Reverse a number using recursion
Here given code implementation process.
//C Program
//Reverse a number using recursion
#include <stdio.h>
int reverse_num(int number, int result)
{
//Base condition to stop the recursion process
if (number > 0)
{
//Recursive function call
return reverse_num(number / 10, result * 10 + (number % 10));
}
//When no digit remaining
return result;
}
//This is handling the request process of reverse number digit
int reverse(int number)
{
//Display given number
printf("\nBefore Number : [%d]\n", number);
if (number < 0)
{
return -reverse_num(-number, 0);
}
else
{
return reverse_num(number, 0);
}
}
int main()
{
//Test Case
int number = 12345;
number = reverse(number);
//After reverse
printf("After Number : [%d]\n", number);
number = reverse(78942);
//After reverse
printf("After Number : [%d]\n", number);
number = reverse(1020);
//After reverse
printf("After Number : [%d]\n", number);
number = reverse(-28);
//After reverse
printf("After Number : [%d]\n", number);
return 0;
}Output
Before Number : [12345]
After Number : [54321]
Before Number : [78942]
After Number : [24987]
Before Number : [1020]
After Number : [201]
Before Number : [-28]
After Number : [-82]// Program for
// Reverse a number using recursion in java
class MyString
{
//This is reversing a number elements recursively
public int reverse_num(int number, int result)
{
//Base condition to stop the recursion process
if (number > 0)
{
//Recursive function call
return reverse_num(number / 10, result * 10 + (number % 10));
}
//When no digit remaining
return result;
}
//This is handling the request process of reverse number digit
public int reverse(int number)
{
//Display given number
System.out.print("\nBefore Number : [" + number + "]\n");
if (number < 0)
{
return -reverse_num(-number, 0);
}
else
{
return reverse_num(number, 0);
}
}
public static void main(String[] args)
{
MyString obj = new MyString();
//Test Case
int number = 12345;
number = obj.reverse(number);
//After reverse
System.out.print("After Number : [" + number + "]\n");
number = obj.reverse(78942);
//After reverse
System.out.print("After Number : [" + number + "]\n");
number = obj.reverse(1020);
//After reverse
System.out.print("After Number : [" + number + "]\n");
number = obj.reverse(-28);
//After reverse
System.out.print("After Number : [" + number + "]\n");
}
}Output
Before Number : [12345]
After Number : [54321]
Before Number : [78942]
After Number : [24987]
Before Number : [1020]
After Number : [201]
Before Number : [-28]
After Number : [-82]//Include header file
#include <iostream>
using namespace std;
// Program for
// Reverse a number using recursion in C++
class MyString
{
public:
//This is reversing a number elements recursively
int reverse_num(int number, int result)
{
//Base condition to stop the recursion process
if (number > 0)
{
//Recursive function call
return this->reverse_num(number / 10, result * 10 + (number % 10));
}
//When no digit remaining
return result;
}
//This is handling the request process of reverse number digit
int reverse(int number)
{
//Display given number
cout << "\nBefore Number : [" << number << "]\n";
if (number < 0)
{
return -this->reverse_num(-number, 0);
}
else
{
return this->reverse_num(number, 0);
}
}
};
int main()
{
MyString obj = MyString();
//Test Case
int number = 12345;
number = obj.reverse(number);
//After reverse
cout << "After Number : [" << number << "]\n";
number = obj.reverse(78942);
//After reverse
cout << "After Number : [" << number << "]\n";
number = obj.reverse(1020);
//After reverse
cout << "After Number : [" << number << "]\n";
number = obj.reverse(-28);
//After reverse
cout << "After Number : [" << number << "]\n";
return 0;
}Output
Before Number : [12345]
After Number : [54321]
Before Number : [78942]
After Number : [24987]
Before Number : [1020]
After Number : [201]
Before Number : [-28]
After Number : [-82]//Include namespace system
using System;
// Program for
// Reverse a number using recursion in C#
class MyString
{
//This is reversing a number elements recursively
public int reverse_num(int number, int result)
{
//Base condition to stop the recursion process
if (number > 0)
{
//Recursive function call
return reverse_num(number / 10, result * 10 + (number % 10));
}
//When no digit remaining
return result;
}
//This is handling the request process of reverse number digit
public int reverse(int number)
{
//Display given number
Console.Write("\nBefore Number : [" + number + "]\n");
if (number < 0)
{
return -reverse_num(-number, 0);
}
else
{
return reverse_num(number, 0);
}
}
public static void Main(String[] args)
{
MyString obj = new MyString();
//Test Case
int number = 12345;
number = obj.reverse(number);
//After reverse
Console.Write("After Number : [" + number + "]\n");
number = obj.reverse(78942);
//After reverse
Console.Write("After Number : [" + number + "]\n");
number = obj.reverse(1020);
//After reverse
Console.Write("After Number : [" + number + "]\n");
number = obj.reverse(-28);
//After reverse
Console.Write("After Number : [" + number + "]\n");
}
}Output
Before Number : [12345]
After Number : [54321]
Before Number : [78942]
After Number : [24987]
Before Number : [1020]
After Number : [201]
Before Number : [-28]
After Number : [-82]<?php
// Program for
// Reverse a number using recursion in Php
class MyString
{
//This is reversing a number elements recursively
public function reverse_num($number, $result)
{
//Base condition to stop the recursion process
if ($number > 0)
{
//Recursive function call
return $this->reverse_num(intval($number / 10), $result * 10 + ($number % 10));
}
//When no digit remaining
return $result;
}
//This is handling the request process of reverse number digit
public function reverse($number)
{
echo "\nBefore Number : [". $number ."]\n";
if ($number < 0)
{
return -$this->reverse_num(-$number, 0);
}
else
{
return $this->reverse_num($number, 0);
}
}
}
function main()
{
$obj = new MyString();
//Test Case
$number = 12345;
$number = $obj->reverse($number);
echo "After Number : [". $number ."]\n";
$number = $obj->reverse(78942);
echo "After Number : [". $number ."]\n";
$number = $obj->reverse(1020);
echo "After Number : [". $number ."]\n";
$number = $obj->reverse(-28);
echo "After Number : [". $number ."]\n";
}
main();Output
Before Number : [12345]
After Number : [54321]
Before Number : [78942]
After Number : [24987]
Before Number : [1020]
After Number : [201]
Before Number : [-28]
After Number : [-82]// Program for
// Reverse a number using recursion in Node Js
class MyString
{
//This is reversing a number elements recursively
reverse_num(number, result)
{
//Base condition to stop the recursion process
if (number > 0)
{
//Recursive function call
return this.reverse_num(parseInt(number / 10), result * 10 + (number % 10));
}
//When no digit remaining
return result;
}
//This is handling the request process of reverse number digit
reverse(number)
{
process.stdout.write("\nBefore Number : [" + number + "]\n");
if (number < 0)
{
return -this.reverse_num(-number, 0);
}
else
{
return this.reverse_num(number, 0);
}
}
}
function main()
{
var obj = new MyString();
//Test Case
var number = 12345;
number = obj.reverse(number);
process.stdout.write("After Number : [" + number + "]\n");
number = obj.reverse(78942);
process.stdout.write("After Number : [" + number + "]\n");
number = obj.reverse(1020);
process.stdout.write("After Number : [" + number + "]\n");
number = obj.reverse(-28);
process.stdout.write("After Number : [" + number + "]\n");
}
main();Output
Before Number : [12345]
After Number : [54321]
Before Number : [78942]
After Number : [24987]
Before Number : [1020]
After Number : [201]
Before Number : [-28]
After Number : [-82]# Program for
# Reverse a number using recursion in Python 3
class MyString :
# This is reversing a number elements recursively
def reverse_num(self, number, result) :
# Base condition to stop the recursion process
if (number > 0) :
# Recursive function call
return self.reverse_num(int(number / 10), result * 10 + (number % 10))
# When no digit remaining
return result
# This is handling the request process of reverse number digit
def reverse(self, number) :
print("\nBefore Number : [", number ,"]\n", end = "")
if (number < 0) :
return -self.reverse_num(-number, 0)
else :
return self.reverse_num(number, 0)
def main() :
obj = MyString()
# Test Case
number = 12345
number = obj.reverse(number)
print("After Number : [", number ,"]\n", end = "")
number = obj.reverse(78942)
print("After Number : [", number ,"]\n", end = "")
number = obj.reverse(1020)
print("After Number : [", number ,"]\n", end = "")
number = obj.reverse(-28)
print("After Number : [", number ,"]\n", end = "")
if __name__ == "__main__": main()Output
Before Number : [ 12345 ]
After Number : [ 54321 ]
Before Number : [ 78942 ]
After Number : [ 24987 ]
Before Number : [ 1020 ]
After Number : [ 201 ]
Before Number : [ -28 ]
After Number : [ -82 ]# Program for
# Reverse a number using recursion in Ruby
class MyString
# This is reversing a number elements recursively
def reverse_num(number, result)
# Base condition to stop the recursion process
if (number > 0)
# Recursive function call
return self.reverse_num(number / 10, result * 10 + (number % 10))
end
# When no digit remaining
return result
end
# This is handling the request process of reverse number digit
def reverse(number)
# Display given number
print("\nBefore Number : [", number ,"]\n")
if (number < 0)
return -self.reverse_num(-number, 0)
else
return self.reverse_num(number, 0)
end
end
end
def main()
obj = MyString.new()
# Test Case
number = 12345
number = obj.reverse(number)
# After reverse
print("After Number : [", number ,"]\n")
number = obj.reverse(78942)
# After reverse
print("After Number : [", number ,"]\n")
number = obj.reverse(1020)
# After reverse
print("After Number : [", number ,"]\n")
number = obj.reverse(-28)
# After reverse
print("After Number : [", number ,"]\n")
end
main()Output
Before Number : [12345]
After Number : [54321]
Before Number : [78942]
After Number : [24987]
Before Number : [1020]
After Number : [201]
Before Number : [-28]
After Number : [-82]
// Program for
// Reverse a number using recursion in Scala
class MyString
{
//This is reversing a number elements recursively
def reverse_num(number: Int, result: Int): Int = {
//Base condition to stop the recursion process
if (number > 0)
{
//Recursive function call
return reverse_num((number / 10).toInt, result * 10 + (number % 10));
}
//When no digit remaining
return result;
}
//This is handling the request process of reverse number digit
def reverse(number: Int): Int = {
//Display given number
print("\nBefore Number : [" + number + "]\n");
if (number < 0)
{
return -reverse_num(-number, 0);
}
else
{
return reverse_num(number, 0);
}
}
}
object Main
{
def main(args: Array[String]): Unit = {
var obj: MyString = new MyString();
//Test Case
var number: Int = 12345;
number = obj.reverse(number);
//After reverse
print("After Number : [" + number + "]\n");
number = obj.reverse(78942);
//After reverse
print("After Number : [" + number + "]\n");
number = obj.reverse(1020);
//After reverse
print("After Number : [" + number + "]\n");
number = obj.reverse(-28);
//After reverse
print("After Number : [" + number + "]\n");
}
}Output
Before Number : [12345]
After Number : [54321]
Before Number : [78942]
After Number : [24987]
Before Number : [1020]
After Number : [201]
Before Number : [-28]
After Number : [-82]// Program for
// Reverse a number using recursion in Swift
class MyString
{
//This is reversing a number elements recursively
func reverse_num(_ number: Int, _ result: Int) -> Int
{
//Base condition to stop the recursion process
if (number > 0)
{
//Recursive function call
return self.reverse_num(number / 10, result * 10 + (number % 10));
}
//When no digit remaining
return result;
}
//This is handling the request process of reverse number digit
func reverse(_ number: Int) -> Int
{
print("\nBefore Number : [", number ,"]\n", terminator: "");
if (number < 0)
{
return -self.reverse_num(-number, 0);
}
else
{
return self.reverse_num(number, 0);
}
}
}
func main()
{
let obj: MyString = MyString();
//Test Case
var number: Int = 12345;
number = obj.reverse(number);
print("After Number : [", number ,"]\n", terminator: "");
number = obj.reverse(78942);
print("After Number : [", number ,"]\n", terminator: "");
number = obj.reverse(1020);
print("After Number : [", number ,"]\n", terminator: "");
number = obj.reverse(-28);
print("After Number : [", number ,"]\n", terminator: "");
}
main();Output
Before Number : [ 12345 ]
After Number : [ 54321 ]
Before Number : [ 78942 ]
After Number : [ 24987 ]
Before Number : [ 1020 ]
After Number : [ 201 ]
Before Number : [ -28 ]
After Number : [ -82 ]
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