Skip to main content

Inorder traversal of binary tree with recursion in scala

Scala program for Inorder traversal of binary tree with recursion. Here problem description and explanation.

/* 
  Scala Program for
  inorder tree traversal of a Binary Tree
  using recursion
*/
// Binary Tree Node
class TreeNode(var data: Int,
	var left: TreeNode,
		var right: TreeNode)
{
	def this(data: Int)
	{
		// Set node value
		this(data, null, null);
	}
}
class BinaryTree(var root: TreeNode)
{
	def this()
	{
		this(null);
	}
	// Display Inorder view of binary tree
	def inorder(node: TreeNode): Unit = {
		if (node != null)
		{
			// Visit left subtree
			inorder(node.left);
			// Print node value
			print("  " + node.data);
			// Visit right subtree
			inorder(node.right);
		}
	}
}
object Main
{
	def main(args: Array[String]): Unit = {
		// Create new tree
		var tree: BinaryTree = new BinaryTree();
		/*
		    Make A Binary Tree
		    ----------------
		        15
		       /  \
		      24   54
		     /    /  \
		    35   62   13
		*/
		// Add tree TreeNode
		tree.root = new TreeNode(15);
		tree.root.left = new TreeNode(24);
		tree.root.right = new TreeNode(54);
		tree.root.right.right = new TreeNode(13);
		tree.root.right.left = new TreeNode(62);
		tree.root.left.left = new TreeNode(35);
		// Display Tree Node
		tree.inorder(tree.root);
	}
}

Output

  35  24  15  62  54  13




Comment

Please share your knowledge to improve code and content standard. Also submit your doubts, and test case. We improve by your feedback. We will try to resolve your query as soon as possible.

New Comment