Print the last k nodes of the linked list in reverse order

Given a linked list print out last kth nodes in reverse order. There can be many solution of this problem?. Here include common solution which is combination of iterative and recursive approach. Let as views an example to implement solution of this problem.

Suppose we are inserted the following (1,2,3,4,5,6,7,8) node in a sequence.

Here given list of code implementation process.

1) Print last k nodes of linked list in reverse order in java 2) Print last k nodes of linked list in reverse order in c 3) Print last k nodes of linked list in reverse order in cpp 4) Print last k nodes of linked list in reverse order in c# 5) Print last k nodes of linked list in reverse order in golang 6) Print last k nodes of linked list in reverse order in php 7) Print last k nodes of linked list in reverse order in scala 8) Print last k nodes of linked list in reverse order in ruby 9) Print last k nodes of linked list in reverse order in python 10) Print last k nodes of linked list in reverse order in swift 11) Print last k nodes of linked list in reverse order in kotlin 12) Print last k nodes of linked list in reverse order in js 13) Print last k nodes of linked list in reverse order in vb.net 14) Print last k nodes of linked list in reverse order in typeScript

Above is simplest solution, We can solve this problem in following ways.

1) Reverse the linked list and display initials k element. And reverse the linked list again to get original state.

2) Use a collection (Array of size k) contains which is store last k elements. And print result in reverse order. This process used extra space.

3) Count length of linked list and store last k element into the stack. And print stack element.

There is standard solution you can solve this problem in many ways.