Minimum number of deletion required to make two strings anagram
Here given code implementation process.
// Include header file
#include <iostream>
#include <string>
#include <unordered_map>
using namespace std;
/*
C++ program for
Minimum number of deletion required to make two strings anagram
*/
class Anagrams
{
public: void countFrequency(string str, unordered_map < char, int > &record)
{
int n = str.length();
// Calculate frequency of given string
for (int i = 0; i < n; ++i)
{
if (record.find(str[i]) != record.end())
{
record[str[i]] = record[str[i]] + 1;
}
else
{
record[str[i]] = 1;
}
}
}
void makeAnagram(string str1, string str2)
{
int operation = 0;
unordered_map < char, int > record1;
unordered_map < char, int > record2;
// Count frequency of given string
this->countFrequency(str1, record1);
this->countFrequency(str2, record2);
int k1 = 0;
int k2 = 0;
// Compare same frequency in both string
for (auto &info: record1)
{
if (record2.find(info.first) != record2.end())
{
k1 = info.second;
k2 = record2[info.first];
if (k1 > k2)
{
operation += k1 - k2;
}
else if (k2 > k1)
{
operation += k2 - k1;
}
// Reset frequency value
record1[info.first] = 0;
record2[info.first] = 0;
}
}
// Add number of extra characters in str1
for (auto &info: record1)
{
operation += info.second;
}
// Add number of extra characters in str2
for (auto &info: record2)
{
operation += info.second;
}
cout << " Given (" << str1 << "),(" << str2 << ")" << endl;
// Display number of remove operation to make anagram
cout << " Result : " << operation << endl;
}
};
int main()
{
Anagrams *task = new Anagrams();
/*
Case A
------
k m e t e o r o i l , r e m f i l l o t e
↓ ↓ ↓ ↓
① ② ③ ④
------------------------------------------------
Remove 4 characters to make both string is anagram
*/
task->makeAnagram("kmeteoroil", "remfillote");
/*
Case B
------
C S I T W I N , W S O I C N L P
↓ ↓ ↓ ↓ ↓
① ② ③ ④ ⑤
----------------------------------------------
Remove 5 characters to make both string is anagram
*/
task->makeAnagram("CSITWIN", "WSOICNLP");
/*
Case C
------
Both string is anagram
*/
task->makeAnagram("123", "321");
return 0;
}
Output
Given (kmeteoroil),(remfillote)
Result : 4
Given (CSITWIN),(WSOICNLP)
Result : 5
Given (123),(321)
Result : 0
import java.util.HashMap;
/*
Java program for
Minimum number of deletion required to make two strings anagram
*/
public class Anagrams
{
public void countFrequency(String str, HashMap < Character, Integer > record)
{
int n = str.length();
// Calculate frequency of given string
for (int i = 0; i < n; ++i)
{
if (record.containsKey(str.charAt(i)))
{
record.put(str.charAt(i), record.get(str.charAt(i)) + 1);
}
else
{
record.put(str.charAt(i), 1);
}
}
}
public void makeAnagram(String str1, String str2)
{
int operation = 0;
HashMap < Character, Integer > record1 = new HashMap < Character, Integer > ();
HashMap < Character, Integer > record2 = new HashMap < Character, Integer > ();
// Count frequency of given string
countFrequency(str1, record1);
countFrequency(str2, record2);
int k1 = 0;
int k2 = 0;
// Compare same frequency in both string
for (char info: record1.keySet())
{
if (record2.containsKey(info))
{
k1 = record1.get(info);
k2 = record2.get(info);
if (k1 > k2)
{
operation += k1 - k2;
}
else if (k2 > k1)
{
operation += k2 - k1;
}
// Reset frequency value
record1.put(info, 0);
record2.put(info, 0);
}
}
// Add number of extra characters in str1
for (char info: record1.keySet())
{
operation += record1.get(info);
}
// Add number of extra characters in str2
for (char info: record2.keySet())
{
operation += record2.get(info);
}
System.out.println(" Given (" + str1 + "),(" + str2 + ")");
// Display number of remove operation to make anagram
System.out.println(" Result : " + operation);
}
public static void main(String[] args)
{
Anagrams task = new Anagrams();
/*
Case A
------
k m e t e o r o i l , r e m f i l l o t e
↓ ↓ ↓ ↓
① ② ③ ④
------------------------------------------------
Remove 4 characters to make both string is anagram
*/
task.makeAnagram("kmeteoroil", "remfillote");
/*
Case B
------
C S I T W I N , W S O I C N L P
↓ ↓ ↓ ↓ ↓
① ② ③ ④ ⑤
----------------------------------------------
Remove 5 characters to make both string is anagram
*/
task.makeAnagram("CSITWIN", "WSOICNLP");
/*
Case C
------
Both string is anagram
*/
task.makeAnagram("123", "321");
}
}
Output
Given (kmeteoroil),(remfillote)
Result : 4
Given (CSITWIN),(WSOICNLP)
Result : 5
Given (123),(321)
Result : 0
// Include namespace system
using System;
using System.Collections.Generic;
/*
Csharp program for
Minimum number of deletion required to make two strings anagram
*/
public class Anagrams
{
public void countFrequency(String str, Dictionary < char, int > record)
{
int n = str.Length;
// Calculate frequency of given string
for (int i = 0; i < n; ++i)
{
if (record.ContainsKey(str[i]))
{
record[str[i]] = record[str[i]] + 1;
}
else
{
record.Add(str[i], 1);
}
}
}
public void makeAnagram(String str1, String str2)
{
int operation = 0;
Dictionary < char, int > record1 =
new Dictionary < char, int > ();
Dictionary < char, int > record2 =
new Dictionary < char, int > ();
// Count frequency of given string
this.countFrequency(str1, record1);
this.countFrequency(str2, record2);
int k1 = 0;
int k2 = 0;
List<char> keys = new List<char>(record1.Keys);
// Compare same frequency in both string
foreach(char key in keys)
{
if (record2.ContainsKey(key))
{
k1 = record1[key];
k2 = record2[key];
if (k1 > k2)
{
operation += k1 - k2;
}
else if (k2 > k1)
{
operation += k2 - k1;
}
// Reset frequency value
record1[key] = 0;
record2[key] = 0;
}
}
// Add number of extra characters in str1
foreach(KeyValuePair < char, int > info in record1)
{
operation += info.Value;
}
// Add number of extra characters in str2
foreach(KeyValuePair < char, int > info in record2)
{
operation += info.Value;
}
Console.WriteLine(" Given (" + str1 + "),(" + str2 + ")");
// Display number of remove operation to make anagram
Console.WriteLine(" Result : " + operation);
}
public static void Main(String[] args)
{
Anagrams task = new Anagrams();
/*
Case A
------
k m e t e o r o i l , r e m f i l l o t e
↓ ↓ ↓ ↓
① ② ③ ④
------------------------------------------------
Remove 4 characters to make both string is anagram
*/
task.makeAnagram("kmeteoroil", "remfillote");
/*
Case B
------
C S I T W I N , W S O I C N L P
↓ ↓ ↓ ↓ ↓
① ② ③ ④ ⑤
----------------------------------------------
Remove 5 characters to make both string is anagram
*/
task.makeAnagram("CSITWIN", "WSOICNLP");
/*
Case C
------
Both string is anagram
*/
task.makeAnagram("123", "321");
}
}
Output
Given (kmeteoroil),(remfillote)
Result : 4
Given (CSITWIN),(WSOICNLP)
Result : 5
Given (123),(321)
Result : 0
package main
import "fmt"
/*
Go program for
Minimum number of deletion required to make two strings anagram
*/
func countFrequency(str string, record map[byte]int) {
var n int = len(str)
// Calculate frequency of given string
for i := 0 ; i < n ; i++ {
if _, found := record[str[i]] ; found {
record[str[i]] = record[str[i]] + 1
} else {
record[str[i]] = 1
}
}
}
func makeAnagram(str1, str2 string) {
var operation int = 0
var record1 = make(map[byte] int)
var record2 = make(map[byte] int)
// Count frequency of given string
countFrequency(str1, record1)
countFrequency(str2, record2)
var k1 int = 0
var k2 int = 0
// Compare same frequency in both string
for k, v := range record1 {
if _, found := record2[k] ; found {
k1 = v
k2 = record2[k]
if k1 > k2 {
operation += k1 - k2
} else if k2 > k1 {
operation += k2 - k1
}
// Reset frequency value
record1[k] = 0
record2[k] = 0
}
}
// Add number of extra characters in str1
for _, v := range record1 {
operation += v
}
// Add number of extra characters in str2
for _, v := range record2 {
operation += v
}
fmt.Println(" Given (", str1, "),(", str2, ")")
// Display number of remove operation to make anagram
fmt.Println(" Result : ", operation)
}
func main() {
/*
Case A
------
k m e t e o r o i l , r e m f i l l o t e
↓ ↓ ↓ ↓
① ② ③ ④
------------------------------------------------
Remove 4 characters to make both string is anagram
*/
makeAnagram("kmeteoroil", "remfillote")
/*
Case B
------
C S I T W I N , W S O I C N L P
↓ ↓ ↓ ↓ ↓
① ② ③ ④ ⑤
----------------------------------------------
Remove 5 characters to make both string is anagram
*/
makeAnagram("CSITWIN", "WSOICNLP")
/*
Case C
------
Both string is anagram
*/
makeAnagram("123", "321")
}
Output
Given (kmeteoroil),(remfillote)
Result : 4
Given (CSITWIN),(WSOICNLP)
Result : 5
Given (123),(321)
Result : 0
<?php
/*
Php program for
Minimum number of deletion required to make two strings anagram
*/
class Anagrams
{
public function countFrequency($str, &$record)
{
$n = strlen($str);
// Calculate frequency of given string
for ($i = 0; $i < $n; ++$i)
{
if (array_key_exists($str[$i], $record))
{
$record[$str[$i]] = $record[$str[$i]] + 1;
}
else
{
$record[$str[$i]] = 1;
}
}
}
public function makeAnagram($str1, $str2)
{
$operation = 0;
$record1 = array();
$record2 = array();
// Count frequency of given string
$this->countFrequency($str1, $record1);
$this->countFrequency($str2, $record2);
$k1 = 0;
$k2 = 0;
// Compare same frequency in both string
foreach($record1 as $key => $value)
{
if (array_key_exists($key, $record2))
{
$k1 = $record1[$key];
$k2 = $record2[$key];
if ($k1 > $k2)
{
$operation += $k1 - $k2;
}
else if ($k2 > $k1)
{
$operation += $k2 - $k1;
}
// Reset frequency value
$record1[$key] = 0;
$record2[$key] = 0;
}
}
// Add number of extra characters in str1
foreach($record1 as $key => $value)
{
$operation += $value;
}
// Add number of extra characters in str2
foreach($record2 as $key => $value)
{
$operation += $value;
}
echo(" Given (".$str1."),(".$str2.")\n");
// Display number of remove operation to make anagram
echo(" Result : ".$operation."\n");
}
}
function main()
{
$task = new Anagrams();
/*
Case A
------
k m e t e o r o i l , r e m f i l l o t e
↓ ↓ ↓ ↓
① ② ③ ④
------------------------------------------------
Remove 4 characters to make both string is anagram
*/
$task->makeAnagram("kmeteoroil", "remfillote");
/*
Case B
------
C S I T W I N , W S O I C N L P
↓ ↓ ↓ ↓ ↓
① ② ③ ④ ⑤
----------------------------------------------
Remove 5 characters to make both string is anagram
*/
$task->makeAnagram("CSITWIN", "WSOICNLP");
/*
Case C
------
Both string is anagram
*/
$task->makeAnagram("123", "321");
}
main();
Output
Given (kmeteoroil),(remfillote)
Result : 4
Given (CSITWIN),(WSOICNLP)
Result : 5
Given (123),(321)
Result : 0
/*
Node JS program for
Minimum number of deletion required to make two strings anagram
*/
class Anagrams
{
countFrequency(str, record)
{
var n = str.length;
// Calculate frequency of given string
for (var i = 0; i < n; ++i)
{
if (record.has(str.charAt(i)))
{
record.set(str.charAt(i), record.get(str.charAt(i)) + 1);
}
else
{
record.set(str.charAt(i), 1);
}
}
}
makeAnagram(str1, str2)
{
var operation = 0;
var record1 = new Map();
var record2 = new Map();
// Count frequency of given string
this.countFrequency(str1, record1);
this.countFrequency(str2, record2);
var k1 = 0;
var k2 = 0;
// Compare same frequency in both string
for (let [key, value] of record1)
{
if (record2.has(key))
{
k1 = value;
k2 = record2.get(key);
if (k1 > k2)
{
operation += k1 - k2;
}
else if (k2 > k1)
{
operation += k2 - k1;
}
// Reset frequency value
record1.set(key, 0);
record2.set(key, 0);
}
}
// Add number of extra characters in str1
for (let [key, value] of record1)
{
operation += value;
}
// Add number of extra characters in str2
for (let [key, value] of record2)
{
operation += value;
}
console.log(" Given (" + str1 + "),(" + str2 + ")");
// Display number of remove operation to make anagram
console.log(" Result : " + operation);
}
}
function main()
{
var task = new Anagrams();
/*
Case A
------
k m e t e o r o i l , r e m f i l l o t e
↓ ↓ ↓ ↓
① ② ③ ④
------------------------------------------------
Remove 4 characters to make both string is anagram
*/
task.makeAnagram("kmeteoroil", "remfillote");
/*
Case B
------
C S I T W I N , W S O I C N L P
↓ ↓ ↓ ↓ ↓
① ② ③ ④ ⑤
----------------------------------------------
Remove 5 characters to make both string is anagram
*/
task.makeAnagram("CSITWIN", "WSOICNLP");
/*
Case C
------
Both string is anagram
*/
task.makeAnagram("123", "321");
}
main();
Output
Given (kmeteoroil),(remfillote)
Result : 4
Given (CSITWIN),(WSOICNLP)
Result : 5
Given (123),(321)
Result : 0
# Python 3 program for
# Minimum number of deletion required to make two strings anagram
class Anagrams :
def countFrequency(self, str, record) :
n = len(str)
i = 0
# Calculate frequency of given string
while (i < n) :
if ((str[i] in record.keys())) :
record[str[i]] = record.get(str[i]) + 1
else :
record[str[i]] = 1
i += 1
def makeAnagram(self, str1, str2) :
operation = 0
record1 = dict()
record2 = dict()
# Count frequency of given string
self.countFrequency(str1, record1)
self.countFrequency(str2, record2)
k1 = 0
k2 = 0
for key, value in record1.items() :
if ((key in record2.keys())) :
k1 = value
k2 = record2.get(key)
if (k1 > k2) :
operation += k1 - k2
elif (k2 > k1) :
operation += k2 - k1
# Reset frequency value
record1[key] = 0
record2[key] = 0
for key, value in record1.items() :
operation += value
for key, value in record2.items() :
operation += value
print(" Given (", str1 ,"),(", str2 ,")",sep="")
# Display number of remove operation to make anagram
print(" Result : ", operation)
def main() :
task = Anagrams()
# Case A
# ------
# k m e t e o r o i l , r e m f i l l o t e
# ↓ ↓ ↓ ↓
# ① ② ③ ④
# ------------------------------------------------
# Remove 4 characters to make both string is anagram
task.makeAnagram("kmeteoroil", "remfillote")
# Case B
# ------
# C S I T W I N , W S O I C N L P
# ↓ ↓ ↓ ↓ ↓
# ① ② ③ ④ ⑤
# ----------------------------------------------
# Remove 5 characters to make both string is anagram
task.makeAnagram("CSITWIN", "WSOICNLP")
# Case C
# ------
# Both string is anagram
task.makeAnagram("123", "321")
if __name__ == "__main__": main()
Output
Given (kmeteoroil),(remfillote)
Result : 4
Given (CSITWIN),(WSOICNLP)
Result : 5
Given (123),(321)
Result : 0
# Ruby program for
# Minimum number of deletion required to make two strings anagram
class Anagrams
def countFrequency(str, record)
n = str.length
i = 0
# Calculate frequency of given string
while (i < n)
if (record.key?(str[i]))
record[str[i]] = record[str[i]] + 1
else
record[str[i]] = 1
end
i += 1
end
end
def makeAnagram(str1, str2)
operation = 0
record1 = Hash.new()
record2 = Hash.new()
# Count frequency of given string
self.countFrequency(str1, record1)
self.countFrequency(str2, record2)
k1 = 0
k2 = 0
# Compare same frequency in both string
record1.each { | key, value |
if (record2.key?(key))
k1 = record1[key]
k2 = record2[key]
if (k1 > k2)
operation += k1 - k2
elsif (k2 > k1)
operation += k2 - k1
end
# Reset frequency value
record1[key] = 0
record2[key] = 0
end
}
# Add number of extra characters in str1
record1.each { | key, value | operation += value}
# Add number of extra characters in str2
record2.each { | key, value | operation += value }
print(" Given (", str1 ,"),(", str2 ,")", "\n")
# Display number of remove operation to make anagram
print(" Result : ", operation, "\n")
end
end
def main()
task = Anagrams.new()
# Case A
# ------
# k m e t e o r o i l , r e m f i l l o t e
# ↓ ↓ ↓ ↓
# ① ② ③ ④
# ------------------------------------------------
# Remove 4 characters to make both string is anagram
task.makeAnagram("kmeteoroil", "remfillote")
# Case B
# ------
# C S I T W I N , W S O I C N L P
# ↓ ↓ ↓ ↓ ↓
# ① ② ③ ④ ⑤
# ----------------------------------------------
# Remove 5 characters to make both string is anagram
task.makeAnagram("CSITWIN", "WSOICNLP")
# Case C
# ------
# Both string is anagram
task.makeAnagram("123", "321")
end
main()
Output
Given (kmeteoroil),(remfillote)
Result : 4
Given (CSITWIN),(WSOICNLP)
Result : 5
Given (123),(321)
Result : 0
import scala.collection.mutable._;
/*
Scala program for
Minimum number of deletion required to make two strings anagram
*/
class Anagrams()
{
def countFrequency(str: String,
record: Map[Character, Int]): Unit = {
var n: Int = str.length();
var i: Int = 0;
// Calculate frequency of given string
while (i < n)
{
if (record.contains(str.charAt(i)))
{
record.addOne(str.charAt(i),
record.get(str.charAt(i)).get + 1);
}
else
{
record.addOne(str.charAt(i), 1);
}
i += 1;
}
}
def makeAnagram(str1: String, str2: String): Unit = {
var operation: Int = 0;
var record1: Map[Character, Int] = Map();
var record2: Map[Character, Int] = Map();
// Count frequency of given string
countFrequency(str1, record1);
countFrequency(str2, record2);
var k1: Int = 0;
var k2: Int = 0;
// Compare same frequency in both string
for ((key,value) <- record1)
{
if (record2.contains(key))
{
k1 = value;
k2 = record2.get(key).get;
if (k1 > k2)
{
operation += k1 - k2;
}
else if (k2 > k1)
{
operation += k2 - k1;
}
// Reset frequency value
record1.addOne(key, 0);
record2.addOne(key, 0);
}
}
// Add number of extra characters in str1
for ((key,value) <- record1)
{
operation += value;
}
// Add number of extra characters in str2
for ((key,value) <- record2)
{
operation += value;
}
println(" Given (" + str1 + "),(" + str2 + ")");
// Display number of remove operation to make anagram
println(" Result : " + operation);
}
}
object Main
{
def main(args: Array[String]): Unit = {
var task: Anagrams = new Anagrams();
/*
Case A
------
k m e t e o r o i l , r e m f i l l o t e
↓ ↓ ↓ ↓
① ② ③ ④
------------------------------------------------
Remove 4 characters to make both string is anagram
*/
task.makeAnagram("kmeteoroil", "remfillote");
/*
Case B
------
C S I T W I N , W S O I C N L P
↓ ↓ ↓ ↓ ↓
① ② ③ ④ ⑤
----------------------------------------------
Remove 5 characters to make both string is anagram
*/
task.makeAnagram("CSITWIN", "WSOICNLP");
/*
Case C
------
Both string is anagram
*/
task.makeAnagram("123", "321");
}
}
Output
Given (kmeteoroil),(remfillote)
Result : 4
Given (CSITWIN),(WSOICNLP)
Result : 5
Given (123),(321)
Result : 0
import Foundation;
/*
Swift 4 program for
Minimum number of deletion required to make two strings anagram
*/
class Anagrams
{
func countFrequency(_ str: [Character], _ record: inout[Character:Int])
{
let n: Int = str.count;
var i: Int = 0;
// Calculate frequency of given string
while (i < n)
{
if (record.keys.contains(str[i]))
{
record[str[i]] = record[str[i]]! + 1;
}
else
{
record[str[i]] = 1;
}
i += 1;
}
}
func makeAnagram(_ str1: String, _ str2: String)
{
var operation: Int = 0;
var record1 = [Character : Int]();
var record2 = [Character : Int]();
// Count frequency of given string
self.countFrequency(Array(str1), &record1);
self.countFrequency(Array(str2), &record2);
var k1: Int = 0;
var k2: Int = 0;
// Compare same frequency in both string
for (key, value) in record1
{
if (record2.keys.contains(key))
{
k1 = value;
k2 = record2[key]!;
if (k1 > k2)
{
operation += k1 - k2;
}
else if (k2 > k1)
{
operation += k2 - k1;
}
// Reset frequency value
record1[key] = 0;
record2[key] = 0;
}
}
// Add number of extra characters in str1
for (_, value) in record1
{
operation += value;
}
// Add number of extra characters in str2
for (_, value) in record2
{
operation += value;
}
print(" Given (", str1 ,"),(", str2 ,")");
// Display number of remove operation to make anagram
print(" Result : ", operation);
}
}
func main()
{
let task: Anagrams = Anagrams();
/*
Case A
------
k m e t e o r o i l , r e m f i l l o t e
↓ ↓ ↓ ↓
① ② ③ ④
------------------------------------------------
Remove 4 characters to make both string is anagram
*/
task.makeAnagram("kmeteoroil", "remfillote");
/*
Case B
------
C S I T W I N , W S O I C N L P
↓ ↓ ↓ ↓ ↓
① ② ③ ④ ⑤
----------------------------------------------
Remove 5 characters to make both string is anagram
*/
task.makeAnagram("CSITWIN", "WSOICNLP");
/*
Case C
------
Both string is anagram
*/
task.makeAnagram("123", "321");
}
main();
Output
Given ( kmeteoroil ),( remfillote )
Result : 4
Given ( CSITWIN ),( WSOICNLP )
Result : 5
Given ( 123 ),( 321 )
Result : 0
/*
Kotlin program for
Minimum number of deletion required to make two strings anagram
*/
class Anagrams
{
fun countFrequency(str: String,
record: MutableMap <Char, Int > ): Unit
{
val n: Int = str.length;
var i: Int = 0;
// Calculate frequency of given string
while (i < n)
{
if (record.containsKey(str.get(i)))
{
record.put(str.get(i), record.getValue(str.get(i)) + 1);
}
else
{
record.put(str.get(i), 1);
}
i += 1;
}
}
fun makeAnagram(str1: String, str2: String): Unit
{
var operation: Int = 0;
var record1 = mutableMapOf<Char, Int>();
var record2 = mutableMapOf<Char, Int>();
// Count frequency of given string
this.countFrequency(str1, record1);
this.countFrequency(str2, record2);
var k1: Int ;
var k2: Int ;
// Compare same frequency in both string
for ((key, value) in record1)
{
if (record2.containsKey(key))
{
k1 = value;
k2 = record2.getValue(key);
if (k1 > k2)
{
operation += k1 - k2;
}
else if (k2 > k1)
{
operation += k2 - k1;
}
// Reset frequency value
record1.put(key, 0);
record2.put(key, 0);
}
}
// Add number of extra characters in str1
for ((_, value) in record1)
{
operation += value;
}
// Add number of extra characters in str2
for ((_, value) in record2)
{
operation += value;
}
println(" Given (" + str1 + "),(" + str2 + ")");
// Display number of remove operation to make anagram
println(" Result : " + operation);
}
}
fun main(args: Array < String > ): Unit
{
val task: Anagrams = Anagrams();
/*
Case A
------
k m e t e o r o i l , r e m f i l l o t e
↓ ↓ ↓ ↓
① ② ③ ④
------------------------------------------------
Remove 4 characters to make both string is anagram
*/
task.makeAnagram("kmeteoroil", "remfillote");
/*
Case B
------
C S I T W I N , W S O I C N L P
↓ ↓ ↓ ↓ ↓
① ② ③ ④ ⑤
----------------------------------------------
Remove 5 characters to make both string is anagram
*/
task.makeAnagram("CSITWIN", "WSOICNLP");
/*
Case C
------
Both string is anagram
*/
task.makeAnagram("123", "321");
}
Output
Given (kmeteoroil),(remfillote)
Result : 4
Given (CSITWIN),(WSOICNLP)
Result : 5
Given (123),(321)
Result : 0
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