Segregate even and odd nodes in sorted order in scala
Scala program for Segregate even and odd nodes in sorted order. Here problem description and other solutions.
// Scala program for
// Segregate even and odd nodes in ascending order
// Linked list node
class LinkNode(var data: Int,
var next: LinkNode)
{
def this(data: Int)
{
this(data, null);
}
}
class SingleLL(var head: LinkNode)
{
def this()
{
this(null);
}
// Add new node at the end of linked list
def insert(value: Int): Unit = {
// Create a node
var node: LinkNode = new LinkNode(value);
if (this.head == null)
{
this.head = node;
}
else
{
var temp: LinkNode = this.head;
// Find last node
while (temp.next != null)
{
// Visit to next node
temp = temp.next;
}
// Add node at last position
temp.next = node;
}
}
// Display all Linked List elements
def display(): Unit = {
if (this.head != null)
{
var temp: LinkNode = this.head;
while (temp != null)
{
// Display node value
print(" " + temp.data);
// Visit to next node
temp = temp.next;
}
}
else
{
println("Empty Linked list");
}
}
def sortedAdd(element: LinkNode): Unit = {
if (this.head == null)
{
this.head = element;
}
else if (this.head.data >= element.data)
{
element.next = this.head;
this.head = element;
}
else
{
var temp: LinkNode = this.head;
// Finding location of inserting node
while (temp.next != null &&
temp.next.data < element.data)
{
// Visit to next node
temp = temp.next;
}
// Add node
element.next = temp.next;
temp.next = element;
}
}
def segregateNode(odd: SingleLL,
even: SingleLL): Unit = {
var node: LinkNode = null;
// Iterating the linked list node
while (this.head != null)
{
node = this.head;
// Visit to next node
this.head = node.next;
// Set null to next node
node.next = null;
if (node.data % 2 == 0)
{
// When node value is Even
even.sortedAdd(node);
}
else
{
// When node value is Odd
odd.sortedAdd(node);
}
}
}
}
object Main
{
def main(args: Array[String]): Unit = {
// Create linked lists
var sll: SingleLL = new SingleLL();
var odd: SingleLL = new SingleLL();
var even: SingleLL = new SingleLL();
// Linked list sll
// 4 → 3 → 5 → 2 → 11 → 1 → 6 → NULL
sll.insert(4);
sll.insert(3);
sll.insert(5);
sll.insert(2);
sll.insert(11);
sll.insert(1);
sll.insert(6);
println("Initial Element");
// Display all node
sll.display();
sll.segregateNode(odd, even);
println("\nEven Element");
// Display all even node
even.display();
println("\nOdd Element");
// Display all odd node
odd.display();
}
}
Output
Initial Element
4 3 5 2 11 1 6
Even Element
2 4 6
Odd Element
1 3 5 11
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