Segregate even and odd nodes in sorted order in python
Python program for Segregate even and odd nodes in sorted order. Here problem description and explanation.
# Python 3 program for
# Segregate even and odd nodes in ascending order
# Linked list node
class LinkNode :
def __init__(self, data) :
self.data = data
self.next = None
class SingleLL :
def __init__(self) :
self.head = None
# Add new node at the end of linked list
def insert(self, value) :
# Create node
node = LinkNode(value)
if (self.head == None) :
self.head = node
else :
temp = self.head
# Find last node
while (temp.next != None) :
# Visit to next node
temp = temp.next
# Add node at last position
temp.next = node
# Display all Linked List elements
def display(self) :
if (self.head != None) :
temp = self.head
while (temp != None) :
# Display node value
print(" ", temp.data, end = " ")
# Visit to next node
temp = temp.next
else :
print("Empty Linked list")
def sortedAdd(self, element) :
if (self.head == None) :
self.head = element
elif (self.head.data >= element.data) :
element.next = self.head
self.head = element
else :
temp = self.head
# Finding location of inserting node
while (temp.next != None and
temp.next.data < element.data) :
# Visit to next node
temp = temp.next
# Add node
element.next = temp.next
temp.next = element
def segregateNode(self, odd, even) :
node = None
# Iterating the linked list node
while (self.head != None) :
node = self.head
# Visit to next node
self.head = node.next
# Set null to next node
node.next = None
if (node.data % 2 == 0) :
# When node value is Even
even.sortedAdd(node)
else :
# When node value is Odd
odd.sortedAdd(node)
def main() :
# Create linked lists
sll = SingleLL()
odd = SingleLL()
even = SingleLL()
# Linked list sll
# 4 → 3 → 5 → 2 → 11 → 1 → 6 → NULL
sll.insert(4)
sll.insert(3)
sll.insert(5)
sll.insert(2)
sll.insert(11)
sll.insert(1)
sll.insert(6)
print("Initial Element")
# Display all node
sll.display()
sll.segregateNode(odd, even)
print("\nEven Element")
# Display all even node
even.display()
print("\nOdd Element")
# Display all odd node
odd.display()
if __name__ == "__main__": main()
Output
Initial Element
4 3 5 2 11 1 6
Even Element
2 4 6
Odd Element
1 3 5 11
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