Flatten binary tree in order of postorder traversal in python

Python program for Flatten binary tree in order of postorder traversal. Here more solutions.
# Python 3 program for
# Flatten binary tree in order of post-order traversal
# Node of Binary Tree
class TreeNode :
def __init__(self, data) :
# Set node value
self.data = data
self.left = None
self.right = None
class BinaryTree :
def __init__(self) :
# Set initial tree root to null
self.root = None
self.back = None
# Recursive function
# Display postorder view of binary tree
def postOrder(self, node) :
if (node != None) :
self.postOrder(node.left)
self.postOrder(node.right)
# Print node value
print(" ",node.data, end ="")
# This are flattening tree nodes in postorder from
def transform(self, node) :
if (node != None) :
# Recursive executing left and right subtree
self.transform(node.left)
self.transform(node.right)
if (self.back == None) :
# This is first node of postorder traversal
# Get first node of transform tree
self.root = node
else :
# Next node
self.back.right = node
# We taking only one direction
self.back.left = None
self.back = node
# This are handling the request of
# flatten tree nodes in post order from.
def flattenNode(self) :
if (self.root == None) :
# When empty tree
return
# Set back node
self.back = None
# Perform flatten operation
self.transform(self.root)
if (self.back != None) :
# Set last node of post order
self.back.left = None
self.back.right = None
self.back = None
# Display flatten elements of tree
def showElement(self) :
if (self.root == None) :
print("\n Empty Tree")
return
print("\n Flatten Tree Node in Postorder : ")
temp = self.root
# Iterate tree elements
while (temp != None) :
# Display node value
print(" ",temp.data, end ="")
# Visit to next node
temp = temp.right
@staticmethod
def main() :
# New tree
tree = BinaryTree()
# Construct Binary Tree
# -----------------------
# 1
# / \
# / \
# 6 8
# / \ / \
# 2 3 7 5
# / / \ \
# 9 4 -6 11
# Add nodes
tree.root = TreeNode(1)
tree.root.left = TreeNode(6)
tree.root.left.left = TreeNode(2)
tree.root.right = TreeNode(8)
tree.root.right.right = TreeNode(5)
tree.root.right.left = TreeNode(7)
tree.root.right.left.right = TreeNode(-6)
tree.root.left.right = TreeNode(3)
tree.root.left.right.left = TreeNode(4)
tree.root.left.left.left = TreeNode(9)
tree.root.right.right.right = TreeNode(11)
# Display tree elements
print("\n Postorder Nodes : ")
tree.postOrder(tree.root)
# Testing
tree.flattenNode()
# After transform
tree.showElement()
if __name__=="__main__":
BinaryTree.main()
Output
Postorder Nodes :
9 2 4 3 6 -6 7 11 5 8 1
Flatten Tree Node in Postorder :
9 2 4 3 6 -6 7 11 5 8 1
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