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Shortest Common Supersequence

Here given code implementation process.

/*
    Java program for
    Shortest Common Supersequence
*/
public class Supersequence
{
	// Returns minimum of given values
	public int minValue(int x, int y)
	{
		if (x < y)
		{
			return x;
		}
		return y;
	}
	// Find length of shortest common Supersequence 
	public void lengthSCS(String a, String b)
	{
		int n = a.length();
		int m = b.length();
		// Auxiliary space
		int[][] dp = new int[n + 1][m + 1];
		// Outer loop, executing this from 0 to n (length of a)
		for (int i = 0; i <= n; ++i)
		{
			// Inner loop, executing this from 0 to m (length of b)
			for (int j = 0; j <= m; ++j)
			{
				if (i == 0)
				{
					// When i is zero
					dp[i][j] = j;
				}
				else if (j == 0)
				{
					// When j is zero
					dp[i][j] = i;
				}
				else if (a.charAt(i - 1) == b.charAt(j - 1))
				{
					//  When character of i-1 and j-1 position are same
					dp[i][j] = dp[i - 1][j - 1] + 1;
				}
				else
				{
					//  When character of i-1 and j-1 position are not same
					dp[i][j] = minValue(dp[i][j - 1], dp[i - 1][j]) + 1;
				}
			}
		}
		// Display given strings
		System.out.println(" Given string a : " + a);
		System.out.println(" Given string b : " + b);
		// Display calculated result
		System.out.println(" Result : " + dp[n][m]);
	}
	public static void main(String[] args)
	{
		Supersequence task = new Supersequence();
		// Test A
		// String a : abc
		// String b : fab
		// [fabc] Supersequence 
		// Result = 4
		task.lengthSCS("abc", "fab");
		// Test B
		// String a : project
		// String b : objects
		// [probjects]  
		// Result : 9
		task.lengthSCS("project", "objects");
		// Test C
		// String a : match
		// String b : attack
		// [mattachk,matatchk,mattackh] etc
		// Result : 8 (length of Supersequence)
		task.lengthSCS("match", "attack");
		// Test D
		// String a : abc
		// String b : abc
		// [abc] etc
		// Result : 3 
		task.lengthSCS("abc", "abc");
	}
}

Output

 Given string a : abc
 Given string b : fab
 Result : 4
 Given string a : project
 Given string b : objects
 Result : 9
 Given string a : match
 Given string b : attack
 Result : 8
 Given string a : abc
 Given string b : abc
 Result : 3
// Include header file
#include <iostream>
#include <string>

using namespace std;
/*
    C++ program for
    Shortest Common Supersequence
*/
class Supersequence
{
	public:
		// Returns minimum of given values
		int minValue(int x, int y)
		{
			if (x < y)
			{
				return x;
			}
			return y;
		}
	// Find length of shortest common Supersequence 
	void lengthSCS(string a, string b)
	{
		int n = a.length();
		int m = b.length();
		// Auxiliary space
		int dp[n + 1][m + 1];
		// Outer loop, executing this from 0 to n (length of a)
		for (int i = 0; i <= n; ++i)
		{
			// Inner loop, executing this from 0 to m (length of b)
			for (int j = 0; j <= m; ++j)
			{
				if (i == 0)
				{
					// When i is zero
					dp[i][j] = j;
				}
				else if (j == 0)
				{
					// When j is zero
					dp[i][j] = i;
				}
				else if (a[i - 1] == b[j - 1])
				{
					//  When character of i-1 and j-1 position are same
					dp[i][j] = dp[i - 1][j - 1] + 1;
				}
				else
				{
					//  When character of i-1 and j-1 position are not same
					dp[i][j] = this->minValue(dp[i][j - 1], dp[i - 1][j]) + 1;
				}
			}
		}
		// Display given strings
		cout << " Given string a : " << a << endl;
		cout << " Given string b : " << b << endl;
		// Display calculated result
		cout << " Result : " << dp[n][m] << endl;
	}
};
int main()
{
	Supersequence *task = new Supersequence();
	// Test A
	// String a : abc
	// String b : fab
	// [fabc] Supersequence 
	// Result = 4
	task->lengthSCS("abc", "fab");
	// Test B
	// String a : project
	// String b : objects
	// [probjects]  
	// Result : 9
	task->lengthSCS("project", "objects");
	// Test C
	// String a : match
	// String b : attack
	// [mattachk,matatchk,mattackh] etc
	// Result : 8 (length of Supersequence)
	task->lengthSCS("match", "attack");
	// Test D
	// String a : abc
	// String b : abc
	// [abc] etc
	// Result : 3 
	task->lengthSCS("abc", "abc");
	return 0;
}

Output

 Given string a : abc
 Given string b : fab
 Result : 4
 Given string a : project
 Given string b : objects
 Result : 9
 Given string a : match
 Given string b : attack
 Result : 8
 Given string a : abc
 Given string b : abc
 Result : 3
// Include namespace system
using System;
/*
    Csharp program for
    Shortest Common Supersequence
*/
public class Supersequence
{
	// Returns minimum of given values
	public int minValue(int x, int y)
	{
		if (x < y)
		{
			return x;
		}
		return y;
	}
	// Find length of shortest common Supersequence 
	public void lengthSCS(String a, String b)
	{
		int n = a.Length;
		int m = b.Length;
		// Auxiliary space
		int[,] dp = new int[n + 1,m + 1];
		// Outer loop, executing this from 0 to n (length of a)
		for (int i = 0; i <= n; ++i)
		{
			// Inner loop, executing this from 0 to m (length of b)
			for (int j = 0; j <= m; ++j)
			{
				if (i == 0)
				{
					// When i is zero
					dp[i,j] = j;
				}
				else if (j == 0)
				{
					// When j is zero
					dp[i,j] = i;
				}
				else if (a[i - 1] == b[j - 1])
				{
					//  When character of i-1 and j-1 position are same
					dp[i,j] = dp[i - 1,j - 1] + 1;
				}
				else
				{
					//  When character of i-1 and j-1 position are not same
					dp[i,j] = this.minValue(dp[i,j - 1], dp[i - 1,j]) + 1;
				}
			}
		}
		// Display given strings
		Console.WriteLine(" Given string a : " + a);
		Console.WriteLine(" Given string b : " + b);
		// Display calculated result
		Console.WriteLine(" Result : " + dp[n,m]);
	}
	public static void Main(String[] args)
	{
		Supersequence task = new Supersequence();
		// Test A
		// String a : abc
		// String b : fab
		// [fabc] Supersequence 
		// Result = 4
		task.lengthSCS("abc", "fab");
		// Test B
		// String a : project
		// String b : objects
		// [probjects]  
		// Result : 9
		task.lengthSCS("project", "objects");
		// Test C
		// String a : match
		// String b : attack
		// [mattachk,matatchk,mattackh] etc
		// Result : 8 (length of Supersequence)
		task.lengthSCS("match", "attack");
		// Test D
		// String a : abc
		// String b : abc
		// [abc] etc
		// Result : 3 
		task.lengthSCS("abc", "abc");
	}
}

Output

 Given string a : abc
 Given string b : fab
 Result : 4
 Given string a : project
 Given string b : objects
 Result : 9
 Given string a : match
 Given string b : attack
 Result : 8
 Given string a : abc
 Given string b : abc
 Result : 3
package main
import "fmt"
/*
    Go program for
    Shortest Common Supersequence
*/

// Returns minimum of given values
func minValue(x, y int) int {
	if x < y {
		return x
	}
	return y
}
// Find length of shortest common Supersequence 
func lengthSCS(a, b string) {
	var n int = len(a)
	var m int = len(b)
	// Auxiliary space
	var dp = make([][] int, n + 1)
	for i := 0; i < n + 1; i++ {
		dp[i] = make([]int,m+1)
	}
	// Outer loop, executing this from 0 to n (length of a)
	for i := 0 ; i <= n ; i++ {
		// Inner loop, executing this from 0 to m (length of b)
		for j := 0 ; j <= m ; j++ {
			if i == 0 {
				// When i is zero
				dp[i][j] = j
			} else if j == 0 {
				// When j is zero
				dp[i][j] = i
			} else if a[i - 1] == b[j - 1] {
				//  When character of i-1 and j-1 position are same
				dp[i][j] = dp[i - 1][j - 1] + 1
			} else {
				//  When character of i-1 and j-1 position are not same
				dp[i][j] = minValue(dp[i][j - 1], dp[i - 1][j]) + 1
			}
		}
	}
	// Display given strings
	fmt.Println(" Given string a : ", a)
	fmt.Println(" Given string b : ", b)
	// Display calculated result
	fmt.Println(" Result : ", dp[n][m])
}
func main() {

	// Test A
	// String a : abc
	// String b : fab
	// [fabc] Supersequence 
	// Result = 4
	lengthSCS("abc", "fab")
	// Test B
	// String a : project
	// String b : objects
	// [probjects]  
	// Result : 9
	lengthSCS("project", "objects")
	// Test C
	// String a : match
	// String b : attack
	// [mattachk,matatchk,mattackh] etc
	// Result : 8 (length of Supersequence)
	lengthSCS("match", "attack")
	// Test D
	// String a : abc
	// String b : abc
	// [abc] etc
	// Result : 3 
	lengthSCS("abc", "abc")
}

Output

 Given string a : abc
 Given string b : fab
 Result : 4
 Given string a : project
 Given string b : objects
 Result : 9
 Given string a : match
 Given string b : attack
 Result : 8
 Given string a : abc
 Given string b : abc
 Result : 3
<?php
/*
    Php program for
    Shortest Common Supersequence
*/
class Supersequence
{
	// Returns minimum of given values
	public	function minValue($x, $y)
	{
		if ($x < $y)
		{
			return $x;
		}
		return $y;
	}
	// Find length of shortest common Supersequence 
	public	function lengthSCS($a, $b)
	{
		$n = strlen($a);
		$m = strlen($b);
		// Auxiliary space
		$dp = array_fill(0, $n + 1, array_fill(0, $m + 1, 0));
		// Outer loop, executing this from 0 to n (length of a)
		for ($i = 0; $i <= $n; ++$i)
		{
			// Inner loop, executing this from 0 to m (length of b)
			for ($j = 0; $j <= $m; ++$j)
			{
				if ($i == 0)
				{
					// When i is zero
					$dp[$i][$j] = $j;
				}
				else if ($j == 0)
				{
					// When j is zero
					$dp[$i][$j] = $i;
				}
				else if ($a[$i - 1] == $b[$j - 1])
				{
					//  When character of i-1 and j-1 position are same
					$dp[$i][$j] = $dp[$i - 1][$j - 1] + 1;
				}
				else
				{
					//  When character of i-1 and j-1 position are not same
					$dp[$i][$j] = $this->minValue($dp[$i][$j - 1], $dp[$i - 1][$j]) + 1;
				}
			}
		}
		// Display given strings
		echo(" Given string a : ".$a.
			"\n");
		echo(" Given string b : ".$b.
			"\n");
		// Display calculated result
		echo(" Result : ".$dp[$n][$m].
			"\n");
	}
}

function main()
{
	$task = new Supersequence();
	// Test A
	// String a : abc
	// String b : fab
	// [fabc] Supersequence 
	// Result = 4
	$task->lengthSCS("abc", "fab");
	// Test B
	// String a : project
	// String b : objects
	// [probjects]  
	// Result : 9
	$task->lengthSCS("project", "objects");
	// Test C
	// String a : match
	// String b : attack
	// [mattachk,matatchk,mattackh] etc
	// Result : 8 (length of Supersequence)
	$task->lengthSCS("match", "attack");
	// Test D
	// String a : abc
	// String b : abc
	// [abc] etc
	// Result : 3 
	$task->lengthSCS("abc", "abc");
}
main();

Output

 Given string a : abc
 Given string b : fab
 Result : 4
 Given string a : project
 Given string b : objects
 Result : 9
 Given string a : match
 Given string b : attack
 Result : 8
 Given string a : abc
 Given string b : abc
 Result : 3
/*
    Node JS program for
    Shortest Common Supersequence
*/
class Supersequence
{
	// Returns minimum of given values
	minValue(x, y)
	{
		if (x < y)
		{
			return x;
		}
		return y;
	}
	// Find length of shortest common Supersequence 
	lengthSCS(a, b)
	{
		var n = a.length;
		var m = b.length;
		// Auxiliary space
		var dp = Array(n + 1).fill(0).map(() => new Array(m + 1).fill(0));
		// Outer loop, executing this from 0 to n (length of a)
		for (var i = 0; i <= n; ++i)
		{
			// Inner loop, executing this from 0 to m (length of b)
			for (var j = 0; j <= m; ++j)
			{
				if (i == 0)
				{
					// When i is zero
					dp[i][j] = j;
				}
				else if (j == 0)
				{
					// When j is zero
					dp[i][j] = i;
				}
				else if (a.charAt(i - 1) == b.charAt(j - 1))
				{
					//  When character of i-1 and j-1 position are same
					dp[i][j] = dp[i - 1][j - 1] + 1;
				}
				else
				{
					//  When character of i-1 and j-1 position are not same
					dp[i][j] = this.minValue(dp[i][j - 1], dp[i - 1][j]) + 1;
				}
			}
		}
		// Display given strings
		console.log(" Given string a : " + a);
		console.log(" Given string b : " + b);
		// Display calculated result
		console.log(" Result : " + dp[n][m]);
	}
}

function main()
{
	var task = new Supersequence();
	// Test A
	// String a : abc
	// String b : fab
	// [fabc] Supersequence 
	// Result = 4
	task.lengthSCS("abc", "fab");
	// Test B
	// String a : project
	// String b : objects
	// [probjects]  
	// Result : 9
	task.lengthSCS("project", "objects");
	// Test C
	// String a : match
	// String b : attack
	// [mattachk,matatchk,mattackh] etc
	// Result : 8 (length of Supersequence)
	task.lengthSCS("match", "attack");
	// Test D
	// String a : abc
	// String b : abc
	// [abc] etc
	// Result : 3 
	task.lengthSCS("abc", "abc");
}
main();

Output

 Given string a : abc
 Given string b : fab
 Result : 4
 Given string a : project
 Given string b : objects
 Result : 9
 Given string a : match
 Given string b : attack
 Result : 8
 Given string a : abc
 Given string b : abc
 Result : 3
#    Python 3 program for
#    Shortest Common Supersequence
class Supersequence :
	#  Returns minimum of given values
	def minValue(self, x, y) :
		if (x < y) :
			return x
		
		return y
	
	#  Find length of shortest common Supersequence 
	def lengthSCS(self, a, b) :
		n = len(a)
		m = len(b)
		#  Auxiliary space
		dp = [[0] * (m + 1) for _ in range(n + 1) ]
		i = 0
		#  Outer loop, executing this from 0 to n (length of a)
		while (i <= n) :
			j = 0
			#  Inner loop, executing this from 0 to m (length of b)
			while (j <= m) :
				if (i == 0) :
					#  When i is zero
					dp[i][j] = j
				elif (j == 0) :
					#  When j is zero
					dp[i][j] = i
				elif (a[i - 1] == b[j - 1]) :
					#   When character of i-1 and j-1 position are same
					dp[i][j] = dp[i - 1][j - 1] + 1
				else :
					#   When character of i-1 and j-1 position are not same
					dp[i][j] = self.minValue(dp[i][j - 1], dp[i - 1][j]) + 1
				
				j += 1
			
			i += 1
		
		#  Display given strings
		print(" Given string a : ", a)
		print(" Given string b : ", b)
		#  Display calculated result
		print(" Result : ", dp[n][m])
	

def main() :
	task = Supersequence()
	#  Test A
	#  String a : abc
	#  String b : fab
	#  [fabc] Supersequence 
	#  Result = 4
	task.lengthSCS("abc", "fab")
	#  Test B
	#  String a : project
	#  String b : objects
	#  [probjects]  
	#  Result : 9
	task.lengthSCS("project", "objects")
	#  Test C
	#  String a : match
	#  String b : attack
	#  [mattachk,matatchk,mattackh] etc
	#  Result : 8 (length of Supersequence)
	task.lengthSCS("match", "attack")
	#  Test D
	#  String a : abc
	#  String b : abc
	#  [abc] etc
	#  Result : 3 
	task.lengthSCS("abc", "abc")

if __name__ == "__main__": main()

Output

 Given string a :  abc
 Given string b :  fab
 Result :  4
 Given string a :  project
 Given string b :  objects
 Result :  9
 Given string a :  match
 Given string b :  attack
 Result :  8
 Given string a :  abc
 Given string b :  abc
 Result :  3
#    Ruby program for
#    Shortest Common Supersequence
class Supersequence 
	#  Returns minimum of given values
	def minValue(x, y) 
		if (x < y) 
			return x
		end

		return y
	end

	#  Find length of shortest common Supersequence 
	def lengthSCS(a, b) 
		n = a.length
		m = b.length
		#  Auxiliary space
		dp = Array.new(n + 1) {Array.new(m + 1) {0}}
		i = 0
		#  Outer loop, executing this from 0 to n (length of a)
		while (i <= n) 
			j = 0
			#  Inner loop, executing this from 0 to m (length of b)
			while (j <= m) 
				if (i == 0) 
					#  When i is zero
					dp[i][j] = j
				elsif (j == 0) 
					#  When j is zero
					dp[i][j] = i
				elsif (a[i - 1] == b[j - 1]) 
					#   When character of i-1 and j-1 position are same
					dp[i][j] = dp[i - 1][j - 1] + 1
				else
 
					#   When character of i-1 and j-1 position are not same
					dp[i][j] = self.minValue(dp[i][j - 1], dp[i - 1][j]) + 1
				end

				j += 1
			end

			i += 1
		end

		#  Display given strings
		print(" Given string a : ", a, "\n")
		print(" Given string b : ", b, "\n")
		#  Display calculated result
		print(" Result : ", dp[n][m], "\n")
	end

end

def main() 
	task = Supersequence.new()
	#  Test A
	#  String a : abc
	#  String b : fab
	#  [fabc] Supersequence 
	#  Result = 4
	task.lengthSCS("abc", "fab")
	#  Test B
	#  String a : project
	#  String b : objects
	#  [probjects]  
	#  Result : 9
	task.lengthSCS("project", "objects")
	#  Test C
	#  String a : match
	#  String b : attack
	#  [mattachk,matatchk,mattackh] etc
	#  Result : 8 (length of Supersequence)
	task.lengthSCS("match", "attack")
	#  Test D
	#  String a : abc
	#  String b : abc
	#  [abc] etc
	#  Result : 3 
	task.lengthSCS("abc", "abc")
end

main()

Output

 Given string a : abc
 Given string b : fab
 Result : 4
 Given string a : project
 Given string b : objects
 Result : 9
 Given string a : match
 Given string b : attack
 Result : 8
 Given string a : abc
 Given string b : abc
 Result : 3

import scala.collection.mutable._;
/*
    Scala program for
    Shortest Common Supersequence
*/
class Supersequence()
{
	// Returns minimum of given values
	def minValue(x: Int, y: Int): Int = {
		if (x < y)
		{
			return x;
		}
		return y;
	}
	// Find length of shortest common Supersequence 
	def lengthSCS(a: String, b: String): Unit = {
		var n: Int = a.length();
		var m: Int = b.length();
		// Auxiliary space
		var dp: Array[Array[Int]] = Array.fill[Int](n + 1, m + 1)(0);
		var i: Int = 0;
		// Outer loop, executing this from 0 to n (length of a)
		while (i <= n)
		{
			var j: Int = 0;
			// Inner loop, executing this from 0 to m (length of b)
			while (j <= m)
			{
				if (i == 0)
				{
					// When i is zero
					dp(i)(j) = j;
				}
				else if (j == 0)
				{
					// When j is zero
					dp(i)(j) = i;
				}
				else if (a.charAt(i - 1) == b.charAt(j - 1))
				{
					//  When character of i-1 and j-1 position are same
					dp(i)(j) = dp(i - 1)(j - 1) + 1;
				}
				else
				{
					//  When character of i-1 and j-1 position are not same
					dp(i)(j) = minValue(dp(i)(j - 1), dp(i - 1)(j)) + 1;
				}
				j += 1;
			}
			i += 1;
		}
		// Display given strings
		println(" Given string a : " + a);
		println(" Given string b : " + b);
		// Display calculated result
		println(" Result : " + dp(n)(m));
	}
}
object Main
{
	def main(args: Array[String]): Unit = {
		var task: Supersequence = new Supersequence();
		// Test A
		// String a : abc
		// String b : fab
		// [fabc] Supersequence 
		// Result = 4
		task.lengthSCS("abc", "fab");
		// Test B
		// String a : project
		// String b : objects
		// [probjects]  
		// Result : 9
		task.lengthSCS("project", "objects");
		// Test C
		// String a : match
		// String b : attack
		// [mattachk,matatchk,mattackh] etc
		// Result : 8 (length of Supersequence)
		task.lengthSCS("match", "attack");
		// Test D
		// String a : abc
		// String b : abc
		// [abc] etc
		// Result : 3 
		task.lengthSCS("abc", "abc");
	}
}

Output

 Given string a : abc
 Given string b : fab
 Result : 4
 Given string a : project
 Given string b : objects
 Result : 9
 Given string a : match
 Given string b : attack
 Result : 8
 Given string a : abc
 Given string b : abc
 Result : 3
import Foundation;
/*
    Swift 4 program for
    Shortest Common Supersequence
*/
class Supersequence
{
	// Returns minimum of given values
	func minValue(_ x: Int, _ y: Int) -> Int
	{
		if (x < y)
		{
			return x;
		}
		return y;
	}
	// Find length of shortest common Supersequence 
	func lengthSCS(_ a1: String, _ b1: String)
	{	
      	let a = Array(a1);
      	let b = Array(b1);
		let n: Int = a.count;
		let m: Int = b.count;
		// Auxiliary space
		var dp: [
			[Int]
		] = Array(repeating: Array(repeating: 0, count: m + 1), count: n + 1);
		var i: Int = 0;
		// Outer loop, executing this from 0 to n (length of a)
		while (i <= n)
		{
			var j: Int = 0;
			// Inner loop, executing this from 0 to m (length of b)
			while (j <= m)
			{
				if (i == 0)
				{
					// When i is zero
					dp[i][j] = j;
				}
				else if (j == 0)
				{
					// When j is zero
					dp[i][j] = i;
				}
				else if (a[i - 1] == b[j - 1])
				{
					//  When character of i-1 and j-1 position are same
					dp[i][j] = dp[i - 1][j - 1] + 1;
				}
				else
				{
					//  When character of i-1 and j-1 position are not same
					dp[i][j] = self.minValue(dp[i][j - 1], dp[i - 1][j]) + 1;
				}
				j += 1;
			}
			i += 1;
		}
		// Display given strings
		print(" Given string a : ", a1);
		print(" Given string b : ", b1);
		// Display calculated result
		print(" Result : ", dp[n][m]);
	}
}
func main()
{
	let task: Supersequence = Supersequence();
	// Test A
	// String a : abc
	// String b : fab
	// [fabc] Supersequence 
	// Result = 4
	task.lengthSCS("abc", "fab");
	// Test B
	// String a : project
	// String b : objects
	// [probjects]  
	// Result : 9
	task.lengthSCS("project", "objects");
	// Test C
	// String a : match
	// String b : attack
	// [mattachk,matatchk,mattackh] etc
	// Result : 8 (length of Supersequence)
	task.lengthSCS("match", "attack");
	// Test D
	// String a : abc
	// String b : abc
	// [abc] etc
	// Result : 3 
	task.lengthSCS("abc", "abc");
}
main();

Output

 Given string a :  abc
 Given string b :  fab
 Result :  4
 Given string a :  project
 Given string b :  objects
 Result :  9
 Given string a :  match
 Given string b :  attack
 Result :  8
 Given string a :  abc
 Given string b :  abc
 Result :  3
/*
    Kotlin program for
    Shortest Common Supersequence
*/
class Supersequence
{
	// Returns minimum of given values
	fun minValue(x: Int, y: Int): Int
	{
		if (x < y)
		{
			return x;
		}
		return y;
	}
	// Find length of shortest common Supersequence 
	fun lengthSCS(a: String, b: String): Unit
	{
		val n: Int = a.length;
		val m: Int = b.length;
		// Auxiliary space
		val dp: Array < Array < Int >> = Array(n + 1)
		{
			Array(m + 1)
			{
				0
			}
		};
		var i: Int = 0;
		// Outer loop, executing this from 0 to n (length of a)
		while (i <= n)
		{
			var j: Int = 0;
			// Inner loop, executing this from 0 to m (length of b)
			while (j <= m)
			{
				if (i == 0)
				{
					// When i is zero
					dp[i][j] = j;
				}
				else if (j == 0)
				{
					// When j is zero
					dp[i][j] = i;
				}
				else if (a.get(i - 1) == b.get(j - 1))
				{
					//  When character of i-1 and j-1 position are same
					dp[i][j] = dp[i - 1][j - 1] + 1;
				}
				else
				{
					//  When character of i-1 and j-1 position are not same
					dp[i][j] = this.minValue(dp[i][j - 1], dp[i - 1][j]) + 1;
				}
				j += 1;
			}
			i += 1;
		}
		// Display given strings
		println(" Given string a : " + a);
		println(" Given string b : " + b);
		// Display calculated result
		println(" Result : " + dp[n][m]);
	}
}
fun main(args: Array < String > ): Unit
{
	val task: Supersequence = Supersequence();
	// Test A
	// String a : abc
	// String b : fab
	// [fabc] Supersequence 
	// Result = 4
	task.lengthSCS("abc", "fab");
	// Test B
	// String a : project
	// String b : objects
	// [probjects]  
	// Result : 9
	task.lengthSCS("project", "objects");
	// Test C
	// String a : match
	// String b : attack
	// [mattachk,matatchk,mattackh] etc
	// Result : 8 (length of Supersequence)
	task.lengthSCS("match", "attack");
	// Test D
	// String a : abc
	// String b : abc
	// [abc] etc
	// Result : 3 
	task.lengthSCS("abc", "abc");
}

Output

 Given string a : abc
 Given string b : fab
 Result : 4
 Given string a : project
 Given string b : objects
 Result : 9
 Given string a : match
 Given string b : attack
 Result : 8
 Given string a : abc
 Given string b : abc
 Result : 3
Last updated on by Kalkicode




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