Longest common subsequence

Here given code implementation process.

// C Program 
// Longest common subsequence
#include <stdio.h>
#include <string.h>

// Returns the max value of given two numbers
int maxValue(int a, int b)
{
	if (a > b)
	{
		return a;
	}
	else
	{
		return b;
	}
}
// Returns the length of common substring
int lcs(const char *s1 , const char *s2, int n1, int n2, int i, int j)
{
	if (i == n1 || j == n2)
	{
		// When string length exceeds
		return 0;
	}
	else if (s1[i] == s2[j])
	{
		// When similar characters meet
		return 1 + lcs(s1, s2, n1, n2, i + 1, j + 1);
	}
	else
	{
		// Through recursively find similar characters
		return maxValue(lcs(s1, s2, n1, n2, i + 1, j), lcs(s1, s2, n1, n2, i, j + 1));
	}
}
int main(int argc, char
	const *argv[])
{
	const char *s1 = "AABCAEGDS";
	const char *s2 = "ADBSEDF";
	// Get the size of string
	int n1 = strlen(s1);
	int n2 = strlen(s2);
	int ans = lcs(s1, s2, n1, n2, 0, 0);
	// Display length of common substring
	printf("\n %d\n", ans);
	return 0;
}

Output

 4
/*
  Java Program for
  Longest common subsequence
*/
class LongestSubsequence
{
	// Returns the max value of given two numbers
	public int maxValue(int a, int b)
	{
		if (a > b)
		{
			return a;
		}
		else
		{
			return b;
		}
	}
	// Returns the length of common substring
	public int lcs(String s1, String s2, int n1, int n2, int i, int j)
	{
		if (i == n1 || j == n2)
		{
			// When string length exceeds
			return 0;
		}
		else if (s1.charAt(i) == s2.charAt(j))
		{
			// When similar characters meet
			return 1 + lcs(s1, s2, n1, n2, i + 1, j + 1);
		}
		else
		{
			// Through recursively find similar characters
			return maxValue(lcs(s1, s2, n1, n2, i + 1, j), lcs(s1, s2, n1, n2, i, j + 1));
		}
	}
	public static void main(String[] args)
	{
		LongestSubsequence task = new LongestSubsequence();
		String s1 = "AABCAEGDS";
		String s2 = "ADBSEDF";
		// Get the size of string
		int n1 = s1.length();
		int n2 = s2.length();
		int ans = task.lcs(s1, s2, n1, n2, 0, 0);
		// Display length of common substring
		System.out.print("\n " + ans + "\n");
	}
}

Output

 4
// Include header file
#include <iostream>
#include<string.h>
using namespace std;
/*
  C++ Program for
  Longest common subsequence
*/
class LongestSubsequence
{
	public:
		// Returns the max value of given two numbers
		int maxValue(int a, int b)
		{
			if (a > b)
			{
				return a;
			}
			else
			{
				return b;
			}
		}
	// Returns the length of common substring
	int lcs(string s1, string s2, int n1, int n2, int i, int j)
	{
		if (i == n1 || j == n2)
		{
			// When string length exceeds
			return 0;
		}
		else if (s1[i] == s2[j])
		{
			// When similar characters meet
			return 1 + this->lcs(s1, s2, n1, n2, i + 1, j + 1);
		}
		else
		{
			// Through recursively find similar characters
			return this->maxValue(this->lcs(s1, s2, n1, n2, i + 1, j), this->lcs(s1, s2, n1, n2, i, j + 1));
		}
	}
};
int main()
{
	LongestSubsequence task = LongestSubsequence();
	string s1 = "AABCAEGDS";
	string s2 = "ADBSEDF";
	// Get the size of string
	int n1 = s1.size();
	int n2 = s2.size();
	int ans = task.lcs(s1, s2, n1, n2, 0, 0);
	// Display length of common substring
	cout << "\n " << ans << "\n";
	return 0;
}

Output

 4
// Include namespace system
using System;
/*
  C# Program for
  Longest common subsequence
*/
public class LongestSubsequence
{
	// Returns the max value of given two numbers
	public int maxValue(int a, int b)
	{
		if (a > b)
		{
			return a;
		}
		else
		{
			return b;
		}
	}
	// Returns the length of common substring
	public int lcs(String s1, String s2, int n1, int n2, int i, int j)
	{
		if (i == n1 || j == n2)
		{
			// When string length exceeds
			return 0;
		}
		else if (s1[i] == s2[j])
		{
			// When similar characters meet
			return 1 + lcs(s1, s2, n1, n2, i + 1, j + 1);
		}
		else
		{
			// Through recursively find similar characters
			return maxValue(lcs(s1, s2, n1, n2, i + 1, j), lcs(s1, s2, n1, n2, i, j + 1));
		}
	}
	public static void Main(String[] args)
	{
		LongestSubsequence task = new LongestSubsequence();
		String s1 = "AABCAEGDS";
		String s2 = "ADBSEDF";
		// Get the size of string
		int n1 = s1.Length;
		int n2 = s2.Length;
		int ans = task.lcs(s1, s2, n1, n2, 0, 0);
		// Display length of common substring
		Console.Write("\n " + ans + "\n");
	}
}

Output

 4
<?php
/*
  Php Program for
  Longest common subsequence
*/
class LongestSubsequence
{
	// Returns the max value of given two numbers
	public	function maxValue($a, $b)
	{
		if ($a > $b)
		{
			return $a;
		}
		else
		{
			return $b;
		}
	}
	// Returns the length of common substring
	public	function lcs($s1, $s2, $n1, $n2, $i, $j)
	{
		if ($i == $n1 || $j == $n2)
		{
			// When string length exceeds
			return 0;
		}
		else if ($s1[$i] == $s2[$j])
		{
			// When similar characters meet
			return 1 + $this->lcs($s1, $s2, $n1, $n2, $i + 1, $j + 1);
		}
		else
		{
			// Through recursively find similar characters
			return $this->maxValue($this->lcs($s1, $s2, $n1, $n2, $i + 1, $j), $this->lcs($s1, $s2, $n1, $n2, $i, $j + 1));
		}
	}
}

function main()
{
	$task = new LongestSubsequence();
	$s1 = "AABCAEGDS";
	$s2 = "ADBSEDF";
	// Get the size of string
	$n1 = strlen($s1);
	$n2 = strlen($s2);
	$ans = $task->lcs($s1, $s2, $n1, $n2, 0, 0);
	// Display length of common substring
	echo "\n ". $ans ."\n";
}
main();

Output

 4
/*
  Node Js Program for
  Longest common subsequence
*/
class LongestSubsequence
{
	// Returns the max value of given two numbers
	maxValue(a, b)
	{
		if (a > b)
		{
			return a;
		}
		else
		{
			return b;
		}
	}
	// Returns the length of common substring
	lcs(s1, s2, n1, n2, i, j)
	{
		if (i == n1 || j == n2)
		{
			// When string length exceeds
			return 0;
		}
		else if (s1[i] == s2[j])
		{
			// When similar characters meet
			return 1 + this.lcs(s1, s2, n1, n2, i + 1, j + 1);
		}
		else
		{
			// Through recursively find similar characters
			return this.maxValue(this.lcs(s1, s2, n1, n2, i + 1, j), this.lcs(s1, s2, n1, n2, i, j + 1));
		}
	}
}

function main()
{
	var task = new LongestSubsequence();
	var s1 = "AABCAEGDS";
	var s2 = "ADBSEDF";
	// Get the size of string
	var n1 = s1.length;
	var n2 = s2.length;
	var ans = task.lcs(s1, s2, n1, n2, 0, 0);
	// Display length of common substring
	process.stdout.write("\n " + ans + "\n");
}
main();

Output

 4
#   Python 3 Program for
#   Longest common subsequence

class LongestSubsequence :
	#  Returns the max value of given two numbers
	def maxValue(self, a, b) :
		if (a > b) :
			return a
		else :
			return b
		
	
	#  Returns the length of common substring
	def lcs(self, s1, s2, n1, n2, i, j) :
		if (i == n1 or j == n2) :
			#  When string length exceeds
			return 0
		
		elif(s1[i] == s2[j]) :
			#  When similar characters meet
			return 1 + self.lcs(s1, s2, n1, n2, i + 1, j + 1)
		else :
			#  Through recursively find similar characters
			return self.maxValue(self.lcs(s1, s2, n1, n2, i + 1, j), self.lcs(s1, s2, n1, n2, i, j + 1))
		
	

def main() :
	task = LongestSubsequence()
	s1 = "AABCAEGDS"
	s2 = "ADBSEDF"
	#  Get the size of string
	n1 = len(s1)
	n2 = len(s2)
	ans = task.lcs(s1, s2, n1, n2, 0, 0)
	#  Display length of common substring
	print("\n ", ans )

if __name__ == "__main__": main()

Output

  4
#   Ruby Program for
#   Longest common subsequence

class LongestSubsequence 
	#  Returns the max value of given two numbers
	def maxValue(a, b) 
		if (a > b) 
			return a
		else 
			return b
		end

	end

	#  Returns the length of common substring
	def lcs(s1, s2, n1, n2, i, j) 
		if (i == n1 || j == n2) 
			#  When string length exceeds
			return 0
		elsif(s1[i] == s2[j]) 
			#  When similar characters meet
			return 1 + self.lcs(s1, s2, n1, n2, i + 1, j + 1)
		else 
			#  Through recursively find similar characters
			return self.maxValue(self.lcs(s1, s2, n1, n2, i + 1, j), self.lcs(s1, s2, n1, n2, i, j + 1))
		end

	end

end

def main() 
	task = LongestSubsequence.new()
	s1 = "AABCAEGDS"
	s2 = "ADBSEDF"
	#  Get the size of string
	n1 = s1.length()
	n2 = s2.length()
	ans = task.lcs(s1, s2, n1, n2, 0, 0)
	#  Display length of common substring
	print("\n ", ans ,"\n")
end

main()

Output

 4
/*
  Scala Program for
  Longest common subsequence
*/
class LongestSubsequence
{
	// Returns the max value of given two numbers
	def maxValue(a: Int, b: Int): Int = {
		if (a > b)
		{
			return a;
		}
		else
		{
			return b;
		}
	}
	// Returns the length of common substring
	def lcs(s1: String, s2: String, n1: Int, n2: Int, i: Int, j: Int): Int = {
		if (i == n1 || j == n2)
		{
			// When string length exceeds
			return 0;
		}
		else if (s1(i) == s2(j))
		{
			// When similar characters meet
			return 1 + this.lcs(s1, s2, n1, n2, i + 1, j + 1);
		}
		else
		{
			// Through recursively find similar characters
			return this.maxValue(this.lcs(s1, s2, n1, n2, i + 1, j), this.lcs(s1, s2, n1, n2, i, j + 1));
		}
	}
}
object Main
{
	def main(args: Array[String]): Unit = {
		var task: LongestSubsequence = new LongestSubsequence();
		var s1: String = "AABCAEGDS";
		var s2: String = "ADBSEDF";
		// Get the size of string
		var n1: Int = s1.length();
		var n2: Int = s2.length();
		var ans: Int = task.lcs(s1, s2, n1, n2, 0, 0);
		// Display length of common substring
		print("\n " + ans + "\n");
	}
}

Output

 4
/*
  Swift 4 Program for
  Longest common subsequence
*/
class LongestSubsequence
{
	// Returns the max value of given two numbers
	func maxValue(_ a: Int, _ b: Int)->Int
	{
		if (a > b)
		{
			return a;
		}
		else
		{
			return b;
		}
	}
	// Returns the length of common substring
	func lcs(_ s1: String, _ s2: String, _ n1: Int, _ n2: Int, _ i: Int, _ j: Int)->Int
	{
		if (i == n1 || j == n2)
		{
			// When string length exceeds
			return 0;
		}
		else if (Array(s1)[i] == Array(s2)[j])
		{
			// When similar characters meet
			return 1 + self.lcs(s1, s2, n1, n2, i + 1, j + 1);
		}
		else
		{
			// Through recursively find similar characters
			return self.maxValue(self.lcs(s1, s2, n1, n2, i + 1, j), self.lcs(s1, s2, n1, n2, i, j + 1));
		}
	}
}
func main()
{
	let task: LongestSubsequence = LongestSubsequence();
	let s1: String = "AABCAEGDS";
	let s2: String = "ADBSEDF";
	// Get the size of string
	let n1: Int = s1.count;
	let n2: Int = s2.count;
	let ans: Int = task.lcs(s1, s2, n1, n2, 0, 0);
	// Display length of common substring
	print("\n ", ans );
}
main();

Output

  4
/*
  Kotlin Program for
  Longest common subsequence
*/
class LongestSubsequence
{
	// Returns the max value of given two numbers
	fun maxValue(a: Int, b: Int): Int
	{
		if (a > b)
		{
			return a;
		}
		else
		{
			return b;
		}
	}
	// Returns the length of common substring
	fun lcs(s1: String, s2: String, n1: Int, n2: Int, i: Int, j: Int): Int
	{
		if (i == n1 || j == n2)
		{
			// When string length exceeds
			return 0;
		}
		else if (s1[i] == s2[j])
		{
			// When similar characters meet
			return 1 + this.lcs(s1, s2, n1, n2, i + 1, j + 1);
		}
		else
		{
			// Through recursively find similar characters
			return this.maxValue(this.lcs(s1, s2, n1, n2, i + 1, j), this.lcs(s1, s2, n1, n2, i, j + 1));
		}
	}
}
fun main(args: Array < String > ): Unit
{
	var task: LongestSubsequence = LongestSubsequence();
	var s1: String = "AABCAEGDS";
	var s2: String = "ADBSEDF";
	// Get the size of string
	var n1: Int = s1.count();
	var n2: Int = s2.count();
	var ans: Int = task.lcs(s1, s2, n1, n2, 0, 0);
	// Display length of common substring
	print("\n " + ans + "\n");
}

Output

 4


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