Posted on by Kalkicode
Code Dynamic Programming

Maximum path sum in a triangle

Given a triangle of numbers, find the maximum possible sum of a path from the top to the bottom of the triangle. A path starts at the top and moves downwards to adjacent numbers on the row below until it reaches the bottom row.

Solution

The given code provides a Java implementation to find the maximum path sum in a triangle. The algorithm uses dynamic programming to efficiently compute the maximum sum.

The main idea behind the solution is to start from the second-to-last row and iterate upwards to the top row. For each element in a row, we calculate the maximum sum by considering the element itself and the maximum sums of the two adjacent elements in the row below.

The algorithm uses a two-dimensional array called "dp" to store the intermediate results. Each element dp[i][j] represents the maximum sum achievable from the top to that element in the triangle.

The algorithm proceeds as follows:

  1. First, we copy the elements of the triangle into the dp array.
  2. We start from the second-to-last row and iterate upwards.
  3. For each element dp[r][c], where r is the current row and c is the column index:
    • If c > 0, we calculate the maximum sum by considering the element itself and the maximum sums of the two adjacent elements in the row below: dp[r][c] = max(dp[r+1][c-1] + dp[r][c], dp[r+1][c] + dp[r][c], dp[r+1][c+1] + dp[r][c]).
    • If c = 0, we can only consider the two adjacent elements in the row below: dp[r][c] = max(dp[r+1][c] + dp[r][c], dp[r+1][c+1] + dp[r][c]).
  4. Finally, the maximum path sum is stored in dp[0][0], which represents the top element of the triangle.

Code Solution

/*
    Java program for
    Maximum path sum in a triangle
*/
public class Path
{

    public int maxValue(int a, int b)
    {
        if(a > b)
        {
            return a;
        }
        return b;
    }
    public void maxPath(int [][]triangle)
    {
       int n = triangle.length;
       int m = triangle[0].length;
       int k = m-2;

       // Auxiliary space
       int [][]dp = new int[n][m];

        // Copy triangle element
        for (int i = 0; i < n  ; ++i ) 
        {
            for (int j = 0; j < m ; ++j ) 
            {
                dp[i][j] = triangle[i][j];       
            }    
        } 


        for ( int r = n-2; r >= 0 ; r-- ) 
        {
            for (int c = k; c >= 0 ; c-- ) 
            {
                if(c > 0)
                {
                    // Set max value of current element and 
                    // combination of bottom element.
                    // Bottom element is combination of three elements
                    dp[r][c] = maxValue(
                        maxValue(dp[r+1][c-1] + dp[r][c],
                            dp[r+1][c] + dp[r][c]), 
                                dp[r+1][c+1] + dp[r][c]);
                } 
                else
                {
                    // Two bottom element are used
                    dp[r][c] = maxValue(dp[r+1][c] + dp[r][c],
                                        dp[r+1][c+1] + dp[r][c]);
                }   
            }    
            k--;
        }

        System.out.println(dp[0][0]);
    }
 
    public static void main(String[] args)
    {
        Path task = new Path();
        
        int [][]triangle = 
        {  
            {1,  0, 0, 0, 0}, 
            {-2, 1, 0, 0, 0},
            {7,  3, 4, 0, 0},
            {5,  4, 2, 3, 0},
            {1,  1, 3, 3, 0}
        };
        /*
            {1,  -,  -, -, -}, 
              ⤡
            {-, 1,   -, -, -},
              ⤢
            {7,  -,  -, -, -},
               ⤡
            {-,  4,  -, -, -},
                   ⤡
            {-,  -,  3, -, -}
            -----------------------
            1 + 1 + 7 + 4 + 3 = 16
        */
        task.maxPath(triangle);
    }
}

Output

16
// Include header file
#include <iostream>
#define N 5
using namespace std;
/*
    C++ program for
    Maximum path sum in a triangle
*/
class Path
{
    public: int maxValue(int a, int b)
    {
        if (a > b)
        {
            return a;
        }
        return b;
    }
    void maxPath(int triangle[N][N])
    {
        int k = N - 2;
        // Auxiliary space
        int dp[N][N];
        // Copy triangle element
        for (int i = 0; i < N; ++i)
        {
            for (int j = 0; j < N; ++j)
            {
                dp[i][j] = triangle[i][j];
            }
        }
        for (int r = N - 2; r >= 0; r--)
        {
            for (int c = k; c >= 0; c--)
            {
                if (c > 0)
                {
                    // Set max value of current element and 
                    // combination of bottom element.
                    // Bottom element is combination of three elements
                    dp[r][c] = this->maxValue(
                      this->maxValue(dp[r + 1][c - 1] + dp[r][c], 
                                     dp[r + 1][c] + dp[r][c]), 
                      dp[r + 1][c + 1] + dp[r][c]);
                }
                else
                {
                    // Two bottom element are used
                    dp[r][c] = this->maxValue(dp[r + 1][c] + dp[r][c], 
                                              dp[r + 1][c + 1] + dp[r][c]);
                }
            }
            k--;
        }
        cout << dp[0][0] << endl;
    }
};
int main()
{
    Path *task = new Path();
    int triangle[N][N] = 
    {  
        {1,  0, 0, 0, 0}, 
        {-2, 1, 0, 0, 0},
        {7,  3, 4, 0, 0},
        {5,  4, 2, 3, 0},
        {1,  1, 3, 3, 0}
    };
    /*
        {1,  -,  -, -, -}, 
          ⤡
        {-, 1,   -, -, -},
          ⤢
        {7,  -,  -, -, -},
           ⤡
        {-,  4,  -, -, -},
               ⤡
        {-,  -,  3, -, -}
        -----------------------
        1 + 1 + 7 + 4 + 3 = 16
    */
    task->maxPath(triangle);
    return 0;
}

Output

16
// Include namespace system
using System;
/*
    Csharp program for
    Maximum path sum in a triangle
*/
public class Path
{
	public int maxValue(int a, int b)
	{
		if (a > b)
		{
			return a;
		}
		return b;
	}
	public void maxPath(int[,] triangle)
	{
		int n = triangle.GetLength(0);
		int m = triangle.GetLength(1);
		int k = m - 2;
		// Auxiliary space
		int[,] dp = new int[n,m];
		// Copy triangle element
		for (int i = 0; i < n; ++i)
		{
			for (int j = 0; j < m; ++j)
			{
				dp[i,j] = triangle[i,j];
			}
		}
		for (int r = n - 2; r >= 0; r--)
		{
			for (int c = k; c >= 0; c--)
			{
				if (c > 0)
				{
					// Set max value of current element and 
					// combination of bottom element.
					// Bottom element is combination of three elements
					dp[r,c] = this.maxValue(
                      this.maxValue(dp[r + 1,c - 1] + dp[r,c], 
                                    dp[r + 1,c] + dp[r,c]), 
                      dp[r + 1,c + 1] + dp[r,c]);
				}
				else
				{
					// Two bottom element are used
					dp[r,c] = this.maxValue(
                      dp[r + 1,c] + dp[r,c], 
                      dp[r + 1,c + 1] + dp[r,c]);
				}
			}
			k--;
		}
		Console.WriteLine(dp[0,0]);
	}
	public static void Main(String[] args)
	{
		Path task = new Path();
		int[,] triangle = {
			{
				1 , 0 , 0 , 0 , 0
			},
			{
				-2 , 1 , 0 , 0 , 0
			},
			{
				7 , 3 , 4 , 0 , 0
			},
			{
				5 , 4 , 2 , 3 , 0
			},
			{
				1 , 1 , 3 , 3 , 0
			}
		};
		/*
		    [1,  -,  -, -, -] 
		      ⤡
		    [-, 1,   -, -, -]
		      ⤢
		    [7,  -,  -, -, -]
		       ⤡
		    [-,  4,  -, -, -]
		           ⤡
		    [-,  -,  3, -, -]
		    -----------------------
		    1 + 1 + 7 + 4 + 3 = 16
		*/
		task.maxPath(triangle);
	}
}

Output

16
package main
import "fmt"
/*
    Go program for
    Maximum path sum in a triangle
*/

func maxValue(a, b int) int {
	if a > b {
		return a
	}
	return b
}
func maxPath(triangle[][] int) {
	var n int = len(triangle)
	var m int = len(triangle[0])
	var k int = m - 2
	// Auxiliary space
	var dp = make([][] int, n)
	for i:= 0;i < n;i++{
		dp[i] = make([]int,m)
	}
	// Copy triangle element
	for i := 0 ; i < n ; i++ {
		for j := 0 ; j < m ; j++ {
			dp[i][j] = triangle[i][j]
		}
	}
	for r := n - 2 ; r >= 0 ; r-- {
		for c := k ; c >= 0 ; c-- {
			if c > 0 {
				// Set max value of current element and 
				// combination of bottom element.
				// Bottom element is combination of three elements
				dp[r][c] = maxValue(
					maxValue(dp[r + 1][c - 1] + dp[r][c], 
						dp[r + 1][c] + dp[r][c]), 
					dp[r + 1][c + 1] + dp[r][c])
			} else {
				// Two bottom element are used
				dp[r][c] = maxValue(
					dp[r + 1][c] + dp[r][c], 
					dp[r + 1][c + 1] + dp[r][c])
			}
		}
		k--
	}
	fmt.Println(dp[0][0])
}
func main() {

	var triangle = [][] int { 
            {1,  0, 0, 0, 0}, 
            {-2, 1, 0, 0, 0},
            {7,  3, 4, 0, 0},
            {5,  4, 2, 3, 0},
            {1,  1, 3, 3, 0},
        }
	/*
	    [1,  -,  -, -, -] 
	      ⤡
	    [-, 1,   -, -, -]
	      ⤢
	    [7,  -,  -, -, -]
	       ⤡
	    [-,  4,  -, -, -]
	           ⤡
	    [-,  -,  3, -, -]
	    -----------------------
	    1 + 1 + 7 + 4 + 3 = 16
	*/
	maxPath(triangle)
}

Output

16
<?php
/*
    Php program for
    Maximum path sum in a triangle
*/
class Path
{
	public	function maxValue($a, $b)
	{
		if ($a > $b)
		{
			return $a;
		}
		return $b;
	}
	public	function maxPath($triangle)
	{
		$n = count($triangle);
		$m = count($triangle[0]);
		$k = $m - 2;
		// Auxiliary space
		$dp = array_fill(0, $n, array_fill(0, $m, 0));
		// Copy triangle element
		for ($i = 0; $i < $n; ++$i)
		{
			for ($j = 0; $j < $m; ++$j)
			{
				$dp[$i][$j] = $triangle[$i][$j];
			}
		}
		for ($r = $n - 2; $r >= 0; $r--)
		{
			for ($c = $k; $c >= 0; $c--)
			{
				if ($c > 0)
				{
					// Set max value of current element and 
					// combination of bottom element.
					// Bottom element is combination of three elements
					$dp[$r][$c] = $this->maxValue(
                      $this->maxValue($dp[$r + 1][$c - 1] + $dp[$r][$c], 
                                      $dp[$r + 1][$c] + $dp[$r][$c]), 
                      $dp[$r + 1][$c + 1] + $dp[$r][$c]);
				}
				else
				{
					// Two bottom element are used
					$dp[$r][$c] = $this->maxValue(
                      $dp[$r + 1][$c] + $dp[$r][$c], 
                      $dp[$r + 1][$c + 1] + $dp[$r][$c]);
				}
			}
			$k--;
		}
		echo($dp[0][0].
			"\n");
	}
}

function main()
{
	$task = new Path();
	$triangle = array(
      array(1, 0, 0, 0, 0), 
      array(-2, 1, 0, 0, 0), 
      array(7, 3, 4, 0, 0), 
      array(5, 4, 2, 3, 0), 
      array(1, 1, 3, 3, 0)
    );
	/*
	    [1,  -,  -, -, -] 
	      ⤡
	    [-, 1,   -, -, -]
	      ⤢
	    [7,  -,  -, -, -]
	       ⤡
	    [-,  4,  -, -, -]
	           ⤡
	    [-,  -,  3, -, -]
	    -----------------------
	    1 + 1 + 7 + 4 + 3 = 16
	*/
	$task->maxPath($triangle);
}
main();

Output

16
/*
    Node JS program for
    Maximum path sum in a triangle
*/
class Path
{
	maxValue(a, b)
	{
		if (a > b)
		{
			return a;
		}
		return b;
	}
	maxPath(triangle)
	{
		var n = triangle.length;
		var m = triangle[0].length;
		var k = m - 2;
		// Auxiliary space
		var dp = Array(n).fill(0).map(() => new Array(m).fill(0));
		// Copy triangle element
		for (var i = 0; i < n; ++i)
		{
			for (var j = 0; j < m; ++j)
			{
				dp[i][j] = triangle[i][j];
			}
		}
		for (var r = n - 2; r >= 0; r--)
		{
			for (var c = k; c >= 0; c--)
			{
				if (c > 0)
				{
					// Set max value of current element and 
					// combination of bottom element.
					// Bottom element is combination of three elements
					dp[r][c] = this.maxValue(
                      this.maxValue(dp[r + 1][c - 1] + dp[r][c], 
                                    dp[r + 1][c] + dp[r][c]), 
                      dp[r + 1][c + 1] + dp[r][c]);
				}
				else
				{
					// Two bottom element are used
					dp[r][c] = this.maxValue(
                      dp[r + 1][c] + dp[r][c], 
                      dp[r + 1][c + 1] + dp[r][c]
                    );
				}
			}
			k--;
		}
		console.log(dp[0][0]);
	}
}

function main()
{
	var task = new Path();
	var triangle = [
		[1, 0, 0, 0, 0],
		[-2, 1, 0, 0, 0],
		[7, 3, 4, 0, 0],
		[5, 4, 2, 3, 0],
		[1, 1, 3, 3, 0]
	];
	/*
	    [1,  -,  -, -, -] 
	      ⤡
	    [-, 1,   -, -, -]
	      ⤢
	    [7,  -,  -, -, -]
	       ⤡
	    [-,  4,  -, -, -]
	           ⤡
	    [-,  -,  3, -, -]
	    -----------------------
	    1 + 1 + 7 + 4 + 3 = 16
	*/
	task.maxPath(triangle);
}
main();

Output

16
#    Python 3 program for
#    Maximum path sum in a triangle
class Path :
	def maxValue(self, a, b) :
		if (a > b) :
			return a
		
		return b
	
	def maxPath(self, triangle) :
		n = len(triangle)
		m = len(triangle[0])
		k = m - 2
		#  Auxiliary space
		dp = [[0] * (m) for _ in range(n) ]
		i = 0
		#  Copy triangle element
		while (i < n) :
			j = 0
			while (j < m) :
				dp[i][j] = triangle[i][j]
				j += 1
			
			i += 1
		
		r = n - 2
		while (r >= 0) :
			c = k
			while (c >= 0) :
				if (c > 0) :
					#  Set max value of current element and 
					#  combination of bottom element.
					#  Bottom element is combination of three elements
					dp[r][c] = self.maxValue(
                      self.maxValue(dp[r + 1][c - 1] + dp[r][c], 
                                    dp[r + 1][c] + dp[r][c]), 
                      dp[r + 1][c + 1] + dp[r][c])
				else :
					#  Two bottom element are used
					dp[r][c] = self.maxValue(dp[r + 1][c] + dp[r][c], 
                                             dp[r + 1][c + 1] + dp[r][c])
				
				c -= 1
			
			k -= 1
			r -= 1
		
		print(dp[0][0])
	

def main() :
	task = Path()
	triangle = [
		[1, 0, 0, 0, 0],
		[-2, 1, 0, 0, 0],
		[7, 3, 4, 0, 0],
		[5, 4, 2, 3, 0],
		[1, 1, 3, 3, 0]
	]
	#    [1,  -,  -, -, -] 
	#      ⤡
	#    [-, 1,   -, -, -]
	#      ⤢
	#    [7,  -,  -, -, -]
	#       ⤡
	#    [-,  4,  -, -, -]
	#           ⤡
	#    [-,  -,  3, -, -]
	#    -----------------------
	#    1 + 1 + 7 + 4 + 3 = 16
	task.maxPath(triangle)

if __name__ == "__main__": main()

Output

16
#    Ruby program for
#    Maximum path sum in a triangle
class Path 
	def maxValue(a, b) 
		if (a > b) 
			return a
		end

		return b
	end

	def maxPath(triangle) 
		n = triangle.length
		m = triangle[0].length
		k = m - 2
		#  Auxiliary space
		dp = Array.new(n) {Array.new(m) {0}}
		i = 0
		#  Copy triangle element
		while (i < n) 
			j = 0
			while (j < m) 
				dp[i][j] = triangle[i][j]
				j += 1
			end

			i += 1
		end

		r = n - 2
		while (r >= 0) 
			c = k
			while (c >= 0) 
				if (c > 0) 
					#  Set max value of current element and 
					#  combination of bottom element.
					#  Bottom element is combination of three elements
					dp[r][c] = self.maxValue(
                      self.maxValue(dp[r + 1][c - 1] + dp[r][c], 
                                    dp[r + 1][c] + dp[r][c]), 
                      dp[r + 1][c + 1] + dp[r][c])
				else
 
					#  Two bottom element are used
					dp[r][c] = self.maxValue(
                      dp[r + 1][c] + dp[r][c], 
                      dp[r + 1][c + 1] + dp[r][c])
				end

				c -= 1
			end

			k -= 1
			r -= 1
		end

		print(dp[0][0], "\n")
	end

end

def main() 
	task = Path.new()
	triangle = [
		[1, 0, 0, 0, 0],
		[-2, 1, 0, 0, 0],
		[7, 3, 4, 0, 0],
		[5, 4, 2, 3, 0],
		[1, 1, 3, 3, 0]
	]
	#    [1,  -,  -, -, -] 
	#      ⤡
	#    [-, 1,   -, -, -]
	#      ⤢
	#    [7,  -,  -, -, -]
	#       ⤡
	#    [-,  4,  -, -, -]
	#           ⤡
	#    [-,  -,  3, -, -]
	#    -----------------------
	#    1 + 1 + 7 + 4 + 3 = 16
	task.maxPath(triangle)
end

main()

Output

16
/*
    Scala program for
    Maximum path sum in a triangle
*/
class Path()
{
	def maxValue(a: Int, b: Int): Int = {
		if (a > b)
		{
			return a;
		}
		return b;
	}
	def maxPath(triangle: Array[Array[Int]]): Unit = {
		var n: Int = triangle.length;
		var m: Int = triangle(0).length;
		var k: Int = m - 2;
		// Auxiliary space
		var dp: Array[Array[Int]] = Array.fill[Int](n, m)(0);
		var i: Int = 0;
		// Copy triangle element
		while (i < n)
		{
			var j: Int = 0;
			while (j < m)
			{
				dp(i)(j) = triangle(i)(j);
				j += 1;
			}
			i += 1;
		}
		var r: Int = n - 2;
		while (r >= 0)
		{
			var c: Int = k;
			while (c >= 0)
			{
				if (c > 0)
				{
					// Set max value of current element and 
					// combination of bottom element.
					// Bottom element is combination of three elements
					dp(r)(c) = maxValue(
                      maxValue(dp(r + 1)(c - 1) + dp(r)(c), 
                               dp(r + 1)(c) + dp(r)(c)), 
                      dp(r + 1)(c + 1) + dp(r)(c));
				}
				else
				{
					// Two bottom element are used
					dp(r)(c) = maxValue(
                      dp(r + 1)(c) + dp(r)(c), 
                      dp(r + 1)(c + 1) + dp(r)(c));
				}
				c -= 1;
			}
			k -= 1;
			r -= 1;
		}
		println(dp(0)(0));
	}
}
object Main
{
	def main(args: Array[String]): Unit = {
		var task: Path = new Path();
		var triangle: Array[Array[Int]] = Array(
          Array(1, 0, 0, 0, 0), 
          Array(-2, 1, 0, 0, 0), 
          Array(7, 3, 4, 0, 0), 
          Array(5, 4, 2, 3, 0), 
          Array(1, 1, 3, 3, 0)
        );
		/*
		    [1,  -,  -, -, -] 
		      ⤡
		    [-, 1,   -, -, -]
		      ⤢
		    [7,  -,  -, -, -]
		       ⤡
		    [-,  4,  -, -, -]
		           ⤡
		    [-,  -,  3, -, -]
		    -----------------------
		    1 + 1 + 7 + 4 + 3 = 16
		*/
		task.maxPath(triangle);
	}
}

Output

16
import Foundation;
/*
    Swift 4 program for
    Maximum path sum in a triangle
*/
class Path
{
	func maxValue(_ a: Int, _ b: Int) -> Int
	{
		if (a > b)
		{
			return a;
		}
		return b;
	}
	func maxPath(_ triangle: [
		[Int]
	])
	{
		let n: Int = triangle.count;
		let m: Int = triangle[0].count;
		var k: Int = m - 2;
		// Auxiliary space
		var dp: [
			[Int]
		] = Array(repeating: Array(repeating: 0, count: m), count: n);
		var i: Int = 0;
		// Copy triangle element
		while (i < n)
		{
			var j: Int = 0;
			while (j < m)
			{
				dp[i][j] = triangle[i][j];
				j += 1;
			}
			i += 1;
		}
		var r: Int = n - 2;
		while (r >= 0)
		{
			var c: Int = k;
			while (c >= 0)
			{
				if (c > 0)
				{
					// Set max value of current element and 
					// combination of bottom element.
					// Bottom element is combination of three elements
					dp[r][c] = 
                      self.maxValue(
                      	self.maxValue(dp[r + 1][c - 1] + dp[r][c], 
                                      dp[r + 1][c] + dp[r][c]), 
                      dp[r + 1][c + 1] + dp[r][c]);
				}
				else
				{
					// Two bottom element are used
					dp[r][c] = self.maxValue(dp[r + 1][c] + dp[r][c], 
                                             dp[r + 1][c + 1] + dp[r][c]);
				}
				c -= 1;
			}
			k -= 1;
			r -= 1;
		}
		print(dp[0][0]);
	}
}
func main()
{
	let task: Path = Path();
	let triangle: [
		[Int]
	] = [
		[1, 0, 0, 0, 0],
		[-2, 1, 0, 0, 0],
		[7, 3, 4, 0, 0],
		[5, 4, 2, 3, 0],
		[1, 1, 3, 3, 0]
	];
	/*
	    [1,  -,  -, -, -] 
	      ⤡
	    [-, 1,   -, -, -]
	      ⤢
	    [7,  -,  -, -, -]
	       ⤡
	    [-,  4,  -, -, -]
	           ⤡
	    [-,  -,  3, -, -]
	    -----------------------
	    1 + 1 + 7 + 4 + 3 = 16
	*/
	task.maxPath(triangle);
}
main();

Output

16
/*
    Kotlin program for
    Maximum path sum in a triangle
*/
class Path
{
	fun maxValue(a: Int, b: Int): Int
	{
		if (a > b)
		{
			return a;
		}
		return b;
	}
	fun maxPath(triangle: Array < Array < Int >> ): Unit
	{
		val n: Int = triangle.count();
		val m: Int = triangle[0].count();
		var k: Int = m - 2;
		// Auxiliary space
		val dp: Array < Array < Int >> = Array(n)
		{
			Array(m)
			{
				0
			}
		};
		var i: Int = 0;
		// Copy triangle element
		while (i < n)
		{
			var j: Int = 0;
			while (j < m)
			{
				dp[i][j] = triangle[i][j];
				j += 1;
			}
			i += 1;
		}
		var r: Int = n - 2;
		while (r >= 0)
		{
			var c: Int = k;
			while (c >= 0)
			{
				if (c > 0)
				{
					// Set max value of current element and 
					// combination of bottom element.
					// Bottom element is combination of three elements
					dp[r][c] = this.maxValue(
                      this.maxValue(dp[r + 1][c - 1] + dp[r][c], 
                                    dp[r + 1][c] + dp[r][c]), 
                      dp[r + 1][c + 1] + dp[r][c]);
				}
				else
				{
					// Two bottom element are used
					dp[r][c] = this.maxValue(
                      dp[r + 1][c] + dp[r][c], 
                      dp[r + 1][c + 1] + dp[r][c]);
				}
				c -= 1;
			}
			k -= 1;
			r -= 1;
		}
		println(dp[0][0]);
	}
}
fun main(args: Array < String > ): Unit
{
	val task: Path = Path();
	val triangle: Array < Array < Int >> = arrayOf(
      arrayOf(1, 0, 0, 0, 0), 
      arrayOf(-2, 1, 0, 0, 0), 
      arrayOf(7, 3, 4, 0, 0), 
      arrayOf(5, 4, 2, 3, 0), 
      arrayOf(1, 1, 3, 3, 0)
    );
	/*
	    [1,  -,  -, -, -] 
	      ⤡
	    [-, 1,   -, -, -]
	      ⤢
	    [7,  -,  -, -, -]
	       ⤡
	    [-,  4,  -, -, -]
	           ⤡
	    [-,  -,  3, -, -]
	    -----------------------
	    1 + 1 + 7 + 4 + 3 = 16
	*/
	task.maxPath(triangle);
}

Output

16

In the provided example, the triangle has the following structure:

          1
        -2  1
       7   3  4
      5   4  2  3
     1   1  3  3
  

By following the calculated maximum sums, the maximum path is determined as follows: 1 + 1 + 7 + 4 + 3 = 16.

Time Complexity

The time complexity of the algorithm is O(n^2), where n is the number of rows in the triangle. This is because we iterate through each element in the triangle and perform constant time operations for each element. Since the triangle has n*(n+1)/2 elements, the overall time complexity is O(n^2).

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