Print all distinct combinations of sum x and n natural number
Here given code implementation process.
// C Program
// Print all distinct combinations of sum x and n natural number
#include <stdio.h>
// Display result
void printSequence(int result[], int k)
{
for (int i = 0; i < k; ++i)
{
printf(" %d", result[i]);
}
printf("\n ");
}
void findCombination(int result[], int index, int sum, int x, int n)
{
if (sum == x)
{
// Display calculated result
printSequence(result, index);
return;
}
if (sum > x || index >= x)
{
// Base case when stop process
return;
}
for (int i = n; i >= 1; --i)
{
// Collect result value
result[index] = i;
findCombination(result, index + 1, sum + i, x, i);
}
}
// Handles the request of find combination of given n and x
void combination(int x,int n)
{
if (n <= 0 || x <= 0)
{
return;
}
printf("\n Given n : %d x : %d \n ", n,x);
// Collect result
int result[x];
// Test
findCombination(result, 0, 0, x, n);
}
int main()
{
// Test A
// n = 3 means use [1,2,3]
int n = 3;
// Sum x = 10
int x = 10;
combination(x,n);
// Test B
// n = 4 means use [1,2,3,4]
n = 4;
// Sum x = 12
x = 12;
combination(x,n);
return 0;
}
Output
Given n : 3 x : 10
3 3 3 1
3 3 2 2
3 3 2 1 1
3 3 1 1 1 1
3 2 2 2 1
3 2 2 1 1 1
3 2 1 1 1 1 1
3 1 1 1 1 1 1 1
2 2 2 2 2
2 2 2 2 1 1
2 2 2 1 1 1 1
2 2 1 1 1 1 1 1
2 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1
Given n : 4 x : 12
4 4 4
4 4 3 1
4 4 2 2
4 4 2 1 1
4 4 1 1 1 1
4 3 3 2
4 3 3 1 1
4 3 2 2 1
4 3 2 1 1 1
4 3 1 1 1 1 1
4 2 2 2 2
4 2 2 2 1 1
4 2 2 1 1 1 1
4 2 1 1 1 1 1 1
4 1 1 1 1 1 1 1 1
3 3 3 3
3 3 3 2 1
3 3 3 1 1 1
3 3 2 2 2
3 3 2 2 1 1
3 3 2 1 1 1 1
3 3 1 1 1 1 1 1
3 2 2 2 2 1
3 2 2 2 1 1 1
3 2 2 1 1 1 1 1
3 2 1 1 1 1 1 1 1
3 1 1 1 1 1 1 1 1 1
2 2 2 2 2 2
2 2 2 2 2 1 1
2 2 2 2 1 1 1 1
2 2 2 1 1 1 1 1 1
2 2 1 1 1 1 1 1 1 1
2 1 1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1 1 1
// Java Program for
// Print all distinct combinations of sum x and n natural number
public class SumCombination
{
// Display result
public void printSequence(int[] result, int k)
{
for (int i = 0; i < k; ++i)
{
System.out.print(" " + result[i]);
}
System.out.print("\n");
}
public void findCombination(int[] result,
int index,
int sum,
int x,
int n)
{
if (sum == x)
{
// Display calculated result
printSequence(result, index);
return;
}
if (sum > x || index >= x)
{
// Base case when stop process
return;
}
for (int i = n; i >= 1; --i)
{
// Collect result value
result[index] = i;
findCombination(result, index + 1, sum + i, x, i);
}
}
// Handles the request of find combination of given n and x
public void combination(int x, int n)
{
if (n <= 0 || x <= 0)
{
return;
}
System.out.println("\n Given n : " + n + " x : " + x);
// Collect result
int[] result = new int[x];
// Test
findCombination(result, 0, 0, x, n);
}
public static void main(String[] args)
{
SumCombination task = new SumCombination();
// Test A
// n = 3 means use [1,2,3]
int n = 3;
// Sum x = 10
int x = 10;
task.combination(x, n);
// Test B
// n = 4 means use [1,2,3,4]
n = 4;
// Sum x = 12
x = 12;
task.combination(x, n);
}
}
Output
Given n : 3 x : 10
3 3 3 1
3 3 2 2
3 3 2 1 1
3 3 1 1 1 1
3 2 2 2 1
3 2 2 1 1 1
3 2 1 1 1 1 1
3 1 1 1 1 1 1 1
2 2 2 2 2
2 2 2 2 1 1
2 2 2 1 1 1 1
2 2 1 1 1 1 1 1
2 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1
Given n : 4 x : 12
4 4 4
4 4 3 1
4 4 2 2
4 4 2 1 1
4 4 1 1 1 1
4 3 3 2
4 3 3 1 1
4 3 2 2 1
4 3 2 1 1 1
4 3 1 1 1 1 1
4 2 2 2 2
4 2 2 2 1 1
4 2 2 1 1 1 1
4 2 1 1 1 1 1 1
4 1 1 1 1 1 1 1 1
3 3 3 3
3 3 3 2 1
3 3 3 1 1 1
3 3 2 2 2
3 3 2 2 1 1
3 3 2 1 1 1 1
3 3 1 1 1 1 1 1
3 2 2 2 2 1
3 2 2 2 1 1 1
3 2 2 1 1 1 1 1
3 2 1 1 1 1 1 1 1
3 1 1 1 1 1 1 1 1 1
2 2 2 2 2 2
2 2 2 2 2 1 1
2 2 2 2 1 1 1 1
2 2 2 1 1 1 1 1 1
2 2 1 1 1 1 1 1 1 1
2 1 1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1 1 1
// Include header file
#include <iostream>
using namespace std;
// C++ Program for
// Print all distinct combinations of sum x and n natural number
class SumCombination
{
public:
// Display result
void printSequence(int result[], int k)
{
for (int i = 0; i < k; ++i)
{
cout << " " << result[i];
}
cout << "\n";
}
void findCombination(int result[], int index, int sum, int x, int n)
{
if (sum == x)
{
// Display calculated result
this->printSequence(result, index);
return;
}
if (sum > x || index >= x)
{
// Base case when stop process
return;
}
for (int i = n; i >= 1; --i)
{
// Collect result value
result[index] = i;
this->findCombination(result, index + 1, sum + i, x, i);
}
}
// Handles the request of find combination of given n and x
void combination(int x, int n)
{
if (n <= 0 || x <= 0)
{
return;
}
cout << "\n Given n : " << n << " x : " << x << endl;
// Collect result
int result[x];
// Test
this->findCombination(result, 0, 0, x, n);
}
};
int main()
{
SumCombination *task = new SumCombination();
// Test A
// n = 3 means use [1,2,3]
int n = 3;
// Sum x = 10
int x = 10;
task->combination(x, n);
// Test B
// n = 4 means use [1,2,3,4]
n = 4;
// Sum x = 12
x = 12;
task->combination(x, n);
return 0;
}
Output
Given n : 3 x : 10
3 3 3 1
3 3 2 2
3 3 2 1 1
3 3 1 1 1 1
3 2 2 2 1
3 2 2 1 1 1
3 2 1 1 1 1 1
3 1 1 1 1 1 1 1
2 2 2 2 2
2 2 2 2 1 1
2 2 2 1 1 1 1
2 2 1 1 1 1 1 1
2 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1
Given n : 4 x : 12
4 4 4
4 4 3 1
4 4 2 2
4 4 2 1 1
4 4 1 1 1 1
4 3 3 2
4 3 3 1 1
4 3 2 2 1
4 3 2 1 1 1
4 3 1 1 1 1 1
4 2 2 2 2
4 2 2 2 1 1
4 2 2 1 1 1 1
4 2 1 1 1 1 1 1
4 1 1 1 1 1 1 1 1
3 3 3 3
3 3 3 2 1
3 3 3 1 1 1
3 3 2 2 2
3 3 2 2 1 1
3 3 2 1 1 1 1
3 3 1 1 1 1 1 1
3 2 2 2 2 1
3 2 2 2 1 1 1
3 2 2 1 1 1 1 1
3 2 1 1 1 1 1 1 1
3 1 1 1 1 1 1 1 1 1
2 2 2 2 2 2
2 2 2 2 2 1 1
2 2 2 2 1 1 1 1
2 2 2 1 1 1 1 1 1
2 2 1 1 1 1 1 1 1 1
2 1 1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1 1 1
package main
import "fmt"
// Go Program for
// Print all distinct combinations of sum x and n natural number
type SumCombination struct {}
func getSumCombination() * SumCombination {
var me *SumCombination = &SumCombination {}
return me
}
// Display result
func(this SumCombination) printSequence(result[] int, k int) {
for i := 0 ; i < k ; i++ {
fmt.Print(" ", result[i])
}
fmt.Print("\n")
}
func(this SumCombination) findCombination(result[] int,
index int, sum int, x int, n int) {
if sum == x {
// Display calculated result
this.printSequence(result, index)
return
}
if sum > x || index >= x {
// Base case when stop process
return
}
for i := n ; i >= 1 ; i-- {
// Collect result value
result[index] = i
this.findCombination(result, index + 1, sum + i, x, i)
}
}
// Handles the request of find combination of given n and x
func(this SumCombination) combination(x, n int) {
if n <= 0 || x <= 0 {
return
}
fmt.Println("\n Given n : ", n, " x : ", x)
// Collect result
var result = make([] int, x)
// Test
this.findCombination(result, 0, 0, x, n)
}
func main() {
var task * SumCombination = getSumCombination()
// Test A
// n = 3 means use [1,2,3]
var n int = 3
// Sum x = 10
var x int = 10
task.combination(x, n)
// Test B
// n = 4 means use [1,2,3,4]
n = 4
// Sum x = 12
x = 12
task.combination(x, n)
}
Output
Given n : 3 x : 10
3 3 3 1
3 3 2 2
3 3 2 1 1
3 3 1 1 1 1
3 2 2 2 1
3 2 2 1 1 1
3 2 1 1 1 1 1
3 1 1 1 1 1 1 1
2 2 2 2 2
2 2 2 2 1 1
2 2 2 1 1 1 1
2 2 1 1 1 1 1 1
2 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1
Given n : 4 x : 12
4 4 4
4 4 3 1
4 4 2 2
4 4 2 1 1
4 4 1 1 1 1
4 3 3 2
4 3 3 1 1
4 3 2 2 1
4 3 2 1 1 1
4 3 1 1 1 1 1
4 2 2 2 2
4 2 2 2 1 1
4 2 2 1 1 1 1
4 2 1 1 1 1 1 1
4 1 1 1 1 1 1 1 1
3 3 3 3
3 3 3 2 1
3 3 3 1 1 1
3 3 2 2 2
3 3 2 2 1 1
3 3 2 1 1 1 1
3 3 1 1 1 1 1 1
3 2 2 2 2 1
3 2 2 2 1 1 1
3 2 2 1 1 1 1 1
3 2 1 1 1 1 1 1 1
3 1 1 1 1 1 1 1 1 1
2 2 2 2 2 2
2 2 2 2 2 1 1
2 2 2 2 1 1 1 1
2 2 2 1 1 1 1 1 1
2 2 1 1 1 1 1 1 1 1
2 1 1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1 1 1
// Include namespace system
using System;
// Csharp Program for
// Print all distinct combinations of sum x and n natural number
public class SumCombination
{
// Display result
public void printSequence(int[] result, int k)
{
for (int i = 0; i < k; ++i)
{
Console.Write(" " + result[i]);
}
Console.Write("\n");
}
public void findCombination(int[] result,
int index,
int sum,
int x,
int n)
{
if (sum == x)
{
// Display calculated result
this.printSequence(result, index);
return;
}
if (sum > x || index >= x)
{
// Base case when stop process
return;
}
for (int i = n; i >= 1; --i)
{
// Collect result value
result[index] = i;
this.findCombination(result, index + 1, sum + i, x, i);
}
}
// Handles the request of find combination of given n and x
public void combination(int x, int n)
{
if (n <= 0 || x <= 0)
{
return;
}
Console.WriteLine("\n Given n : " + n + " x : " + x);
// Collect result
int[] result = new int[x];
// Test
this.findCombination(result, 0, 0, x, n);
}
public static void Main(String[] args)
{
SumCombination task = new SumCombination();
// Test A
// n = 3 means use [1,2,3]
int n = 3;
// Sum x = 10
int x = 10;
task.combination(x, n);
// Test B
// n = 4 means use [1,2,3,4]
n = 4;
// Sum x = 12
x = 12;
task.combination(x, n);
}
}
Output
Given n : 3 x : 10
3 3 3 1
3 3 2 2
3 3 2 1 1
3 3 1 1 1 1
3 2 2 2 1
3 2 2 1 1 1
3 2 1 1 1 1 1
3 1 1 1 1 1 1 1
2 2 2 2 2
2 2 2 2 1 1
2 2 2 1 1 1 1
2 2 1 1 1 1 1 1
2 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1
Given n : 4 x : 12
4 4 4
4 4 3 1
4 4 2 2
4 4 2 1 1
4 4 1 1 1 1
4 3 3 2
4 3 3 1 1
4 3 2 2 1
4 3 2 1 1 1
4 3 1 1 1 1 1
4 2 2 2 2
4 2 2 2 1 1
4 2 2 1 1 1 1
4 2 1 1 1 1 1 1
4 1 1 1 1 1 1 1 1
3 3 3 3
3 3 3 2 1
3 3 3 1 1 1
3 3 2 2 2
3 3 2 2 1 1
3 3 2 1 1 1 1
3 3 1 1 1 1 1 1
3 2 2 2 2 1
3 2 2 2 1 1 1
3 2 2 1 1 1 1 1
3 2 1 1 1 1 1 1 1
3 1 1 1 1 1 1 1 1 1
2 2 2 2 2 2
2 2 2 2 2 1 1
2 2 2 2 1 1 1 1
2 2 2 1 1 1 1 1 1
2 2 1 1 1 1 1 1 1 1
2 1 1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1 1 1
<?php
// Php Program for
// Print all distinct combinations of sum x and n natural number
class SumCombination
{
// Display result
public function printSequence($result, $k)
{
for ($i = 0; $i < $k; ++$i)
{
echo(" ".$result[$i]);
}
echo("\n");
}
public function findCombination($result, $index, $sum, $x, $n)
{
if ($sum == $x)
{
// Display calculated result
$this->printSequence($result, $index);
return;
}
if ($sum > $x || $index >= $x)
{
// Base case when stop process
return;
}
for ($i = $n; $i >= 1; --$i)
{
// Collect result value
$result[$index] = $i;
$this->findCombination($result, $index + 1, $sum + $i, $x, $i);
}
}
// Handles the request of find combination of given n and x
public function combination($x, $n)
{
if ($n <= 0 || $x <= 0)
{
return;
}
echo("\n Given n : ".$n.
" x : ".$x.
"\n");
// Collect result
$result = array_fill(0, $x, 0);
// Test
$this->findCombination($result, 0, 0, $x, $n);
}
}
function main()
{
$task = new SumCombination();
// Test A
// n = 3 means use [1,2,3]
$n = 3;
// Sum x = 10
$x = 10;
$task->combination($x, $n);
// Test B
// n = 4 means use [1,2,3,4]
$n = 4;
// Sum x = 12
$x = 12;
$task->combination($x, $n);
}
main();
Output
Given n : 3 x : 10
3 3 3 1
3 3 2 2
3 3 2 1 1
3 3 1 1 1 1
3 2 2 2 1
3 2 2 1 1 1
3 2 1 1 1 1 1
3 1 1 1 1 1 1 1
2 2 2 2 2
2 2 2 2 1 1
2 2 2 1 1 1 1
2 2 1 1 1 1 1 1
2 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1
Given n : 4 x : 12
4 4 4
4 4 3 1
4 4 2 2
4 4 2 1 1
4 4 1 1 1 1
4 3 3 2
4 3 3 1 1
4 3 2 2 1
4 3 2 1 1 1
4 3 1 1 1 1 1
4 2 2 2 2
4 2 2 2 1 1
4 2 2 1 1 1 1
4 2 1 1 1 1 1 1
4 1 1 1 1 1 1 1 1
3 3 3 3
3 3 3 2 1
3 3 3 1 1 1
3 3 2 2 2
3 3 2 2 1 1
3 3 2 1 1 1 1
3 3 1 1 1 1 1 1
3 2 2 2 2 1
3 2 2 2 1 1 1
3 2 2 1 1 1 1 1
3 2 1 1 1 1 1 1 1
3 1 1 1 1 1 1 1 1 1
2 2 2 2 2 2
2 2 2 2 2 1 1
2 2 2 2 1 1 1 1
2 2 2 1 1 1 1 1 1
2 2 1 1 1 1 1 1 1 1
2 1 1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1 1 1
// Node JS Program for
// Print all distinct combinations of sum x and n natural number
class SumCombination
{
// Display result
printSequence(result, k)
{
for (var i = 0; i < k; ++i)
{
process.stdout.write(" " + result[i]);
}
process.stdout.write("\n");
}
findCombination(result, index, sum, x, n)
{
if (sum == x)
{
// Display calculated result
this.printSequence(result, index);
return;
}
if (sum > x || index >= x)
{
// Base case when stop process
return;
}
for (var i = n; i >= 1; --i)
{
// Collect result value
result[index] = i;
this.findCombination(result, index + 1, sum + i, x, i);
}
}
// Handles the request of find combination of given n and x
combination(x, n)
{
if (n <= 0 || x <= 0)
{
return;
}
console.log("\n Given n : " + n + " x : " + x);
// Collect result
var result = Array(x).fill(0);
// Test
this.findCombination(result, 0, 0, x, n);
}
}
function main()
{
var task = new SumCombination();
// Test A
// n = 3 means use [1,2,3]
var n = 3;
// Sum x = 10
var x = 10;
task.combination(x, n);
// Test B
// n = 4 means use [1,2,3,4]
n = 4;
// Sum x = 12
x = 12;
task.combination(x, n);
}
main();
Output
Given n : 3 x : 10
3 3 3 1
3 3 2 2
3 3 2 1 1
3 3 1 1 1 1
3 2 2 2 1
3 2 2 1 1 1
3 2 1 1 1 1 1
3 1 1 1 1 1 1 1
2 2 2 2 2
2 2 2 2 1 1
2 2 2 1 1 1 1
2 2 1 1 1 1 1 1
2 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1
Given n : 4 x : 12
4 4 4
4 4 3 1
4 4 2 2
4 4 2 1 1
4 4 1 1 1 1
4 3 3 2
4 3 3 1 1
4 3 2 2 1
4 3 2 1 1 1
4 3 1 1 1 1 1
4 2 2 2 2
4 2 2 2 1 1
4 2 2 1 1 1 1
4 2 1 1 1 1 1 1
4 1 1 1 1 1 1 1 1
3 3 3 3
3 3 3 2 1
3 3 3 1 1 1
3 3 2 2 2
3 3 2 2 1 1
3 3 2 1 1 1 1
3 3 1 1 1 1 1 1
3 2 2 2 2 1
3 2 2 2 1 1 1
3 2 2 1 1 1 1 1
3 2 1 1 1 1 1 1 1
3 1 1 1 1 1 1 1 1 1
2 2 2 2 2 2
2 2 2 2 2 1 1
2 2 2 2 1 1 1 1
2 2 2 1 1 1 1 1 1
2 2 1 1 1 1 1 1 1 1
2 1 1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1 1 1
# Python 3 Program for
# Print all distinct combinations of sum x and n natural number
class SumCombination :
# Display result
def printSequence(self, result, k) :
i = 0
while (i < k) :
print(" ", result[i], end = "")
i += 1
print(end = "\n")
def findCombination(self, result, index, sum, x, n) :
if (sum == x) :
# Display calculated result
self.printSequence(result, index)
return
if (sum > x or index >= x) :
# Base case when stop process
return
i = n
while (i >= 1) :
# Collect result value
result[index] = i
self.findCombination(result, index + 1, sum + i, x, i)
i -= 1
# Handles the request of find combination of given n and x
def combination(self, x, n) :
if (n <= 0 or x <= 0) :
return
print("\n Given n : ", n ," x : ", x)
# Collect result
result = [0] * (x)
# Test
self.findCombination(result, 0, 0, x, n)
def main() :
task = SumCombination()
# Test A
# n = 3 means use [1,2,3]
n = 3
# Sum x = 10
x = 10
task.combination(x, n)
# Test B
# n = 4 means use [1,2,3,4]
n = 4
# Sum x = 12
x = 12
task.combination(x, n)
if __name__ == "__main__": main()
Output
Given n : 3 x : 10
3 3 3 1
3 3 2 2
3 3 2 1 1
3 3 1 1 1 1
3 2 2 2 1
3 2 2 1 1 1
3 2 1 1 1 1 1
3 1 1 1 1 1 1 1
2 2 2 2 2
2 2 2 2 1 1
2 2 2 1 1 1 1
2 2 1 1 1 1 1 1
2 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1
Given n : 4 x : 12
4 4 4
4 4 3 1
4 4 2 2
4 4 2 1 1
4 4 1 1 1 1
4 3 3 2
4 3 3 1 1
4 3 2 2 1
4 3 2 1 1 1
4 3 1 1 1 1 1
4 2 2 2 2
4 2 2 2 1 1
4 2 2 1 1 1 1
4 2 1 1 1 1 1 1
4 1 1 1 1 1 1 1 1
3 3 3 3
3 3 3 2 1
3 3 3 1 1 1
3 3 2 2 2
3 3 2 2 1 1
3 3 2 1 1 1 1
3 3 1 1 1 1 1 1
3 2 2 2 2 1
3 2 2 2 1 1 1
3 2 2 1 1 1 1 1
3 2 1 1 1 1 1 1 1
3 1 1 1 1 1 1 1 1 1
2 2 2 2 2 2
2 2 2 2 2 1 1
2 2 2 2 1 1 1 1
2 2 2 1 1 1 1 1 1
2 2 1 1 1 1 1 1 1 1
2 1 1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1 1 1
# Ruby Program for
# Print all distinct combinations of sum x and n natural number
class SumCombination
# Display result
def printSequence(result, k)
i = 0
while (i < k)
print(" ", result[i])
i += 1
end
print("\n")
end
def findCombination(result, index, sum, x, n)
if (sum == x)
# Display calculated result
self.printSequence(result, index)
return
end
if (sum > x || index >= x)
# Base case when stop process
return
end
i = n
while (i >= 1)
# Collect result value
result[index] = i
self.findCombination(result, index + 1, sum + i, x, i)
i -= 1
end
end
# Handles the request of find combination of given n and x
def combination(x, n)
if (n <= 0 || x <= 0)
return
end
print("\n Given n : ", n ," x : ", x, "\n")
# Collect result
result = Array.new(x) {0}
# Test
self.findCombination(result, 0, 0, x, n)
end
end
def main()
task = SumCombination.new()
# Test A
# n = 3 means use [1,2,3]
n = 3
# Sum x = 10
x = 10
task.combination(x, n)
# Test B
# n = 4 means use [1,2,3,4]
n = 4
# Sum x = 12
x = 12
task.combination(x, n)
end
main()
Output
Given n : 3 x : 10
3 3 3 1
3 3 2 2
3 3 2 1 1
3 3 1 1 1 1
3 2 2 2 1
3 2 2 1 1 1
3 2 1 1 1 1 1
3 1 1 1 1 1 1 1
2 2 2 2 2
2 2 2 2 1 1
2 2 2 1 1 1 1
2 2 1 1 1 1 1 1
2 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1
Given n : 4 x : 12
4 4 4
4 4 3 1
4 4 2 2
4 4 2 1 1
4 4 1 1 1 1
4 3 3 2
4 3 3 1 1
4 3 2 2 1
4 3 2 1 1 1
4 3 1 1 1 1 1
4 2 2 2 2
4 2 2 2 1 1
4 2 2 1 1 1 1
4 2 1 1 1 1 1 1
4 1 1 1 1 1 1 1 1
3 3 3 3
3 3 3 2 1
3 3 3 1 1 1
3 3 2 2 2
3 3 2 2 1 1
3 3 2 1 1 1 1
3 3 1 1 1 1 1 1
3 2 2 2 2 1
3 2 2 2 1 1 1
3 2 2 1 1 1 1 1
3 2 1 1 1 1 1 1 1
3 1 1 1 1 1 1 1 1 1
2 2 2 2 2 2
2 2 2 2 2 1 1
2 2 2 2 1 1 1 1
2 2 2 1 1 1 1 1 1
2 2 1 1 1 1 1 1 1 1
2 1 1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1 1 1
// Scala Program for
// Print all distinct combinations of sum x and n natural number
class SumCombination()
{
// Display result
def printSequence(result: Array[Int], k: Int): Unit = {
var i: Int = 0;
while (i < k)
{
print(" " + result(i));
i += 1;
}
print("\n");
}
def findCombination(result: Array[Int],
index: Int, sum: Int, x: Int, n: Int): Unit = {
if (sum == x)
{
// Display calculated result
printSequence(result, index);
return;
}
if (sum > x || index >= x)
{
// Base case when stop process
return;
}
var i: Int = n;
while (i >= 1)
{
// Collect result value
result(index) = i;
findCombination(result, index + 1, sum + i, x, i);
i -= 1;
}
}
// Handles the request of find combination of given n and x
def combination(x: Int, n: Int): Unit = {
if (n <= 0 || x <= 0)
{
return;
}
println("\n Given n : " + n + " x : " + x);
// Collect result
var result: Array[Int] = Array.fill[Int](x)(0);
// Test
findCombination(result, 0, 0, x, n);
}
}
object Main
{
def main(args: Array[String]): Unit = {
var task: SumCombination = new SumCombination();
// Test A
// n = 3 means use [1,2,3]
var n: Int = 3;
// Sum x = 10
var x: Int = 10;
task.combination(x, n);
// Test B
// n = 4 means use [1,2,3,4]
n = 4;
// Sum x = 12
x = 12;
task.combination(x, n);
}
}
Output
Given n : 3 x : 10
3 3 3 1
3 3 2 2
3 3 2 1 1
3 3 1 1 1 1
3 2 2 2 1
3 2 2 1 1 1
3 2 1 1 1 1 1
3 1 1 1 1 1 1 1
2 2 2 2 2
2 2 2 2 1 1
2 2 2 1 1 1 1
2 2 1 1 1 1 1 1
2 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1
Given n : 4 x : 12
4 4 4
4 4 3 1
4 4 2 2
4 4 2 1 1
4 4 1 1 1 1
4 3 3 2
4 3 3 1 1
4 3 2 2 1
4 3 2 1 1 1
4 3 1 1 1 1 1
4 2 2 2 2
4 2 2 2 1 1
4 2 2 1 1 1 1
4 2 1 1 1 1 1 1
4 1 1 1 1 1 1 1 1
3 3 3 3
3 3 3 2 1
3 3 3 1 1 1
3 3 2 2 2
3 3 2 2 1 1
3 3 2 1 1 1 1
3 3 1 1 1 1 1 1
3 2 2 2 2 1
3 2 2 2 1 1 1
3 2 2 1 1 1 1 1
3 2 1 1 1 1 1 1 1
3 1 1 1 1 1 1 1 1 1
2 2 2 2 2 2
2 2 2 2 2 1 1
2 2 2 2 1 1 1 1
2 2 2 1 1 1 1 1 1
2 2 1 1 1 1 1 1 1 1
2 1 1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1 1 1
// Swift 4 Program for
// Print all distinct combinations of sum x and n natural number
class SumCombination
{
// Display result
func printSequence(_ result: [Int], _ k: Int)
{
var i: Int = 0;
while (i < k)
{
print(" ", result[i], terminator: "");
i += 1;
}
print(terminator: "\n");
}
func findCombination(_ result: inout[Int],
_ index: Int, _ sum: Int, _ x: Int, _ n: Int)
{
if (sum == x)
{
// Display calculated result
self.printSequence(result, index);
return;
}
if (sum > x || index >= x)
{
// Base case when stop process
return;
}
var i: Int = n;
while (i >= 1)
{
// Collect result value
result[index] = i;
self.findCombination(&result, index + 1, sum + i, x, i);
i -= 1;
}
}
// Handles the request of find combination of given n and x
func combination(_ x: Int, _ n: Int)
{
if (n <= 0 || x <= 0)
{
return;
}
print("\n Given n : ", n ," x : ", x);
// Collect result
var result: [Int] = Array(repeating: 0, count: x);
// Test
self.findCombination(&result, 0, 0, x, n);
}
}
func main()
{
let task: SumCombination = SumCombination();
// Test A
// n = 3 means use [1,2,3]
var n: Int = 3;
// Sum x = 10
var x: Int = 10;
task.combination(x, n);
// Test B
// n = 4 means use [1,2,3,4]
n = 4;
// Sum x = 12
x = 12;
task.combination(x, n);
}
main();
Output
Given n : 3 x : 10
3 3 3 1
3 3 2 2
3 3 2 1 1
3 3 1 1 1 1
3 2 2 2 1
3 2 2 1 1 1
3 2 1 1 1 1 1
3 1 1 1 1 1 1 1
2 2 2 2 2
2 2 2 2 1 1
2 2 2 1 1 1 1
2 2 1 1 1 1 1 1
2 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1
Given n : 4 x : 12
4 4 4
4 4 3 1
4 4 2 2
4 4 2 1 1
4 4 1 1 1 1
4 3 3 2
4 3 3 1 1
4 3 2 2 1
4 3 2 1 1 1
4 3 1 1 1 1 1
4 2 2 2 2
4 2 2 2 1 1
4 2 2 1 1 1 1
4 2 1 1 1 1 1 1
4 1 1 1 1 1 1 1 1
3 3 3 3
3 3 3 2 1
3 3 3 1 1 1
3 3 2 2 2
3 3 2 2 1 1
3 3 2 1 1 1 1
3 3 1 1 1 1 1 1
3 2 2 2 2 1
3 2 2 2 1 1 1
3 2 2 1 1 1 1 1
3 2 1 1 1 1 1 1 1
3 1 1 1 1 1 1 1 1 1
2 2 2 2 2 2
2 2 2 2 2 1 1
2 2 2 2 1 1 1 1
2 2 2 1 1 1 1 1 1
2 2 1 1 1 1 1 1 1 1
2 1 1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1 1 1
// Kotlin Program for
// Print all distinct combinations of sum x and n natural number
class SumCombination
{
// Display result
fun printSequence(result: Array < Int > , k: Int): Unit
{
var i: Int = 0;
while (i < k)
{
print(" " + result[i]);
i += 1;
}
print("\n");
}
fun findCombination(result: Array < Int > ,
index: Int, sum: Int,
x: Int, n: Int): Unit
{
if (sum == x)
{
// Display calculated result
this.printSequence(result, index);
return;
}
if (sum > x || index >= x)
{
// Base case when stop process
return;
}
var i: Int = n;
while (i >= 1)
{
// Collect result value
result[index] = i;
this.findCombination(result, index + 1, sum + i, x, i);
i -= 1;
}
}
// Handles the request of find combination of given n and x
fun combination(x: Int, n: Int): Unit
{
if (n <= 0 || x <= 0)
{
return;
}
println("\n Given n : " + n + " x : " + x);
// Collect result
val result: Array < Int > = Array(x)
{
0
};
// Test
this.findCombination(result, 0, 0, x, n);
}
}
fun main(args: Array < String > ): Unit
{
val task: SumCombination = SumCombination();
// Test A
// n = 3 means use [1,2,3]
var n: Int = 3;
// Sum x = 10
var x: Int = 10;
task.combination(x, n);
// Test B
// n = 4 means use [1,2,3,4]
n = 4;
// Sum x = 12
x = 12;
task.combination(x, n);
}
Output
Given n : 3 x : 10
3 3 3 1
3 3 2 2
3 3 2 1 1
3 3 1 1 1 1
3 2 2 2 1
3 2 2 1 1 1
3 2 1 1 1 1 1
3 1 1 1 1 1 1 1
2 2 2 2 2
2 2 2 2 1 1
2 2 2 1 1 1 1
2 2 1 1 1 1 1 1
2 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1
Given n : 4 x : 12
4 4 4
4 4 3 1
4 4 2 2
4 4 2 1 1
4 4 1 1 1 1
4 3 3 2
4 3 3 1 1
4 3 2 2 1
4 3 2 1 1 1
4 3 1 1 1 1 1
4 2 2 2 2
4 2 2 2 1 1
4 2 2 1 1 1 1
4 2 1 1 1 1 1 1
4 1 1 1 1 1 1 1 1
3 3 3 3
3 3 3 2 1
3 3 3 1 1 1
3 3 2 2 2
3 3 2 2 1 1
3 3 2 1 1 1 1
3 3 1 1 1 1 1 1
3 2 2 2 2 1
3 2 2 2 1 1 1
3 2 2 1 1 1 1 1
3 2 1 1 1 1 1 1 1
3 1 1 1 1 1 1 1 1 1
2 2 2 2 2 2
2 2 2 2 2 1 1
2 2 2 2 1 1 1 1
2 2 2 1 1 1 1 1 1
2 2 1 1 1 1 1 1 1 1
2 1 1 1 1 1 1 1 1 1 1
1 1 1 1 1 1 1 1 1 1 1 1
Please share your knowledge to improve code and content standard. Also submit your doubts, and test case. We improve by your feedback. We will try to resolve your query as soon as possible.
New Comment