insert node at beginning of circular linked list in ruby
Ruby program for insert node at beginning of circular linked list. Here problem description and explanation.
# Ruby Program
# Insert node at beginning of circular linked list
# Define class of linked list Node
class LinkNode
# Define the accessor and reader of class LinkNode
attr_reader :data, :next
attr_accessor :data, :next
def initialize(data, first)
self.data = data
self.next = first
end
end
class CircularLinkedList
# Define the accessor and reader of class CircularLinkedList
attr_reader :head
attr_accessor :head
# Class constructors
def initialize()
self.head = nil
end
# Insert node at begining of circular linked list
def insert(value)
# Create a node
node = LinkNode.new(value, self.head)
if (self.head == nil)
# First node of linked list
self.head = node
node.next = self.head
else
temp = self.head
# Find the last node
while (temp.next != self.head)
# Visit to next node
temp = temp.next
end
# Add node
temp.next = node
# make new head node
self.head = node
end
end
# Display node element of circular linked list
def display()
if (self.head == nil)
print("Empty Linked List\n")
else
print(" Linked List Element : \n")
# Get first node
temp = self.head
# iterate linked list
while (temp != nil)
# Display node
print(" ", temp.data)
# Visit to next node
temp = temp.next
if (temp == self.head)
# Stop iteration
return
end
end
end
end
end
def main()
task = CircularLinkedList.new()
# Add following linked list nodes
task.insert(8)
task.insert(7)
task.insert(6)
task.insert(5)
task.insert(4)
task.insert(3)
task.insert(2)
task.insert(1)
# Display node
task.display()
end
main()
Output
Linked List Element :
1 2 3 4 5 6 7 8
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