Remove all subtree of Even values node in binary tree

Here given code implementation process.

// C Program 
// Remove all subtree of Even values node in binary tree
#include <stdio.h>
#include <stdlib.h>

// Tree Node
struct TreeNode
{
	int data;
	struct TreeNode *left;
	struct TreeNode *right;
};
// Binary Tree
struct BinaryTree
{
	struct TreeNode *root;
};
// Create new tree
struct BinaryTree *newTree()
{
	// Create dynamic node
	struct BinaryTree *tree = 
      (struct BinaryTree *) malloc(sizeof(struct BinaryTree));
	if (tree != NULL)
	{
		tree->root = NULL;
	}
	else
	{
		printf("Memory Overflow to Create tree Tree\n");
	}
	//return new tree
	return tree;
}
// This is creates and returns the new binary tree node
struct TreeNode *newNode(int data)
{
	// Create dynamic node
	struct TreeNode *new_node = 
      (struct TreeNode *) malloc(sizeof(struct TreeNode));
	if (new_node != NULL)
	{
		//Set data and pointer values
		new_node->data = data;
		new_node->left = NULL;
		new_node->right = NULL;
	}
	else
	{
		//This is indicates, 
		// segmentation fault or memory overflow problem
		printf("Memory Overflow\n");
		exit(0);
	}
	//return new node
	return new_node;
}

struct TreeNode *deleteEvenSubTree(struct TreeNode *node)
{
	if (node != NULL)
	{
		node->left = deleteEvenSubTree(node->left);
		node->right = deleteEvenSubTree(node->right);
		if (node->left == NULL && 
            node->right == NULL &&
            node->data % 2 == 0)
		{
			// free Node
			free(node);
			return NULL;
		}
	}
	return node;
}
int main(int argc, char
	const *argv[])
{
	struct BinaryTree *tree1 = newTree();
	struct BinaryTree *tree2 = newTree();
	/*
	         1                            
	       /   \    
	      2     7    
	     / \     \               
	    6   3     8
	             /  \
	            10   12 
	    ------------
	    Binary tree A
	*/
	// Tree A
	tree1->root = newNode(1);
	tree1->root->left = newNode(2);
	tree1->root->right = newNode(7);
	tree1->root->right->right = newNode(8);
	tree1->root->left->right = newNode(3);
	tree1->root->left->left = newNode(6);
	tree1->root->right->right->left = newNode(10);
	tree1->root->right->right->right = newNode(12);
	/*
	Construct Tree number 2
	---------

	         10                            
	       /   \    
	      2     7    
	     / \     \               
	    6   4     8
	       / \
	      8   20
	    ------------
	    Binary tree B
	*/
	// Tree B
	tree2->root = newNode(10);
	tree2->root->left = newNode(2);
	tree2->root->right = newNode(7);
	tree2->root->right->right = newNode(8);
	tree2->root->left->right = newNode(4);
	tree2->root->left->left = newNode(6);
	tree2->root->left->right->left = newNode(8);
	tree2->root->left->right->right = newNode(20);
	// Test A
	printf("\n Before Delete Tree 1 \n");
	preorder(tree1->root);
	// Remove subtree which contains all Even nodes
	tree1->root = deleteEvenSubTree(tree1->root);
	/*
	         1                            
	       /   \    
	      2     7    
	       \                    
	        3            
	    ------------
	    After delete Even node subtrees
	*/
	printf("\n After Delete Tree 1 \n");
	preorder(tree1->root);
	// Test B
	printf("\n Before Delete Tree 2 \n");
	preorder(tree2->root);
	// Remove subtree which contains all Even nodes
	tree2->root = deleteEvenSubTree(tree2->root);
	/*
	         10                            
	           \    
	            7            
	    ------------
	    After delete Even node subtrees
	*/
	printf("\n After Delete Tree 2 \n");
	preorder(tree2->root);
	return 0;
}

Output

 Before Delete Tree 1
  1  2  6  3  7  8  10  12
 After Delete Tree 1
  1  2  3  7
 Before Delete Tree 2
  10  2  6  4  8  20  7  8
 After Delete Tree 2
  10  7
/*
  Java program for
  Remove all subtree of Even values node in binary tree
*/
// Binary Tree node
class TreeNode
{
	public int data;
	public TreeNode left;
	public TreeNode right;
	public TreeNode(int data)
	{
		// Set node value
		this.data = data;
		this.left = null;
		this.right = null;
	}
}
public class BinaryTree
{
	public TreeNode root;
	public BinaryTree()
	{
		// Set initial value
		this.root = null;
	}
	// Display preorder view of binary tree
	public void preorder(TreeNode node)
	{
		if (node != null)
		{
			//Print node value
			System.out.print("  " + node.data);
			preorder(node.left);
			preorder(node.right);
		}
	}
	public TreeNode deleteEvenSubTree(TreeNode node)
	{
		if (node != null)
		{
			node.left = deleteEvenSubTree(node.left);
			node.right = deleteEvenSubTree(node.right);
			if (node.left == null && 
                node.right == null && 
                node.data % 2 == 0)
			{
				// delete Node
				return null;
			}
		}
		return node;
	}
	public static void main(String[] args)
	{
		BinaryTree tree1 = new BinaryTree();
		BinaryTree tree2 = new BinaryTree();
		/*
		         1                            
		       /   \    
		      2     7    
		     / \     \               
		    6   3     8
		             /  \
		            10   12 
		    ------------
		    Binary tree A
		*/
		// Tree A
		tree1.root = new TreeNode(1);
		tree1.root.left = new TreeNode(2);
		tree1.root.right = new TreeNode(7);
		tree1.root.right.right = new TreeNode(8);
		tree1.root.left.right = new TreeNode(3);
		tree1.root.left.left = new TreeNode(6);
		tree1.root.right.right.left = new TreeNode(10);
		tree1.root.right.right.right = new TreeNode(12);
		/*
		    Construct Tree number 2
		    ---------
		         10                            
		       /   \    
		      2     7    
		     / \     \               
		    6   4     8
		       / \
		      8   20
		    ------------
		    Binary tree B
		*/
		// Tree B
		tree2.root = new TreeNode(10);
		tree2.root.left = new TreeNode(2);
		tree2.root.right = new TreeNode(7);
		tree2.root.right.right = new TreeNode(8);
		tree2.root.left.right = new TreeNode(4);
		tree2.root.left.left = new TreeNode(6);
		tree2.root.left.right.left = new TreeNode(8);
		tree2.root.left.right.right = new TreeNode(20);
		// Test A
		System.out.print("\n Before Delete Tree 1 \n");
		tree1.preorder(tree1.root);
		// Remove subtree which contains all Even nodes
		tree1.root = tree1.deleteEvenSubTree(tree1.root);
		/*
		     1                            
		   /   \    
		  2     7    
		   \                    
		    3            
		    ------------
		    After delete Even node subtrees
		*/
		System.out.print("\n After Delete Tree 1 \n");
		tree1.preorder(tree1.root);
		// Test B
		System.out.print("\n Before Delete Tree 2 \n");
		tree2.preorder(tree2.root);
		// Remove subtree which contains all Even nodes
		tree2.root = tree2.deleteEvenSubTree(tree2.root);
		/*
		   10                            
		     \    
		      7            
		    ------------
		    After delete Even node subtrees
		*/
		System.out.print("\n After Delete Tree 2 \n");
		tree2.preorder(tree2.root);
	}
}

Output

 Before Delete Tree 1
  1  2  6  3  7  8  10  12
 After Delete Tree 1
  1  2  3  7
 Before Delete Tree 2
  10  2  6  4  8  20  7  8
 After Delete Tree 2
  10  7
// Include header file
#include <iostream>

using namespace std;
/*
  C++ program for
  Remove all subtree of Even values node in binary tree
*/
// Binary Tree node
class TreeNode
{
	public: int data;
	TreeNode *left;
	TreeNode *right;
	TreeNode(int data)
	{
		// Set node value
		this->data = data;
		this->left = NULL;
		this->right = NULL;
	}
};
class BinaryTree
{
	public: TreeNode *root;
	BinaryTree()
	{
		this->root = NULL;
	}
	// Display preorder view of binary tree
	void preorder(TreeNode *node)
	{
		if (node != NULL)
		{
			//Print node value
			cout << "  " << node->data;
			this->preorder(node->left);
			this->preorder(node->right);
		}
	}
	TreeNode *deleteEvenSubTree(TreeNode *node)
	{
		if (node != NULL)
		{
			node->left = this->deleteEvenSubTree(node->left);
			node->right = this->deleteEvenSubTree(node->right);
			if (node->left == NULL && 
                node->right == NULL && 
                node->data % 2 == 0)
			{
				// delete Node
              	delete node;
				return NULL;
			}
		}
		return node;
	}
};
int main()
{
	BinaryTree *tree1 = new BinaryTree();
	BinaryTree *tree2 = new BinaryTree();
	/*
	         1                            
	       /   \    
	      2     7    
	     / \     \               
	    6   3     8
	             /  \
	            10   12 
	    ------------
	    Binary tree A
	*/
	// Tree A
	tree1->root = new TreeNode(1);
	tree1->root->left = new TreeNode(2);
	tree1->root->right = new TreeNode(7);
	tree1->root->right->right = new TreeNode(8);
	tree1->root->left->right = new TreeNode(3);
	tree1->root->left->left = new TreeNode(6);
	tree1->root->right->right->left = new TreeNode(10);
	tree1->root->right->right->right = new TreeNode(12);
	/*
	    Construct Tree number 2
	    ---------
	         10                            
	       /   \    
	      2     7    
	     / \     \               
	    6   4     8
	       / \
	      8   20
	    ------------
	    Binary tree B
	*/
	// Tree B
	tree2->root = new TreeNode(10);
	tree2->root->left = new TreeNode(2);
	tree2->root->right = new TreeNode(7);
	tree2->root->right->right = new TreeNode(8);
	tree2->root->left->right = new TreeNode(4);
	tree2->root->left->left = new TreeNode(6);
	tree2->root->left->right->left = new TreeNode(8);
	tree2->root->left->right->right = new TreeNode(20);
	// Test A
	cout << "\n Before Delete Tree 1 \n";
	tree1->preorder(tree1->root);
	// Remove subtree which contains all Even nodes
	tree1->root = tree1->deleteEvenSubTree(tree1->root);
	/*
	     1                            
	   /   \    
	  2     7    
	   \                    
	    3            
	    ------------
	    After delete Even node subtrees
	*/
	cout << "\n After Delete Tree 1 \n";
	tree1->preorder(tree1->root);
	// Test B
	cout << "\n Before Delete Tree 2 \n";
	tree2->preorder(tree2->root);
	// Remove subtree which contains all Even nodes
	tree2->root = tree2->deleteEvenSubTree(tree2->root);
	/*
	   10                            
	     \    
	      7            
	    ------------
	    After delete Even node subtrees
	*/
	cout << "\n After Delete Tree 2 \n";
	tree2->preorder(tree2->root);
	return 0;
}

Output

 Before Delete Tree 1
  1  2  6  3  7  8  10  12
 After Delete Tree 1
  1  2  3  7
 Before Delete Tree 2
  10  2  6  4  8  20  7  8
 After Delete Tree 2
  10  7
// Include namespace system
using System;
/*
  Csharp program for
  Remove all subtree of Even values node in binary tree
*/
// Binary Tree node
public class TreeNode
{
	public int data;
	public TreeNode left;
	public TreeNode right;
	public TreeNode(int data)
	{
		// Set node value
		this.data = data;
		this.left = null;
		this.right = null;
	}
}
public class BinaryTree
{
	public TreeNode root;
	public BinaryTree()
	{
		// Set initial value
		this.root = null;
	}
	// Display preorder view of binary tree
	public void preorder(TreeNode node)
	{
		if (node != null)
		{
			//Print node value
			Console.Write("  " + node.data);
			this.preorder(node.left);
			this.preorder(node.right);
		}
	}
	public TreeNode deleteEvenSubTree(TreeNode node)
	{
		if (node != null)
		{
			node.left = this.deleteEvenSubTree(node.left);
			node.right = this.deleteEvenSubTree(node.right);
			if (node.left == null && 
                node.right == null &&
                node.data % 2 == 0)
			{
				// delete Node
				return null;
			}
		}
		return node;
	}
	public static void Main(String[] args)
	{
		BinaryTree tree1 = new BinaryTree();
		BinaryTree tree2 = new BinaryTree();
		/*
		         1                            
		       /   \    
		      2     7    
		     / \     \               
		    6   3     8
		             /  \
		            10   12 
		    ------------
		    Binary tree A
		*/
		// Tree A
		tree1.root = new TreeNode(1);
		tree1.root.left = new TreeNode(2);
		tree1.root.right = new TreeNode(7);
		tree1.root.right.right = new TreeNode(8);
		tree1.root.left.right = new TreeNode(3);
		tree1.root.left.left = new TreeNode(6);
		tree1.root.right.right.left = new TreeNode(10);
		tree1.root.right.right.right = new TreeNode(12);
		/*
		    Construct Tree number 2
		    ---------
		         10                            
		       /   \    
		      2     7    
		     / \     \               
		    6   4     8
		       / \
		      8   20
		    ------------
		    Binary tree B
		*/
		// Tree B
		tree2.root = new TreeNode(10);
		tree2.root.left = new TreeNode(2);
		tree2.root.right = new TreeNode(7);
		tree2.root.right.right = new TreeNode(8);
		tree2.root.left.right = new TreeNode(4);
		tree2.root.left.left = new TreeNode(6);
		tree2.root.left.right.left = new TreeNode(8);
		tree2.root.left.right.right = new TreeNode(20);
		// Test A
		Console.Write("\n Before Delete Tree 1 \n");
		tree1.preorder(tree1.root);
		// Remove subtree which contains all Even nodes
		tree1.root = tree1.deleteEvenSubTree(tree1.root);
		/*
		     1                            
		   /   \    
		  2     7    
		   \                    
		    3            
		    ------------
		    After delete Even node subtrees
		*/
		Console.Write("\n After Delete Tree 1 \n");
		tree1.preorder(tree1.root);
		// Test B
		Console.Write("\n Before Delete Tree 2 \n");
		tree2.preorder(tree2.root);
		// Remove subtree which contains all Even nodes
		tree2.root = tree2.deleteEvenSubTree(tree2.root);
		/*
		   10                            
		     \    
		      7            
		    ------------
		    After delete Even node subtrees
		*/
		Console.Write("\n After Delete Tree 2 \n");
		tree2.preorder(tree2.root);
	}
}

Output

 Before Delete Tree 1
  1  2  6  3  7  8  10  12
 After Delete Tree 1
  1  2  3  7
 Before Delete Tree 2
  10  2  6  4  8  20  7  8
 After Delete Tree 2
  10  7
package main
import "fmt"
/*
  Go program for
  Remove all subtree of Even values node in binary tree
*/
// Binary Tree node
type TreeNode struct {
	data int
	left * TreeNode
	right * TreeNode
}
func getTreeNode(data int) * TreeNode {
	var me *TreeNode = &TreeNode {}
	// Set node value
	me.data = data
	me.left = nil
	me.right = nil
	return me
}
type BinaryTree struct {
	root * TreeNode
}
func getBinaryTree() * BinaryTree {
	var me *BinaryTree = &BinaryTree {}
	// Set initial value
	me.root = nil
	return me
}
// Display preorder view of binary tree
func(this BinaryTree) preorder(node * TreeNode) {
	if node != nil {
		//Print node value
		fmt.Print("  ", node.data)
		this.preorder(node.left)
		this.preorder(node.right)
	}
}
func(this BinaryTree) deleteEvenSubTree(node * TreeNode) * TreeNode {
	if node != nil {
		node.left = this.deleteEvenSubTree(node.left)
		node.right = this.deleteEvenSubTree(node.right)
		if node.left == nil && 
		node.right == nil && 
		node.data % 2 == 0 {
			// delete Node
			return nil
		}
	}
	return node
}
func main() {
	var tree1 * BinaryTree = getBinaryTree()
	var tree2 * BinaryTree = getBinaryTree()
	/*
	         1                            
	       /   \    
	      2     7    
	     / \     \               
	    6   3     8
	             /  \
	            10   12 
	    ------------
	    Binary tree A
	*/
	// Tree A
	tree1.root = getTreeNode(1)
	tree1.root.left = getTreeNode(2)
	tree1.root.right = getTreeNode(7)
	tree1.root.right.right = getTreeNode(8)
	tree1.root.left.right = getTreeNode(3)
	tree1.root.left.left = getTreeNode(6)
	tree1.root.right.right.left = getTreeNode(10)
	tree1.root.right.right.right = getTreeNode(12)
	/*
	    Construct Tree number 2
	    ---------
	         10                            
	       /   \    
	      2     7    
	     / \     \               
	    6   4     8
	       / \
	      8   20
	    ------------
	    Binary tree B
	*/
	// Tree B
	tree2.root = getTreeNode(10)
	tree2.root.left = getTreeNode(2)
	tree2.root.right = getTreeNode(7)
	tree2.root.right.right = getTreeNode(8)
	tree2.root.left.right = getTreeNode(4)
	tree2.root.left.left = getTreeNode(6)
	tree2.root.left.right.left = getTreeNode(8)
	tree2.root.left.right.right = getTreeNode(20)
	// Test A
	fmt.Print("\n Before Delete Tree 1 \n")
	tree1.preorder(tree1.root)
	// Remove subtree which contains all Even nodes
	tree1.root = tree1.deleteEvenSubTree(tree1.root)
	/*
	     1                            
	   /   \    
	  2     7    
	   \                    
	    3            
	    ------------
	    After delete Even node subtrees
	*/
	fmt.Print("\n After Delete Tree 1 \n")
	tree1.preorder(tree1.root)
	// Test B
	fmt.Print("\n Before Delete Tree 2 \n")
	tree2.preorder(tree2.root)
	// Remove subtree which contains all Even nodes
	tree2.root = tree2.deleteEvenSubTree(tree2.root)
	/*
	   10                            
	     \    
	      7            
	    ------------
	    After delete Even node subtrees
	*/
	fmt.Print("\n After Delete Tree 2 \n")
	tree2.preorder(tree2.root)
}

Output

 Before Delete Tree 1
  1  2  6  3  7  8  10  12
 After Delete Tree 1
  1  2  3  7
 Before Delete Tree 2
  10  2  6  4  8  20  7  8
 After Delete Tree 2
  10  7
<?php
/*
  Php program for
  Remove all subtree of Even values node in binary tree
*/
// Binary Tree node
class TreeNode
{
	public $data;
	public $left;
	public $right;
	public	function __construct($data)
	{
		// Set node value
		$this->data = $data;
		$this->left = NULL;
		$this->right = NULL;
	}
}
class BinaryTree
{
	public $root;
	public	function __construct()
	{
		$this->root = NULL;
	}
	// Display preorder view of binary tree
	public	function preorder($node)
	{
		if ($node != NULL)
		{
			//Print node value
			echo("  ".$node->data);
			$this->preorder($node->left);
			$this->preorder($node->right);
		}
	}
	public	function deleteEvenSubTree($node)
	{
		if ($node != NULL)
		{
			$node->left = $this->deleteEvenSubTree($node->left);
			$node->right = $this->deleteEvenSubTree($node->right);
			if ($node->left == NULL && 
                $node->right == NULL && 
                $node->data % 2 == 0)
			{
				// delete Node
				return NULL;
			}
		}
		return $node;
	}
}

function main()
{
	$tree1 = new BinaryTree();
	$tree2 = new BinaryTree();
	/*
	         1                            
	       /   \    
	      2     7    
	     / \     \               
	    6   3     8
	             /  \
	            10   12 
	    ------------
	    Binary tree A
	*/
	// Tree A
	$tree1->root = new TreeNode(1);
	$tree1->root->left = new TreeNode(2);
	$tree1->root->right = new TreeNode(7);
	$tree1->root->right->right = new TreeNode(8);
	$tree1->root->left->right = new TreeNode(3);
	$tree1->root->left->left = new TreeNode(6);
	$tree1->root->right->right->left = new TreeNode(10);
	$tree1->root->right->right->right = new TreeNode(12);
	/*
	    Construct Tree number 2
	    ---------
	         10                            
	       /   \    
	      2     7    
	     / \     \               
	    6   4     8
	       / \
	      8   20
	    ------------
	    Binary tree B
	*/
	// Tree B
	$tree2->root = new TreeNode(10);
	$tree2->root->left = new TreeNode(2);
	$tree2->root->right = new TreeNode(7);
	$tree2->root->right->right = new TreeNode(8);
	$tree2->root->left->right = new TreeNode(4);
	$tree2->root->left->left = new TreeNode(6);
	$tree2->root->left->right->left = new TreeNode(8);
	$tree2->root->left->right->right = new TreeNode(20);
	// Test A
	echo("\n Before Delete Tree 1 \n");
	$tree1->preorder($tree1->root);
	// Remove subtree which contains all Even nodes
	$tree1->root = $tree1->deleteEvenSubTree($tree1->root);
	/*
	     1                            
	   /   \    
	  2     7    
	   \                    
	    3            
	    ------------
	    After delete Even node subtrees
	*/
	echo("\n After Delete Tree 1 \n");
	$tree1->preorder($tree1->root);
	// Test B
	echo("\n Before Delete Tree 2 \n");
	$tree2->preorder($tree2->root);
	// Remove subtree which contains all Even nodes
	$tree2->root = $tree2->deleteEvenSubTree($tree2->root);
	/*
	   10                            
	     \    
	      7            
	    ------------
	    After delete Even node subtrees
	*/
	echo("\n After Delete Tree 2 \n");
	$tree2->preorder($tree2->root);
}
main();

Output

 Before Delete Tree 1
  1  2  6  3  7  8  10  12
 After Delete Tree 1
  1  2  3  7
 Before Delete Tree 2
  10  2  6  4  8  20  7  8
 After Delete Tree 2
  10  7
/*
  Node JS program for
  Remove all subtree of Even values node in binary tree
*/
// Binary Tree node
class TreeNode
{
	constructor(data)
	{
		// Set node value
		this.data = data;
		this.left = null;
		this.right = null;
	}
}
class BinaryTree
{
	constructor()
	{
		this.root = null;
	}
	// Display preorder view of binary tree
	preorder(node)
	{
		if (node != null)
		{
			//Print node value
			process.stdout.write("  " + node.data);
			this.preorder(node.left);
			this.preorder(node.right);
		}
	}
	deleteEvenSubTree(node)
	{
		if (node != null)
		{
			node.left = this.deleteEvenSubTree(node.left);
			node.right = this.deleteEvenSubTree(node.right);
			if (node.left == null && 
                node.right == null && 
                node.data % 2 == 0)
			{
				// delete Node
				return null;
			}
		}
		return node;
	}
}

function main()
{
	var tree1 = new BinaryTree();
	var tree2 = new BinaryTree();
	/*
	         1                            
	       /   \    
	      2     7    
	     / \     \               
	    6   3     8
	             /  \
	            10   12 
	    ------------
	    Binary tree A
	*/
	// Tree A
	tree1.root = new TreeNode(1);
	tree1.root.left = new TreeNode(2);
	tree1.root.right = new TreeNode(7);
	tree1.root.right.right = new TreeNode(8);
	tree1.root.left.right = new TreeNode(3);
	tree1.root.left.left = new TreeNode(6);
	tree1.root.right.right.left = new TreeNode(10);
	tree1.root.right.right.right = new TreeNode(12);
	/*
	    Construct Tree number 2
	    ---------
	         10                            
	       /   \    
	      2     7    
	     / \     \               
	    6   4     8
	       / \
	      8   20
	    ------------
	    Binary tree B
	*/
	// Tree B
	tree2.root = new TreeNode(10);
	tree2.root.left = new TreeNode(2);
	tree2.root.right = new TreeNode(7);
	tree2.root.right.right = new TreeNode(8);
	tree2.root.left.right = new TreeNode(4);
	tree2.root.left.left = new TreeNode(6);
	tree2.root.left.right.left = new TreeNode(8);
	tree2.root.left.right.right = new TreeNode(20);
	// Test A
	process.stdout.write("\n Before Delete Tree 1 \n");
	tree1.preorder(tree1.root);
	// Remove subtree which contains all Even nodes
	tree1.root = tree1.deleteEvenSubTree(tree1.root);
	/*
	     1                            
	   /   \    
	  2     7    
	   \                    
	    3            
	    ------------
	    After delete Even node subtrees
	*/
	process.stdout.write("\n After Delete Tree 1 \n");
	tree1.preorder(tree1.root);
	// Test B
	process.stdout.write("\n Before Delete Tree 2 \n");
	tree2.preorder(tree2.root);
	// Remove subtree which contains all Even nodes
	tree2.root = tree2.deleteEvenSubTree(tree2.root);
	/*
	   10                            
	     \    
	      7            
	    ------------
	    After delete Even node subtrees
	*/
	process.stdout.write("\n After Delete Tree 2 \n");
	tree2.preorder(tree2.root);
}
main();

Output

 Before Delete Tree 1
  1  2  6  3  7  8  10  12
 After Delete Tree 1
  1  2  3  7
 Before Delete Tree 2
  10  2  6  4  8  20  7  8
 After Delete Tree 2
  10  7
#  Python 3 program for
#  Remove all subtree of Even values node in binary tree

#  Binary Tree node
class TreeNode :
	def __init__(self, data) :
		#  Set node value
		self.data = data
		self.left = None
		self.right = None
	

class BinaryTree :
	def __init__(self) :
		self.root = None
	
	#  Display preorder view of binary tree
	def preorder(self, node) :
		if (node != None) :
			# Print node value
			print("  ", node.data, end = "")
			self.preorder(node.left)
			self.preorder(node.right)
		
	
	def deleteEvenSubTree(self, node) :
		if (node != None) :
			node.left = self.deleteEvenSubTree(node.left)
			node.right = self.deleteEvenSubTree(node.right)
			if (node.left == None and 
                node.right == None and 
                node.data % 2 == 0) :
				#  delete Node
				return None
			
		
		return node
	

def main() :
	tree1 = BinaryTree()
	tree2 = BinaryTree()
	#         1                            
	#       /   \    
	#      2     7    
	#     / \     \               
	#    6   3     8
	#             /  \
	#            10   12 
	#    ------------
	#    Binary tree A
	#  Tree A
	tree1.root = TreeNode(1)
	tree1.root.left = TreeNode(2)
	tree1.root.right = TreeNode(7)
	tree1.root.right.right = TreeNode(8)
	tree1.root.left.right = TreeNode(3)
	tree1.root.left.left = TreeNode(6)
	tree1.root.right.right.left = TreeNode(10)
	tree1.root.right.right.right = TreeNode(12)
	#    Construct Tree number 2
	#    ---------
	#         10                            
	#       /   \    
	#      2     7    
	#     / \     \               
	#    6   4     8
	#       / \
	#      8   20
	#    ------------
	#    Binary tree B
	#  Tree B
	tree2.root = TreeNode(10)
	tree2.root.left = TreeNode(2)
	tree2.root.right = TreeNode(7)
	tree2.root.right.right = TreeNode(8)
	tree2.root.left.right = TreeNode(4)
	tree2.root.left.left = TreeNode(6)
	tree2.root.left.right.left = TreeNode(8)
	tree2.root.left.right.right = TreeNode(20)
	#  Test A
	print("\n Before Delete Tree 1 ")
	tree1.preorder(tree1.root)
	#  Remove subtree which contains all Even nodes
	tree1.root = tree1.deleteEvenSubTree(tree1.root)
	#     1                            
	#   /   \    
	#  2     7    
	#   \                    
	#    3            
	#    ------------
	#    After delete Even node subtrees
	print("\n After Delete Tree 1 ")
	tree1.preorder(tree1.root)
	#  Test B
	print("\n Before Delete Tree 2 ")
	tree2.preorder(tree2.root)
	#  Remove subtree which contains all Even nodes
	tree2.root = tree2.deleteEvenSubTree(tree2.root)
	#   10                            
	#     \    
	#      7            
	#    ------------
	#    After delete Even node subtrees
	print("\n After Delete Tree 2 ")
	tree2.preorder(tree2.root)

if __name__ == "__main__": main()

Output

 Before Delete Tree 1
   1   2   6   3   7   8   10   12
 After Delete Tree 1
   1   2   3   7
 Before Delete Tree 2
   10   2   6   4   8   20   7   8
 After Delete Tree 2
   10   7
#  Ruby program for
#  Remove all subtree of Even values node in binary tree

#  Binary Tree node
class TreeNode 
	# Define the accessor and reader of class TreeNode
	attr_reader :data, :left, :right
	attr_accessor :data, :left, :right
	def initialize(data) 
		#  Set node value
		self.data = data
		self.left = nil
		self.right = nil
	end

end

class BinaryTree 
	# Define the accessor and reader of class BinaryTree
	attr_reader :root
	attr_accessor :root
	def initialize() 
		self.root = nil
	end

	#  Display preorder view of binary tree
	def preorder(node) 
		if (node != nil) 
			# Print node value
			print("  ", node.data)
			self.preorder(node.left)
			self.preorder(node.right)
		end

	end

	def deleteEvenSubTree(node) 
		if (node != nil) 
			node.left = self.deleteEvenSubTree(node.left)
			node.right = self.deleteEvenSubTree(node.right)
			if (node.left == nil && 
                node.right == nil && 
                node.data % 2 == 0) 
				#  delete Node
				return nil
			end

		end

		return node
	end

end

def main() 
	tree1 = BinaryTree.new()
	tree2 = BinaryTree.new()
	#         1                            
	#       /   \    
	#      2     7    
	#     / \     \               
	#    6   3     8
	#             /  \
	#            10   12 
	#    ------------
	#    Binary tree A
	#  Tree A
	tree1.root = TreeNode.new(1)
	tree1.root.left = TreeNode.new(2)
	tree1.root.right = TreeNode.new(7)
	tree1.root.right.right = TreeNode.new(8)
	tree1.root.left.right = TreeNode.new(3)
	tree1.root.left.left = TreeNode.new(6)
	tree1.root.right.right.left = TreeNode.new(10)
	tree1.root.right.right.right = TreeNode.new(12)
	#    Construct Tree number 2
	#    ---------
	#         10                            
	#       /   \    
	#      2     7    
	#     / \     \               
	#    6   4     8
	#       / \
	#      8   20
	#    ------------
	#    Binary tree B
	#  Tree B
	tree2.root = TreeNode.new(10)
	tree2.root.left = TreeNode.new(2)
	tree2.root.right = TreeNode.new(7)
	tree2.root.right.right = TreeNode.new(8)
	tree2.root.left.right = TreeNode.new(4)
	tree2.root.left.left = TreeNode.new(6)
	tree2.root.left.right.left = TreeNode.new(8)
	tree2.root.left.right.right = TreeNode.new(20)
	#  Test A
	print("\n Before Delete Tree 1 \n")
	tree1.preorder(tree1.root)
	#  Remove subtree which contains all Even nodes
	tree1.root = tree1.deleteEvenSubTree(tree1.root)
	#     1                            
	#   /   \    
	#  2     7    
	#   \                    
	#    3            
	#    ------------
	#    After delete Even node subtrees
	print("\n After Delete Tree 1 \n")
	tree1.preorder(tree1.root)
	#  Test B
	print("\n Before Delete Tree 2 \n")
	tree2.preorder(tree2.root)
	#  Remove subtree which contains all Even nodes
	tree2.root = tree2.deleteEvenSubTree(tree2.root)
	#   10                            
	#     \    
	#      7            
	#    ------------
	#    After delete Even node subtrees
	print("\n After Delete Tree 2 \n")
	tree2.preorder(tree2.root)
end

main()

Output

 Before Delete Tree 1 
  1  2  6  3  7  8  10  12
 After Delete Tree 1 
  1  2  3  7
 Before Delete Tree 2 
  10  2  6  4  8  20  7  8
 After Delete Tree 2 
  10  7
/*
  Scala program for
  Remove all subtree of Even values node in binary tree
*/
// Binary Tree node
class TreeNode(var data: Int,
	var left: TreeNode,
		var right: TreeNode)
{
	def this(data: Int)
	{
		// Set node value
		this(data,null,null);
	}
}
class BinaryTree(var root: TreeNode)
{
	def this()
	{
		this(null);
	}
	// Display preorder view of binary tree
	def preorder(node: TreeNode): Unit = {
		if (node != null)
		{
			//Print node value
			print("  " + node.data);
			preorder(node.left);
			preorder(node.right);
		}
	}
	def deleteEvenSubTree(node: TreeNode): TreeNode = {
		if (node != null)
		{
			node.left = deleteEvenSubTree(node.left);
			node.right = deleteEvenSubTree(node.right);
			if (node.left == null && 
                node.right == null && 
                node.data % 2 == 0)
			{
				// delete Node
				return null;
			}
		}
		return node;
	}
}
object Main
{
	def main(args: Array[String]): Unit = {
		var tree1: BinaryTree = new BinaryTree();
		var tree2: BinaryTree = new BinaryTree();
		/*
		         1                            
		       /   \    
		      2     7    
		     / \     \               
		    6   3     8
		             /  \
		            10   12 
		    ------------
		    Binary tree A
		*/
		// Tree A
		tree1.root = new TreeNode(1);
		tree1.root.left = new TreeNode(2);
		tree1.root.right = new TreeNode(7);
		tree1.root.right.right = new TreeNode(8);
		tree1.root.left.right = new TreeNode(3);
		tree1.root.left.left = new TreeNode(6);
		tree1.root.right.right.left = new TreeNode(10);
		tree1.root.right.right.right = new TreeNode(12);
		/*
		    Construct Tree number 2
		    ---------
		         10                            
		       /   \    
		      2     7    
		     / \     \               
		    6   4     8
		       / \
		      8   20
		    ------------
		    Binary tree B
		*/
		// Tree B
		tree2.root = new TreeNode(10);
		tree2.root.left = new TreeNode(2);
		tree2.root.right = new TreeNode(7);
		tree2.root.right.right = new TreeNode(8);
		tree2.root.left.right = new TreeNode(4);
		tree2.root.left.left = new TreeNode(6);
		tree2.root.left.right.left = new TreeNode(8);
		tree2.root.left.right.right = new TreeNode(20);
		// Test A
		print("\n Before Delete Tree 1 \n");
		tree1.preorder(tree1.root);
		// Remove subtree which contains all Even nodes
		tree1.root = tree1.deleteEvenSubTree(tree1.root);
		/*
		     1                            
		   /   \    
		  2     7    
		   \                    
		    3            
		    ------------
		    After delete Even node subtrees
		*/
		print("\n After Delete Tree 1 \n");
		tree1.preorder(tree1.root);
		// Test B
		print("\n Before Delete Tree 2 \n");
		tree2.preorder(tree2.root);
		// Remove subtree which contains all Even nodes
		tree2.root = tree2.deleteEvenSubTree(tree2.root);
		/*
		   10                            
		     \    
		      7            
		    ------------
		    After delete Even node subtrees
		*/
		print("\n After Delete Tree 2 \n");
		tree2.preorder(tree2.root);
	}
}

Output

 Before Delete Tree 1
  1  2  6  3  7  8  10  12
 After Delete Tree 1
  1  2  3  7
 Before Delete Tree 2
  10  2  6  4  8  20  7  8
 After Delete Tree 2
  10  7
/*
  Swift 4 program for
  Remove all subtree of Even values node in binary tree
*/
// Binary Tree node
class TreeNode
{
	var data: Int;
	var left: TreeNode? ;
	var right: TreeNode? ;
	init(_ data: Int)
	{
		// Set node value
		self.data = data;
		self.left = nil;
		self.right = nil;
	}
}
class BinaryTree
{
	var root: TreeNode? ;
	init()
	{
		self.root = nil;
	}
	// Display preorder view of binary tree
	func preorder(_ node: TreeNode? )
	{
		if (node  != nil)
		{
			//Print node value
			print("  ", node!.data, terminator: "");
			self.preorder(node!.left);
			self.preorder(node!.right);
		}
	}
	func deleteEvenSubTree(_ node: TreeNode? ) -> TreeNode?
	{
		if (node  != nil)
		{
			node!.left = self.deleteEvenSubTree(node!.left);
			node!.right = self.deleteEvenSubTree(node!.right);
			if (node!.left == nil && 
                node!.right == nil && 
                node!.data % 2 == 0)
			{
				// delete Node
				return nil;
			}
		}
		return node;
	}
}
func main()
{
	let tree1: BinaryTree = BinaryTree();
	let tree2: BinaryTree = BinaryTree();
	/*
	         1                            
	       /   \    
	      2     7    
	     / \     \               
	    6   3     8
	             /  \
	            10   12 
	    ------------
	    Binary tree A
	*/
	// Tree A
	tree1.root = TreeNode(1);
	tree1.root!.left = TreeNode(2);
	tree1.root!.right = TreeNode(7);
	tree1.root!.right!.right = TreeNode(8);
	tree1.root!.left!.right = TreeNode(3);
	tree1.root!.left!.left = TreeNode(6);
	tree1.root!.right!.right!.left = TreeNode(10);
	tree1.root!.right!.right!.right = TreeNode(12);
	/*
	    Construct Tree number 2
	    ---------
	         10                            
	       /   \    
	      2     7    
	     / \     \               
	    6   4     8
	       / \
	      8   20
	    ------------
	    Binary tree B
	*/
	// Tree B
	tree2.root = TreeNode(10);
	tree2.root!.left = TreeNode(2);
	tree2.root!.right = TreeNode(7);
	tree2.root!.right!.right = TreeNode(8);
	tree2.root!.left!.right = TreeNode(4);
	tree2.root!.left!.left = TreeNode(6);
	tree2.root!.left!.right!.left = TreeNode(8);
	tree2.root!.left!.right!.right = TreeNode(20);
	// Test A
	print("\n Before Delete Tree 1 ");
	tree1.preorder(tree1.root);
	// Remove subtree which contains all Even nodes
	tree1.root = tree1.deleteEvenSubTree(tree1.root);
	/*
	     1                            
	   /   \    
	  2     7    
	   \                    
	    3            
	    ------------
	    After delete Even node subtrees
	*/
	print("\n After Delete Tree 1 ");
	tree1.preorder(tree1.root);
	// Test B
	print("\n Before Delete Tree 2 ");
	tree2.preorder(tree2.root);
	// Remove subtree which contains all Even nodes
	tree2.root = tree2.deleteEvenSubTree(tree2.root);
	/*
	   10                            
	     \    
	      7            
	    ------------
	    After delete Even node subtrees
	*/
	print("\n After Delete Tree 2 ");
	tree2.preorder(tree2.root);
}
main();

Output

 Before Delete Tree 1
   1   2   6   3   7   8   10   12
 After Delete Tree 1
   1   2   3   7
 Before Delete Tree 2
   10   2   6   4   8   20   7   8
 After Delete Tree 2
   10   7
/*
  Kotlin program for
  Remove all subtree of Even values node in binary tree
*/
// Binary Tree node
class TreeNode
{
	var data: Int;
	var left: TreeNode ? ;
	var right: TreeNode ? ;
	constructor(data: Int)
	{
		// Set node value
		this.data = data;
		this.left = null;
		this.right = null;
	}
}
class BinaryTree
{
	var root: TreeNode ? ;
	constructor()
	{
		this.root = null;
	}
	// Display preorder view of binary tree
	fun preorder(node: TreeNode ? ): Unit
	{
		if (node != null)
		{
			//Print node value
			print("  " + node.data);
			this.preorder(node.left);
			this.preorder(node.right);
		}
	}
	fun deleteEvenSubTree(node: TreeNode ? ): TreeNode ?
	{
		if (node != null)
		{
			node.left = this.deleteEvenSubTree(node.left);
			node.right = this.deleteEvenSubTree(node.right);
			if (node.left == null && 
                node.right == null && 
                node.data % 2 == 0)
			{
				// delete Node
				return null;
			}
		}
		return node;
	}
}
fun main(args: Array < String > ): Unit
{
	val tree1: BinaryTree = BinaryTree();
	val tree2: BinaryTree = BinaryTree();
	/*
	         1                            
	       /   \    
	      2     7    
	     / \     \               
	    6   3     8
	             /  \
	            10   12 
	    ------------
	    Binary tree A
	*/
	// Tree A
	tree1.root = TreeNode(1);
	tree1.root?.left = TreeNode(2);
	tree1.root?.right = TreeNode(7);
	tree1.root?.right?.right = TreeNode(8);
	tree1.root?.left?.right = TreeNode(3);
	tree1.root?.left?.left = TreeNode(6);
	tree1.root?.right?.right?.left = TreeNode(10);
	tree1.root?.right?.right?.right = TreeNode(12);
	/*
	    Construct Tree number 2
	    ---------
	         10                            
	       /   \    
	      2     7    
	     / \     \               
	    6   4     8
	       / \
	      8   20
	    ------------
	    Binary tree B
	*/
	// Tree B
	tree2.root = TreeNode(10);
	tree2.root?.left = TreeNode(2);
	tree2.root?.right = TreeNode(7);
	tree2.root?.right?.right = TreeNode(8);
	tree2.root?.left?.right = TreeNode(4);
	tree2.root?.left?.left = TreeNode(6);
	tree2.root?.left?.right?.left = TreeNode(8);
	tree2.root?.left?.right?.right = TreeNode(20);
	// Test A
	print("\n Before Delete Tree 1 \n");
	tree1.preorder(tree1.root);
	// Remove subtree which contains all Even nodes
	tree1.root = tree1.deleteEvenSubTree(tree1.root);
	/*
	     1                            
	   /   \    
	  2     7    
	   \                    
	    3            
	    ------------
	    After delete Even node subtrees
	*/
	print("\n After Delete Tree 1 \n");
	tree1.preorder(tree1.root);
	// Test B
	print("\n Before Delete Tree 2 \n");
	tree2.preorder(tree2.root);
	// Remove subtree which contains all Even nodes
	tree2.root = tree2.deleteEvenSubTree(tree2.root);
	/*
	   10                            
	     \    
	      7            
	    ------------
	    After delete Even node subtrees
	*/
	print("\n After Delete Tree 2 \n");
	tree2.preorder(tree2.root);
}

Output

 Before Delete Tree 1
  1  2  6  3  7  8  10  12
 After Delete Tree 1
  1  2  3  7
 Before Delete Tree 2
  10  2  6  4  8  20  7  8
 After Delete Tree 2
  10  7


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