kadane's algorithm for maximum sum subarray

Here given code implementation process.

// C Program
// kadane's algorithm for maximum sum subarray
#include <stdio.h>

// Returns a maximum value of given number
int maxValue(int a, int b)
{
	if (a > b)
	{
		return a;
	}
	return b;
}
int findMaxSumSubarray(int arr[], int n)
{
	int bestSum = 0;
	int currentSum = 0;
	for (int i = 0; i < n; ++i)
	{
		// Sum of subarray
		currentSum = maxValue(0, currentSum + arr[i]);
		// Get best result
		bestSum = maxValue(bestSum, currentSum);
	}
	return bestSum;
}
int main()
{
	// Given array elements
	int arr1[] = {
		1 , 2 , -5 , 1 , 2 , -3 , 3 , -2 , 8
	};
	int arr2[] = {
		-5 , 1 , 2 , -10 , 3 , 1 , 2 , 8 , -2
	};
	// Test A
	// Get the number of elements
	int n = sizeof(arr1) / sizeof(arr1[0]);
	// [3, -2,  8]
	// Result 9
	int result = findMaxSumSubarray(arr1, n);
	printf("\n %d", result);
	// Test B
	// Get the number of elements
	n = sizeof(arr2) / sizeof(arr2[0]);
	// [3, 1, 2, 8]
	// Result 14
	result = findMaxSumSubarray(arr2, n);
	printf("\n %d", result);
	return 0;
}

Output

 9
 14
/*
    Java Program
    kadane's algorithm for maximum sum subarray
*/
public class MaxSubArray
{
	// Returns a maximum value of given number
	public int maxValue(int a, int b)
	{
		if (a > b)
		{
			return a;
		}
		return b;
	}
	public int findMaxSumSubarray(int[] arr, int n)
	{
		int bestSum = 0;
		int currentSum = 0;
		for (int i = 0; i < n; ++i)
		{
			// Sum of subarray
			currentSum = maxValue(0, currentSum + arr[i]);
			// Get best result
			bestSum = maxValue(bestSum, currentSum);
		}
		return bestSum;
	}
	public static void main(String[] args)
	{
		MaxSubArray task = new MaxSubArray();
		// Given array elements
		int[] arr1 = {
			1 , 2 , -5 , 1 , 2 , -3 , 3 , -2 , 8
		};
		int[] arr2 = {
			-5 , 1 , 2 , -10 , 3 , 1 , 2 , 8 , -2
		};
		// Test A
		// Get the number of elements
		int n = arr1.length;
		// [3, -2,  8]
		// Result 9
		int result = task.findMaxSumSubarray(arr1, n);
		System.out.print("\n " + result);
		// Test B
		// Get the number of elements
		n = arr2.length;
		// [3, 1, 2, 8]
		// Result 14
		result = task.findMaxSumSubarray(arr2, n);
		System.out.print("\n " + result);
	}
}

Output

 9
 14
// Include header file
#include <iostream>
using namespace std;
/*
    C++ Program
    kadane's algorithm for maximum sum subarray
*/
class MaxSubArray
{
	public:
		// Returns a maximum value of given number
		int maxValue(int a, int b)
		{
			if (a > b)
			{
				return a;
			}
			return b;
		}
	int findMaxSumSubarray(int arr[], int n)
	{
		int bestSum = 0;
		int currentSum = 0;
		for (int i = 0; i < n; ++i)
		{
			// Sum of subarray
			currentSum = this->maxValue(0, currentSum + arr[i]);
			// Get best result
			bestSum = this->maxValue(bestSum, currentSum);
		}
		return bestSum;
	}
};
int main()
{
	MaxSubArray *task = new MaxSubArray();
	// Given array elements
	int arr1[] = {
		1 , 2 , -5 , 1 , 2 , -3 , 3 , -2 , 8
	};
	int arr2[] = {
		-5 , 1 , 2 , -10 , 3 , 1 , 2 , 8 , -2
	};
	// Test A
	// Get the number of elements
	int n = sizeof(arr1) / sizeof(arr1[0]);
	// [3, -2,  8]
	// Result 9
	int result = task->findMaxSumSubarray(arr1, n);
	cout << "\n " << result;
	// Test B
	// Get the number of elements
	n = sizeof(arr2) / sizeof(arr2[0]);
	// [3, 1, 2, 8]
	// Result 14
	result = task->findMaxSumSubarray(arr2, n);
	cout << "\n " << result;
	return 0;
}

Output

 9
 14
// Include namespace system
using System;
/*
    Csharp Program
    kadane's algorithm for maximum sum subarray
*/
public class MaxSubArray
{
	// Returns a maximum value of given number
	public int maxValue(int a, int b)
	{
		if (a > b)
		{
			return a;
		}
		return b;
	}
	public int findMaxSumSubarray(int[] arr, int n)
	{
		int bestSum = 0;
		int currentSum = 0;
		for (int i = 0; i < n; ++i)
		{
			// Sum of subarray
			currentSum = this.maxValue(0, currentSum + arr[i]);
			// Get best result
			bestSum = this.maxValue(bestSum, currentSum);
		}
		return bestSum;
	}
	public static void Main(String[] args)
	{
		MaxSubArray task = new MaxSubArray();
		// Given array elements
		int[] arr1 = {
			1 , 2 , -5 , 1 , 2 , -3 , 3 , -2 , 8
		};
		int[] arr2 = {
			-5 , 1 , 2 , -10 , 3 , 1 , 2 , 8 , -2
		};
		// Test A
		// Get the number of elements
		int n = arr1.Length;
		// [3, -2,  8]
		// Result 9
		int result = task.findMaxSumSubarray(arr1, n);
		Console.Write("\n " + result);
		// Test B
		// Get the number of elements
		n = arr2.Length;
		// [3, 1, 2, 8]
		// Result 14
		result = task.findMaxSumSubarray(arr2, n);
		Console.Write("\n " + result);
	}
}

Output

 9
 14
package main
import "fmt"
/*
    Go Program
    kadane's algorithm for maximum sum subarray
*/

// Returns a maximum value of given number
func maxValue(a, b int) int {
	if a > b {
		return a
	}
	return b
}
func findMaxSumSubarray(arr[] int, n int) int {
	var bestSum int = 0
	var currentSum int = 0
	for i := 0 ; i < n ; i++ {
		// Sum of subarray
		currentSum = maxValue(0, currentSum + arr[i])
		// Get best result
		bestSum = maxValue(bestSum, currentSum)
	}
	return bestSum
}
func main() {

	// Given array elements
	var arr1 = [] int {1 , 2 , -5 , 1 , 2 , -3 , 3 , -2 , 8}
	var arr2 = [] int {-5, 1, 2, -10, 3, 1, 2, 8, -2 }
	// Test A
	// Get the number of elements
	var n int = len(arr1)
	// [3, -2,  8]
	// Result 9
	var result int = findMaxSumSubarray(arr1, n)
	fmt.Print("\n ", result)
	// Test B
	// Get the number of elements
	n = len(arr2)
	// [3, 1, 2, 8]
	// Result 14
	result = findMaxSumSubarray(arr2, n)
	fmt.Print("\n ", result)
}

Output

 9
 14
<?php
/*
    Php Program
    kadane's algorithm for maximum sum subarray
*/
class MaxSubArray
{
	// Returns a maximum value of given number
	public	function maxValue($a, $b)
	{
		if ($a > $b)
		{
			return $a;
		}
		return $b;
	}
	public	function findMaxSumSubarray($arr, $n)
	{
		$bestSum = 0;
		$currentSum = 0;
		for ($i = 0; $i < $n; ++$i)
		{
			// Sum of subarray
			$currentSum = $this->maxValue(0, $currentSum + $arr[$i]);
			// Get best result
			$bestSum = $this->maxValue($bestSum, $currentSum);
		}
		return $bestSum;
	}
}

function main()
{
	$task = new MaxSubArray();
	// Given array elements
	$arr1 = array(1, 2, -5, 1, 2, -3, 3, -2, 8);
	$arr2 = array(-5, 1, 2, -10, 3, 1, 2, 8, -2);
	// Test A
	// Get the number of elements
	$n = count($arr1);
	// [3, -2,  8]
	// Result 9
	$result = $task->findMaxSumSubarray($arr1, $n);
	echo("\n ".$result);
	// Test B
	// Get the number of elements
	$n = count($arr2);
	// [3, 1, 2, 8]
	// Result 14
	$result = $task->findMaxSumSubarray($arr2, $n);
	echo("\n ".$result);
}
main();

Output

 9
 14
/*
    Node JS Program
    kadane's algorithm for maximum sum subarray
*/
class MaxSubArray
{
	// Returns a maximum value of given number
	maxValue(a, b)
	{
		if (a > b)
		{
			return a;
		}
		return b;
	}
	findMaxSumSubarray(arr, n)
	{
		var bestSum = 0;
		var currentSum = 0;
		for (var i = 0; i < n; ++i)
		{
			// Sum of subarray
			currentSum = this.maxValue(0, currentSum + arr[i]);
			// Get best result
			bestSum = this.maxValue(bestSum, currentSum);
		}
		return bestSum;
	}
}

function main()
{
	var task = new MaxSubArray();
	// Given array elements
	var arr1 = [1, 2, -5, 1, 2, -3, 3, -2, 8];
	var arr2 = [-5, 1, 2, -10, 3, 1, 2, 8, -2];
	// Test A
	// Get the number of elements
	var n = arr1.length;
	// [3, -2,  8]
	// Result 9
	var result = task.findMaxSumSubarray(arr1, n);
	process.stdout.write("\n " + result);
	// Test B
	// Get the number of elements
	n = arr2.length;
	// [3, 1, 2, 8]
	// Result 14
	result = task.findMaxSumSubarray(arr2, n);
	process.stdout.write("\n " + result);
}
main();

Output

 9
 14
#    Python 3 Program
#    kadane's algorithm for maximum sum subarray
class MaxSubArray :
	#  Returns a maximum value of given number
	def maxValue(self, a, b) :
		if (a > b) :
			return a
		
		return b
	
	def findMaxSumSubarray(self, arr, n) :
		bestSum = 0
		currentSum = 0
		i = 0
		while (i < n) :
			#  Sum of sublist
			currentSum = self.maxValue(0, currentSum + arr[i])
			#  Get best result
			bestSum = self.maxValue(bestSum, currentSum)
			i += 1
		
		return bestSum
	

def main() :
	task = MaxSubArray()
	#  Given list elements
	arr1 = [1, 2, -5, 1, 2, -3, 3, -2, 8]
	arr2 = [-5, 1, 2, -10, 3, 1, 2, 8, -2]
	#  Test A
	#  Get the number of elements
	n = len(arr1)
	#  [3, -2,  8]
	#  Result 9
	result = task.findMaxSumSubarray(arr1, n)
	print("\n ", result, end = "")
	#  Test B
	#  Get the number of elements
	n = len(arr2)
	#  [3, 1, 2, 8]
	#  Result 14
	result = task.findMaxSumSubarray(arr2, n)
	print("\n ", result, end = "")

if __name__ == "__main__": main()

Output

  9
  14
#    Ruby Program
#    kadane's algorithm for maximum sum subarray
class MaxSubArray 
	#  Returns a maximum value of given number
	def maxValue(a, b) 
		if (a > b) 
			return a
		end

		return b
	end

	def findMaxSumSubarray(arr, n) 
		bestSum = 0
		currentSum = 0
		i = 0
		while (i < n) 
			#  Sum of subarray
			currentSum = self.maxValue(0, currentSum + arr[i])
			#  Get best result
			bestSum = self.maxValue(bestSum, currentSum)
			i += 1
		end

		return bestSum
	end

end

def main() 
	task = MaxSubArray.new()
	#  Given array elements
	arr1 = [1, 2, -5, 1, 2, -3, 3, -2, 8]
	arr2 = [-5, 1, 2, -10, 3, 1, 2, 8, -2]
	#  Test A
	#  Get the number of elements
	n = arr1.length
	#  [3, -2,  8]
	#  Result 9
	result = task.findMaxSumSubarray(arr1, n)
	print("\n ", result)
	#  Test B
	#  Get the number of elements
	n = arr2.length
	#  [3, 1, 2, 8]
	#  Result 14
	result = task.findMaxSumSubarray(arr2, n)
	print("\n ", result)
end

main()

Output

 9
 14
/*
    Scala Program
    kadane's algorithm for maximum sum subarray
*/
class MaxSubArray()
{
	// Returns a maximum value of given number
	def maxValue(a: Int, b: Int): Int = {
		if (a > b)
		{
			return a;
		}
		return b;
	}
	def findMaxSumSubarray(arr: Array[Int], n: Int): Int = {
		var bestSum: Int = 0;
		var currentSum: Int = 0;
		var i: Int = 0;
		while (i < n)
		{
			// Sum of subarray
			currentSum = maxValue(0, currentSum + arr(i));
			// Get best result
			bestSum = maxValue(bestSum, currentSum);
			i += 1;
		}
		return bestSum;
	}
}
object Main
{
	def main(args: Array[String]): Unit = {
		var task: MaxSubArray = new MaxSubArray();
		// Given array elements
		var arr1: Array[Int] = Array(1, 2, -5, 1, 2, -3, 3, -2, 8);
		var arr2: Array[Int] = Array(-5, 1, 2, -10, 3, 1, 2, 8, -2);
		// Test A
		// Get the number of elements
		var n: Int = arr1.length;
		// [3, -2,  8]
		// Result 9
		var result: Int = task.findMaxSumSubarray(arr1, n);
		print("\n " + result);
		// Test B
		// Get the number of elements
		n = arr2.length;
		// [3, 1, 2, 8]
		// Result 14
		result = task.findMaxSumSubarray(arr2, n);
		print("\n " + result);
	}
}

Output

 9
 14
import Foundation;
/*
    Swift 4 Program
    kadane's algorithm for maximum sum subarray
*/
class MaxSubArray
{
	// Returns a maximum value of given number
	func maxValue(_ a: Int, _ b: Int) -> Int
	{
		if (a > b)
		{
			return a;
		}
		return b;
	}
	func findMaxSumSubarray(_ arr: [Int], _ n: Int) -> Int
	{
		var bestSum: Int = 0;
		var currentSum: Int = 0;
		var i: Int = 0;
		while (i < n)
		{
			// Sum of subarray
			currentSum = self.maxValue(0, currentSum + arr[i]);
			// Get best result
			bestSum = self.maxValue(bestSum, currentSum);
			i += 1;
		}
		return bestSum;
	}
}
func main()
{
	let task: MaxSubArray = MaxSubArray();
	// Given array elements
	let arr1: [Int] = [1, 2, -5, 1, 2, -3, 3, -2, 8];
	let arr2: [Int] = [-5, 1, 2, -10, 3, 1, 2, 8, -2];
	// Test A
	// Get the number of elements
	var n: Int = arr1.count;
	// [3, -2,  8]
	// Result 9
	var result: Int = task.findMaxSumSubarray(arr1, n);
	print("\n ", result, terminator: "");
	// Test B
	// Get the number of elements
	n = arr2.count;
	// [3, 1, 2, 8]
	// Result 14
	result = task.findMaxSumSubarray(arr2, n);
	print("\n ", result, terminator: "");
}
main();

Output

  9
  14
/*
    Kotlin Program
    kadane's algorithm for maximum sum subarray
*/
class MaxSubArray
{
	// Returns a maximum value of given number
	fun maxValue(a: Int, b: Int): Int
	{
		if (a > b)
		{
			return a;
		}
		return b;
	}
	fun findMaxSumSubarray(arr: Array < Int > , n: Int): Int
	{
		var bestSum: Int = 0;
		var currentSum: Int = 0;
		var i: Int = 0;
		while (i < n)
		{
			// Sum of subarray
			currentSum = this.maxValue(0, currentSum + arr[i]);
			// Get best result
			bestSum = this.maxValue(bestSum, currentSum);
			i += 1;
		}
		return bestSum;
	}
}
fun main(args: Array < String > ): Unit
{
	val task: MaxSubArray = MaxSubArray();
	// Given array elements
	val arr1: Array < Int > = arrayOf(1, 2, -5, 1, 2, -3, 3, -2, 8);
	val arr2: Array < Int > = arrayOf(-5, 1, 2, -10, 3, 1, 2, 8, -2);
	// Test A
	// Get the number of elements
	var n: Int = arr1.count();
	// [3, -2,  8]
	// Result 9
	var result: Int = task.findMaxSumSubarray(arr1, n);
	print("\n " + result);
	// Test B
	// Get the number of elements
	n = arr2.count();
	// [3, 1, 2, 8]
	// Result 14
	result = task.findMaxSumSubarray(arr2, n);
	print("\n " + result);
}

Output

 9
 14



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