Insert node at middle of linked list in scala

Suppose we are inserted the following (1, 2, 3, 4, 5, 6, 7) node in a sequence. In this post are implement second approach.

insert linked list node in middle position
// Scala Program for
// Insert linked list element at middle position

// Linked list node
class LinkNode(var data: Int,
    var next: LinkNode)
{
    def this(data: Int)
    {
        this(data, null);
    }
}
class LinkedList(var head: LinkNode)
{
    // Class constructors
    def this()
    {
        this(null);
    }
    // Insert node in middle position
    def insert(value: Int): Unit = {
        // Create a new node
        var node: LinkNode = new LinkNode(value);
        if (this.head == null)
        {
            // First node
            this.head = node;
        }
        else
        {
            var temp: LinkNode = this.head;
            var middle: LinkNode = this.head;
            // Find the middle node
            while (temp.next != null && temp.next.next != null)
            {
                temp = temp.next.next;
                middle = middle.next;
            }
            // add node
            node.next = middle.next;
            middle.next = node;
        }
    }
    // Display linked list element
    def display(): Unit = {
        if (this.head == null)
        {
            return;
        }
        var temp: LinkNode = this.head;
        // iterating linked list elements
        while (temp != null)
        {
            print(""+temp.data + " → ");
            // Visit to next node
            temp = temp.next;
        }
        print("NULL\n");
    }
}
object Main
{
    def main(args: Array[String]): Unit = {
        var sll: LinkedList = new LinkedList();
        // Add node
        sll.insert(1);
        sll.insert(2);
        sll.insert(3);
        sll.insert(4);
        sll.insert(5);
        sll.insert(6);
        sll.insert(7);
        // 1 → 3 → 5 → 7 → 6 → 4 → 2 → NULL
        sll.display();
    }
}
 1 → 3 → 5 → 7 → 6 → 4 → 2 → NULL


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