Inorder Tree Traversal of a Binary Tree
There are two standard solution to traversal of binary tree in inorder form. First is recursion and second is iterative approach using stack. In this post view both of solution. Before traversal of tree in inorder form that is important to know about what will be the result of inorder traversal of any tree.
Note that nodes are print from left to right in a sequence. That is also indicates the form of,(L R' R). Here L is for left, (R') for root (current node) and R for right.
Recursive Solution
That is simplest method to traversal tree using system stack (recursion).
1) In this process start of root node of tree.
2) And check it current node value is NULL or not. When that is not NULL then visit left sub tree (left child node). Again repeat this process until current node are not NULL.
3) When current node is NULL in this case current execution are back to previous recursively function. In this time we are printed this node value and repeted step 4.
4) When we are printed node value, after that visit right child (right subtree) of current node. After that repeat the step of 2 and 3.
Here given code implementation process.

1) Inorder traversal of binary tree with recursion in java
2) Inorder traversal of binary tree with recursion in c
3) Inorder traversal of binary tree with recursion in c++
4) Inorder traversal of binary tree with recursion in c#
5) Inorder traversal of binary tree with recursion in golang
6) Inorder traversal of binary tree with recursion in kotlin
7) Inorder traversal of binary tree with recursion in php
8) Inorder traversal of binary tree with recursion in python
9) Inorder traversal of binary tree with recursion in ruby
10) Inorder traversal of binary tree with recursion in swift
11) Inorder traversal of binary tree with recursion in vb.net
12) Inorder traversal of binary tree with recursion in node js
13) Inorder traversal of binary tree with recursion in typescript
14) Inorder traversal of binary tree with recursion in scala
Iterative Solution
In iterative approach we can solve this problem using stack. Stack are main two operation push() and pop(). When find new binary tree nodes then this element are push to stack and when no new node are found then print top element of stack, and pop() remove to top element.

1) Inorder traversal of binary tree using stack in java
2) Inorder traversal of binary tree using stack in c++
3) Inorder traversal of binary tree using stack in c#
4) Inorder traversal of binary tree using stack in c
5) Inorder traversal of binary tree using stack in golang
6) Inorder traversal of binary tree using stack in php
7) Inorder traversal of binary tree using stack in ruby
8) Inorder traversal of binary tree using stack in python
9) Inorder traversal of binary tree using stack in kotlin
10) Inorder traversal of binary tree using stack in swift
11) Inorder traversal of binary tree using stack in scala
12) Inorder traversal of binary tree using stack in typescript
13) Inorder traversal of binary tree using stack in node js
14) Inorder traversal of binary tree using stack in vb.net
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