Print distinct combinations of given sum without repeating number

Here given code implementation process.

// C Program
// Print distinct combinations of given sum without repeating number
#include <stdio.h>

// This is use to display calculated result
void printResult(int result[], int sum)
{
	printf("\n[");
	for (int i = 0; i < sum; ++i)
	{
		if (result[i] == 1)
		{
			printf(" %d ", i + 1);
		}
	}
	printf("]");
}
void printCombinations(int result[], int sum, int index, int k)
{
	if (k == sum)
	{
		// When k is equal to given sum.
		printResult(result, sum);
		return;
	}
	else if (k > sum || index < 0)
	{
		// When k value is greater than given sum or
		// Index is less than zero.
		// Need to stop process.
		return;
	}
	for (int i = index; i >= 0; --i)
	{
		// Active result element
		result[i] = 1;
		// Find combinations using recursion
		printCombinations(result, sum, i - 1, k + (i + 1));
		// InActive result element
		result[i] = 0;
	}
}
void combinations(int sum)
{
	if (sum <= 0)
	{
		return;
	}
	// Use to collect result
	int result[sum];
	// Provide initial value. 
	// Here zero indicates its not a part of result.
	for (int i = 0; i < sum; ++i)
	{
		result[i] = 0;
	}
	// Test
	printCombinations(result, sum, sum - 1, 0);
}
int main()
{
	//Test Case
	combinations(10);
	return 0;
}

Output

[ 10 ]
[ 1  9 ]
[ 2  8 ]
[ 3  7 ]
[ 1  2  7 ]
[ 4  6 ]
[ 1  3  6 ]
[ 1  4  5 ]
[ 2  3  5 ]
[ 1  2  3  4 ]
// Java Program
// Print distinct combinations of given sum without repeating number
class SumGroup
{
    // This is use to display calculated result
    public void printResult(int[] result, int sum)
    {
        System.out.print("\n[");
        for (int i = 0; i < sum; ++i)
        {
            if (result[i] == 1)
            {
                System.out.print(" " + (i + 1) + " ");
            }
        }
        System.out.print("]");
    }
    public void printCombinations(
      int[] result, 
      int sum, 
      int index, 
      int k)
    {
        if (k == sum)
        {
            // When k is equal to given sum.
            printResult(result, sum);
            return;
        }
        else if (k > sum || index < 0)
        {
            // When k value is greater than given sum or
            // Index is less than zero.
            // Need to stop process.
            return;
        }
        for (int i = index; i >= 0; --i)
        {
            // Active result element
            result[i] = 1;
            // Find combinations using recursion
            printCombinations(result, sum, i - 1, k + (i + 1));
            // InActive result element
            result[i] = 0;
        }
    }
    public void combinations(int sum)
    {
        if (sum <= 0)
        {
            return;
        }
        // Use to collect result
        int[] result = new int[sum];
        // Provide initial value. 
        // Here zero indicates its not a part of result.
        for (int i = 0; i < sum; ++i)
        {
            result[i] = 0;
        }
        // Test
        printCombinations(result, sum, sum - 1, 0);
    }
    public static void main(String[] args)
    {
        SumGroup task = new SumGroup();
        // Test Case
        task.combinations(10);
    }
}

Output

[ 10 ]
[ 1  9 ]
[ 2  8 ]
[ 3  7 ]
[ 1  2  7 ]
[ 4  6 ]
[ 1  3  6 ]
[ 1  4  5 ]
[ 2  3  5 ]
[ 1  2  3  4 ]
// Include header file
#include <iostream>
using namespace std;
// C++ Program
// Print distinct combinations of given sum without repeating number
class SumGroup
{
	public:
		// This is use to display calculated result
		void printResult(int result[], int sum)
		{
			cout << "\n[";
			for (int i = 0; i < sum; ++i)
			{
				if (result[i] == 1)
				{
					cout << " " << (i + 1) << " ";
				}
			}
			cout << "]";
		}
	void printCombinations(int result[], int sum, int index, int k)
	{
		if (k == sum)
		{
			// When k is equal to given sum.
			this->printResult(result, sum);
			return;
		}
		else if (k > sum || index < 0)
		{
			// When k value is greater than given sum or
			// Index is less than zero.
			// Need to stop process.
			return;
		}
		for (int i = index; i >= 0; --i)
		{
			// Active result element
			result[i] = 1;
			// Find combinations using recursion
			this->printCombinations(result, sum, i - 1, k + (i + 1));
			// InActive result element
			result[i] = 0;
		}
	}
	void combinations(int sum)
	{
		if (sum <= 0)
		{
			return;
		}
		// Use to collect result
		int result[sum];
		// Provide initial value. 
		// Here zero indicates its not a part of result.
		for (int i = 0; i < sum; ++i)
		{
			result[i] = 0;
		}
		// Test
		this->printCombinations(result, sum, sum - 1, 0);
	}
};
int main()
{
	SumGroup *task = new SumGroup();
	// Test Case
	task->combinations(10);
	return 0;
}

Output

[ 10 ]
[ 1  9 ]
[ 2  8 ]
[ 3  7 ]
[ 1  2  7 ]
[ 4  6 ]
[ 1  3  6 ]
[ 1  4  5 ]
[ 2  3  5 ]
[ 1  2  3  4 ]
// Include namespace system
using System;
// Csharp Program
// Print distinct combinations of given sum without repeating number
public class SumGroup
{
	// This is use to display calculated result
	public void printResult(int[] result, int sum)
	{
		Console.Write("\n[");
		for (int i = 0; i < sum; ++i)
		{
			if (result[i] == 1)
			{
				Console.Write(" " + (i + 1) + " ");
			}
		}
		Console.Write("]");
	}
	public void printCombinations(
      int[] result, int sum, 
      int index, int k)
	{
		if (k == sum)
		{
			// When k is equal to given sum.
			this.printResult(result, sum);
			return;
		}
		else if (k > sum || index < 0)
		{
			// When k value is greater than given sum or
			// Index is less than zero.
			// Need to stop process.
			return;
		}
		for (int i = index; i >= 0; --i)
		{
			// Active result element
			result[i] = 1;
			// Find combinations using recursion
			this.printCombinations(result, sum, 
                                   i - 1, k + (i + 1));
			// InActive result element
			result[i] = 0;
		}
	}
	public void combinations(int sum)
	{
		if (sum <= 0)
		{
			return;
		}
		// Use to collect result
		int[] result = new int[sum];
		// Provide initial value. 
		// Here zero indicates its not a part of result.
		for (int i = 0; i < sum; ++i)
		{
			result[i] = 0;
		}
		// Test
		this.printCombinations(result, sum, sum - 1, 0);
	}
	public static void Main(String[] args)
	{
		SumGroup task = new SumGroup();
		// Test Case
		task.combinations(10);
	}
}

Output

[ 10 ]
[ 1  9 ]
[ 2  8 ]
[ 3  7 ]
[ 1  2  7 ]
[ 4  6 ]
[ 1  3  6 ]
[ 1  4  5 ]
[ 2  3  5 ]
[ 1  2  3  4 ]
package main
import "fmt"
// Go Program
// Print distinct combinations of given sum without repeating number
type SumGroup struct {}
func getSumGroup() * SumGroup {
	var me *SumGroup = &SumGroup {}
	return me
}
// This is use to display calculated result
func(this SumGroup) printResult(result[] int, 
	sum int) {
	fmt.Print("\n[")
	for i := 0 ; i < sum ; i++ {
		if result[i] == 1 {
			fmt.Print(" ", (i + 1), " ")
		}
	}
	fmt.Print("]")
}
func(this SumGroup) printCombinations(result[] int, 
	sum int, index int, k int) {
	if k == sum {
		// When k is equal to given sum.
		this.printResult(result, sum)
		return
	} else if k > sum || index < 0 {
		// When k value is greater than given sum or
		// Index is less than zero.
		// Need to stop process.
		return
	}
	for i := index ; i >= 0 ; i-- {
		// Active result element
		result[i] = 1
		// Find combinations using recursion
		this.printCombinations(result, sum, 
							  i - 1, k + (i + 1))
		// InActive result element
		result[i] = 0
	}
}
func(this SumGroup) combinations(sum int) {
	if sum <= 0 {
		return
	}
	// Use to collect result
	var result = make([] int, sum)
	// Provide initial value. 
	// Here zero indicates its not a part of result.
	for i := 0 ; i < sum ; i++ {
		result[i] = 0
	}
	// Test
	this.printCombinations(result, sum, sum - 1, 0)
}
func main() {
	var task * SumGroup = getSumGroup()
	// Test Case
	task.combinations(10)
}

Output

[ 10 ]
[ 1  9 ]
[ 2  8 ]
[ 3  7 ]
[ 1  2  7 ]
[ 4  6 ]
[ 1  3  6 ]
[ 1  4  5 ]
[ 2  3  5 ]
[ 1  2  3  4 ]
<?php
// Php Program
// Print distinct combinations of given sum without repeating number
class SumGroup
{
	// This is use to display calculated result
	public	function printResult($result, $sum)
	{
		echo("\n[");
		for ($i = 0; $i < $sum; ++$i)
		{
			if ($result[$i] == 1)
			{
				echo(" ".($i + 1).
					" ");
			}
		}
		echo("]");
	}
	public	function printCombinations($result, $sum, $index, $k)
	{
		if ($k == $sum)
		{
			// When k is equal to given sum.
			$this->printResult($result, $sum);
			return;
		}
		else if ($k > $sum || $index < 0)
		{
			// When k value is greater than given sum or
			// Index is less than zero.
			// Need to stop process.
			return;
		}
		for ($i = $index; $i >= 0; --$i)
		{
			// Active result element
			$result[$i] = 1;
			// Find combinations using recursion
			$this->printCombinations($result, $sum, 
                                     $i - 1, $k + ($i + 1));
			// InActive result element
			$result[$i] = 0;
		}
	}
	public	function combinations($sum)
	{
		if ($sum <= 0)
		{
			return;
		}
		// Use to collect result
		$result = array_fill(0, $sum, 0);
		// Provide initial value. 
		// Here zero indicates its not a part of result.
		for ($i = 0; $i < $sum; ++$i)
		{
			$result[$i] = 0;
		}
		// Test
		$this->printCombinations($result, $sum, $sum - 1, 0);
	}
}

function main()
{
	$task = new SumGroup();
	// Test Case
	$task->combinations(10);
}
main();

Output

[ 10 ]
[ 1  9 ]
[ 2  8 ]
[ 3  7 ]
[ 1  2  7 ]
[ 4  6 ]
[ 1  3  6 ]
[ 1  4  5 ]
[ 2  3  5 ]
[ 1  2  3  4 ]
// Node JS Program
// Print distinct combinations of given sum without repeating number
class SumGroup
{
	// This is use to display calculated result
	printResult(result, sum)
	{
		process.stdout.write("\n[");
		for (var i = 0; i < sum; ++i)
		{
			if (result[i] == 1)
			{
				process.stdout.write(" " + (i + 1) + " ");
			}
		}
		process.stdout.write("]");
	}
	printCombinations(result, sum, index, k)
	{
		if (k == sum)
		{
			// When k is equal to given sum.
			this.printResult(result, sum);
			return;
		}
		else if (k > sum || index < 0)
		{
			// When k value is greater than given sum or
			// Index is less than zero.
			// Need to stop process.
			return;
		}
		for (var i = index; i >= 0; --i)
		{
			// Active result element
			result[i] = 1;
			// Find combinations using recursion
			this.printCombinations(result, sum, i - 1, k + (i + 1));
			// InActive result element
			result[i] = 0;
		}
	}
	combinations(sum)
	{
		if (sum <= 0)
		{
			return;
		}
		// Use to collect result
		var result = Array(sum).fill(0);
		// Provide initial value. 
		// Here zero indicates its not a part of result.
		for (var i = 0; i < sum; ++i)
		{
			result[i] = 0;
		}
		// Test
		this.printCombinations(result, sum, sum - 1, 0);
	}
}

function main()
{
	var task = new SumGroup();
	// Test Case
	task.combinations(10);
}
main();

Output

[ 10 ]
[ 1  9 ]
[ 2  8 ]
[ 3  7 ]
[ 1  2  7 ]
[ 4  6 ]
[ 1  3  6 ]
[ 1  4  5 ]
[ 2  3  5 ]
[ 1  2  3  4 ]
#  Python 3 Program
#  Print distinct combinations of given sum without repeating number
class SumGroup :
	#  This is use to display calculated result
	def printResult(self, result, sum) :
		print("\n[", end = "")
		i = 0
		while (i < sum) :
			if (result[i] == 1) :
				print("", (i + 1) ,"", end = "")
			
			i += 1
		
		print("]", end = "")
	
	def printCombinations(self, result, sum, index, k) :
		if (k == sum) :
			#  When k is equal to given sum.
			self.printResult(result, sum)
			return
		elif (k > sum or index < 0) :
			#  When k value is greater than given sum or
			#  Index is less than zero.
			#  Need to stop process.
			return
		
		i = index
		while (i >= 0) :
			#  Active result element
			result[i] = 1
			#  Find combinations using recursion
			self.printCombinations(result, sum, i - 1, k + (i + 1))
			#  InActive result element
			result[i] = 0
			i -= 1
		
	
	def combinations(self, sum) :
		if (sum <= 0) :
			return
		
		#  Use to collect result
		result = [0] * (sum)
		i = 0
		#  Provide initial value. 
		#  Here zero indicates its not a part of result.
		while (i < sum) :
			result[i] = 0
			i += 1
		
		#  Test
		self.printCombinations(result, sum, sum - 1, 0)
	

def main() :
	task = SumGroup()
	#  Test Case
	task.combinations(10)

if __name__ == "__main__": main()

Output

[ 10 ]
[ 1  9 ]
[ 2  8 ]
[ 3  7 ]
[ 1  2  7 ]
[ 4  6 ]
[ 1  3  6 ]
[ 1  4  5 ]
[ 2  3  5 ]
[ 1  2  3  4 ]
#  Ruby Program
#  Print distinct combinations of given sum without repeating number
class SumGroup 
	#  This is use to display calculated result
	def printResult(result, sum) 
		print("\n[")
		i = 0
		while (i < sum) 
			if (result[i] == 1) 
				print(" ", (i + 1) ," ")
			end

			i += 1
		end

		print("]")
	end

	def printCombinations(result, sum, index, k) 
		if (k == sum) 
			#  When k is equal to given sum.
			self.printResult(result, sum)
			return
		elsif (k > sum || index < 0) 
			#  When k value is greater than given sum or
			#  Index is less than zero.
			#  Need to stop process.
			return
		end

		i = index
		while (i >= 0) 
			#  Active result element
			result[i] = 1
			#  Find combinations using recursion
			self.printCombinations(result, sum, i - 1, k + (i + 1))
			#  InActive result element
			result[i] = 0
			i -= 1
		end

	end

	def combinations(sum) 
		if (sum <= 0) 
			return
		end

		#  Use to collect result
		result = Array.new(sum) {0}
		i = 0
		#  Provide initial value. 
		#  Here zero indicates its not a part of result.
		while (i < sum) 
			result[i] = 0
			i += 1
		end

		#  Test
		self.printCombinations(result, sum, sum - 1, 0)
	end

end

def main() 
	task = SumGroup.new()
	#  Test Case
	task.combinations(10)
end

main()

Output

[ 10 ]
[ 1  9 ]
[ 2  8 ]
[ 3  7 ]
[ 1  2  7 ]
[ 4  6 ]
[ 1  3  6 ]
[ 1  4  5 ]
[ 2  3  5 ]
[ 1  2  3  4 ]
// Scala Program
// Print distinct combinations of given sum without repeating number
class SumGroup()
{
	// This is use to display calculated result
	def printResult(result: Array[Int], sum: Int): Unit = {
		print("\n[");
		var i: Int = 0;
		while (i < sum)
		{
			if (result(i) == 1)
			{
				print(" " + (i + 1) + " ");
			}
			i += 1;
		}
		print("]");
	}
	def printCombinations(
      result: Array[Int], 
      sum: Int, index: Int, 
        k: Int): Unit = {
		if (k == sum)
		{
			// When k is equal to given sum.
			printResult(result, sum);
			return;
		}
		else if (k > sum || index < 0)
		{
			// When k value is greater than given sum or
			// Index is less than zero.
			// Need to stop process.
			return;
		}
		var i: Int = index;
		while (i >= 0)
		{
			// Active result element
			result(i) = 1;
			// Find combinations using recursion
			printCombinations(result, sum, i - 1, k + (i + 1));
			// InActive result element
			result(i) = 0;
			i -= 1;
		}
	}
	def combinations(sum: Int): Unit = {
		if (sum <= 0)
		{
			return;
		}
		// Use to collect result
		var result: Array[Int] = Array.fill[Int](sum)(0);
		var i: Int = 0;
		// Provide initial value. 
		// Here zero indicates its not a part of result.
		while (i < sum)
		{
			result(i) = 0;
			i += 1;
		}
		// Test
		printCombinations(result, sum, sum - 1, 0);
	}
}
object Main
{
	def main(args: Array[String]): Unit = {
		var task: SumGroup = new SumGroup();
		// Test Case
		task.combinations(10);
	}
}

Output

[ 10 ]
[ 1  9 ]
[ 2  8 ]
[ 3  7 ]
[ 1  2  7 ]
[ 4  6 ]
[ 1  3  6 ]
[ 1  4  5 ]
[ 2  3  5 ]
[ 1  2  3  4 ]
// Swift 4 Program
// Print distinct combinations of given sum without repeating number
class SumGroup
{
	// This is use to display calculated result
	func printResult(_ result: [Int], _ sum: Int)
	{
		print("\n[", terminator: "");
		var i: Int = 0;
		while (i < sum)
		{
			if (result[i] == 1)
			{
				print("", (i + 1) ,"", terminator: "");
			}
			i += 1;
		}
		print("]", terminator: "");
	}
	func printCombinations(_ result: inout[Int], 
      _ sum: Int,
      _ index: Int, 
      _ k: Int)
	{
		if (k == sum)
		{
			// When k is equal to given sum.
			self.printResult(result, sum);
			return;
		}
		else if (k > sum || index < 0)
		{
			// When k value is greater than given sum or
			// Index is less than zero.
			// Need to stop process.
			return;
		}
		var i: Int = index;
		while (i >= 0)
		{
			// Active result element
			result[i] = 1;
			// Find combinations using recursion
			self.printCombinations(&result, sum, i - 1, k + (i + 1));
			// InActive result element
			result[i] = 0;
			i -= 1;
		}
	}
	func combinations(_ sum: Int)
	{
		if (sum <= 0)
		{
			return;
		}
		// Use to collect result
		var result: [Int] = Array(repeating: 0, count: sum);
		var i: Int = 0;
		// Provide initial value. 
		// Here zero indicates its not a part of result.
		while (i < sum)
		{
			result[i] = 0;
			i += 1;
		}
		// Test
		self.printCombinations(&result, sum, sum - 1, 0);
	}
}
func main()
{
	let task: SumGroup = SumGroup();
	// Test Case
	task.combinations(10);
}
main();

Output

[ 10 ]
[ 1  9 ]
[ 2  8 ]
[ 3  7 ]
[ 1  2  7 ]
[ 4  6 ]
[ 1  3  6 ]
[ 1  4  5 ]
[ 2  3  5 ]
[ 1  2  3  4 ]
// Kotlin Program
// Print distinct combinations of given sum without repeating number
class SumGroup
{
	// This is use to display calculated result
	fun printResult(result: Array < Int > , sum: Int): Unit
	{
		print("\n[");
		var i: Int = 0;
		while (i < sum)
		{
			if (result[i] == 1)
			{
				print(" " + (i + 1) + " ");
			}
			i += 1;
		}
		print("]");
	}
	fun printCombinations(
      result: Array < Int > , 
      sum: Int, 
      index: Int,
      k: Int): Unit
	{
		if (k == sum)
		{
			// When k is equal to given sum.
			this.printResult(result, sum);
			return;
		}
		else if (k > sum || index < 0)
		{
			// When k value is greater than given sum or
			// Index is less than zero.
			// Need to stop process.
			return;
		}
		var i: Int = index;
		while (i >= 0)
		{
			// Active result element
			result[i] = 1;
			// Find combinations using recursion
			this.printCombinations(result, sum, i - 1, k + (i + 1));
			// InActive result element
			result[i] = 0;
			i -= 1;
		}
	}
	fun combinations(sum: Int): Unit
	{
		if (sum <= 0)
		{
			return;
		}
		// Use to collect result
		val result: Array < Int > = Array(sum)
		{
			0
		};
		var i: Int = 0;
		// Provide initial value. 
		// Here zero indicates its not a part of result.
		while (i < sum)
		{
			result[i] = 0;
			i += 1;
		}
		// Test
		this.printCombinations(result, sum, sum - 1, 0);
	}
}
fun main(args: Array < String > ): Unit
{
	val task: SumGroup = SumGroup();
	// Test Case
	task.combinations(10);
}

Output

[ 10 ]
[ 1  9 ]
[ 2  8 ]
[ 3  7 ]
[ 1  2  7 ]
[ 4  6 ]
[ 1  3  6 ]
[ 1  4  5 ]
[ 2  3  5 ]
[ 1  2  3  4 ]


Please share your knowledge to improve code and content standard. Also submit your doubts, and test case. We improve by your feedback. We will try to resolve your query as soon as possible.

New Comment







© 2021, kalkicode.com, All rights reserved