Generate combinations of integer product whose adjacent numbers are not similar

Here given code implementation process.

// C Program
// Generate combinations of integer product whose adjacent numbers are not similar
#include <stdio.h>

// Display result
void printSequence(int result[], int n)
{
	for (int i = 0; i < n; ++i)
	{
		printf("  %d", result[i]);
	}
	printf("\n");
}
void findCombination(int num, int result[], int index, int product)
{
	if (product == num)
	{
		// Display calculated result
		printSequence(result, index);
		return;
	}
	if (index >= num || product > num)
	{
		// Base case when stop process
		return;
	}
	for (int i = 2; i <= num / 2; ++i)
	{
		if (index == 0 || result[index - 1] != i)
		{
			// Collects resultant value
			result[index] = i;
			// Find other combination using recursion
			findCombination(num, result, index + 1, product *i);
		}
	}
}
void combination(int num)
{
	if (num <= 0)
	{
		return;
	}
	if (num == 1)
	{
		printf("\n 1 \n");
		return;
	}
	printf("\n Given Number : %d\n", num);
	// Collect result
	int result[num];
	// Test
	findCombination(num, result, 0, 1);
}
int main()
{
	int num = 20;
	/*
	    num = 20
	    --------
	    2  5  2
	    2  10
	    4   5
	    5   4
	    10  2
	    ------
	    Note 2 x 2 x 5 = 20
	    But 2 and 2 are adjacent
	*/
	combination(num);
	num = 32;
	/*
	    num = 32
	    --------
	    2  8  2
	    2  16
	    4  2  4
	    4  8
	    8  4
	    16  2
	    ------
	    Here not consider following pairs
	    [2,2,8] [4,4,8] [2,2,2,2,2],[2,2,2,4]...
         - -     - -     - - - - -   - - - 
	    Because few adjacent elements same in this pairs
	*/
	combination(num);
	return 0;
}

Output

 Given Number : 20
  2  5  2
  2  10
  4  5
  5  4
  10  2

 Given Number : 32
  2  8  2
  2  16
  4  2  4
  4  8
  8  4
  16  2
// Java Program 
// Generate combinations of integer product whose adjacent numbers are not similar
public class Product
{
	// Display result
	public void printSequence(int[] result, int n)
	{
		for (int i = 0; i < n; ++i)
		{
			System.out.print(" " + result[i]);
		}
		System.out.print("\n");
	}
	public void findCombination(int num, int[] result, 
      int index, int product)
	{
		if (product == num)
		{
			// Display calculated result
			printSequence(result, index);
			return;
		}
		if (index >= num || product > num)
		{
			// Base case when stop process
			return;
		}
		for (int i = 2; i <= num / 2; ++i)
		{
			if (index == 0 || result[index - 1] != i)
			{
				// Collects resultant value
				result[index] = i;
				// Find other combination using recursion
				findCombination(num, result, index + 1, product * i);
			}
		}
	}
	public void combination(int num)
	{
		if (num <= 0)
		{
			return;
		}
		if (num == 1)
		{
			System.out.print("\n 1 \n");
			return;
		}
		System.out.println("\n Given Number : " + num );
		// Collect result
		int[] result = new int[num];
		// Test
		findCombination(num, result, 0, 1);
	}
	public static void main(String args[])
	{
		Product task = new Product();

		int num = 20;
		/*
		    num = 20
		    --------
		    2  5  2
		    2  10
		    4   5
		    5   4
		    10  2
		    ------
		    Note 2 x 2 x 5 = 20
		    But 2 and 2 are adjacent
		*/
		task.combination(num);
		num = 32;
		/*
		    num = 32
		    --------
		    2  8  2
		    2  16
		    4  2  4
		    4  8
		    8  4
		    16  2
		    ------
		    Here not consider following pairs
		    [2,2,8] [4,4,8] [2,2,2,2,2],[2,2,2,4]...
	         - -     - -     - - - - -   - - - 
		    Because few adjacent elements same in this pairs
		*/
		task.combination(num);
	}
}

Output

 Given Number : 20
 2 5 2
 2 10
 4 5
 5 4
 10 2

 Given Number : 32
 2 8 2
 2 16
 4 2 4
 4 8
 8 4
 16 2
// Include namespace system
using System;
// Csharp Program
// Generate combinations of integer product whose adjacent numbers are not similar
public class Product
{
	// Display result
	public void printSequence(int[] result, int n)
	{
		for (int i = 0; i < n; ++i)
		{
			Console.Write(" " + result[i]);
		}
		Console.Write("\n");
	}
	public void findCombination(int num, int[] result, int index, int product)
	{
		if (product == num)
		{
			// Display calculated result
			this.printSequence(result, index);
			return;
		}
		if (index >= num || product > num)
		{
			// Base case when stop process
			return;
		}
		for (int i = 2; i <= num / 2; ++i)
		{
			if (index == 0 || result[index - 1] != i)
			{
				// Collects resultant value
				result[index] = i;
				// Find other combination using recursion
				this.findCombination(num, result, index + 1, product * i);
			}
		}
	}
	public void combination(int num)
	{
		if (num <= 0)
		{
			return;
		}
		if (num == 1)
		{
			Console.Write("\n 1 \n");
			return;
		}
		Console.WriteLine("\n Given Number : " + num);
		// Collect result
		int[] result = new int[num];
		// Test
		this.findCombination(num, result, 0, 1);
	}
	public static void Main(String[] args)
	{
		Product task = new Product();
		int num = 20;
		/*
		    num = 20
		    --------
		    2  5  2
		    2  10
		    4   5
		    5   4
		    10  2
		    ------
		    Note 2 x 2 x 5 = 20
		    But 2 and 2 are adjacent
		*/
		task.combination(num);
		num = 32;
		/*
			    num = 32
			    --------
			    2  8  2
			    2  16
			    4  2  4
			    4  8
			    8  4
			    16  2
			    ------
			    Here not consider following pairs
			    [2,2,8] [4,4,8] [2,2,2,2,2],[2,2,2,4]...
		         - -     - -     - - - - -   - - - 
			    Because few adjacent elements same in this pairs
		*/
		task.combination(num);
	}
}

Output

 Given Number : 20
 2 5 2
 2 10
 4 5
 5 4
 10 2

 Given Number : 32
 2 8 2
 2 16
 4 2 4
 4 8
 8 4
 16 2
package main
import "fmt"
// Go Program
// Generate combinations of integer product whose adjacent numbers are not similar
type Product struct {}
func getProduct() * Product {
	var me *Product = &Product {}
	return me
}
// Display result
func(this Product) printSequence(result[] int, n int) {
	for i := 0 ; i < n ; i++ {
		fmt.Print(" ", result[i])
	}
	fmt.Print("\n")
}
func(this Product) findCombination(num int, 
	result[] int, index int, product int) {
	if product == num {
		// Display calculated result
		this.printSequence(result, index)
		return
	}
	if index >= num || product > num {
		// Base case when stop process
		return
	}
	for i := 2 ; i <= num / 2 ; i++ {
		if index == 0 || result[index - 1] != i {
			// Collects resultant value
			result[index] = i
			// Find other combination using recursion
			this.findCombination(num, 
				result, index + 1, product * i)
		}
	}
}
func(this Product) combination(num int) {
	if num <= 0 {
		return
	}
	if num == 1 {
		fmt.Print("\n 1 \n")
		return
	}
	fmt.Println("\n Given Number : ", num)
	// Collect result
	var result = make([] int, num)
	// Test
	this.findCombination(num, result, 0, 1)
}
func main() {
	var task * Product = getProduct()
	var num int = 20
	/*
	    num = 20
	    --------
	    2  5  2
	    2  10
	    4   5
	    5   4
	    10  2
	    ------
	    Note 2 x 2 x 5 = 20
	    But 2 and 2 are adjacent
	*/
	task.combination(num)
	num = 32
	/*
	    num = 32
	    --------
	    2  8  2
	    2  16
	    4  2  4
	    4  8
	    8  4
	    16  2
	    ------
	    Here not consider following pairs
	    [2,2,8] [4,4,8] [2,2,2,2,2],[2,2,2,4]...
         - -     - -     - - - - -   - - - 
	    Because few adjacent elements same in this pairs
	*/
	task.combination(num)
}

Output

 Given Number :  20
  2  5  2
  2  10
  4  5
  5  4
  10  2

 Given Number :  32
  2  8  2
  2  16
  4  2  4
  4  8
  8  4
  16  2
<?php
// Php Program
// Generate combinations of integer product whose adjacent numbers are not similar
class Product
{
	// Display result
	public	function printSequence($result, $n)
	{
		for ($i = 0; $i < $n; ++$i)
		{
			echo(" ".$result[$i]);
		}
		echo("\n");
	}
	public	function findCombination($num, $result, $index, $product)
	{
		if ($product == $num)
		{
			// Display calculated result
			$this->printSequence($result, $index);
			return;
		}
		if ($index >= $num || $product > $num)
		{
			// Base case when stop process
			return;
		}
		for ($i = 2; $i <= (int)($num / 2); ++$i)
		{
			if ($index == 0 || $result[$index - 1] != $i)
			{
				// Collects resultant value
				$result[$index] = $i;
				// Find other combination using recursion
				$this->findCombination($num, $result, $index + 1, $product * $i);
			}
		}
	}
	public	function combination($num)
	{
		if ($num <= 0)
		{
			return;
		}
		if ($num == 1)
		{
			echo("\n 1 \n");
			return;
		}
		echo("\n Given Number : ".$num.
			"\n");
		// Collect result
		$result = array_fill(0, $num, 0);
		// Test
		$this->findCombination($num, $result, 0, 1);
	}
}

function main()
{
	$task = new Product();
	$num = 20;
	/*
	    num = 20
	    --------
	    2  5  2
	    2  10
	    4   5
	    5   4
	    10  2
	    ------
	    Note 2 x 2 x 5 = 20
	    But 2 and 2 are adjacent
	*/
	$task->combination($num);
	$num = 32;
	/*
		    num = 32
		    --------
		    2  8  2
		    2  16
		    4  2  4
		    4  8
		    8  4
		    16  2
		    ------
		    Here not consider following pairs
		    [2,2,8] [4,4,8] [2,2,2,2,2],[2,2,2,4]...
	         - -     - -     - - - - -   - - - 
		    Because few adjacent elements same in this pairs
	*/
	$task->combination($num);
}
main();

Output

 Given Number : 20
 2 5 2
 2 10
 4 5
 5 4
 10 2

 Given Number : 32
 2 8 2
 2 16
 4 2 4
 4 8
 8 4
 16 2
// Node JS Program
// Generate combinations of integer product whose adjacent numbers are not similar
class Product
{
	// Display result
	printSequence(result, n)
	{
		for (var i = 0; i < n; ++i)
		{
			process.stdout.write(" " + result[i]);
		}
		process.stdout.write("\n");
	}
	findCombination(num, result, index, product)
	{
		if (product == num)
		{
			// Display calculated result
			this.printSequence(result, index);
			return;
		}
		if (index >= num || product > num)
		{
			// Base case when stop process
			return;
		}
		for (var i = 2; i <= parseInt(num / 2); ++i)
		{
			if (index == 0 || result[index - 1] != i)
			{
				// Collects resultant value
				result[index] = i;
				// Find other combination using recursion
				this.findCombination(num, result, index + 1, product * i);
			}
		}
	}
	combination(num)
	{
		if (num <= 0)
		{
			return;
		}
		if (num == 1)
		{
			process.stdout.write("\n 1 \n");
			return;
		}
		console.log("\n Given Number : " + num);
		// Collect result
		var result = Array(num).fill(0);
		// Test
		this.findCombination(num, result, 0, 1);
	}
}

function main()
{
	var task = new Product();
	var num = 20;
	/*
	    num = 20
	    --------
	    2  5  2
	    2  10
	    4   5
	    5   4
	    10  2
	    ------
	    Note 2 x 2 x 5 = 20
	    But 2 and 2 are adjacent
	*/
	task.combination(num);
	num = 32;
	/*
		    num = 32
		    --------
		    2  8  2
		    2  16
		    4  2  4
		    4  8
		    8  4
		    16  2
		    ------
		    Here not consider following pairs
		    [2,2,8] [4,4,8] [2,2,2,2,2],[2,2,2,4]...
	         - -     - -     - - - - -   - - - 
		    Because few adjacent elements same in this pairs
	*/
	task.combination(num);
}
main();

Output

 Given Number : 20
 2 5 2
 2 10
 4 5
 5 4
 10 2

 Given Number : 32
 2 8 2
 2 16
 4 2 4
 4 8
 8 4
 16 2
#  Python 3 Program
#  Generate combinations of integer product whose adjacent numbers are not similar
class Product :
	#  Display result
	def printSequence(self, result, n) :
		i = 0
		while (i < n) :
			print(" ", result[i], end = "")
			i += 1
		
		print(end = "\n")
	
	def findCombination(self, num, result, index, product) :
		if (product == num) :
			#  Display calculated result
			self.printSequence(result, index)
			return
		
		if (index >= num or product > num) :
			#  Base case when stop process
			return
		
		i = 2
		while (i <= int(num / 2)) :
			if (index == 0 or result[index - 1] != i) :
				#  Collects resultant value
				result[index] = i
				#  Find other combination using recursion
				self.findCombination(num, result, index + 1, product * i)
			
			i += 1
		
	
	def combination(self, num) :
		if (num <= 0) :
			return
		
		if (num == 1) :
			print("\n 1 ")
			return
		
		print("\n Given Number : ", num)
		#  Collect result
		result = [0] * (num)
		#  Test
		self.findCombination(num, result, 0, 1)
	

def main() :
	task = Product()
	num = 20
	#    num = 20
	#    --------
	#    2  5  2
	#    2  10
	#    4   5
	#    5   4
	#    10  2
	#    ------
	#    Note 2 x 2 x 5 = 20
	#    But 2 and 2 are adjacent
	task.combination(num)
	num = 32
	# 	    num = 32
	# 	    --------
	# 	    2  8  2
	# 	    2  16
	# 	    4  2  4
	# 	    4  8
	# 	    8  4
	# 	    16  2
	# 	    ------
	# 	    Here not consider following pairs
	# 	    [2,2,8] [4,4,8] [2,2,2,2,2],[2,2,2,4]...
	#         - -     - -     - - - - -   - - - 
	# 	    Because few adjacent elements same in this pairs
	task.combination(num)

if __name__ == "__main__": main()

Output

 Given Number :  20
  2  5  2
  2  10
  4  5
  5  4
  10  2

 Given Number :  32
  2  8  2
  2  16
  4  2  4
  4  8
  8  4
  16  2
#  Ruby Program
#  Generate combinations of integer product whose adjacent numbers are not similar
class Product 
	#  Display result
	def printSequence(result, n) 
		i = 0
		while (i < n) 
			print(" ", result[i])
			i += 1
		end

		print("\n")
	end

	def findCombination(num, result, index, product) 
		if (product == num) 
			#  Display calculated result
			self.printSequence(result, index)
			return
		end

		if (index >= num || product > num) 
			#  Base case when stop process
			return
		end

		i = 2
		while (i <= num / 2) 
			if (index == 0 || result[index - 1] != i) 
				#  Collects resultant value
				result[index] = i
				#  Find other combination using recursion
				self.findCombination(num, result, index + 1, product * i)
			end

			i += 1
		end

	end

	def combination(num) 
		if (num <= 0) 
			return
		end

		if (num == 1) 
			print("\n 1 \n")
			return
		end

		print("\n Given Number : ", num, "\n")
		#  Collect result
		result = Array.new(num) {0}
		#  Test
		self.findCombination(num, result, 0, 1)
	end

end

def main() 
	task = Product.new()
	num = 20
	#    num = 20
	#    --------
	#    2  5  2
	#    2  10
	#    4   5
	#    5   4
	#    10  2
	#    ------
	#    Note 2 x 2 x 5 = 20
	#    But 2 and 2 are adjacent
	task.combination(num)
	num = 32
	# 	    num = 32
	# 	    --------
	# 	    2  8  2
	# 	    2  16
	# 	    4  2  4
	# 	    4  8
	# 	    8  4
	# 	    16  2
	# 	    ------
	# 	    Here not consider following pairs
	# 	    [2,2,8] [4,4,8] [2,2,2,2,2],[2,2,2,4]...
	#         - -     - -     - - - - -   - - - 
	# 	    Because few adjacent elements same in this pairs
	task.combination(num)
end

main()

Output

 Given Number : 20
 2 5 2
 2 10
 4 5
 5 4
 10 2

 Given Number : 32
 2 8 2
 2 16
 4 2 4
 4 8
 8 4
 16 2
// Scala Program
// Generate combinations of integer product whose adjacent numbers are not similar
class Product()
{
	// Display result
	def printSequence(result: Array[Int], n: Int): Unit = {
		var i: Int = 0;
		while (i < n)
		{
			print(" " + result(i));
			i += 1;
		}
		print("\n");
	}
	def findCombination(num: Int, result: Array[Int], 
      index: Int, product: Int): Unit = {
		if (product == num)
		{
			// Display calculated result
			printSequence(result, index);
			return;
		}
		if (index >= num || product > num)
		{
			// Base case when stop process
			return;
		}
		var i: Int = 2;
		while (i <= num / 2)
		{
			if (index == 0 || result(index - 1) != i)
			{
				// Collects resultant value
				result(index) = i;
				// Find other combination using recursion
				findCombination(num, result, index + 1, product * i);
			}
			i += 1;
		}
	}
	def combination(num: Int): Unit = {
		if (num <= 0)
		{
			return;
		}
		if (num == 1)
		{
			print("\n 1 \n");
			return;
		}
		println("\n Given Number : " + num);
		// Collect result
		var result: Array[Int] = Array.fill[Int](num)(0);
		// Test
		findCombination(num, result, 0, 1);
	}
}
object Main
{
	def main(args: Array[String]): Unit = {
		var task: Product = new Product();
		var num: Int = 20;
		/*
		    num = 20
		    --------
		    2  5  2
		    2  10
		    4   5
		    5   4
		    10  2
		    ------
		    Note 2 x 2 x 5 = 20
		    But 2 and 2 are adjacent
		*/
		task.combination(num);
		num = 32;
		/*
			    num = 32
			    --------
			    2  8  2
			    2  16
			    4  2  4
			    4  8
			    8  4
			    16  2
			    ------
			    Here not consider following pairs
			    [2,2,8] [4,4,8] [2,2,2,2,2],[2,2,2,4]...
		         - -     - -     - - - - -   - - - 
			    Because few adjacent elements same in this pairs
		*/
		task.combination(num);
	}
}

Output

 Given Number : 20
 2 5 2
 2 10
 4 5
 5 4
 10 2

 Given Number : 32
 2 8 2
 2 16
 4 2 4
 4 8
 8 4
 16 2
// Swift 4 Program
// Generate combinations of integer product whose adjacent numbers are not similar
class Product
{
	// Display result
	func printSequence(_ result: [Int], _ n: Int)
	{
		var i: Int = 0;
		while (i < n)
		{
			print(" ", result[i], terminator: "");
			i += 1;
		}
		print(terminator: "\n");
	}
	func findCombination(_ num: Int, 
                         _ result: inout[Int],
      _ index: Int, 
      _ product: Int)
	{
		if (product == num)
		{
			// Display calculated result
			self.printSequence(result, index);
			return;
		}
		if (index >= num || product > num)
		{
			// Base case when stop process
			return;
		}
		var i: Int = 2;
		while (i <= num / 2)
		{
			if (index == 0 || result[index - 1]  != i)
			{
				// Collects resultant value
				result[index] = i;
				// Find other combination using recursion
				self.findCombination(num, &result, index + 1, product * i);
			}
			i += 1;
		}
	}
	func combination(_ num: Int)
	{
		if (num <= 0)
		{
			return;
		}
		if (num == 1)
		{
			print("\n 1 ");
			return;
		}
		print("\n Given Number : ", num);
		// Collect result
		var result: [Int] = Array(repeating: 0, count: num);
		// Test
		self.findCombination(num, &result, 0, 1);
	}
}
func main()
{
	let task: Product = Product();
	var num: Int = 20;
	/*
	    num = 20
	    --------
	    2  5  2
	    2  10
	    4   5
	    5   4
	    10  2
	    ------
	    Note 2 x 2 x 5 = 20
	    But 2 and 2 are adjacent
	*/
	task.combination(num);
	num = 32;
	/*
		    num = 32
		    --------
		    2  8  2
		    2  16
		    4  2  4
		    4  8
		    8  4
		    16  2
		    ------
		    Here not consider following pairs
		    [2,2,8] [4,4,8] [2,2,2,2,2],[2,2,2,4]...
	         - -     - -     - - - - -   - - - 
		    Because few adjacent elements same in this pairs
	*/
	task.combination(num);
}
main();

Output

 Given Number :  20
  2  5  2
  2  10
  4  5
  5  4
  10  2

 Given Number :  32
  2  8  2
  2  16
  4  2  4
  4  8
  8  4
  16  2
// Kotlin Program
// Generate combinations of integer product whose adjacent numbers are not similar
class Product
{
	// Display result
	fun printSequence(result: Array < Int > , n: Int): Unit
	{
		var i: Int = 0;
		while (i < n)
		{
			print(" " + result[i]);
			i += 1;
		}
		print("\n");
	}
	fun findCombination(num: Int, result: Array < Int > , 
                        index: Int, product: Int): Unit
	{
		if (product == num)
		{
			// Display calculated result
			this.printSequence(result, index);
			return;
		}
		if (index >= num || product > num)
		{
			// Base case when stop process
			return;
		}
		var i: Int = 2;
		while (i <= num / 2)
		{
			if (index == 0 || result[index - 1] != i)
			{
				// Collects resultant value
				result[index] = i;
				// Find other combination using recursion
				this.findCombination(num, result, 
                                     index + 1, product * i);
			}
			i += 1;
		}
	}
	fun combination(num: Int): Unit
	{
		if (num <= 0)
		{
			return;
		}
		if (num == 1)
		{
			print("\n 1 \n");
			return;
		}
		println("\n Given Number : " + num);
		// Collect result
		val result: Array < Int > = Array(num)
		{
			0
		};
		// Test
		this.findCombination(num, result, 0, 1);
	}
}
fun main(args: Array < String > ): Unit
{
	val task: Product = Product();
	var num: Int = 20;
	/*
	    num = 20
	    --------
	    2  5  2
	    2  10
	    4   5
	    5   4
	    10  2
	    ------
	    Note 2 x 2 x 5 = 20
	    But 2 and 2 are adjacent
	*/
	task.combination(num);
	num = 32;
	/*
		    num = 32
		    --------
		    2  8  2
		    2  16
		    4  2  4
		    4  8
		    8  4
		    16  2
		    ------
		    Here not consider following pairs
		    [2,2,8] [4,4,8] [2,2,2,2,2],[2,2,2,4]...
	         - -     - -     - - - - -   - - - 
		    Because few adjacent elements same in this pairs
	*/
	task.combination(num);
}

Output

 Given Number : 20
 2 5 2
 2 10
 4 5
 5 4
 10 2

 Given Number : 32
 2 8 2
 2 16
 4 2 4
 4 8
 8 4
 16 2


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