reverse a number using recursion in golang

Go program for reverse a number using recursion . Here problem description and explanation.

// Go program for
// Reverse a number using recursion
package main
import "fmt"

// This is reversing a number elements recursively
func reverseNum(number, result int) int {
	// Base condition to stop the recursion process
	if number > 0 {
		// Recursive function call
		return reverseNum(number / 10, 
			result * 10 + (number % 10))
	}
	// When no digit remaining
	return result
}
// This is handling the request process of reverse number digit
func reverse(number int) int {
	// Display given number
	fmt.Println("\nBefore Number : [", number, "]")
	if number < 0 {
		// Handle negative number
		return -reverseNum(-number, 0)
	} else {
		return reverseNum(number, 0)
	}
}
func main() {

	// Test Case 
	var number int = 12345
	number = reverse(number)
	// After reverse	
	fmt.Println("After Number  : [", number, "]")
	number = reverse(78942)
	// After reverse	
	fmt.Println("After Number  : [", number, "]")
	number = reverse(1020)
	// After reverse	
	fmt.Println("After Number  : [", number, "]")
	number = reverse(-28)
	// After reverse	
	fmt.Println("After Number  : [", number, "]")
}

Output

Before Number : [12345]
After Number  : [54321]

Before Number : [78942]
After Number  : [24987]

Before Number : [1020]
After Number  : [201]

Before Number : [-28]
After Number  : [-82]