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Print reverse character bridge pattern

Here given code implementation process.

// C Program
// Print reverse character bridge pattern
#include <stdio.h>

void printBridgePattern(int n)
{
	if (n <= 0 || n > 26)
	{
		return;
	}
	// Loop controlling variables
	int i = 0;
	int j = 0;
	// Display given n
	printf("\nGiven n : %d \n\n", n);
	// iterating the loop through by size n
	for (i = 0; i < n; ++i)
	{
		// Print left side pattern
		for (j = 0; j < n - i; ++j)
		{
			printf("%c", ('A' + j));
		}
		for (j = 0; j < i + i; ++j)
		{
			// Include intermediate space
			printf(" ");
		}
		// Print right side pattern
		for (j = 'A' + (n - i - 1); j >= 'A'; --j)
		{
			printf("%c", j);
		}
		// Include new line
		printf("\n");
	}
}
int main(int argc, char const *argv[])
{
	// Test cases
	printBridgePattern(7);
	printBridgePattern(10);
	return 0;
}

input

Given n : 7

ABCDEFGGFEDCBA
ABCDEF  FEDCBA
ABCDE    EDCBA
ABCD      DCBA
ABC        CBA
AB          BA
A            A

Given n : 10

ABCDEFGHIJJIHGFEDCBA
ABCDEFGHI  IHGFEDCBA
ABCDEFGH    HGFEDCBA
ABCDEFG      GFEDCBA
ABCDEF        FEDCBA
ABCDE          EDCBA
ABCD            DCBA
ABC              CBA
AB                BA
A                  A
// Java program for
// Print reverse character bridge pattern
public class BridgePattern
{
	public void printBridgePattern(int n)
	{
		if (n <= 0 || n > 26)
		{
			return;
		}
		// Loop controlling variables
		int i = 0;
		int j = 0;
		// Display given n
		System.out.print("\nGiven n : " + n + " \n\n");
		// iterating the loop through by size n
		for (i = 0; i < n; ++i)
		{
			// Print left side pattern
			for (j = 0; j < n - i; ++j)
			{
				System.out.print( (char)('A' + j));
			}
			for (j = 0; j < i + i; ++j)
			{
				// Include intermediate space
				System.out.print(" ");
			}
			// Print right side pattern
			for (j = 'A' + (n - i - 1); j >= 'A'; --j)
			{
				System.out.print((char) j);
			}
			// Include new line
			System.out.print("\n");
		}
	}
	public static void main(String[] args)
	{
		BridgePattern task = new BridgePattern();
		// Test cases
		task.printBridgePattern(7);
		task.printBridgePattern(10);
	}
}

input

Given n : 7

ABCDEFGGFEDCBA
ABCDEF  FEDCBA
ABCDE    EDCBA
ABCD      DCBA
ABC        CBA
AB          BA
A            A

Given n : 10

ABCDEFGHIJJIHGFEDCBA
ABCDEFGHI  IHGFEDCBA
ABCDEFGH    HGFEDCBA
ABCDEFG      GFEDCBA
ABCDEF        FEDCBA
ABCDE          EDCBA
ABCD            DCBA
ABC              CBA
AB                BA
A                  A
// Include header file
#include <iostream>

using namespace std;
// C++ program for
// Print reverse character bridge pattern
class BridgePattern
{
	public: void printBridgePattern(int n)
	{
		if (n <= 0 || n > 26)
		{
			return;
		}
		// Loop controlling variables
		int i = 0;
		int j = 0;
		// Display given n
		cout << "\nGiven n : " << n << " \n\n";
		// iterating the loop through by size n
		for (i = 0; i < n; ++i)
		{
			// Print left side pattern
			for (j = 0; j < n - i; ++j)
			{
				cout << (char)('A' + j);
			}
			for (j = 0; j < i + i; ++j)
			{
				// Include intermediate space
				cout << " ";
			}
			// Print right side pattern
			for (j = 'A' + (n - i - 1); j >= 'A'; --j)
			{
				cout << (char) j;
			}
			// Include new line
			cout << "\n";
		}
	}
};
int main()
{
	BridgePattern *task = new BridgePattern();
	// Test cases
	task->printBridgePattern(7);
	task->printBridgePattern(10);
	return 0;
}

input

Given n : 7

ABCDEFGGFEDCBA
ABCDEF  FEDCBA
ABCDE    EDCBA
ABCD      DCBA
ABC        CBA
AB          BA
A            A

Given n : 10

ABCDEFGHIJJIHGFEDCBA
ABCDEFGHI  IHGFEDCBA
ABCDEFGH    HGFEDCBA
ABCDEFG      GFEDCBA
ABCDEF        FEDCBA
ABCDE          EDCBA
ABCD            DCBA
ABC              CBA
AB                BA
A                  A
// Include namespace system
using System;
// Csharp program for
// Print reverse character bridge pattern
public class BridgePattern
{
	public void printBridgePattern(int n)
	{
		if (n <= 0 || n > 26)
		{
			return;
		}
		// Loop controlling variables
		int i = 0;
		int j = 0;
		// Display given n
		Console.Write("\nGiven n : " + n + " \n\n");
		// iterating the loop through by size n
		for (i = 0; i < n; ++i)
		{
			// Print left side pattern
			for (j = 0; j < n - i; ++j)
			{
				Console.Write((char)('A' + j));
			}
			for (j = 0; j < i + i; ++j)
			{
				// Include intermediate space
				Console.Write(" ");
			}
			// Print right side pattern
			for (j = 'A' + (n - i - 1); j >= 'A'; --j)
			{
				Console.Write((char) j);
			}
			// Include new line
			Console.Write("\n");
		}
	}
	public static void Main(String[] args)
	{
		BridgePattern task = new BridgePattern();
		// Test cases
		task.printBridgePattern(7);
		task.printBridgePattern(10);
	}
}

input

Given n : 7

ABCDEFGGFEDCBA
ABCDEF  FEDCBA
ABCDE    EDCBA
ABCD      DCBA
ABC        CBA
AB          BA
A            A

Given n : 10

ABCDEFGHIJJIHGFEDCBA
ABCDEFGHI  IHGFEDCBA
ABCDEFGH    HGFEDCBA
ABCDEFG      GFEDCBA
ABCDEF        FEDCBA
ABCDE          EDCBA
ABCD            DCBA
ABC              CBA
AB                BA
A                  A
<?php
// Php program for
// Print reverse character bridge pattern
class BridgePattern
{
	public	function printBridgePattern($n)
	{
		if ($n <= 0 || $n > 26)
		{
			return;
		}
		// Loop controlling variables
		$i = 0;
		$j = 0;
		// Display given n
		echo("\nGiven n : ".$n.
			" \n\n");
		// iterating the loop through by size n
		for ($i = 0; $i < $n; ++$i)
		{
			// Print left side pattern
			for ($j = 0; $j < $n - $i; ++$j)
			{
				echo(chr((ord('A') + $j)));
			}
			for ($j = 0; $j < $i + $i; ++$j)
			{
				// Include intermediate space
				echo(" ");
			}
			// Print right side pattern
			for ($j = ord('A') + ($n - $i - 1); $j >= ord('A'); --$j)
			{
				echo(chr($j));
			}
			// Include new line
			echo("\n");
		}
	}
}

function main()
{
	$task = new BridgePattern();
	// Test cases
	$task->printBridgePattern(7);
	$task->printBridgePattern(10);
}
main();

input

Given n : 7

ABCDEFGGFEDCBA
ABCDEF  FEDCBA
ABCDE    EDCBA
ABCD      DCBA
ABC        CBA
AB          BA
A            A

Given n : 10

ABCDEFGHIJJIHGFEDCBA
ABCDEFGHI  IHGFEDCBA
ABCDEFGH    HGFEDCBA
ABCDEFG      GFEDCBA
ABCDEF        FEDCBA
ABCDE          EDCBA
ABCD            DCBA
ABC              CBA
AB                BA
A                  A
// Node JS program for
// Print reverse character bridge pattern
class BridgePattern
{
	printBridgePattern(n)
	{
		if (n <= 0 || n > 26)
		{
			return;
		}
		// Loop controlling variables
		var i = 0;
		var j = 0;
		// Display given n
		process.stdout.write("\nGiven n : " + n + " \n\n");
		// iterating the loop through by size n
		for (i = 0; i < n; ++i)
		{
			// Print left side pattern
			for (j = 0; j < n - i; ++j)
			{
				process.stdout.write(
                  String.fromCharCode(('A'.charCodeAt(0) + j)));
			}
			for (j = 0; j < i + i; ++j)
			{
				// Include intermediate space
				process.stdout.write(" ");
			}
			// Print right side pattern
			for (j = 'A'.charCodeAt(0) + (n - i - 1); 
                 j >= 'A'.charCodeAt(0); 
                 --j)
			{
				process.stdout.write(String.fromCharCode(j));
			}
			// Include new line
			process.stdout.write("\n");
		}
	}
}

function main()
{
	var task = new BridgePattern();
	// Test cases
	task.printBridgePattern(7);
	task.printBridgePattern(10);
}
main();

input

Given n : 7

ABCDEFGGFEDCBA
ABCDEF  FEDCBA
ABCDE    EDCBA
ABCD      DCBA
ABC        CBA
AB          BA
A            A

Given n : 10

ABCDEFGHIJJIHGFEDCBA
ABCDEFGHI  IHGFEDCBA
ABCDEFGH    HGFEDCBA
ABCDEFG      GFEDCBA
ABCDEF        FEDCBA
ABCDE          EDCBA
ABCD            DCBA
ABC              CBA
AB                BA
A                  A
#  Python 3 program for
#  Print reverse character bridge pattern
class BridgePattern :
	def printBridgePattern(self, n) :
		if (n <= 0 or n > 26) :
			return
		
		#  Loop controlling variables
		i = 0
		j = 0
		#  Display given n
		print("\nGiven n : ", n ," \n")
		#  iterating the loop through by size n
		while (i < n) :
			#  Print left side pattern
			j = 0
			while (j < n - i) :
				print(chr((ord('A') + j)), end = "")
				j += 1
			
			j = 0
			while (j < i + i) :
				#  Include intermediate space
				print(" ", end = "")
				j += 1
			
			#  Print right side pattern
			j = ord('A') + (n - i - 1)
			while (j >= ord('A')) :
				print(chr(j), end = "")
				j -= 1
			
			#  Include new line
			print(end = "\n")
			i += 1
		
	

def main() :
	task = BridgePattern()
	#  Test cases
	task.printBridgePattern(7)
	task.printBridgePattern(10)

if __name__ == "__main__": main()

input

Given n :  7

ABCDEFGGFEDCBA
ABCDEF  FEDCBA
ABCDE    EDCBA
ABCD      DCBA
ABC        CBA
AB          BA
A            A

Given n :  10

ABCDEFGHIJJIHGFEDCBA
ABCDEFGHI  IHGFEDCBA
ABCDEFGH    HGFEDCBA
ABCDEFG      GFEDCBA
ABCDEF        FEDCBA
ABCDE          EDCBA
ABCD            DCBA
ABC              CBA
AB                BA
A                  A
#  Ruby program for
#  Print reverse character bridge pattern
class BridgePattern 
	def printBridgePattern(n) 
		if (n <= 0 || n > 26) 
			return
		end

		#  Loop controlling variables
		i = 0
		j = 0
		#  Display given n
		print("\nGiven n : ", n ," \n\n")
		#  iterating the loop through by size n
		while (i < n) 
			#  Print left side pattern
			j = 0
			while (j < n - i) 
				print((('A'.ord + j)).chr)
				j += 1
			end

			j = 0
			while (j < i + i) 
				#  Include intermediate space
				print(" ")
				j += 1
			end

			#  Print right side pattern
			j = 'A'.ord + (n - i - 1)
			while (j >= 'A'.ord) 
				print((j).chr)
				j -= 1
			end

			#  Include new line
			print("\n")
			i += 1
		end

	end

end

def main() 
	task = BridgePattern.new()
	#  Test cases
	task.printBridgePattern(7)
	task.printBridgePattern(10)
end

main()

input

Given n : 7 

ABCDEFGGFEDCBA
ABCDEF  FEDCBA
ABCDE    EDCBA
ABCD      DCBA
ABC        CBA
AB          BA
A            A

Given n : 10 

ABCDEFGHIJJIHGFEDCBA
ABCDEFGHI  IHGFEDCBA
ABCDEFGH    HGFEDCBA
ABCDEFG      GFEDCBA
ABCDEF        FEDCBA
ABCDE          EDCBA
ABCD            DCBA
ABC              CBA
AB                BA
A                  A

// Scala program for
// Print reverse character bridge pattern
class BridgePattern()
{
	def printBridgePattern(n: Int): Unit = {
		if (n <= 0 || n > 26)
		{
			return;
		}
		// Loop controlling variables
		var i: Int = 0;
		var j: Int = 0;
		// Display given n
		print("\nGiven n : " + n + " \n\n");
		// iterating the loop through by size n
		while (i < n)
		{
			// Print left side pattern
			j = 0;
			while (j < n - i)
			{
				print(('A'.toInt + j).toChar);
				j += 1;
			}
			j = 0;
			while (j < i + i)
			{
				// Include intermediate space
				print(" ");
				j += 1;
			}
			// Print right side pattern
			j = 'A'.toInt + (n - i - 1);
			while (j >= 'A'.toInt)
			{
				print(j.toChar);
				j -= 1;
			}
			// Include new line
			print("\n");
			i += 1;
		}
	}
}
object Main
{
	def main(args: Array[String]): Unit = {
		var task: BridgePattern = new BridgePattern();
		// Test cases
		task.printBridgePattern(7);
		task.printBridgePattern(10);
	}
}

input

Given n : 7

ABCDEFGGFEDCBA
ABCDEF  FEDCBA
ABCDE    EDCBA
ABCD      DCBA
ABC        CBA
AB          BA
A            A

Given n : 10

ABCDEFGHIJJIHGFEDCBA
ABCDEFGHI  IHGFEDCBA
ABCDEFGH    HGFEDCBA
ABCDEFG      GFEDCBA
ABCDEF        FEDCBA
ABCDE          EDCBA
ABCD            DCBA
ABC              CBA
AB                BA
A                  A
// Swift 4 program for
// Print reverse character bridge pattern
class BridgePattern
{
	func printBridgePattern(_ n: Int)
	{
		if (n <= 0 || n > 26)
		{
			return;
		}
		// Loop controlling variables
		var i = 0;
		var j = 0;
		// Display given n
		print("\nGiven n : ", n ," \n");
		// iterating the loop through by size n
		while (i < n)
		{
			// Print left side pattern
			j = 0;
			while (j < n - i)
			{
				print(Character(UnicodeScalar(65 + j)!), terminator: "");
				j += 1;
			}
			j = 0;
			while (j < i + i)
			{
				// Include intermediate space
				print(" ", terminator: "");
				j += 1;
			}
			// Print right side pattern
			j = 65 + (n - i - 1);
			while (j >= 65)
			{
				print(Character(UnicodeScalar(j)!), terminator: "");
				j -= 1;
			}
			// Include new line
			print(terminator: "\n");
			i += 1;
		}
	}
}
func main()
{
	let task = BridgePattern();
	// Test cases
	task.printBridgePattern(7);
	task.printBridgePattern(10);
}
main();

input

Given n :  7

ABCDEFGGFEDCBA
ABCDEF  FEDCBA
ABCDE    EDCBA
ABCD      DCBA
ABC        CBA
AB          BA
A            A

Given n :  10

ABCDEFGHIJJIHGFEDCBA
ABCDEFGHI  IHGFEDCBA
ABCDEFGH    HGFEDCBA
ABCDEFG      GFEDCBA
ABCDEF        FEDCBA
ABCDE          EDCBA
ABCD            DCBA
ABC              CBA
AB                BA
A                  A
// Kotlin program for
// Print reverse character bridge pattern
class BridgePattern
{
	fun printBridgePattern(n: Int): Unit
	{
		if (n <= 0 || n > 26)
		{
			return;
		}
		// Loop controlling variables
		var i: Int = 0;
		var j: Int = 0;
		// Display given n
		print("\nGiven n : " + n + " \n\n");
		// iterating the loop through by size n
		while (i < n)
		{
			// Print left side pattern
			
			while (j < n - i)
			{
				print(('A'.toInt() + j).toChar());
				j += 1;
			}
			j = 0;
			while (j < i + i)
			{
				// Include intermediate space
				print(" ");
				j += 1;
			}
			// Print right side pattern
			j = 'A'.toInt() + (n - i - 1);
			while (j >= 'A'.toInt())
			{
				print(j.toChar());
				j -= 1;
			}
			// Include new line
			print("\n");
			i += 1;
          	j = 0;
		}
	}
}
fun main(args: Array < String > ): Unit
{
	val task: BridgePattern = BridgePattern();
	// Test cases
	task.printBridgePattern(7);
	task.printBridgePattern(10);
}

input

Given n : 7

ABCDEFGGFEDCBA
ABCDEF  FEDCBA
ABCDE    EDCBA
ABCD      DCBA
ABC        CBA
AB          BA
A            A

Given n : 10

ABCDEFGHIJJIHGFEDCBA
ABCDEFGHI  IHGFEDCBA
ABCDEFGH    HGFEDCBA
ABCDEFG      GFEDCBA
ABCDEF        FEDCBA
ABCDE          EDCBA
ABCD            DCBA
ABC              CBA
AB                BA
A                  A
Last updated on by Kalkicode




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