# Find all triplets which sum less than given value x

Here given code implementation process.

``````// C Program
// Find all triplets which sum less than given value x
#include <stdio.h>

//Function which is display array elements
void display(int arr[], int size)
{
for (int i = 0; i < size; ++i)
{
printf("%d ", arr[i]);
}
}
// Find all triplets which sum less than x
void tripletsWithLessThanX(int arr[], int size, int x)
{
if (size < 3)
{
return;
}
printf(" Array : ");
//Display array elements
display(arr, size);
printf("\n Given x : %d", x);
// Result indicator
int status = 0;
// Loop which is iterate the first element of result
for (int i = 0; i < size - 2; ++i)
{
// Loop which is iterate the second element of result
for (int j = i + 1; j < size - 1; ++j)
{
// Loop which is iterate the third element of result
for (int k = j + 1; k < size; ++k)
{
// Check if whether resultant sum is to zero or not
if (arr[i] + arr[j] + arr[k] < x)
{
status = 1;
// Display three elements
printf("\n (%d + %d + %d) = %d",
arr[i], arr[j], arr[k],
(arr[i] + arr[j] + arr[k]));
}
}
}
}
if (status == 0)
{
printf(" \n None\n");
}
printf("\n");
}
int main()
{
//Define array elements
int arr1[] = {
8 , 2 , 0 , 6 , -2 , 6 , -1 , 9 , 4 , 3
};
// Define array elements
int arr2[] = {
9 , 2 , -7 , 4 , 1 , 3 , 0 , 7 , 22 , 8 , -4
};
// Test A
int size = sizeof(arr1) / sizeof(arr1[0]);
tripletsWithLessThanX(arr1, size, 3);
tripletsWithLessThanX(arr1, size, -6);
// Test B
size = sizeof(arr2) / sizeof(arr2[0]);
tripletsWithLessThanX(arr2, size, -2);
return 0;
}``````

#### Output

`````` Array : 8 2 0 6 -2 6 -1 9 4 3
Given x : 3
(2 + 0 + -2) = 0
(2 + 0 + -1) = 1
(2 + -2 + -1) = -1
(0 + -2 + -1) = -3
(0 + -2 + 4) = 2
(0 + -2 + 3) = 1
(0 + -1 + 3) = 2
(-2 + -1 + 4) = 1
(-2 + -1 + 3) = 0
Array : 8 2 0 6 -2 6 -1 9 4 3
Given x : -6
None

Array : 9 2 -7 4 1 3 0 7 22 8 -4
Given x : -2
(2 + -7 + 1) = -4
(2 + -7 + 0) = -5
(2 + -7 + -4) = -9
(-7 + 4 + 0) = -3
(-7 + 4 + -4) = -7
(-7 + 1 + 3) = -3
(-7 + 1 + 0) = -6
(-7 + 1 + -4) = -10
(-7 + 3 + 0) = -4
(-7 + 3 + -4) = -8
(-7 + 0 + -4) = -11
(-7 + 7 + -4) = -4
(-7 + 8 + -4) = -3
(1 + 0 + -4) = -3``````
``````/*
Java Program for
Find all triplets which sum less than given value x
*/
public class Triplets
{
//Function which is display array elements
public void display(int[] arr, int size)
{
for (int i = 0; i < size; ++i)
{
System.out.print("  " + arr[i]);
}
}
// Find all triplets which sum less than x
public void tripletsWithLessThanX(int[] arr, int size, int x)
{
if (size < 3)
{
return;
}
System.out.print("\n Array : ");
//Display array elements
display(arr, size);
System.out.print("\n Given x : " + x);
// Result indicator
boolean status = false;
// Loop which is iterate the first element of result
for (int i = 0; i < size - 2; ++i)
{
// Loop which is iterate the second element of result
for (int j = i + 1; j < size - 1; ++j)
{
// Loop which is iterate the third element of result
for (int k = j + 1; k < size; ++k)
{
// Check if whether resultant sum is to zero or not
if (arr[i] + arr[j] + arr[k] < x)
{
status = true;
// Display three elements
System.out.print("\n (" +
arr[i] + " + " +
arr[j] + " + " +
arr[k] + ") = " +
(arr[i] + arr[j] + arr[k]));
}
}
}
}
if (status == false)
{
System.out.print(" \n None\n");
}
}
public static void main(String[] args)
{
// Define array elements
int[] arr1 = {
8 , 2 , 0 , 6 , -2 , 6 , -1 , 9 , 4 , 3
};
// Define array elements
int[] arr2 = {
9 , 2 , -7 , 4 , 1 , 3 , 0 , 7 , 22 , 8 , -4
};
// Test A
int size = arr1.length;
// Test B
size = arr2.length;
}
}``````

#### Output

`````` Array :   8  2  0  6  -2  6  -1  9  4  3
Given x : 3
(2 + 0 + -2) = 0
(2 + 0 + -1) = 1
(2 + -2 + -1) = -1
(0 + -2 + -1) = -3
(0 + -2 + 4) = 2
(0 + -2 + 3) = 1
(0 + -1 + 3) = 2
(-2 + -1 + 4) = 1
(-2 + -1 + 3) = 0
Array :   8  2  0  6  -2  6  -1  9  4  3
Given x : -6
None

Array :   9  2  -7  4  1  3  0  7  22  8  -4
Given x : -2
(2 + -7 + 1) = -4
(2 + -7 + 0) = -5
(2 + -7 + -4) = -9
(-7 + 4 + 0) = -3
(-7 + 4 + -4) = -7
(-7 + 1 + 3) = -3
(-7 + 1 + 0) = -6
(-7 + 1 + -4) = -10
(-7 + 3 + 0) = -4
(-7 + 3 + -4) = -8
(-7 + 0 + -4) = -11
(-7 + 7 + -4) = -4
(-7 + 8 + -4) = -3
(1 + 0 + -4) = -3``````
``````// Include header file
#include <iostream>
using namespace std;
/*
C++ Program for
Find all triplets which sum less than given value x
*/
class Triplets
{
public:
//Function which is display array elements
void display(int arr[], int size)
{
for (int i = 0; i < size; ++i)
{
cout << "  " << arr[i];
}
}
// Find all triplets which sum less than x
void tripletsWithLessThanX(int arr[], int size, int x)
{
if (size < 3)
{
return;
}
cout << "\n Array : ";
//Display array elements
this->display(arr, size);
cout << "\n Given x : " << x;
// Result indicator
bool status = false;
// Loop which is iterate the first element of result
for (int i = 0; i < size - 2; ++i)
{
// Loop which is iterate the second element of result
for (int j = i + 1; j < size - 1; ++j)
{
// Loop which is iterate the third element of result
for (int k = j + 1; k < size; ++k)
{
// Check if whether resultant sum is to zero or not
if (arr[i] + arr[j] + arr[k] < x)
{
status = true;
// Display three elements
cout << "\n (" << arr[i]
<< " + " << arr[j] << " + "
<< arr[k] << ") = "
<< (arr[i] + arr[j] + arr[k]);
}
}
}
}
if (status == false)
{
cout << " \n None\n";
}
}
};
int main()
{
// Define array elements
int arr1[] = {
8 , 2 , 0 , 6 , -2 , 6 , -1 , 9 , 4 , 3
};
// Define array elements
int arr2[] = {
9 , 2 , -7 , 4 , 1 , 3 , 0 , 7 , 22 , 8 , -4
};
// Test A
int size = sizeof(arr1) / sizeof(arr1[0]);
// Test B
size = sizeof(arr2) / sizeof(arr2[0]);
return 0;
}``````

#### Output

`````` Array :   8  2  0  6  -2  6  -1  9  4  3
Given x : 3
(2 + 0 + -2) = 0
(2 + 0 + -1) = 1
(2 + -2 + -1) = -1
(0 + -2 + -1) = -3
(0 + -2 + 4) = 2
(0 + -2 + 3) = 1
(0 + -1 + 3) = 2
(-2 + -1 + 4) = 1
(-2 + -1 + 3) = 0
Array :   8  2  0  6  -2  6  -1  9  4  3
Given x : -6
None

Array :   9  2  -7  4  1  3  0  7  22  8  -4
Given x : -2
(2 + -7 + 1) = -4
(2 + -7 + 0) = -5
(2 + -7 + -4) = -9
(-7 + 4 + 0) = -3
(-7 + 4 + -4) = -7
(-7 + 1 + 3) = -3
(-7 + 1 + 0) = -6
(-7 + 1 + -4) = -10
(-7 + 3 + 0) = -4
(-7 + 3 + -4) = -8
(-7 + 0 + -4) = -11
(-7 + 7 + -4) = -4
(-7 + 8 + -4) = -3
(1 + 0 + -4) = -3``````
``````// Include namespace system
using System;
/*
Csharp Program for
Find all triplets which sum less than given value x
*/
public class Triplets
{
//Function which is display array elements
public void display(int[] arr, int size)
{
for (int i = 0; i < size; ++i)
{
Console.Write("  " + arr[i]);
}
}
// Find all triplets which sum less than x
public void tripletsWithLessThanX(int[] arr, int size, int x)
{
if (size < 3)
{
return;
}
Console.Write("\n Array : ");
//Display array elements
this.display(arr, size);
Console.Write("\n Given x : " + x);
// Result indicator
Boolean status = false;
// Loop which is iterate the first element of result
for (int i = 0; i < size - 2; ++i)
{
// Loop which is iterate the second element of result
for (int j = i + 1; j < size - 1; ++j)
{
// Loop which is iterate the third element of result
for (int k = j + 1; k < size; ++k)
{
// Check if whether resultant sum is to zero or not
if (arr[i] + arr[j] + arr[k] < x)
{
status = true;
// Display three elements
Console.Write("\n (" +
arr[i] + " + " +
arr[j] + " + " +
arr[k] + ") = " +
(arr[i] + arr[j] + arr[k]));
}
}
}
}
if (status == false)
{
Console.Write(" \n None\n");
}
}
public static void Main(String[] args)
{
// Define array elements
int[] arr1 = {
8 , 2 , 0 , 6 , -2 , 6 , -1 , 9 , 4 , 3
};
// Define array elements
int[] arr2 = {
9 , 2 , -7 , 4 , 1 , 3 , 0 , 7 , 22 , 8 , -4
};
// Test A
int size = arr1.Length;
// Test B
size = arr2.Length;
}
}``````

#### Output

`````` Array :   8  2  0  6  -2  6  -1  9  4  3
Given x : 3
(2 + 0 + -2) = 0
(2 + 0 + -1) = 1
(2 + -2 + -1) = -1
(0 + -2 + -1) = -3
(0 + -2 + 4) = 2
(0 + -2 + 3) = 1
(0 + -1 + 3) = 2
(-2 + -1 + 4) = 1
(-2 + -1 + 3) = 0
Array :   8  2  0  6  -2  6  -1  9  4  3
Given x : -6
None

Array :   9  2  -7  4  1  3  0  7  22  8  -4
Given x : -2
(2 + -7 + 1) = -4
(2 + -7 + 0) = -5
(2 + -7 + -4) = -9
(-7 + 4 + 0) = -3
(-7 + 4 + -4) = -7
(-7 + 1 + 3) = -3
(-7 + 1 + 0) = -6
(-7 + 1 + -4) = -10
(-7 + 3 + 0) = -4
(-7 + 3 + -4) = -8
(-7 + 0 + -4) = -11
(-7 + 7 + -4) = -4
(-7 + 8 + -4) = -3
(1 + 0 + -4) = -3``````
``````package main
import "fmt"
/*
Go Program for
Find all triplets which sum less than given value x
*/

//Function which is display array elements
func display(arr[] int, size int) {
for i := 0 ; i < size ; i++ {
fmt.Print("  ", arr[i])
}
}
// Find all triplets which sum less than x
func tripletsWithLessThanX(arr[] int, size int, x int) {
if size < 3 {
return
}
fmt.Print("\n Array : ")
//Display array elements
display(arr, size)
fmt.Print("\n Given x : ", x)
// Result indicator
var status bool = false
// Loop which is iterate the first element of result
for i := 0 ; i < size - 2 ; i++ {
// Loop which is iterate the second element of result
for j := i + 1 ; j < size - 1 ; j++ {
// Loop which is iterate the third element of result
for k := j + 1 ; k < size ; k++ {
// Check if whether resultant sum is to zero or not
if arr[i] + arr[j] + arr[k] < x {
status = true
// Display three elements
fmt.Print("\n (", arr[i], " + ",
arr[j], " + ", arr[k], ") = ",
(arr[i] + arr[j] + arr[k]))
}
}
}
}
if status == false {
fmt.Print(" \n None\n")
}
}
func main() {

// Define array elements
var arr1 = [] int {8 , 2 , 0 , 6 , -2 , 6 , -1 , 9 , 4 , 3}
// Define array elements
var arr2 = [] int {9 , 2 , -7 , 4 , 1 , 3 , 0 , 7 , 22 , 8 , -4}
// Test A
var size int = len(arr1)
tripletsWithLessThanX(arr1, size, 3)
tripletsWithLessThanX(arr1, size, -6)
// Test B
size = len(arr2)
tripletsWithLessThanX(arr2, size, -2)
}``````

#### Output

`````` Array :   8  2  0  6  -2  6  -1  9  4  3
Given x : 3
(2 + 0 + -2) = 0
(2 + 0 + -1) = 1
(2 + -2 + -1) = -1
(0 + -2 + -1) = -3
(0 + -2 + 4) = 2
(0 + -2 + 3) = 1
(0 + -1 + 3) = 2
(-2 + -1 + 4) = 1
(-2 + -1 + 3) = 0
Array :   8  2  0  6  -2  6  -1  9  4  3
Given x : -6
None

Array :   9  2  -7  4  1  3  0  7  22  8  -4
Given x : -2
(2 + -7 + 1) = -4
(2 + -7 + 0) = -5
(2 + -7 + -4) = -9
(-7 + 4 + 0) = -3
(-7 + 4 + -4) = -7
(-7 + 1 + 3) = -3
(-7 + 1 + 0) = -6
(-7 + 1 + -4) = -10
(-7 + 3 + 0) = -4
(-7 + 3 + -4) = -8
(-7 + 0 + -4) = -11
(-7 + 7 + -4) = -4
(-7 + 8 + -4) = -3
(1 + 0 + -4) = -3``````
``````<?php
/*
Php Program for
Find all triplets which sum less than given value x
*/
class Triplets
{
//Function which is display array elements
public	function display(\$arr, \$size)
{
for (\$i = 0; \$i < \$size; ++\$i)
{
echo("  ".\$arr[\$i]);
}
}
// Find all triplets which sum less than x
public	function tripletsWithLessThanX(\$arr, \$size, \$x)
{
if (\$size < 3)
{
return;
}
echo("\n Array : ");
//Display array elements
\$this->display(\$arr, \$size);
echo("\n Given x : ".\$x);
// Result indicator
\$status = false;
// Loop which is iterate the first element of result
for (\$i = 0; \$i < \$size - 2; ++\$i)
{
// Loop which is iterate the second element of result
for (\$j = \$i + 1; \$j < \$size - 1; ++\$j)
{
// Loop which is iterate the third element of result
for (\$k = \$j + 1; \$k < \$size; ++\$k)
{
// Check if whether resultant sum is to zero or not
if (\$arr[\$i] + \$arr[\$j] + \$arr[\$k] < \$x)
{
\$status = true;
// Display three elements
echo("\n (".\$arr[\$i].
" + ".\$arr[\$j].
" + ".\$arr[\$k].
") = ".(\$arr[\$i] + \$arr[\$j] + \$arr[\$k]));
}
}
}
}
if (\$status == false)
{
echo(" \n None\n");
}
}
}

function main()
{
// Define array elements
\$arr1 = array(8, 2, 0, 6, -2, 6, -1, 9, 4, 3);
// Define array elements
\$arr2 = array(9, 2, -7, 4, 1, 3, 0, 7, 22, 8, -4);
// Test A
\$size = count(\$arr1);
// Test B
\$size = count(\$arr2);
}
main();``````

#### Output

`````` Array :   8  2  0  6  -2  6  -1  9  4  3
Given x : 3
(2 + 0 + -2) = 0
(2 + 0 + -1) = 1
(2 + -2 + -1) = -1
(0 + -2 + -1) = -3
(0 + -2 + 4) = 2
(0 + -2 + 3) = 1
(0 + -1 + 3) = 2
(-2 + -1 + 4) = 1
(-2 + -1 + 3) = 0
Array :   8  2  0  6  -2  6  -1  9  4  3
Given x : -6
None

Array :   9  2  -7  4  1  3  0  7  22  8  -4
Given x : -2
(2 + -7 + 1) = -4
(2 + -7 + 0) = -5
(2 + -7 + -4) = -9
(-7 + 4 + 0) = -3
(-7 + 4 + -4) = -7
(-7 + 1 + 3) = -3
(-7 + 1 + 0) = -6
(-7 + 1 + -4) = -10
(-7 + 3 + 0) = -4
(-7 + 3 + -4) = -8
(-7 + 0 + -4) = -11
(-7 + 7 + -4) = -4
(-7 + 8 + -4) = -3
(1 + 0 + -4) = -3``````
``````/*
Node JS Program for
Find all triplets which sum less than given value x
*/
class Triplets
{
//Function which is display array elements
display(arr, size)
{
for (var i = 0; i < size; ++i)
{
process.stdout.write("  " + arr[i]);
}
}
// Find all triplets which sum less than x
tripletsWithLessThanX(arr, size, x)
{
if (size < 3)
{
return;
}
process.stdout.write("\n Array : ");
//Display array elements
this.display(arr, size);
process.stdout.write("\n Given x : " + x);
// Result indicator
var status = false;
// Loop which is iterate the first element of result
for (var i = 0; i < size - 2; ++i)
{
// Loop which is iterate the second element of result
for (var j = i + 1; j < size - 1; ++j)
{
// Loop which is iterate the third element of result
for (var k = j + 1; k < size; ++k)
{
// Check if whether resultant sum is to zero or not
if (arr[i] + arr[j] + arr[k] < x)
{
status = true;
// Display three elements
process.stdout.write("\n (" +
arr[i] + " + " +
arr[j] + " + " +
arr[k] + ") = " +
(arr[i] + arr[j] + arr[k]));
}
}
}
}
if (status == false)
{
process.stdout.write(" \n None\n");
}
}
}

function main()
{
// Define array elements
var arr1 = [8, 2, 0, 6, -2, 6, -1, 9, 4, 3];
// Define array elements
var arr2 = [9, 2, -7, 4, 1, 3, 0, 7, 22, 8, -4];
// Test A
var size = arr1.length;
// Test B
size = arr2.length;
}
main();``````

#### Output

`````` Array :   8  2  0  6  -2  6  -1  9  4  3
Given x : 3
(2 + 0 + -2) = 0
(2 + 0 + -1) = 1
(2 + -2 + -1) = -1
(0 + -2 + -1) = -3
(0 + -2 + 4) = 2
(0 + -2 + 3) = 1
(0 + -1 + 3) = 2
(-2 + -1 + 4) = 1
(-2 + -1 + 3) = 0
Array :   8  2  0  6  -2  6  -1  9  4  3
Given x : -6
None

Array :   9  2  -7  4  1  3  0  7  22  8  -4
Given x : -2
(2 + -7 + 1) = -4
(2 + -7 + 0) = -5
(2 + -7 + -4) = -9
(-7 + 4 + 0) = -3
(-7 + 4 + -4) = -7
(-7 + 1 + 3) = -3
(-7 + 1 + 0) = -6
(-7 + 1 + -4) = -10
(-7 + 3 + 0) = -4
(-7 + 3 + -4) = -8
(-7 + 0 + -4) = -11
(-7 + 7 + -4) = -4
(-7 + 8 + -4) = -3
(1 + 0 + -4) = -3``````
``````#    Python 3 Program for
#    Find all triplets which sum less than given value x
class Triplets :
# Function which is display list elements
def display(self, arr, size) :
i = 0
while (i < size) :
print("  ", arr[i], end = "")
i += 1

#  Find all triplets which sum less than x
def tripletsWithLessThanX(self, arr, size, x) :
if (size < 3) :
return

print("\n Array : ", end = "")
# Display list elements
self.display(arr, size)
print("\n Given x : ", x, end = "")
#  Result indicator
status = False
i = 0
#  Loop which is iterate the first element of result
while (i < size - 2) :
j = i + 1
#  Loop which is iterate the second element of result
while (j < size - 1) :
k = j + 1
#  Loop which is iterate the third element of result
while (k < size) :
#  Check if whether resultant sum is to zero or not
if (arr[i] + arr[j] + arr[k] < x) :
status = True
#  Display three elements
print("\n (", arr[i] ," + ",
arr[j] ," + ", arr[k] ,") = ",
(arr[i] + arr[j] + arr[k]), end = "")

k += 1

j += 1

i += 1

if (status == False) :
print(" \n None")

def main() :
#  Define list elements
arr1 = [8, 2, 0, 6, -2, 6, -1, 9, 4, 3]
#  Define list elements
arr2 = [9, 2, -7, 4, 1, 3, 0, 7, 22, 8, -4]
#  Test A
size = len(arr1)
#  Test B
size = len(arr2)

if __name__ == "__main__": main()``````

#### Output

`````` Array :    8   2   0   6   -2   6   -1   9   4   3
Given x :  3
( 2  +  0  +  -2 ) =  0
( 2  +  0  +  -1 ) =  1
( 2  +  -2  +  -1 ) =  -1
( 0  +  -2  +  -1 ) =  -3
( 0  +  -2  +  4 ) =  2
( 0  +  -2  +  3 ) =  1
( 0  +  -1  +  3 ) =  2
( -2  +  -1  +  4 ) =  1
( -2  +  -1  +  3 ) =  0
Array :    8   2   0   6   -2   6   -1   9   4   3
Given x :  -6
None

Array :    9   2   -7   4   1   3   0   7   22   8   -4
Given x :  -2
( 2  +  -7  +  1 ) =  -4
( 2  +  -7  +  0 ) =  -5
( 2  +  -7  +  -4 ) =  -9
( -7  +  4  +  0 ) =  -3
( -7  +  4  +  -4 ) =  -7
( -7  +  1  +  3 ) =  -3
( -7  +  1  +  0 ) =  -6
( -7  +  1  +  -4 ) =  -10
( -7  +  3  +  0 ) =  -4
( -7  +  3  +  -4 ) =  -8
( -7  +  0  +  -4 ) =  -11
( -7  +  7  +  -4 ) =  -4
( -7  +  8  +  -4 ) =  -3
( 1  +  0  +  -4 ) =  -3``````
``````#    Ruby Program for
#    Find all triplets which sum less than given value x
class Triplets
# Function which is display array elements
def display(arr, size)
i = 0
while (i < size)
print("  ", arr[i])
i += 1
end

end

#  Find all triplets which sum less than x
def tripletsWithLessThanX(arr, size, x)
if (size < 3)
return
end

print("\n Array : ")
# Display array elements
self.display(arr, size)
print("\n Given x : ", x)
#  Result indicator
status = false
i = 0
#  Loop which is iterate the first element of result
while (i < size - 2)
j = i + 1
#  Loop which is iterate the second element of result
while (j < size - 1)
k = j + 1
#  Loop which is iterate the third element of result
while (k < size)
#  Check if whether resultant sum is to zero or not
if (arr[i] + arr[j] + arr[k] < x)
status = true
#  Display three elements
print("\n (",
arr[i] ," + ",
arr[j] ," + ",
arr[k] ,") = ",
(arr[i] + arr[j] + arr[k]))
end

k += 1
end

j += 1
end

i += 1
end

if (status == false)
print(" \n None\n")
end

end

end

def main()
#  Define array elements
arr1 = [8, 2, 0, 6, -2, 6, -1, 9, 4, 3]
#  Define array elements
arr2 = [9, 2, -7, 4, 1, 3, 0, 7, 22, 8, -4]
#  Test A
size = arr1.length
#  Test B
size = arr2.length
end

main()``````

#### Output

`````` Array :   8  2  0  6  -2  6  -1  9  4  3
Given x : 3
(2 + 0 + -2) = 0
(2 + 0 + -1) = 1
(2 + -2 + -1) = -1
(0 + -2 + -1) = -3
(0 + -2 + 4) = 2
(0 + -2 + 3) = 1
(0 + -1 + 3) = 2
(-2 + -1 + 4) = 1
(-2 + -1 + 3) = 0
Array :   8  2  0  6  -2  6  -1  9  4  3
Given x : -6
None

Array :   9  2  -7  4  1  3  0  7  22  8  -4
Given x : -2
(2 + -7 + 1) = -4
(2 + -7 + 0) = -5
(2 + -7 + -4) = -9
(-7 + 4 + 0) = -3
(-7 + 4 + -4) = -7
(-7 + 1 + 3) = -3
(-7 + 1 + 0) = -6
(-7 + 1 + -4) = -10
(-7 + 3 + 0) = -4
(-7 + 3 + -4) = -8
(-7 + 0 + -4) = -11
(-7 + 7 + -4) = -4
(-7 + 8 + -4) = -3
(1 + 0 + -4) = -3``````
``````/*
Scala Program for
Find all triplets which sum less than given value x
*/
class Triplets()
{
//Function which is display array elements
def display(arr: Array[Int], size: Int): Unit = {
var i: Int = 0;
while (i < size)
{
print("  " + arr(i));
i += 1;
}
}
// Find all triplets which sum less than x
def tripletsWithLessThanX(arr: Array[Int], size: Int, x: Int): Unit = {
if (size < 3)
{
return;
}
print("\n Array : ");
//Display array elements
display(arr, size);
print("\n Given x : " + x);
// Result indicator
var status: Boolean = false;
var i: Int = 0;
// Loop which is iterate the first element of result
while (i < size - 2)
{
var j: Int = i + 1;
// Loop which is iterate the second element of result
while (j < size - 1)
{
var k: Int = j + 1;
// Loop which is iterate the third element of result
while (k < size)
{
// Check if whether resultant sum is to zero or not
if (arr(i) + arr(j) + arr(k) < x)
{
status = true;
// Display three elements
print("\n (" + arr(i) + " + " +
arr(j) + " + " + arr(k) + ") = " +
(arr(i) + arr(j) + arr(k)));
}
k += 1;
}
j += 1;
}
i += 1;
}
if (status == false)
{
print(" \n None\n");
}
}
}
object Main
{
def main(args: Array[String]): Unit = {
var task: Triplets = new Triplets();
// Define array elements
var arr1: Array[Int] = Array(8, 2, 0, 6, -2, 6, -1, 9, 4, 3);
// Define array elements
var arr2: Array[Int] = Array(9, 2, -7, 4, 1, 3, 0, 7, 22, 8, -4);
// Test A
var size: Int = arr1.length;
// Test B
size = arr2.length;
}
}``````

#### Output

`````` Array :   8  2  0  6  -2  6  -1  9  4  3
Given x : 3
(2 + 0 + -2) = 0
(2 + 0 + -1) = 1
(2 + -2 + -1) = -1
(0 + -2 + -1) = -3
(0 + -2 + 4) = 2
(0 + -2 + 3) = 1
(0 + -1 + 3) = 2
(-2 + -1 + 4) = 1
(-2 + -1 + 3) = 0
Array :   8  2  0  6  -2  6  -1  9  4  3
Given x : -6
None

Array :   9  2  -7  4  1  3  0  7  22  8  -4
Given x : -2
(2 + -7 + 1) = -4
(2 + -7 + 0) = -5
(2 + -7 + -4) = -9
(-7 + 4 + 0) = -3
(-7 + 4 + -4) = -7
(-7 + 1 + 3) = -3
(-7 + 1 + 0) = -6
(-7 + 1 + -4) = -10
(-7 + 3 + 0) = -4
(-7 + 3 + -4) = -8
(-7 + 0 + -4) = -11
(-7 + 7 + -4) = -4
(-7 + 8 + -4) = -3
(1 + 0 + -4) = -3``````
``````import Foundation;
/*
Swift 4 Program for
Find all triplets which sum less than given value x
*/
class Triplets
{
//Function which is display array elements
func display(_ arr: [Int], _ size: Int)
{
var i: Int = 0;
while (i < size)
{
print("  ", arr[i], terminator: "");
i += 1;
}
}
// Find all triplets which sum less than x
func tripletsWithLessThanX(_ arr: [Int], _ size: Int, _ x: Int)
{
if (size < 3)
{
return;
}
print("\n Array : ", terminator: "");
//Display array elements
self.display(arr, size);
print("\n Given x : ", x, terminator: "");
// Result indicator
var status: Bool = false;
var i: Int = 0;
// Loop which is iterate the first element of result
while (i < size - 2)
{
var j: Int = i + 1;
// Loop which is iterate the second element of result
while (j < size - 1)
{
var k: Int = j + 1;
// Loop which is iterate the third element of result
while (k < size)
{
// Check if whether resultant sum is to zero or not
if (arr[i] + arr[j] + arr[k] < x)
{
status = true;
// Display three elements
print("\n (", arr[i] ,"+",
arr[j] ,"+", arr[k] ,") = ",
(arr[i] + arr[j] + arr[k]), terminator: "");
}
k += 1;
}
j += 1;
}
i += 1;
}
if (status == false)
{
print(" \n None");
}
}
}
func main()
{
// Define array elements
let arr1: [Int] = [8, 2, 0, 6, -2, 6, -1, 9, 4, 3];
// Define array elements
let arr2: [Int] = [9, 2, -7, 4, 1, 3, 0, 7, 22, 8, -4];
// Test A
var size: Int = arr1.count;
// Test B
size = arr2.count;
}
main();``````

#### Output

`````` Array :    8   2   0   6   -2   6   -1   9   4   3
Given x :  3
( 2 + 0 + -2 ) =  0
( 2 + 0 + -1 ) =  1
( 2 + -2 + -1 ) =  -1
( 0 + -2 + -1 ) =  -3
( 0 + -2 + 4 ) =  2
( 0 + -2 + 3 ) =  1
( 0 + -1 + 3 ) =  2
( -2 + -1 + 4 ) =  1
( -2 + -1 + 3 ) =  0
Array :    8   2   0   6   -2   6   -1   9   4   3
Given x :  -6
None

Array :    9   2   -7   4   1   3   0   7   22   8   -4
Given x :  -2
( 2 + -7 + 1 ) =  -4
( 2 + -7 + 0 ) =  -5
( 2 + -7 + -4 ) =  -9
( -7 + 4 + 0 ) =  -3
( -7 + 4 + -4 ) =  -7
( -7 + 1 + 3 ) =  -3
( -7 + 1 + 0 ) =  -6
( -7 + 1 + -4 ) =  -10
( -7 + 3 + 0 ) =  -4
( -7 + 3 + -4 ) =  -8
( -7 + 0 + -4 ) =  -11
( -7 + 7 + -4 ) =  -4
( -7 + 8 + -4 ) =  -3
( 1 + 0 + -4 ) =  -3``````
``````/*
Kotlin Program for
Find all triplets which sum less than given value x
*/
class Triplets
{
//Function which is display array elements
fun display(arr: Array < Int > , size: Int): Unit
{
var i: Int = 0;
while (i < size)
{
print("  " + arr[i]);
i += 1;
}
}
// Find all triplets which sum less than x
fun tripletsWithLessThanX(arr: Array < Int > , size: Int, x: Int): Unit
{
if (size < 3)
{
return;
}
print("\n Array : ");
//Display array elements
this.display(arr, size);
print("\n Given x : " + x);
// Result indicator
var status: Boolean = false;
var i: Int = 0;
// Loop which is iterate the first element of result
while (i < size - 2)
{
var j: Int = i + 1;
// Loop which is iterate the second element of result
while (j < size - 1)
{
var k: Int = j + 1;
// Loop which is iterate the third element of result
while (k < size)
{
// Check if whether resultant sum is to zero or not
if (arr[i] + arr[j] + arr[k] < x)
{
status = true;
// Display three elements
print("\n (" + arr[i] + " + " +
arr[j] + " + " + arr[k] + ") = " +
(arr[i] + arr[j] + arr[k]));
}
k += 1;
}
j += 1;
}
i += 1;
}
if (status == false)
{
print(" \n None\n");
}
}
}
fun main(args: Array < String > ): Unit
{
// Define array elements
val arr1: Array < Int > = arrayOf(8, 2, 0, 6, -2, 6, -1, 9, 4, 3);
// Define array elements
val arr2: Array < Int > = arrayOf(9, 2, -7, 4, 1, 3, 0, 7, 22, 8, -4);
// Test A
var size: Int = arr1.count();
// Test B
size = arr2.count();
}``````

#### Output

`````` Array :   8  2  0  6  -2  6  -1  9  4  3
Given x : 3
(2 + 0 + -2) = 0
(2 + 0 + -1) = 1
(2 + -2 + -1) = -1
(0 + -2 + -1) = -3
(0 + -2 + 4) = 2
(0 + -2 + 3) = 1
(0 + -1 + 3) = 2
(-2 + -1 + 4) = 1
(-2 + -1 + 3) = 0
Array :   8  2  0  6  -2  6  -1  9  4  3
Given x : -6
None

Array :   9  2  -7  4  1  3  0  7  22  8  -4
Given x : -2
(2 + -7 + 1) = -4
(2 + -7 + 0) = -5
(2 + -7 + -4) = -9
(-7 + 4 + 0) = -3
(-7 + 4 + -4) = -7
(-7 + 1 + 3) = -3
(-7 + 1 + 0) = -6
(-7 + 1 + -4) = -10
(-7 + 3 + 0) = -4
(-7 + 3 + -4) = -8
(-7 + 0 + -4) = -11
(-7 + 7 + -4) = -4
(-7 + 8 + -4) = -3
(1 + 0 + -4) = -3``````

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