (i <= m)
{
var j: Int = 1;
while (j <= n)
{
var k: Int = j - 1;
while (k >= 0 && str2.get(k) != str1.get(i - 1))
{
k -= 1;
}
if (k == -1)
{
dp[i][j] = 1;
}
else
{
dp[i][j] = this.minValue(dp[i - 1][j], dp[i - 1][k] + 1);
}
j += 1;
}
i += 1;
}
if (dp[m][n] != max)
{
result = dp[m][n];
}
// Display given strings
println(" String A : " + str1);
println(" String B : " + str2);
// Display calculated result
println(" " + result);
}
}
fun main(args: Array < String > ): Unit
{
val task: Subsequence = Subsequence();
var str1: String = "aecb";
var str2: String = "bace";
// Case A
/*
Example 1
str1 = aecb
str2 = bace
------------
[ab,cb,eb,aecb,acb,ecb] Subsequences exists in
str1 but not str2
--------------------------------------------
Length of shortest subsequence is 2
Ans = 2
*/
task.uncommonSubsequence(str1, str2);
// Case B
str1 = "ABCCDBE";
str2 = "ABCCDBE";
/*
Example 2
str1 = ABCCDBE
str2 = ABCCDBE
------------
all subsequence str1 exist in str2
*/
task.uncommonSubsequence(str1, str2);
// Case C
str1 = "CCCCCB";
str2 = "CCB";
/*
Example 3
str1 = CCCCCB
str2 = CCB
------------
'CCC' Shortest subsequence which exist in str1 but not on str2.
Note ['CCCC',CCCCCB,CCCCB] is also uncommon subsequence
but its length more than 3.
--------------------------------------------------------
Ans = 3
*/
task.uncommonSubsequence(str1, str2);
// Case D
str1 = "fbi";
str2 = "ice";
/*
Example 4
str1 = fbi
str2 = ice
------------
[f,b,fb,fbi]
Subsequences which is exist in str1 but not on str2.
--------------------------------------------------------
Ans = 1 [length of f or b]
*/
task.uncommonSubsequence(str1, str2);
}
Output
String A : aecb
String B : bace
2
String A : ABCCDBE
String B : ABCCDBE
0
String A : CCCCCB
String B : CCB
3
String A : fbi
String B : ice
1
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