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Rod Cutting Problem

Here given code implementation process.

// C program
// Rod Cutting Problem 
#include <stdio.h>

#include <limits.h>

// Return a maximum value in given two numbers
int max_value(int a, int b)
{
	if (a > b)
	{
		return a;
	}
	else
	{
		return b;
	}
}
int cut_rod(int price[], int n)
{
	//Auxiliary space to calculate result
	int result[n + 1];
	int max_val = INT_MIN;
	//Loop controlling variables
	int i = 0;
	int j = 0;
	//Set the first result value
	result[i] = 0;
	//Outer loop
	for (i = 1; i <= n; i++)
	{
		//Inner loop
		for (j = 0; j < i; j++)
		{
			max_val = max_value(max_val, price[j] + result[i - j - 1]);
		}
		// Put the calculated max value
		result[i] = max_val;
		// Reset the max value
		max_val = INT_MIN;
	}
	return result[n];
}
int main()
{
	int price[] = {
		1,
		2,
		5,
		13,
		17,
		19,
		19,
		24
	};
	// Actual rod size from (1 to n)
	// Get total number of price
	int size = sizeof(price) / sizeof(price[0]);
	printf("Max profit are %d", cut_rod(price, size));
	return 0;
}

Output

Max profit are 26
// Java Program 
// Rod Cutting Problem 
class RodCutting
{
	// Return a maximum value in given two numbers
	public int max_value(int a, int b)
	{
		if (a > b)
		{
			return a;
		}
		else
		{
			return b;
		}
	}
	public int cut_rod(int[] price, int n)
	{
		//Auxiliary space to calculate result
		int[] result = new int[n + 1];
		int max_val = Integer.MIN_VALUE;
		//Loop controlling variables
		int i = 0;
		int j = 0;
		//Set the first result value
		result[i] = 0;
		//Outer loop
		for (i = 1; i <= n; i++)
		{
			//Inner loop
			for (j = 0; j < i; j++)
			{
				max_val = max_value(max_val, price[j] + result[i - j - 1]);
			}
			// Put the calculated max value
			result[i] = max_val;
			// Reset the max value
			max_val = Integer.MIN_VALUE;
		}
		return result[n];
	}
	public static void main(String[] args)
	{
		//Make object 
		RodCutting obj = new RodCutting();
		int[] price = {
			1,
			2,
			5,
			13,
			17,
			19,
			19,
			24
		};
		// Get total number of price
		int size = price.length;
		System.out.print("Max profit are " + obj.cut_rod(price, size));
	}
}

Output

Max profit are 26
//Include header file
#include <iostream>
#include<limits.h>
using namespace std;

// C++ Program 
// Rod Cutting Problem 

class RodCutting
{
	public:
		// Return a maximum value in given two numbers
		int max_value(int a, int b)
		{
			if (a > b)
			{
				return a;
			}
			else
			{
				return b;
			}
		}
	int cut_rod(int price[], int n)
	{
		//Auxiliary space to calculate result
		int result[n+1];
		int max_val = INT_MIN;
		//Loop controlling variables
		int i = 0;
		int j = 0;
		//Set the first result value
		result[i] = 0;
		//Outer loop
		for (i = 1; i <= n; i++)
		{
			//Inner loop
			for (j = 0; j < i; j++)
			{
				max_val = this->max_value(max_val, price[j] + result[i - j - 1]);
			}
			// Put the calculated max value
			result[i] = max_val;
			// Reset the max value
			max_val = INT_MIN;
		}
		return result[n];
	}
};
int main()
{
	//Make object 
	RodCutting obj = RodCutting();
	int price[] = {
		1 , 2 , 5 , 13 , 17 , 19 , 19 , 24
	};
	// Get total number of price
	int size = sizeof(price) / sizeof(price[0]);
	cout << "Max profit are " << obj.cut_rod(price, size);
	return 0;
}

Output

Max profit are 26
//Include namespace system
using System;

// C# Program 
// Rod Cutting Problem 

class RodCutting
{
	// Return a maximum value in given two numbers
	public int max_value(int a, int b)
	{
		if (a > b)
		{
			return a;
		}
		else
		{
			return b;
		}
	}
	public int cut_rod(int[] price, int n)
	{
		//Auxiliary space to calculate result
		int[] result = new int[n + 1];
		int max_val = int.MinValue;
		//Loop controlling variables
		int i = 0;
		int j = 0;
		//Set the first result value
		result[i] = 0;
		//Outer loop
		for (i = 1; i <= n; i++)
		{
			//Inner loop
			for (j = 0; j < i; j++)
			{
				max_val = max_value(max_val, price[j] + result[i - j - 1]);
			}
			// Put the calculated max value
			result[i] = max_val;
			// Reset the max value
			max_val = int.MinValue;
		}
		return result[n];
	}
	public static void Main(String[] args)
	{
		//Make object 
		RodCutting obj = new RodCutting();
		int[] price = {
			1 , 2 , 5 , 13 , 17 , 19 , 19 , 24
		};
		// Get total number of price
		int size = price.Length;
		Console.Write("Max profit are " + obj.cut_rod(price, size));
	}
}

Output

Max profit are 26
<?php

// Php Program 
// Rod Cutting Problem 

class RodCutting
{
	// Return a maximum value in given two numbers
	public	function max_value($a, $b)
	{
		if ($a > $b)
		{
			return $a;
		}
		else
		{
			return $b;
		}
	}
	public	function cut_rod( $price, $n)
	{
		//Auxiliary space to calculate result
		$result = array_fill(0, $n + 1, 0);
		$max_val = -PHP_INT_MAX;
		//Loop controlling variables
		$i = 0;
		$j = 0;
		//Set the first result value
		$result[$i] = 0;
		//Outer loop
		for ($i = 1; $i <= $n; $i++)
		{
			//Inner loop
			for ($j = 0; $j < $i; $j++)
			{
				$max_val = $this->max_value($max_val, $price[$j] + $result[$i - $j - 1]);
			}
			// Put the calculated max value
			$result[$i] = $max_val;
			// Reset the max value
			$max_val = -PHP_INT_MAX;
		}
		return $result[$n];
	}
}

function main()
{
	//Make object 
	$obj = new RodCutting();
	$price = array(1, 2, 5, 13, 17, 19, 19, 24);
	// Get total number of price
	$size = count($price);
	echo "Max profit are ". $obj->cut_rod($price, $size);
}
main();

Output

Max profit are 26
// Node Js Program 
// Rod Cutting Problem 
class RodCutting
{
	// Return a maximum value in given two numbers
	max_value(a, b)
	{
		if (a > b)
		{
			return a;
		}
		else
		{
			return b;
		}
	}
	cut_rod(price, n)
	{
		//Auxiliary space to calculate result
		var result = Array(n + 1).fill(0);
		var max_val = -Number.MAX_VALUE;
		//Loop controlling variables
		var i = 0;
		var j = 0;
		//Outer loop
		for (i = 1; i <= n; i++)
		{
			//Inner loop
			for (j = 0; j < i; j++)
			{
				max_val = this.max_value(max_val, price[j] + result[i - j - 1]);
			}
			// Put the calculated max value
			result[i] = max_val;
			// Reset the max value
			max_val = -Number.MAX_VALUE;
		}
		return result[n];
	}
}

function main()
{
	//Make object 
	var obj = new RodCutting();
	var price = [1, 2, 5, 13, 17, 19, 19, 24];
	// Get total number of price
	var size = price.length;
	process.stdout.write("Max profit are " + obj.cut_rod(price, size));
}
main();

Output

Max profit are 26
import sys

#  Python 3 Program 
#  Rod Cutting Problem 

class RodCutting :
	#  Return a maximum value in given two numbers
	def max_value(self, a, b) :
		if (a > b) :
			return a
		else :
			return b
		
	
	def cut_rod(self, price, n) :
		# Auxiliary space to calculate result
		result = [0] * (n + 1)
		max_val = -sys.maxsize
		# Loop controlling variables
		i = 1
		j = 0
		while (i <= n) :
			# Inner loop
			j = 0
			while (j < i) :
				max_val = self.max_value(max_val, price[j] + result[i - j - 1])
				j += 1
			
			#  Put the calculated max value
			result[i] = max_val
			#  Reset the max value
			max_val = -sys.maxsize
			i += 1
		
		return result[n]
	

def main() :
	# Make object 
	obj = RodCutting()
	price = [1, 2, 5, 13, 17, 19, 19, 24]
	#  Get total number of price
	size = len(price)
	print("Max profit are ", obj.cut_rod(price, size), end = "")

if __name__ == "__main__": main()

Output

Max profit are  26
#  Ruby Program 
#  Rod Cutting Problem 

class RodCutting 
	#  Return a maximum value in given two numbers
	def max_value(a, b) 
		if (a > b) 
			return a
		else 
			return b
		end
	end
	def cut_rod(price, n) 
		# Auxiliary space to calculate result
		result = Array.new(n + 1) {0}
		max_val = -(2 ** (0. size * 8 - 2))
		# Loop controlling variables
		i = 1
		j = 0
		while (i <= n) 
			# Inner loop
			j = 0
			while (j < i) 
				max_val = self.max_value(max_val, price[j] + result[i - j - 1])
				j += 1
			end
			#  Put the calculated max value
			result[i] = max_val
			#  Reset the max value
			max_val = -(2 ** (0. size * 8 - 2))
			i += 1
		end
		return result[n]
	end
end
def main() 
	# Make object 
	obj = RodCutting.new()
	price = [1, 2, 5, 13, 17, 19, 19, 24]
	#  Get total number of price
	size = price.length
	print("Max profit are ", obj.cut_rod(price, size))
end
main()

Output

Max profit are 26
// Scala Program 
// Rod Cutting Problem 

class RodCutting
{
	// Return a maximum value in given two numbers
	def max_value(a: Int, b: Int): Int = {
		if (a > b)
		{
			return a;
		}
		else
		{
			return b;
		}
	}
	def cut_rod(price: Array[Int], n: Int): Int = {
		//Auxiliary space to calculate result
		var result: Array[Int] = Array.fill[Int](n + 1)(0);
		var max_val: Int = Int.MinValue;
		//Loop controlling variables
		var i: Int = 1;
		var j: Int = 0;
		while (i <= n)
		{
			//Inner loop
			j = 0;
			while (j < i)
			{
				max_val = max_value(max_val, price(j) + result(i - j - 1));
				j += 1;
			}
			// Put the calculated max value
			result(i) = max_val;
			// Reset the max value
			max_val = Int.MinValue;
			i += 1;
		}
		return result(n);
	}
}
object Main
{
	def main(args: Array[String]): Unit = {
		//Make object 
		var obj: RodCutting = new RodCutting();
		var price: Array[Int] = Array(1, 2, 5, 13, 17, 19, 19, 24);
		// Get total number of price
		var size: Int = price.length;
		print("Max profit are " + obj.cut_rod(price, size));
	}
}

Output

Max profit are 26
// Swift 4 Program 
// Rod Cutting Problem 

class RodCutting
{
	// Return a maximum value in given two numbers
	func max_value(_ a: Int, _ b: Int) -> Int
	{
		if (a > b)
		{
			return a;
		}
		else
		{
			return b;
		}
	}
	func cut_rod(_ price: [Int], _ n: Int) -> Int
	{
		//Auxiliary space to calculate result
		var result: [Int] = Array(repeating: 0, count: n + 1);
		var max_val: Int = Int.min;
		//Loop controlling variables
		var i: Int = 1;
		var j: Int = 0;
		while (i <= n)
		{
			//Inner loop
			j = 0;
			while (j < i)
			{
				max_val = self.max_value(max_val, price[j] + result[i - j - 1]);
				j += 1;
			}
			// Put the calculated max value
			result[i] = max_val;
			// Reset the max value
			max_val = Int.min;
			i += 1;
		}
		return result[n];
	}
}
func main()
{
	//Make object 
	let obj: RodCutting = RodCutting();
	let price: [Int] = [1, 2, 5, 13, 17, 19, 19, 24];
	// Get total number of price
	let size: Int = price.count;
	print("Max profit are ", obj.cut_rod(price, size), terminator: "");
}
main();

Output

Max profit are  26
Last updated on by Kalkicode




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