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Remove specific word from string

Here given code implementation process.

// Java program
// Remove specific word from string
class MyString
{
	// This method are removing given word from given string
	// Assuming that given word is single word and it can not containing 
	// [ - or space]
	// String Words are separated by space and - symbol
	public String remove_word(String str_data, String word)
	{
		String auxiliary = "";
		String result = "";
		//Loop contolling variables
		int i = 0, j = 0;
		System.out.print("\n Given String \n [" + str_data + "]\n");
		//Loop which is iterate given string character elements
		for (i = 0; i < str_data.length(); i++)
		{
			if (str_data.charAt(i) != ' ' && str_data.charAt(i) != '-')
			{
				//reset variable
				auxiliary = "";
				//loop, combine string text
				for (j = i; j < str_data.length(); j++)
				{
					//Check that given character is space character or not
					if (str_data.charAt(j) != ' ' && str_data.charAt(j) != '-')
					{
						//When not get space
						auxiliary = auxiliary + str_data.charAt(j);
					}
					else
					{
						//When find space or - break this loop 
						break;
					}
				}
				//Check that given word is equal to find word or not
				if (!auxiliary.equals(word))
				{
					//When not equal
					result = result + auxiliary;
					if (j < str_data.length())
					{
						result = result + str_data.charAt(j);
					}
				}
				i = j;
			}
			else
			{
				//When get space
				result = result + str_data.charAt(i);
			}
		}
		return result;
	}
	public static void main(String[] args)
	{
		MyString obj = new MyString();
		// Simple case
		String text = "bug-error This is very diagnosis error please resolve this error";
		String word = "error";
		text = obj.remove_word(text, word);
		System.out.print(" After Remove Word [" + word + "] \n [" + text + "]\n");
		text = "an animal, an antidote, a     n anything";
		word = "an";
		text = obj.remove_word(text, word);
		System.out.print(" After Remove Word [" + word + "] \n [" + text + "]\n");
	}
}

Output

 Given String
 [bug-error This is very diagnosis error please resolve this error]
 After Remove Word [error]
 [bug-This is very diagnosis please resolve this ]

 Given String
 [an animal, an antidote, a     n anything]
 After Remove Word [an]
 [animal, antidote, a     n anything]
//Include header file
#include <iostream>
#include<string.h>
using namespace std;

// C++ program
// Remove specific word from string
class MyString
{
	public:
		// This method are removing given word from given string
		// Assuming that given word is single word and it can not containing 
		// [ - or space]
		// String Words are separated by space and - symbol
		string remove_word(string str_data, string word)
		{
			string auxiliary = "";
			string result = "";
			//Loop contolling variables
			int i = 0, j = 0;
			cout << "\n Given String \n [" << str_data << "]\n";
			//Loop which is iterate given string character elements
			for (i = 0; i < str_data.size(); i++)
			{
				if (str_data[i] != ' ' && str_data[i] != '-')
				{
					//reset variable
					auxiliary = "";
					//loop, combine string text
					for (j = i; j < str_data.size(); j++)
					{
						//Check that given character is space character or not
						if (str_data[j] != ' ' && str_data[j] != '-')
						{
							//When not get space
							auxiliary = auxiliary + str_data[j];
						}
						else
						{
							//When find space or - break this loop 
							break;
						}
					}
					//Check that given word is equal to find word or not
					if (auxiliary.compare(word)!=0)
					{
						//When not equal
						result = result + auxiliary;
						if (j < str_data.size())
						{
							result = result + str_data[j];
						}
					}
					i = j;
				}
				else
				{
					//When get space
					result = result + str_data[i];
				}
			}
			return result;
		}
};
int main()
{
	MyString obj = MyString();
	// Simple case
	string text = "bug-error This is very diagnosis error please resolve this error";
	string word = "error";
	text = obj.remove_word(text, word);
	cout << " After Remove Word [" << word << "] \n [" << text << "]\n";
	text = "an animal, an antidote, a     n anything";
	word = "an";
	text = obj.remove_word(text, word);
	cout << " After Remove Word [" << word << "] \n [" << text << "]\n";
	return 0;
}

Output

 Given String
 [bug-error This is very diagnosis error please resolve this error]
 After Remove Word [error]
 [bug-This is very diagnosis please resolve this ]

 Given String
 [an animal, an antidote, a     n anything]
 After Remove Word [an]
 [animal, antidote, a     n anything]
//Include namespace system
using System;
// C# program
// Remove specific word from string
class MyString
{
	// This method are removing given word from given string
	// Assuming that given word is single word and it can not containing 
	// [ - or space]
	// String Words are separated by space and - symbol
	public String remove_word(String str_data, String word)
	{
		String auxiliary = "";
		String result = "";
		//Loop contolling variables
		int i = 0, j = 0;
		Console.Write("\n Given String \n [" + str_data + "]\n");
		//Loop which is iterate given string character elements
		for (i = 0; i < str_data.Length; i++)
		{
			if (str_data[i] != ' ' && str_data[i] != '-')
			{
				//reset variable
				auxiliary = "";
				//loop, combine string text
				for (j = i; j < str_data.Length; j++)
				{
					//Check that given character is space character or not
					if (str_data[j] != ' ' && str_data[j] != '-')
					{
						//When not get space
						auxiliary = auxiliary + str_data[j];
					}
					else
					{
						//When find space or - break this loop 
						break;
					}
				}
				//Check that given word is equal to find word or not
				if (!auxiliary.Equals(word))
				{
					//When not equal
					result = result + auxiliary;
					if (j < str_data.Length)
					{
						result = result + str_data[j];
					}
				}
				i = j;
			}
			else
			{
				//When get space
				result = result + str_data[i];
			}
		}
		return result;
	}
	public static void Main(String[] args)
	{
		MyString obj = new MyString();
		// Simple case
		String text = "bug-error This is very diagnosis error please resolve this error";
		String word = "error";
		text = obj.remove_word(text, word);
		Console.Write(" After Remove Word [" + word + "] \n [" + text + "]\n");
		text = "an animal, an antidote, a     n anything";
		word = "an";
		text = obj.remove_word(text, word);
		Console.Write(" After Remove Word [" + word + "] \n [" + text + "]\n");
	}
}

Output

 Given String
 [bug-error This is very diagnosis error please resolve this error]
 After Remove Word [error]
 [bug-This is very diagnosis please resolve this ]

 Given String
 [an animal, an antidote, a     n anything]
 After Remove Word [an]
 [animal, antidote, a     n anything]
<?php
// Php program
// Remove specific word from string
class MyString
{
	// This method are removing given word from given string
	// Assuming that given word is single word and it can not containing 
	// [ - or space]
	// String Words are separated by space and - symbol
	public	function remove_word($str_data, $word)
	{
		$auxiliary = "";
		$result = "";
		//Loop contolling variables
		$i = 0;
		$j = 0;
		echo "\n Given String \n [". $str_data ."]\n";
		//Loop which is iterate given string character elements
		for ($i = 0; $i < strlen($str_data); $i++)
		{
			if ($str_data[$i] != ' ' && $str_data[$i] != '-')
			{
				//reset variable
				$auxiliary = "";
				//loop, combine string text
				for ($j = $i; $j < strlen($str_data); $j++)
				{
					//Check that given character is space character or not
					if ($str_data[$j] != ' ' && $str_data[$j] != '-')
					{
						//When not get space
						$auxiliary = $auxiliary . $str_data[$j];
					}
					else
					{
						//When find space or - break this loop 
						break;
					}
				}
				//Check that given word is equal to find word or not
				if ($word!=$auxiliary)
				{
					//When not equal
					$result = $result . $auxiliary;
					if ($j < strlen($str_data))
					{
						$result = $result . $str_data[$j];
					}
				}
				$i = $j;
			}
			else
			{
				//When get space
				$result = $result . $str_data[$i];
			}
		}
		return $result;
	}
}

function main()
{
	$obj = new MyString();
	// Simple case
	$text = "bug-error This is very diagnosis error please resolve this error";
	$word = "error";
	$text = $obj->remove_word($text, $word);
	echo " After Remove Word [". $word ."] \n [". $text ."]\n";
	$text = "an animal, an antidote, a     n anything";
	$word = "an";
	$text = $obj->remove_word($text, $word);
	echo " After Remove Word [". $word ."] \n [". $text ."]\n";
}
main();

Output

 Given String
 [bug-error This is very diagnosis error please resolve this error]
 After Remove Word [error]
 [bug-This is very diagnosis please resolve this ]

 Given String
 [an animal, an antidote, a     n anything]
 After Remove Word [an]
 [animal, antidote, a     n anything]
// Node Js program
// Remove specific word from string
class MyString
{
	// This method are removing given word from given string
	// Assuming that given word is single word and it can not containing 
	// [ - or space]
	// String Words are separated by space and - symbol
	remove_word(str_data, word)
	{
		var auxiliary = "";
		var result = "";
		//Loop contolling variables
		var i = 0;
		var j = 0;
		process.stdout.write("\n Given String \n [" + str_data + "]\n");
		//Loop which is iterate given string character elements
		for (i = 0; i < str_data.length; i++)
		{
			if (str_data[i] != ' ' && str_data[i] != '-')
			{
				//reset variable
				auxiliary = "";
				//loop, combine string text
				for (j = i; j < str_data.length; j++)
				{
					//Check that given character is space character or not
					if (str_data[j] != ' ' && str_data[j] != '-')
					{
						//When not get space
						auxiliary = auxiliary + str_data[j];
					}
					else
					{
						//When find space or - break this loop 
						break;
					}
				}
				//Check that given word is equal to find word or not
				if (auxiliary!=word)
				{
					//When not equal
					result = result + auxiliary;
					if (j < str_data.length)
					{
						result = result + str_data[j];
					}
				}
				i = j;
			}
			else
			{
				//When get space
				result = result + str_data[i];
			}
		}
		return result;
	}
}

function main()
{
	var obj = new MyString();
	// Simple case
	var text = "bug-error This is very diagnosis error please resolve this error";
	var word = "error";
	text = obj.remove_word(text, word);
	process.stdout.write(" After Remove Word [" + word + "] \n [" + text + "]\n");
	text = "an animal, an antidote, a     n anything";
	word = "an";
	text = obj.remove_word(text, word);
	process.stdout.write(" After Remove Word [" + word + "] \n [" + text + "]\n");
}
main();

Output

 Given String
 [bug-error This is very diagnosis error please resolve this error]
 After Remove Word [error]
 [bug-This is very diagnosis please resolve this ]

 Given String
 [an animal, an antidote, a     n anything]
 After Remove Word [an]
 [animal, antidote, a     n anything]
#  Python 3 program
#  Remove specific word from string
class MyString :
	#  This method are removing given word from given string
	#  Assuming that given word is single word and it can not containing 
	#  [ - or space]
	#  String Words are separated by space and - symbol
	def remove_word(self, str_data, word) :
		auxiliary = ""
		result = ""
		# Loop contolling variables
		i = 0
		j = 0
		print("\n Given String \n [", str_data ,"]\n", end = "")
		# Loop which is iterate given string character elements
		i = 0
		while (i < len(str_data)) :
			if (str_data[i] != ' '
				and str_data[i] != '-') :
				# reset variable
				auxiliary = ""
				# loop, combine string text
				j = i
				while (j < len(str_data)) :
					# Check that given character is space character or not
					if (str_data[j] != ' '
						and str_data[j] != '-') :
						# When not get space
						auxiliary = auxiliary + str_data[j]
					else :
						# When find space or - break this loop 
						break
					
					j += 1
				
				# Check that given word is equal to find word or not
				if (auxiliary != word) :
					# When not equal
					result = result + auxiliary
					if (j < len(str_data)) :
						result = result + str_data[j]
					
				
				i = j
			else :
				# When get space
				result = result + str_data[i]
			
			i += 1
		
		return result
	

def main() :
	obj = MyString()
	#  Simple case
	text = "bug-error This is very diagnosis error please resolve this error"
	word = "error"
	text = obj.remove_word(text, word)
	print(" After Remove Word [", word ,"] \n [", text ,"]\n", end = "")
	text = "an animal, an antidote, a     n anything"
	word = "an"
	text = obj.remove_word(text, word)
	print(" After Remove Word [", word ,"] \n [", text ,"]\n", end = "")

if __name__ == "__main__": main()

Output

 Given String
 [ bug-error This is very diagnosis error please resolve this error ]
 After Remove Word [ error ]
 [ bug-This is very diagnosis please resolve this  ]

 Given String
 [ an animal, an antidote, a     n anything ]
 After Remove Word [ an ]
 [ animal, antidote, a     n anything ]
#  Ruby program
#  Remove specific word from string
class MyString

	#  This method are removing given word from given string
	#  Assuming that given word is single word and it can not containing 
	#  [ - or space]
	#  String Words are separated by space and - symbol
	def remove_word(str_data, word)
	
		auxiliary = ""
		result = ""
		# Loop contolling variables
		i = 0
		j = 0
		print("\n Given String \n [", str_data ,"]\n")
		# Loop which is iterate given string character elements
		i = 0
		while (i < str_data.length())
		
			if (str_data[i] != ' ' && str_data[i] != '-')
			
				# reset variable
				auxiliary = ""
				# loop, combine string text
				j = i
				while (j < str_data.length())
				
					# Check that given character is space character or not
					if (str_data[j] != ' ' && str_data[j] != '-')
					
						# When not get space
						auxiliary = auxiliary + str_data[j]
					else
					
						# When find space or - break this loop 
						break
					end
					j += 1
				end
				# Check that given word is equal to find word or not
				if (auxiliary != word)
				
					# When not equal
					result = result + auxiliary
					if (j < str_data.length())
					
						result = result + str_data[j]
					end
				end
				i = j
			else
			
				# When get space
				result = result + str_data[i]
			end
			i += 1
		end
		return result
	end
end
def main()

	obj = MyString.new()
	#  Simple case
	text = "bug-error This is very diagnosis error please resolve this error"
	word = "error"
	text = obj.remove_word(text, word)
	print(" After Remove Word [", word ,"] \n [", text ,"]\n")
	text = "an animal, an antidote, a     n anything"
	word = "an"
	text = obj.remove_word(text, word)
	print(" After Remove Word [", word ,"] \n [", text ,"]\n")
end
main()

Output

 Given String 
 [bug-error This is very diagnosis error please resolve this error]
 After Remove Word [error] 
 [bug-This is very diagnosis please resolve this ]

 Given String 
 [an animal, an antidote, a     n anything]
 After Remove Word [an] 
 [animal, antidote, a     n anything]

// Scala program
// Remove specific word from string
import scala.util.control.Breaks._
class MyString
{
	// This method are removing given word from given string
	// Assuming that given word is single word and it can not containing 
	// [ - or space]
	// String Words are separated by space and - symbol
	def remove_word(str_data: String, word: String): String = {
		var auxiliary: String = "";
		var result: String = "";
		//Loop contolling variables
		var i: Int = 0;
		var j: Int = 0;
		print("\n Given String \n [" + str_data + "]\n");
		//Loop which is iterate given string character elements
		i = 0;
		while (i < str_data.length())
		{
			if (str_data(i) != ' ' && str_data(i) != '-')
			{
				//reset variable
				auxiliary = "";
				//loop, combine string text
				j = i;
             	breakable {
				while (j < str_data.length())
				{
					//Check that given character is space character or not
					if (str_data(j) != ' ' && str_data(j) != '-')
					{
						//When not get space
						auxiliary = auxiliary + str_data(j);
					}
					else
					{
						//When find space or - break this loop 
						break;
					}
					j += 1;
				}
                }
				//Check that given word is equal to find word or not
				if (!auxiliary.equals(word))
				{
					//When not equal
					result = result + auxiliary;
					if (j < str_data.length())
					{
						result = result + str_data(j);
					}
				}
				i = j;
			}
			else
			{
				//When get space
				result = result + str_data(i);
			}
			i += 1;
		}
		return result;
	}
}
object Main
{
	def main(args: Array[String]): Unit = {
		var obj: MyString = new MyString();
		// Simple case
		var text: String = "bug-error This is very diagnosis error please resolve this error";
		var word: String = "error";
		text = obj.remove_word(text, word);
		print(" After Remove Word [" + word + "] \n [" + text + "]\n");
		text = "an animal, an antidote, a     n anything";
		word = "an";
		text = obj.remove_word(text, word);
		print(" After Remove Word [" + word + "] \n [" + text + "]\n");
	}
}

Output

 Given String
 [bug-error This is very diagnosis error please resolve this error]
 After Remove Word [error]
 [bug-This is very diagnosis please resolve this ]

 Given String
 [an animal, an antidote, a     n anything]
 After Remove Word [an]
 [animal, antidote, a     n anything]
// Swift program
// Remove specific word from string
class MyString
{
	// This method are removing given word from given string
	// Assuming that given word is single word and it can not containing 
	// [ - or space]
	// String Words are separated by space and - symbol
	func remove_word(_ text: String, _ word: String) -> String
	{
		var auxiliary: String = "";
		var result: String = "";
      	let str_data = Array(text);
		//Loop contolling variables
		var i: Int = 0;
		var j: Int = 0;
		print("\n Given String \n [", text ,"]\n", terminator: "");
		//Loop which is iterate given string character elements
		i = 0;
		while (i < str_data.count)
		{
			if (str_data[i] != " " && str_data[i] != "-")
			{
				//reset variable
				auxiliary = "";
				//loop, combine string text
				j = i;
				while (j < str_data.count)
				{
					//Check that given character is space character or not
					if (str_data[j] != " " && str_data[j] != "-")
					{
						//When not get space
						auxiliary = auxiliary + String(str_data[j]);
					}
					else
					{
						//When find space or - break this loop 
						break;
					}
					j += 1;
				}
				//Check that given word is equal to find word or not
				if (!( auxiliary==word))
				{
					//When not equal
					result = result + auxiliary;
					if (j < str_data.count)
					{
						result = result + String(str_data[j]);
					}
				}
				i = j;
			}
			else
			{
				//When get space
				result = result + String(str_data[i]);
			}
			i += 1;
		}
		return result;
	}
}
func main()
{
	let obj: MyString = MyString();
	// Simple case
	var text: String = "bug-error This is very diagnosis error please resolve this error";
	var word: String = "error";
	text = obj.remove_word(text, word);
	print(" After Remove Word [", word ,"] \n [", text ,"]\n", terminator: "");
	text = "an animal, an antidote, a     n anything";
	word = "an";
	text = obj.remove_word(text, word);
	print(" After Remove Word [", word ,"] \n [", text ,"]\n", terminator: "");
}
main();

Output

 Given String
 [ bug-error This is very diagnosis error please resolve this error ]
 After Remove Word [ error ]
 [ bug-This is very diagnosis please resolve this  ]

 Given String
 [ an animal, an antidote, a     n anything ]
 After Remove Word [ an ]
 [ animal, antidote, a     n anything ]
Last updated on by Kalkicode




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