Print even and odd level nodes in binary tree in java

Java program for Print even and odd level nodes in binary tree. Here more solutions.
/*
Java program for
Print the nodes of even and odd levels of binary tree
*/
// Binary Tree node
class TreeNode
{
public int data;
public TreeNode left;
public TreeNode right;
public TreeNode(int data)
{
// Set node value
this.data = data;
this.left = null;
this.right = null;
}
}
class BinaryTree
{
public TreeNode root;
public BinaryTree()
{
// Set initial tree root
this.root = null;
}
// Print all nodes which is exist in odd Level
public void oddLevel(TreeNode node, int level)
{
if (node != null)
{
if (level % 2 != 0)
{
System.out.print(" " + node.data);
}
oddLevel(node.left, level+1);
oddLevel(node.right, level+1);
}
}
// Print all nodes which is exist in even Level
public void evenLevel(TreeNode node, int level)
{
if (node != null)
{
if (level % 2 == 0)
{
System.out.print(" " + node.data);
}
evenLevel(node.left, level+1);
evenLevel(node.right, level+1);
}
}
public static void main(String[] args)
{
// Create new tree
BinaryTree tree = new BinaryTree();
/*
Binary Tree
-------------
10
/ \
2 4
/ / \
3 6 5
\ \
9 7
\
11
*/
// Add tree nodes
tree.root = new TreeNode(10);
tree.root.left = new TreeNode(2);
tree.root.left.left = new TreeNode(3);
tree.root.left.left.right = new TreeNode(9);
tree.root.right = new TreeNode(4);
tree.root.right.right = new TreeNode(5);
tree.root.right.left = new TreeNode(6);
tree.root.right.left.right = new TreeNode(7);
tree.root.right.left.right.right = new TreeNode(11);
System.out.print("\n Even Level Nodes : ");
tree.evenLevel(tree.root, 1);
System.out.print("\n Odd Level Nodes : ");
tree.oddLevel(tree.root, 1);
}
}
Output
Even Level Nodes : 2 9 4 7
Odd Level Nodes : 10 3 6 11 5
Please share your knowledge to improve code and content standard. Also submit your doubts, and test case. We improve by your feedback. We will try to resolve your query as soon as possible.
New Comment