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Generic root of a number

Here given code implementation process.

//  C program 
//  Generic root of a number
#include <stdio.h>

// Find generic root of a given number
void genericRoot(int num)
{
	int n = num;
	if (n < 0)
	{
		n = -n;
	}
	int sum = 0;
	// Execute loop until when the value of n is not zero
	while (n != 0)
	{
		// Add last digit
		sum += n % 10;
		// Remove last digit
		n /= 10;
		if (n == 0 && sum > 9)
		{
			//  When n is zero but sum is not a form of single digit
			//  Assign sum value to n
			n = sum;
			sum = 0;
		}
	}
	// Display given number
	printf("\n Number : %d", num);
	printf("\n Result : %d", sum);
}
int main(int argc, char
	const *argv[])
{
	// Test case
	// 221  (2+2+1) => 5
	genericRoot(221);
	// 786  (7+8+6) => 21 (2+1) => 3
	genericRoot(786);
	// 19   (1+9)   => 10 (1+0) => 1
	genericRoot(19);
	return 0;
}

Output

 Number : 221
 Result : 5
 Number : 786
 Result : 3
 Number : 19
 Result : 1
/*
  Java program
  Generic root of a number
*/
public class Simplification
{
	// Find generic root of a given number
	public void genericRoot(int num)
	{
		int n = num;
		if (n < 0)
		{
			n = -n;
		}
		int sum = 0;
		// Execute loop until when the value of n is not zero
		while (n != 0)
		{
			// Add last digit
			sum += n % 10;
			// Remove last digit
			n /= 10;
			if (n == 0 && sum > 9)
			{
				//  When n is zero but sum is not a form of single digit
				//  Assign sum value to n
				n = sum;
				sum = 0;
			}
		}
		// Display given number
		System.out.print("\n Number : " + num);
		System.out.print("\n Result : " + sum);
	}
	public static void main(String[] args)
	{
		Simplification task = new Simplification();
		// Test case
		// 221  (2+2+1) => 5
		task.genericRoot(221);
		// 786  (7+8+6) => 21 (2+1) => 3
		task.genericRoot(786);
		// 19   (1+9)   => 10 (1+0) => 1
		task.genericRoot(19);
	}
}

Output

 Number : 221
 Result : 5
 Number : 786
 Result : 3
 Number : 19
 Result : 1
// Include header file
#include <iostream>
using namespace std;

/*
  C++ program
  Generic root of a number
*/

class Simplification
{
	public:
		// Find generic root of a given number
		void genericRoot(int num)
		{
			int n = num;
			if (n < 0)
			{
				n = -n;
			}
			int sum = 0;
			// Execute loop until when the value of n is not zero
			while (n != 0)
			{
				// Add last digit
				sum += n % 10;
				// Remove last digit
				n /= 10;
				if (n == 0 && sum > 9)
				{
					//  When n is zero but sum is not a form of single digit
					//  Assign sum value to n
					n = sum;
					sum = 0;
				}
			}
			// Display given number
			cout << "\n Number : " << num;
			cout << "\n Result : " << sum;
		}
};
int main()
{
	Simplification task = Simplification();
	// Test case
	// 221  (2+2+1) => 5
	task.genericRoot(221);
	// 786  (7+8+6) => 21 (2+1) => 3
	task.genericRoot(786);
	// 19   (1+9)   => 10 (1+0) => 1
	task.genericRoot(19);
	return 0;
}

Output

 Number : 221
 Result : 5
 Number : 786
 Result : 3
 Number : 19
 Result : 1
// Include namespace system
using System;
/*
  C# program
  Generic root of a number
*/
public class Simplification
{
	// Find generic root of a given number
	public void genericRoot(int num)
	{
		int n = num;
		if (n < 0)
		{
			n = -n;
		}
		int sum = 0;
		// Execute loop until when the value of n is not zero
		while (n != 0)
		{
			// Add last digit
			sum += n % 10;
			// Remove last digit
			n /= 10;
			if (n == 0 && sum > 9)
			{
				//  When n is zero but sum is not a form of single digit
				//  Assign sum value to n
				n = sum;
				sum = 0;
			}
		}
		// Display given number
		Console.Write("\n Number : " + num);
		Console.Write("\n Result : " + sum);
	}
	public static void Main(String[] args)
	{
		Simplification task = new Simplification();
		// Test case
		// 221  (2+2+1) => 5
		task.genericRoot(221);
		// 786  (7+8+6) => 21 (2+1) => 3
		task.genericRoot(786);
		// 19   (1+9)   => 10 (1+0) => 1
		task.genericRoot(19);
	}
}

Output

 Number : 221
 Result : 5
 Number : 786
 Result : 3
 Number : 19
 Result : 1
<?php
/*
  Php program
  Generic root of a number
*/
class Simplification
{
	// Find generic root of a given number
	public	function genericRoot($num)
	{
		$n = $num;
		if ($n < 0)
		{
			$n = -$n;
		}
		$sum = 0;
		// Execute loop until when the value of n is not zero
		while ($n != 0)
		{
			// Add last digit
			$sum += $n % 10;
			// Remove last digit
			$n = intval($n / 10);
			if ($n == 0 && $sum > 9)
			{
				//  When n is zero but sum is not a form of single digit
				//  Assign sum value to n
				$n = $sum;
				$sum = 0;
			}
		}
		// Display given number
		echo "\n Number : ". $num;
		echo "\n Result : ". $sum;
	}
}

function main()
{
	$task = new Simplification();
	// Test case
	// 221  (2+2+1) => 5
	$task->genericRoot(221);
	// 786  (7+8+6) => 21 (2+1) => 3
	$task->genericRoot(786);
	// 19   (1+9)   => 10 (1+0) => 1
	$task->genericRoot(19);
}
main();

Output

 Number : 221
 Result : 5
 Number : 786
 Result : 3
 Number : 19
 Result : 1
/*
  Node Js program
  Generic root of a number
*/
class Simplification
{
	// Find generic root of a given number
	genericRoot(num)
	{
		var n = num;
		if (n < 0)
		{
			n = -n;
		}
		var sum = 0;
		// Execute loop until when the value of n is not zero
		while (n != 0)
		{
			// Add last digit
			sum += n % 10;
			// Remove last digit
			n = parseInt(n / 10);
			if (n == 0 && sum > 9)
			{
				//  When n is zero but sum is not a form of single digit
				//  Assign sum value to n
				n = sum;
				sum = 0;
			}
		}
		// Display given number
		process.stdout.write("\n Number : " + num);
		process.stdout.write("\n Result : " + sum);
	}
}

function main()
{
	var task = new Simplification();
	// Test case
	// 221  (2+2+1) => 5
	task.genericRoot(221);
	// 786  (7+8+6) => 21 (2+1) => 3
	task.genericRoot(786);
	// 19   (1+9)   => 10 (1+0) => 1
	task.genericRoot(19);
}
main();

Output

 Number : 221
 Result : 5
 Number : 786
 Result : 3
 Number : 19
 Result : 1
#   Python 3 program
#   Generic root of a number

class Simplification :
	#  Find generic root of a given number
	def genericRoot(self, num) :
		n = num
		if (n < 0) :
			n = -n
		
		sum = 0
		#  Execute loop until when the value of n is not zero
		while (n != 0) :
			#  Add last digit
			sum += n % 10
                       #  Remove last digit
			n = int(n / 10)
			if (n == 0 and sum > 9) :
				#   When n is zero but sum is not a form of single digit
				#   Assign sum value to n
				n = sum
				sum = 0
			
		
		#  Display given number
		print("\n Number : ", num, end = "")
		print("\n Result : ", sum, end = "")
	

def main() :
	task = Simplification()
	#  Test case
	#  221  (2+2+1) => 5
	task.genericRoot(221)
	#  786  (7+8+6) => 21 (2+1) => 3
	task.genericRoot(786)
	#  19   (1+9)   => 10 (1+0) => 1
	task.genericRoot(19)

if __name__ == "__main__": main()

Output

 Number :  221
 Result :  5
 Number :  786
 Result :  3
 Number :  19
 Result :  1
#   Ruby program
#   Generic root of a number

class Simplification 
	#  Find generic root of a given number
	def genericRoot(num) 
		n = num
		if (n < 0) 
			n = -n
		end

		sum = 0
		#  Execute loop until when the value of n is not zero
		while (n != 0) 
			#  Add last digit
			sum += n % 10
			#  Remove last digit
			n /= 10
			if (n == 0 && sum > 9) 
				#   When n is zero but sum is not a form of single digit
				#   Assign sum value to n
				n = sum
				sum = 0
			end

		end

		#  Display given number
		print("\n Number : ", num)
		print("\n Result : ", sum)
	end

end

def main() 
	task = Simplification.new()
	#  Test case
	#  221  (2+2+1) => 5
	task.genericRoot(221)
	#  786  (7+8+6) => 21 (2+1) => 3
	task.genericRoot(786)
	#  19   (1+9)   => 10 (1+0) => 1
	task.genericRoot(19)
end

main()

Output

 Number : 221
 Result : 5
 Number : 786
 Result : 3
 Number : 19
 Result : 1
/*
  Scala program
  Generic root of a number
*/
class Simplification
{
	// Find generic root of a given number
	def genericRoot(num: Int): Unit = {
		var n: Int = num;
		if (n < 0)
		{
			n = -n;
		}
		var sum: Int = 0;
		// Execute loop until when the value of n is not zero
		while (n != 0)
		{
			// Add last digit
			sum += n % 10;
			// Remove last digit
			n = (n / 10).toInt;
			if (n == 0 && sum > 9)
			{
				//  When n is zero but sum is not a form of single digit
				//  Assign sum value to n
				n = sum;
				sum = 0;
			}
		}
		// Display given number
		print("\n Number : " + num);
		print("\n Result : " + sum);
	}
}
object Main
{
	def main(args: Array[String]): Unit = {
		var task: Simplification = new Simplification();
		// Test case
		// 221  (2+2+1) => 5
		task.genericRoot(221);
		// 786  (7+8+6) => 21 (2+1) => 3
		task.genericRoot(786);
		// 19   (1+9)   => 10 (1+0) => 1
		task.genericRoot(19);
	}
}

Output

 Number : 221
 Result : 5
 Number : 786
 Result : 3
 Number : 19
 Result : 1
/*
  Swift 4 program
  Generic root of a number
*/
class Simplification
{
	// Find generic root of a given number
	func genericRoot(_ num: Int)
	{
		var n: Int = num;
		if (n < 0)
		{
			n = -n;
		}
		var sum: Int = 0;
		// Execute loop until when the value of n is not zero
		while (n  != 0)
		{
			// Add last digit
			sum += n % 10;
			// Remove last digit
			n /= 10;
			if (n == 0 && sum > 9)
			{
				//  When n is zero but sum is not a form of single digit
				//  Assign sum value to n
				n = sum;
				sum = 0;
			}
		}
		// Display given number
		print("\n Number : ", num, terminator: "");
		print("\n Result : ", sum, terminator: "");
	}
}
func main()
{
	let task: Simplification = Simplification();
	// Test case
	// 221  (2+2+1) => 5
	task.genericRoot(221);
	// 786  (7+8+6) => 21 (2+1) => 3
	task.genericRoot(786);
	// 19   (1+9)   => 10 (1+0) => 1
	task.genericRoot(19);
}
main();

Output

 Number :  221
 Result :  5
 Number :  786
 Result :  3
 Number :  19
 Result :  1
/*
  Kotlin program
  Generic root of a number
*/
class Simplification
{
	// Find generic root of a given number
	fun genericRoot(num: Int): Unit
	{
		var n: Int = num;
		if (n < 0)
		{
			n = -n;
		}
		var sum: Int = 0;
		// Execute loop until when the value of n is not zero
		while (n != 0)
		{
			// Add last digit
			sum += n % 10;
			// Remove last digit
			n /= 10;
			if (n == 0 && sum > 9)
			{
				//  When n is zero but sum is not a form of single digit
				//  Assign sum value to n
				n = sum;
				sum = 0;
			}
		}
		// Display given number
		print("\n Number : " + num);
		print("\n Result : " + sum);
	}
}
fun main(args: Array < String > ): Unit
{
	var task: Simplification = Simplification();
	// Test case
	// 221  (2+2+1) => 5
	task.genericRoot(221);
	// 786  (7+8+6) => 21 (2+1) => 3
	task.genericRoot(786);
	// 19   (1+9)   => 10 (1+0) => 1
	task.genericRoot(19);
}

Output

 Number : 221
 Result : 5
 Number : 786
 Result : 3
 Number : 19
 Result : 1
Last updated on by Kalkicode




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