Move all negative elements to end in kotlin

Kotlin program for Move all negative elements to end. Here mentioned other language solution.

// Kotlin program for
// Move all negative elements at the end of array
class MyArray
{
	// Display array elements
	fun display(arr: Array < Int > , n: Int): Unit
	{
		var i: Int = 0;
		while (i < n)
		{
			print("  " + arr[i]);
			i += 1;
		}
		println();
	}
	// Swap the given array elements
	fun swap(arr: Array < Int > , start: Int, end: Int): Unit
	{
		val temp: Int = arr[start];
		arr[start] = arr[end];
		arr[end] = temp;
	}
	// Method which is move negative elements
	fun moveNegative(arr: Array < Int > , n: Int): Unit
	{
		// first index
		var i: Int = 0;
		// last index
		var j: Int = n - 1;
		while (i < j)
		{
			if (arr[i] < 0 && arr[j] >= 0)
			{
				// When [i] index are have negative value 
				// And [j] is positive then swapping elements values
				this.swap(arr, i, j);
				// Modified index
				i += 1;
				j -= 1;
			}
			else if (arr[i] >= 0)
			{
				// When element of [i] is not negative
				i += 1;
			}
			else
			{
				j -= 1;
			}
		}
	}
}
fun main(args: Array < String > ): Unit
{
	val task: MyArray = MyArray();
	// Array which are containing positive and negative values
	var arr: Array < Int > = arrayOf(1, -1, 3, 2, -7, -5, 11, 6);
	val n: Int = arr.count();
	println("Before Arrange : ");
	// Before move element
	task.display(arr, n);
	// Move negative elements
	task.moveNegative(arr, n);
	// After arrange
	println("After Arrange : ");
	// After move element
	task.display(arr, n);
}

Output

Before Arrange :
  1  -1  3  2  -7  -5  11  6
After Arrange :
  1  6  3  2  11  -5  -7  -1