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Find the volume of a sphere

A sphere is a three-dimensional geometric object that is perfectly round and symmetric. Finding the volume of a sphere involves calculating the amount of space enclosed within its boundaries. This calculation is important in various fields such as physics, astronomy, and engineering, where spheres are used to represent celestial bodies, particles, and geometric shapes.

Problem Statement

Given the radius of the sphere, the task is to calculate its volume. The formula for finding the volume of a sphere in terms of its radius 'r' is:

Volume = (4/3) * π * r³

Example Scenario

Imagine you are an astronomer studying planets. To determine the internal composition and density of a planet, you need to calculate its volume. This calculation helps you understand the planet's overall size and its potential to support various atmospheric and geological phenomena.

Idea to Solve the Problem

To solve this problem, we can follow these steps:

  1. Accept the radius of the sphere as input.
  2. Check if the input radius is non-negative.
  3. Use the formula to calculate the volume of the sphere.
  4. Display the calculated volume.

Pseudocode

function sphere_volume(r):
    if r < 0:
        return
    
    volume = (4/3) * π * (r * r * r)
    return volume

main:
    radius1 = 5
    radius2 = 9
    radius3 = 4.3
    radius4 = 6.7
    
    volume1 = sphere_volume(radius1)
    volume2 = sphere_volume(radius2)
    volume3 = sphere_volume(radius3)
    volume4 = sphere_volume(radius4)
    
    print("Sphere Size [ r :", radius1, "]")
    print("Volume :", volume1)
    
    print("Sphere Size [ r :", radius2, "]")
    print("Volume :", volume2)
    
    print("Sphere Size [ r :", radius3, "]")
    print("Volume :", volume3)
    
    print("Sphere Size [ r :", radius4, "]")
    print("Volume :", volume4)

Algorithm Explanation

  1. Define a function sphere_volume that takes the radius as input.
  2. Inside the function, check if the input radius is non-negative. If it's negative, return without calculating the volume.
  3. If the radius is non-negative, use the provided formula to calculate the volume of the sphere.
  4. In the main function, set four test cases with different values for the radius.
  5. Calculate the volumes for each test case by calling the sphere_volume function.
  6. Display the calculated volumes along with their respective radius values.

Code Solution

//C Program
//Find the volume of a sphere
#include <stdio.h>

#include <math.h>
 //Calculate volume of sphere by given radius 
void sphere_volume(double r)
{
	if (r < 0.0)
	{
		return;
	}
	// Formula
	//  4   
	// -- πr³ 
	//  3
	// Here r is radius
	double volume = 4 * M_PI * (r * r * r) / 3;
	//Display result
	printf(" Sphere Size [ r : %lf ] ", r);
	printf("\n Volume : %lf\n\n", volume);
}
int main()
{
	//Test Case
	sphere_volume(5);
	sphere_volume(9);
	sphere_volume(4.3);
	sphere_volume(6.7);
	return 0;
}

Output

 Sphere Size [ r : 5.000000 ]
 Volume : 523.598776

 Sphere Size [ r : 9.000000 ]
 Volume : 3053.628059

 Sphere Size [ r : 4.300000 ]
 Volume : 333.038143

 Sphere Size [ r : 6.700000 ]
 Volume : 1259.833108

// Java Program
// Find the volume of a sphere
class Sphere
{
	//Calculate volume of sphere by given radius 
	public void sphere_volume(double r)
	{
		if (r < 0.0)
		{
			return;
		}
		// Formula
		//  4   
		// -- πr³ 
		//  3
		// Here r is radius
		double volume = 4 * Math.PI * (r * r * r) / 3;
		//Display result
		System.out.print(" Sphere Size [ r : " + r + " ] ");
		System.out.print("\n Volume : " + volume + "\n\n");
	}
	public static void main(String[] args)
	{
		Sphere obj = new Sphere();
		//Test Case
		obj.sphere_volume(5);
		obj.sphere_volume(9);
		obj.sphere_volume(4.3);
		obj.sphere_volume(6.7);
	}
}

Output

 Sphere Size [ r : 5.0 ]
 Volume : 523.5987755982989

 Sphere Size [ r : 9.0 ]
 Volume : 3053.6280592892786

 Sphere Size [ r : 4.3 ]
 Volume : 333.03814281195156

 Sphere Size [ r : 6.7 ]
 Volume : 1259.8331083621695

// C++ Program
// Find the volume of a sphere
#include<iostream>
#include <math.h>
using namespace std;
class Sphere
{
	public:
		//Calculate volume of sphere by given radius 
		void sphere_volume(double r)
		{
			if (r < 0.0)
			{
				return;
			}
			// Formula
			//  4   
			// -- πr³ 
			//  3
			// Here r is radius
			double volume = 4 * M_PI *(r *r *r) / 3;
			cout << " Sphere Size [ r : " << r << " ] ";
			cout << "\n Volume : " << volume << "\n\n";
		}
};
int main()
{
	Sphere obj ;
	//Test Case
	obj.sphere_volume(5);
	obj.sphere_volume(9);
	obj.sphere_volume(4.3);
	obj.sphere_volume(6.7);
	return 0;
}

Output

 Sphere Size [ r : 5 ]
 Volume : 523.599

 Sphere Size [ r : 9 ]
 Volume : 3053.63

 Sphere Size [ r : 4.3 ]
 Volume : 333.038

 Sphere Size [ r : 6.7 ]
 Volume : 1259.83

// C# Program
// Find the volume of a sphere
using System;
class Sphere
{
	//Calculate volume of sphere by given radius 
	public void sphere_volume(double r)
	{
		if (r < 0.0)
		{
			return;
		}
		// Formula
		//  4   
		// -- πr³ 
		//  3
		// Here r is radius
		double volume = 4 * Math.PI * (r * r * r) / 3;
		Console.Write(" Sphere Size [ r : " + r + " ] ");
		Console.Write("\n Volume : " + volume + "\n\n");
	}
	public static void Main(String[] args)
	{
		Sphere obj = new Sphere();
		//Test Case
		obj.sphere_volume(5);
		obj.sphere_volume(9);
		obj.sphere_volume(4.3);
		obj.sphere_volume(6.7);
	}
}

Output

 Sphere Size [ r : 5 ]
 Volume : 523.598775598299

 Sphere Size [ r : 9 ]
 Volume : 3053.62805928928

 Sphere Size [ r : 4.3 ]
 Volume : 333.038142811952

 Sphere Size [ r : 6.7 ]
 Volume : 1259.83310836217

<?php
// Php Program
// Find the volume of a sphere
class Sphere
{
	//Calculate volume of sphere by given radius 
	public 	function sphere_volume($r)
	{
		if ($r < 0.0)
		{
			return;
		}
		// Formula
		//  4   
		// -- πr³ 
		//  3
		// Here r is radius
		$volume = 4 * M_PI *($r *$r *$r) / 3;
		//Display result
		echo(" Sphere Size [ r : ". $r ." ] ");
		echo("\n Volume : ". $volume ."\n\n");
	}
}

function main()
{
	$obj = new Sphere();
	//Test Case
	$obj->sphere_volume(5);
	$obj->sphere_volume(9);
	$obj->sphere_volume(4.3);
	$obj->sphere_volume(6.7);
}
main();

Output

 Sphere Size [ r : 5 ]
 Volume : 523.5987755983

 Sphere Size [ r : 9 ]
 Volume : 3053.6280592893

 Sphere Size [ r : 4.3 ]
 Volume : 333.03814281195

 Sphere Size [ r : 6.7 ]
 Volume : 1259.8331083622

// Node Js Program
// Find the volume of a sphere
class Sphere
{
	//Calculate volume of sphere by given radius 
	sphere_volume(r)
	{
		if (r < 0.0)
		{
			return;
		}
		// Formula
		//  4   
		// -- πr³ 
		//  3
		// Here r is radius
		var volume = 4 *Math.PI *(r *r *r) / 3;
		//Display result
		process.stdout.write(" Sphere Size [ r : " + r + " ] ");
		process.stdout.write("\n Volume : " + volume + "\n\n");
	}
}

function main(args)
{
	var obj = new Sphere();
	//Test Case
	obj.sphere_volume(5);
	obj.sphere_volume(9);
	obj.sphere_volume(4.3);
	obj.sphere_volume(6.7);
}
main();

Output

 Sphere Size [ r : 5 ]
 Volume : 523.5987755982989

 Sphere Size [ r : 9 ]
 Volume : 3053.6280592892786

 Sphere Size [ r : 4.3 ]
 Volume : 333.03814281195156

 Sphere Size [ r : 6.7 ]
 Volume : 1259.8331083621695

#  Python 3 Program
#  Find the volume of a sphere
import math
class Sphere :
	# Calculate volume of sphere by given radius 
	def sphere_volume(self, r) :
		if (r < 0.0) :
			return
		
		#  Formula
		#   4   
		#  -- πr³ 
		#   3
		#  Here r is radius
		volume = int(4 * math.pi * (r * r * r) / 3)
		# Display result
		print(" Sphere Size [ r : ", r ," ] ", end = "")
		print("\n Volume : ", volume ,"\n\n", end = "")
	

def main() :
	obj = Sphere()
	# Test Case
	obj.sphere_volume(5)
	obj.sphere_volume(9)
	obj.sphere_volume(4.3)
	obj.sphere_volume(6.7)


if __name__ == "__main__": main()

Output

 Sphere Size [ r :  5  ]
 Volume :  523

 Sphere Size [ r :  9  ]
 Volume :  3053

 Sphere Size [ r :  4.3  ]
 Volume :  333

 Sphere Size [ r :  6.7  ]
 Volume :  1259

#  Ruby Program
#  Find the volume of a sphere
class Sphere

	# Calculate volume of sphere by given radius 
	def sphere_volume(r)
	
		if (r < 0.0)
		
			return
		end
		#  Formula
		#   4   
		#  -- πr³ 
		#   3
		#  Here r is radius
		volume = 4 * Math::PI * (r * r * r) / 3
		# Display result
		print(" Sphere Size [ r  :", r ," ] ")
		print("\n Volume  :", volume ,"\n\n")
	end
end
def main()

	obj = Sphere.new()
	# Test Case
	obj.sphere_volume(5)
	obj.sphere_volume(9)
	obj.sphere_volume(4.3)
	obj.sphere_volume(6.7)
end
main()

Output

 Sphere Size [ r  :5 ] 
 Volume  :523.5987755982989

 Sphere Size [ r  :9 ] 
 Volume  :3053.6280592892786

 Sphere Size [ r  :4.3 ] 
 Volume  :333.03814281195156

 Sphere Size [ r  :6.7 ] 
 Volume  :1259.8331083621695


// Scala Program
// Find the volume of a sphere
class Sphere
{
	//Calculate volume of sphere by given radius 
	def sphere_volume(r: Double): Unit = {
		if (r < 0.0)
		{
			return;
		}
		// Formula
		//  4   
		// -- πr³ 
		//  3
		// Here r is radius
		var volume: Double = 4 * Math.PI * (r * r * r) / 3;
		//Display result
		print(" Sphere Size [ r : " + r + " ] ");
		print("\n Volume : " + volume + "\n\n");
	}
}
object Main
{
	def main(args: Array[String]): Unit = {
		var obj: Sphere = new Sphere();
		//Test Case
		obj.sphere_volume(5);
		obj.sphere_volume(9);
		obj.sphere_volume(4.3);
		obj.sphere_volume(6.7);
	}
}

Output

 Sphere Size [ r : 5.0 ]
 Volume : 523.5987755982989

 Sphere Size [ r : 9.0 ]
 Volume : 3053.6280592892786

 Sphere Size [ r : 4.3 ]
 Volume : 333.03814281195156

 Sphere Size [ r : 6.7 ]
 Volume : 1259.8331083621695

// Swift Program
// Find the volume of a sphere
class Sphere
{
	//Calculate volume of sphere by given radius 
	func sphere_volume(_ r: Double)
	{
		if (r < 0.0)
		{
			return;
		}
		// Formula
		//  4   
		// -- πr³ 
		//  3
		// Here r is radius
		let volume: Double = 4 * Double.pi * (r * r * r) / 3;
		//Display result
		print(" Sphere Size [ r : ", r ," ] ");
		print(" Volume : ", volume ,"\n");
	}
}
func main()
{
	let obj: Sphere = Sphere();
	//Test Case
	obj.sphere_volume(5);
	obj.sphere_volume(9);
	obj.sphere_volume(4.3);
	obj.sphere_volume(6.7);
}
main();

Output

 Sphere Size [ r :  5.0  ]
 Volume :  523.598775598299

 Sphere Size [ r :  9.0  ]
 Volume :  3053.62805928928

 Sphere Size [ r :  4.3  ]
 Volume :  333.038142811952

 Sphere Size [ r :  6.7  ]
 Volume :  1259.83310836217

Output Explanation

The code calculates the volume for each test case and displays the results. For a sphere with a radius of 5, the volume is approximately 523.598776. Similarly, for radius 9, the volume is approximately 3053.628059. The third and fourth test cases follow the same pattern.

Time Complexity

The time complexity of this code is constant O(1) because the calculations involve basic arithmetic operations and the value of π, which are calculated in constant time regardless of the input size. The program performs a fixed number of operations for each test case, making it efficient.

Last updated on by Kalkicode




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