Find all triplets which sum less than given value x
Here given code implementation process.
// C Program
// Find all triplets which sum less than given value x
#include <stdio.h>
//Function which is display array elements
void display(int arr[], int size)
{
for (int i = 0; i < size; ++i)
{
printf("%d ", arr[i]);
}
}
// Find all triplets which sum less than x
void tripletsWithLessThanX(int arr[], int size, int x)
{
if (size < 3)
{
return;
}
printf(" Array : ");
//Display array elements
display(arr, size);
printf("\n Given x : %d", x);
// Result indicator
int status = 0;
// Loop which is iterate the first element of result
for (int i = 0; i < size - 2; ++i)
{
// Loop which is iterate the second element of result
for (int j = i + 1; j < size - 1; ++j)
{
// Loop which is iterate the third element of result
for (int k = j + 1; k < size; ++k)
{
// Check if whether resultant sum is to zero or not
if (arr[i] + arr[j] + arr[k] < x)
{
status = 1;
// Display three elements
printf("\n (%d + %d + %d) = %d",
arr[i], arr[j], arr[k],
(arr[i] + arr[j] + arr[k]));
}
}
}
}
if (status == 0)
{
printf(" \n None\n");
}
printf("\n");
}
int main()
{
//Define array elements
int arr1[] = {
8 , 2 , 0 , 6 , -2 , 6 , -1 , 9 , 4 , 3
};
// Define array elements
int arr2[] = {
9 , 2 , -7 , 4 , 1 , 3 , 0 , 7 , 22 , 8 , -4
};
// Test A
int size = sizeof(arr1) / sizeof(arr1[0]);
tripletsWithLessThanX(arr1, size, 3);
tripletsWithLessThanX(arr1, size, -6);
// Test B
size = sizeof(arr2) / sizeof(arr2[0]);
tripletsWithLessThanX(arr2, size, -2);
return 0;
}Output
Array : 8 2 0 6 -2 6 -1 9 4 3
Given x : 3
(2 + 0 + -2) = 0
(2 + 0 + -1) = 1
(2 + -2 + -1) = -1
(0 + -2 + -1) = -3
(0 + -2 + 4) = 2
(0 + -2 + 3) = 1
(0 + -1 + 3) = 2
(-2 + -1 + 4) = 1
(-2 + -1 + 3) = 0
Array : 8 2 0 6 -2 6 -1 9 4 3
Given x : -6
None
Array : 9 2 -7 4 1 3 0 7 22 8 -4
Given x : -2
(2 + -7 + 1) = -4
(2 + -7 + 0) = -5
(2 + -7 + -4) = -9
(-7 + 4 + 0) = -3
(-7 + 4 + -4) = -7
(-7 + 1 + 3) = -3
(-7 + 1 + 0) = -6
(-7 + 1 + -4) = -10
(-7 + 3 + 0) = -4
(-7 + 3 + -4) = -8
(-7 + 0 + -4) = -11
(-7 + 7 + -4) = -4
(-7 + 8 + -4) = -3
(1 + 0 + -4) = -3/*
Java Program for
Find all triplets which sum less than given value x
*/
public class Triplets
{
//Function which is display array elements
public void display(int[] arr, int size)
{
for (int i = 0; i < size; ++i)
{
System.out.print(" " + arr[i]);
}
}
// Find all triplets which sum less than x
public void tripletsWithLessThanX(int[] arr, int size, int x)
{
if (size < 3)
{
return;
}
System.out.print("\n Array : ");
//Display array elements
display(arr, size);
System.out.print("\n Given x : " + x);
// Result indicator
boolean status = false;
// Loop which is iterate the first element of result
for (int i = 0; i < size - 2; ++i)
{
// Loop which is iterate the second element of result
for (int j = i + 1; j < size - 1; ++j)
{
// Loop which is iterate the third element of result
for (int k = j + 1; k < size; ++k)
{
// Check if whether resultant sum is to zero or not
if (arr[i] + arr[j] + arr[k] < x)
{
status = true;
// Display three elements
System.out.print("\n (" +
arr[i] + " + " +
arr[j] + " + " +
arr[k] + ") = " +
(arr[i] + arr[j] + arr[k]));
}
}
}
}
if (status == false)
{
System.out.print(" \n None\n");
}
}
public static void main(String[] args)
{
Triplets task = new Triplets();
// Define array elements
int[] arr1 = {
8 , 2 , 0 , 6 , -2 , 6 , -1 , 9 , 4 , 3
};
// Define array elements
int[] arr2 = {
9 , 2 , -7 , 4 , 1 , 3 , 0 , 7 , 22 , 8 , -4
};
// Test A
int size = arr1.length;
task.tripletsWithLessThanX(arr1, size, 3);
task.tripletsWithLessThanX(arr1, size, -6);
// Test B
size = arr2.length;
task.tripletsWithLessThanX(arr2, size, -2);
}
}Output
Array : 8 2 0 6 -2 6 -1 9 4 3
Given x : 3
(2 + 0 + -2) = 0
(2 + 0 + -1) = 1
(2 + -2 + -1) = -1
(0 + -2 + -1) = -3
(0 + -2 + 4) = 2
(0 + -2 + 3) = 1
(0 + -1 + 3) = 2
(-2 + -1 + 4) = 1
(-2 + -1 + 3) = 0
Array : 8 2 0 6 -2 6 -1 9 4 3
Given x : -6
None
Array : 9 2 -7 4 1 3 0 7 22 8 -4
Given x : -2
(2 + -7 + 1) = -4
(2 + -7 + 0) = -5
(2 + -7 + -4) = -9
(-7 + 4 + 0) = -3
(-7 + 4 + -4) = -7
(-7 + 1 + 3) = -3
(-7 + 1 + 0) = -6
(-7 + 1 + -4) = -10
(-7 + 3 + 0) = -4
(-7 + 3 + -4) = -8
(-7 + 0 + -4) = -11
(-7 + 7 + -4) = -4
(-7 + 8 + -4) = -3
(1 + 0 + -4) = -3// Include header file
#include <iostream>
using namespace std;
/*
C++ Program for
Find all triplets which sum less than given value x
*/
class Triplets
{
public:
//Function which is display array elements
void display(int arr[], int size)
{
for (int i = 0; i < size; ++i)
{
cout << " " << arr[i];
}
}
// Find all triplets which sum less than x
void tripletsWithLessThanX(int arr[], int size, int x)
{
if (size < 3)
{
return;
}
cout << "\n Array : ";
//Display array elements
this->display(arr, size);
cout << "\n Given x : " << x;
// Result indicator
bool status = false;
// Loop which is iterate the first element of result
for (int i = 0; i < size - 2; ++i)
{
// Loop which is iterate the second element of result
for (int j = i + 1; j < size - 1; ++j)
{
// Loop which is iterate the third element of result
for (int k = j + 1; k < size; ++k)
{
// Check if whether resultant sum is to zero or not
if (arr[i] + arr[j] + arr[k] < x)
{
status = true;
// Display three elements
cout << "\n (" << arr[i]
<< " + " << arr[j] << " + "
<< arr[k] << ") = "
<< (arr[i] + arr[j] + arr[k]);
}
}
}
}
if (status == false)
{
cout << " \n None\n";
}
}
};
int main()
{
Triplets *task = new Triplets();
// Define array elements
int arr1[] = {
8 , 2 , 0 , 6 , -2 , 6 , -1 , 9 , 4 , 3
};
// Define array elements
int arr2[] = {
9 , 2 , -7 , 4 , 1 , 3 , 0 , 7 , 22 , 8 , -4
};
// Test A
int size = sizeof(arr1) / sizeof(arr1[0]);
task->tripletsWithLessThanX(arr1, size, 3);
task->tripletsWithLessThanX(arr1, size, -6);
// Test B
size = sizeof(arr2) / sizeof(arr2[0]);
task->tripletsWithLessThanX(arr2, size, -2);
return 0;
}Output
Array : 8 2 0 6 -2 6 -1 9 4 3
Given x : 3
(2 + 0 + -2) = 0
(2 + 0 + -1) = 1
(2 + -2 + -1) = -1
(0 + -2 + -1) = -3
(0 + -2 + 4) = 2
(0 + -2 + 3) = 1
(0 + -1 + 3) = 2
(-2 + -1 + 4) = 1
(-2 + -1 + 3) = 0
Array : 8 2 0 6 -2 6 -1 9 4 3
Given x : -6
None
Array : 9 2 -7 4 1 3 0 7 22 8 -4
Given x : -2
(2 + -7 + 1) = -4
(2 + -7 + 0) = -5
(2 + -7 + -4) = -9
(-7 + 4 + 0) = -3
(-7 + 4 + -4) = -7
(-7 + 1 + 3) = -3
(-7 + 1 + 0) = -6
(-7 + 1 + -4) = -10
(-7 + 3 + 0) = -4
(-7 + 3 + -4) = -8
(-7 + 0 + -4) = -11
(-7 + 7 + -4) = -4
(-7 + 8 + -4) = -3
(1 + 0 + -4) = -3// Include namespace system
using System;
/*
Csharp Program for
Find all triplets which sum less than given value x
*/
public class Triplets
{
//Function which is display array elements
public void display(int[] arr, int size)
{
for (int i = 0; i < size; ++i)
{
Console.Write(" " + arr[i]);
}
}
// Find all triplets which sum less than x
public void tripletsWithLessThanX(int[] arr, int size, int x)
{
if (size < 3)
{
return;
}
Console.Write("\n Array : ");
//Display array elements
this.display(arr, size);
Console.Write("\n Given x : " + x);
// Result indicator
Boolean status = false;
// Loop which is iterate the first element of result
for (int i = 0; i < size - 2; ++i)
{
// Loop which is iterate the second element of result
for (int j = i + 1; j < size - 1; ++j)
{
// Loop which is iterate the third element of result
for (int k = j + 1; k < size; ++k)
{
// Check if whether resultant sum is to zero or not
if (arr[i] + arr[j] + arr[k] < x)
{
status = true;
// Display three elements
Console.Write("\n (" +
arr[i] + " + " +
arr[j] + " + " +
arr[k] + ") = " +
(arr[i] + arr[j] + arr[k]));
}
}
}
}
if (status == false)
{
Console.Write(" \n None\n");
}
}
public static void Main(String[] args)
{
Triplets task = new Triplets();
// Define array elements
int[] arr1 = {
8 , 2 , 0 , 6 , -2 , 6 , -1 , 9 , 4 , 3
};
// Define array elements
int[] arr2 = {
9 , 2 , -7 , 4 , 1 , 3 , 0 , 7 , 22 , 8 , -4
};
// Test A
int size = arr1.Length;
task.tripletsWithLessThanX(arr1, size, 3);
task.tripletsWithLessThanX(arr1, size, -6);
// Test B
size = arr2.Length;
task.tripletsWithLessThanX(arr2, size, -2);
}
}Output
Array : 8 2 0 6 -2 6 -1 9 4 3
Given x : 3
(2 + 0 + -2) = 0
(2 + 0 + -1) = 1
(2 + -2 + -1) = -1
(0 + -2 + -1) = -3
(0 + -2 + 4) = 2
(0 + -2 + 3) = 1
(0 + -1 + 3) = 2
(-2 + -1 + 4) = 1
(-2 + -1 + 3) = 0
Array : 8 2 0 6 -2 6 -1 9 4 3
Given x : -6
None
Array : 9 2 -7 4 1 3 0 7 22 8 -4
Given x : -2
(2 + -7 + 1) = -4
(2 + -7 + 0) = -5
(2 + -7 + -4) = -9
(-7 + 4 + 0) = -3
(-7 + 4 + -4) = -7
(-7 + 1 + 3) = -3
(-7 + 1 + 0) = -6
(-7 + 1 + -4) = -10
(-7 + 3 + 0) = -4
(-7 + 3 + -4) = -8
(-7 + 0 + -4) = -11
(-7 + 7 + -4) = -4
(-7 + 8 + -4) = -3
(1 + 0 + -4) = -3package main
import "fmt"
/*
Go Program for
Find all triplets which sum less than given value x
*/
//Function which is display array elements
func display(arr[] int, size int) {
for i := 0 ; i < size ; i++ {
fmt.Print(" ", arr[i])
}
}
// Find all triplets which sum less than x
func tripletsWithLessThanX(arr[] int, size int, x int) {
if size < 3 {
return
}
fmt.Print("\n Array : ")
//Display array elements
display(arr, size)
fmt.Print("\n Given x : ", x)
// Result indicator
var status bool = false
// Loop which is iterate the first element of result
for i := 0 ; i < size - 2 ; i++ {
// Loop which is iterate the second element of result
for j := i + 1 ; j < size - 1 ; j++ {
// Loop which is iterate the third element of result
for k := j + 1 ; k < size ; k++ {
// Check if whether resultant sum is to zero or not
if arr[i] + arr[j] + arr[k] < x {
status = true
// Display three elements
fmt.Print("\n (", arr[i], " + ",
arr[j], " + ", arr[k], ") = ",
(arr[i] + arr[j] + arr[k]))
}
}
}
}
if status == false {
fmt.Print(" \n None\n")
}
}
func main() {
// Define array elements
var arr1 = [] int {8 , 2 , 0 , 6 , -2 , 6 , -1 , 9 , 4 , 3}
// Define array elements
var arr2 = [] int {9 , 2 , -7 , 4 , 1 , 3 , 0 , 7 , 22 , 8 , -4}
// Test A
var size int = len(arr1)
tripletsWithLessThanX(arr1, size, 3)
tripletsWithLessThanX(arr1, size, -6)
// Test B
size = len(arr2)
tripletsWithLessThanX(arr2, size, -2)
}Output
Array : 8 2 0 6 -2 6 -1 9 4 3
Given x : 3
(2 + 0 + -2) = 0
(2 + 0 + -1) = 1
(2 + -2 + -1) = -1
(0 + -2 + -1) = -3
(0 + -2 + 4) = 2
(0 + -2 + 3) = 1
(0 + -1 + 3) = 2
(-2 + -1 + 4) = 1
(-2 + -1 + 3) = 0
Array : 8 2 0 6 -2 6 -1 9 4 3
Given x : -6
None
Array : 9 2 -7 4 1 3 0 7 22 8 -4
Given x : -2
(2 + -7 + 1) = -4
(2 + -7 + 0) = -5
(2 + -7 + -4) = -9
(-7 + 4 + 0) = -3
(-7 + 4 + -4) = -7
(-7 + 1 + 3) = -3
(-7 + 1 + 0) = -6
(-7 + 1 + -4) = -10
(-7 + 3 + 0) = -4
(-7 + 3 + -4) = -8
(-7 + 0 + -4) = -11
(-7 + 7 + -4) = -4
(-7 + 8 + -4) = -3
(1 + 0 + -4) = -3<?php
/*
Php Program for
Find all triplets which sum less than given value x
*/
class Triplets
{
//Function which is display array elements
public function display($arr, $size)
{
for ($i = 0; $i < $size; ++$i)
{
echo(" ".$arr[$i]);
}
}
// Find all triplets which sum less than x
public function tripletsWithLessThanX($arr, $size, $x)
{
if ($size < 3)
{
return;
}
echo("\n Array : ");
//Display array elements
$this->display($arr, $size);
echo("\n Given x : ".$x);
// Result indicator
$status = false;
// Loop which is iterate the first element of result
for ($i = 0; $i < $size - 2; ++$i)
{
// Loop which is iterate the second element of result
for ($j = $i + 1; $j < $size - 1; ++$j)
{
// Loop which is iterate the third element of result
for ($k = $j + 1; $k < $size; ++$k)
{
// Check if whether resultant sum is to zero or not
if ($arr[$i] + $arr[$j] + $arr[$k] < $x)
{
$status = true;
// Display three elements
echo("\n (".$arr[$i].
" + ".$arr[$j].
" + ".$arr[$k].
") = ".($arr[$i] + $arr[$j] + $arr[$k]));
}
}
}
}
if ($status == false)
{
echo(" \n None\n");
}
}
}
function main()
{
$task = new Triplets();
// Define array elements
$arr1 = array(8, 2, 0, 6, -2, 6, -1, 9, 4, 3);
// Define array elements
$arr2 = array(9, 2, -7, 4, 1, 3, 0, 7, 22, 8, -4);
// Test A
$size = count($arr1);
$task->tripletsWithLessThanX($arr1, $size, 3);
$task->tripletsWithLessThanX($arr1, $size, -6);
// Test B
$size = count($arr2);
$task->tripletsWithLessThanX($arr2, $size, -2);
}
main();Output
Array : 8 2 0 6 -2 6 -1 9 4 3
Given x : 3
(2 + 0 + -2) = 0
(2 + 0 + -1) = 1
(2 + -2 + -1) = -1
(0 + -2 + -1) = -3
(0 + -2 + 4) = 2
(0 + -2 + 3) = 1
(0 + -1 + 3) = 2
(-2 + -1 + 4) = 1
(-2 + -1 + 3) = 0
Array : 8 2 0 6 -2 6 -1 9 4 3
Given x : -6
None
Array : 9 2 -7 4 1 3 0 7 22 8 -4
Given x : -2
(2 + -7 + 1) = -4
(2 + -7 + 0) = -5
(2 + -7 + -4) = -9
(-7 + 4 + 0) = -3
(-7 + 4 + -4) = -7
(-7 + 1 + 3) = -3
(-7 + 1 + 0) = -6
(-7 + 1 + -4) = -10
(-7 + 3 + 0) = -4
(-7 + 3 + -4) = -8
(-7 + 0 + -4) = -11
(-7 + 7 + -4) = -4
(-7 + 8 + -4) = -3
(1 + 0 + -4) = -3/*
Node JS Program for
Find all triplets which sum less than given value x
*/
class Triplets
{
//Function which is display array elements
display(arr, size)
{
for (var i = 0; i < size; ++i)
{
process.stdout.write(" " + arr[i]);
}
}
// Find all triplets which sum less than x
tripletsWithLessThanX(arr, size, x)
{
if (size < 3)
{
return;
}
process.stdout.write("\n Array : ");
//Display array elements
this.display(arr, size);
process.stdout.write("\n Given x : " + x);
// Result indicator
var status = false;
// Loop which is iterate the first element of result
for (var i = 0; i < size - 2; ++i)
{
// Loop which is iterate the second element of result
for (var j = i + 1; j < size - 1; ++j)
{
// Loop which is iterate the third element of result
for (var k = j + 1; k < size; ++k)
{
// Check if whether resultant sum is to zero or not
if (arr[i] + arr[j] + arr[k] < x)
{
status = true;
// Display three elements
process.stdout.write("\n (" +
arr[i] + " + " +
arr[j] + " + " +
arr[k] + ") = " +
(arr[i] + arr[j] + arr[k]));
}
}
}
}
if (status == false)
{
process.stdout.write(" \n None\n");
}
}
}
function main()
{
var task = new Triplets();
// Define array elements
var arr1 = [8, 2, 0, 6, -2, 6, -1, 9, 4, 3];
// Define array elements
var arr2 = [9, 2, -7, 4, 1, 3, 0, 7, 22, 8, -4];
// Test A
var size = arr1.length;
task.tripletsWithLessThanX(arr1, size, 3);
task.tripletsWithLessThanX(arr1, size, -6);
// Test B
size = arr2.length;
task.tripletsWithLessThanX(arr2, size, -2);
}
main();Output
Array : 8 2 0 6 -2 6 -1 9 4 3
Given x : 3
(2 + 0 + -2) = 0
(2 + 0 + -1) = 1
(2 + -2 + -1) = -1
(0 + -2 + -1) = -3
(0 + -2 + 4) = 2
(0 + -2 + 3) = 1
(0 + -1 + 3) = 2
(-2 + -1 + 4) = 1
(-2 + -1 + 3) = 0
Array : 8 2 0 6 -2 6 -1 9 4 3
Given x : -6
None
Array : 9 2 -7 4 1 3 0 7 22 8 -4
Given x : -2
(2 + -7 + 1) = -4
(2 + -7 + 0) = -5
(2 + -7 + -4) = -9
(-7 + 4 + 0) = -3
(-7 + 4 + -4) = -7
(-7 + 1 + 3) = -3
(-7 + 1 + 0) = -6
(-7 + 1 + -4) = -10
(-7 + 3 + 0) = -4
(-7 + 3 + -4) = -8
(-7 + 0 + -4) = -11
(-7 + 7 + -4) = -4
(-7 + 8 + -4) = -3
(1 + 0 + -4) = -3# Python 3 Program for
# Find all triplets which sum less than given value x
class Triplets :
# Function which is display list elements
def display(self, arr, size) :
i = 0
while (i < size) :
print(" ", arr[i], end = "")
i += 1
# Find all triplets which sum less than x
def tripletsWithLessThanX(self, arr, size, x) :
if (size < 3) :
return
print("\n Array : ", end = "")
# Display list elements
self.display(arr, size)
print("\n Given x : ", x, end = "")
# Result indicator
status = False
i = 0
# Loop which is iterate the first element of result
while (i < size - 2) :
j = i + 1
# Loop which is iterate the second element of result
while (j < size - 1) :
k = j + 1
# Loop which is iterate the third element of result
while (k < size) :
# Check if whether resultant sum is to zero or not
if (arr[i] + arr[j] + arr[k] < x) :
status = True
# Display three elements
print("\n (", arr[i] ," + ",
arr[j] ," + ", arr[k] ,") = ",
(arr[i] + arr[j] + arr[k]), end = "")
k += 1
j += 1
i += 1
if (status == False) :
print(" \n None")
def main() :
task = Triplets()
# Define list elements
arr1 = [8, 2, 0, 6, -2, 6, -1, 9, 4, 3]
# Define list elements
arr2 = [9, 2, -7, 4, 1, 3, 0, 7, 22, 8, -4]
# Test A
size = len(arr1)
task.tripletsWithLessThanX(arr1, size, 3)
task.tripletsWithLessThanX(arr1, size, -6)
# Test B
size = len(arr2)
task.tripletsWithLessThanX(arr2, size, -2)
if __name__ == "__main__": main()Output
Array : 8 2 0 6 -2 6 -1 9 4 3
Given x : 3
( 2 + 0 + -2 ) = 0
( 2 + 0 + -1 ) = 1
( 2 + -2 + -1 ) = -1
( 0 + -2 + -1 ) = -3
( 0 + -2 + 4 ) = 2
( 0 + -2 + 3 ) = 1
( 0 + -1 + 3 ) = 2
( -2 + -1 + 4 ) = 1
( -2 + -1 + 3 ) = 0
Array : 8 2 0 6 -2 6 -1 9 4 3
Given x : -6
None
Array : 9 2 -7 4 1 3 0 7 22 8 -4
Given x : -2
( 2 + -7 + 1 ) = -4
( 2 + -7 + 0 ) = -5
( 2 + -7 + -4 ) = -9
( -7 + 4 + 0 ) = -3
( -7 + 4 + -4 ) = -7
( -7 + 1 + 3 ) = -3
( -7 + 1 + 0 ) = -6
( -7 + 1 + -4 ) = -10
( -7 + 3 + 0 ) = -4
( -7 + 3 + -4 ) = -8
( -7 + 0 + -4 ) = -11
( -7 + 7 + -4 ) = -4
( -7 + 8 + -4 ) = -3
( 1 + 0 + -4 ) = -3# Ruby Program for
# Find all triplets which sum less than given value x
class Triplets
# Function which is display array elements
def display(arr, size)
i = 0
while (i < size)
print(" ", arr[i])
i += 1
end
end
# Find all triplets which sum less than x
def tripletsWithLessThanX(arr, size, x)
if (size < 3)
return
end
print("\n Array : ")
# Display array elements
self.display(arr, size)
print("\n Given x : ", x)
# Result indicator
status = false
i = 0
# Loop which is iterate the first element of result
while (i < size - 2)
j = i + 1
# Loop which is iterate the second element of result
while (j < size - 1)
k = j + 1
# Loop which is iterate the third element of result
while (k < size)
# Check if whether resultant sum is to zero or not
if (arr[i] + arr[j] + arr[k] < x)
status = true
# Display three elements
print("\n (",
arr[i] ," + ",
arr[j] ," + ",
arr[k] ,") = ",
(arr[i] + arr[j] + arr[k]))
end
k += 1
end
j += 1
end
i += 1
end
if (status == false)
print(" \n None\n")
end
end
end
def main()
task = Triplets.new()
# Define array elements
arr1 = [8, 2, 0, 6, -2, 6, -1, 9, 4, 3]
# Define array elements
arr2 = [9, 2, -7, 4, 1, 3, 0, 7, 22, 8, -4]
# Test A
size = arr1.length
task.tripletsWithLessThanX(arr1, size, 3)
task.tripletsWithLessThanX(arr1, size, -6)
# Test B
size = arr2.length
task.tripletsWithLessThanX(arr2, size, -2)
end
main()Output
Array : 8 2 0 6 -2 6 -1 9 4 3
Given x : 3
(2 + 0 + -2) = 0
(2 + 0 + -1) = 1
(2 + -2 + -1) = -1
(0 + -2 + -1) = -3
(0 + -2 + 4) = 2
(0 + -2 + 3) = 1
(0 + -1 + 3) = 2
(-2 + -1 + 4) = 1
(-2 + -1 + 3) = 0
Array : 8 2 0 6 -2 6 -1 9 4 3
Given x : -6
None
Array : 9 2 -7 4 1 3 0 7 22 8 -4
Given x : -2
(2 + -7 + 1) = -4
(2 + -7 + 0) = -5
(2 + -7 + -4) = -9
(-7 + 4 + 0) = -3
(-7 + 4 + -4) = -7
(-7 + 1 + 3) = -3
(-7 + 1 + 0) = -6
(-7 + 1 + -4) = -10
(-7 + 3 + 0) = -4
(-7 + 3 + -4) = -8
(-7 + 0 + -4) = -11
(-7 + 7 + -4) = -4
(-7 + 8 + -4) = -3
(1 + 0 + -4) = -3/*
Scala Program for
Find all triplets which sum less than given value x
*/
class Triplets()
{
//Function which is display array elements
def display(arr: Array[Int], size: Int): Unit = {
var i: Int = 0;
while (i < size)
{
print(" " + arr(i));
i += 1;
}
}
// Find all triplets which sum less than x
def tripletsWithLessThanX(arr: Array[Int], size: Int, x: Int): Unit = {
if (size < 3)
{
return;
}
print("\n Array : ");
//Display array elements
display(arr, size);
print("\n Given x : " + x);
// Result indicator
var status: Boolean = false;
var i: Int = 0;
// Loop which is iterate the first element of result
while (i < size - 2)
{
var j: Int = i + 1;
// Loop which is iterate the second element of result
while (j < size - 1)
{
var k: Int = j + 1;
// Loop which is iterate the third element of result
while (k < size)
{
// Check if whether resultant sum is to zero or not
if (arr(i) + arr(j) + arr(k) < x)
{
status = true;
// Display three elements
print("\n (" + arr(i) + " + " +
arr(j) + " + " + arr(k) + ") = " +
(arr(i) + arr(j) + arr(k)));
}
k += 1;
}
j += 1;
}
i += 1;
}
if (status == false)
{
print(" \n None\n");
}
}
}
object Main
{
def main(args: Array[String]): Unit = {
var task: Triplets = new Triplets();
// Define array elements
var arr1: Array[Int] = Array(8, 2, 0, 6, -2, 6, -1, 9, 4, 3);
// Define array elements
var arr2: Array[Int] = Array(9, 2, -7, 4, 1, 3, 0, 7, 22, 8, -4);
// Test A
var size: Int = arr1.length;
task.tripletsWithLessThanX(arr1, size, 3);
task.tripletsWithLessThanX(arr1, size, -6);
// Test B
size = arr2.length;
task.tripletsWithLessThanX(arr2, size, -2);
}
}Output
Array : 8 2 0 6 -2 6 -1 9 4 3
Given x : 3
(2 + 0 + -2) = 0
(2 + 0 + -1) = 1
(2 + -2 + -1) = -1
(0 + -2 + -1) = -3
(0 + -2 + 4) = 2
(0 + -2 + 3) = 1
(0 + -1 + 3) = 2
(-2 + -1 + 4) = 1
(-2 + -1 + 3) = 0
Array : 8 2 0 6 -2 6 -1 9 4 3
Given x : -6
None
Array : 9 2 -7 4 1 3 0 7 22 8 -4
Given x : -2
(2 + -7 + 1) = -4
(2 + -7 + 0) = -5
(2 + -7 + -4) = -9
(-7 + 4 + 0) = -3
(-7 + 4 + -4) = -7
(-7 + 1 + 3) = -3
(-7 + 1 + 0) = -6
(-7 + 1 + -4) = -10
(-7 + 3 + 0) = -4
(-7 + 3 + -4) = -8
(-7 + 0 + -4) = -11
(-7 + 7 + -4) = -4
(-7 + 8 + -4) = -3
(1 + 0 + -4) = -3import Foundation;
/*
Swift 4 Program for
Find all triplets which sum less than given value x
*/
class Triplets
{
//Function which is display array elements
func display(_ arr: [Int], _ size: Int)
{
var i: Int = 0;
while (i < size)
{
print(" ", arr[i], terminator: "");
i += 1;
}
}
// Find all triplets which sum less than x
func tripletsWithLessThanX(_ arr: [Int], _ size: Int, _ x: Int)
{
if (size < 3)
{
return;
}
print("\n Array : ", terminator: "");
//Display array elements
self.display(arr, size);
print("\n Given x : ", x, terminator: "");
// Result indicator
var status: Bool = false;
var i: Int = 0;
// Loop which is iterate the first element of result
while (i < size - 2)
{
var j: Int = i + 1;
// Loop which is iterate the second element of result
while (j < size - 1)
{
var k: Int = j + 1;
// Loop which is iterate the third element of result
while (k < size)
{
// Check if whether resultant sum is to zero or not
if (arr[i] + arr[j] + arr[k] < x)
{
status = true;
// Display three elements
print("\n (", arr[i] ,"+",
arr[j] ,"+", arr[k] ,") = ",
(arr[i] + arr[j] + arr[k]), terminator: "");
}
k += 1;
}
j += 1;
}
i += 1;
}
if (status == false)
{
print(" \n None");
}
}
}
func main()
{
let task: Triplets = Triplets();
// Define array elements
let arr1: [Int] = [8, 2, 0, 6, -2, 6, -1, 9, 4, 3];
// Define array elements
let arr2: [Int] = [9, 2, -7, 4, 1, 3, 0, 7, 22, 8, -4];
// Test A
var size: Int = arr1.count;
task.tripletsWithLessThanX(arr1, size, 3);
task.tripletsWithLessThanX(arr1, size, -6);
// Test B
size = arr2.count;
task.tripletsWithLessThanX(arr2, size, -2);
}
main();Output
Array : 8 2 0 6 -2 6 -1 9 4 3
Given x : 3
( 2 + 0 + -2 ) = 0
( 2 + 0 + -1 ) = 1
( 2 + -2 + -1 ) = -1
( 0 + -2 + -1 ) = -3
( 0 + -2 + 4 ) = 2
( 0 + -2 + 3 ) = 1
( 0 + -1 + 3 ) = 2
( -2 + -1 + 4 ) = 1
( -2 + -1 + 3 ) = 0
Array : 8 2 0 6 -2 6 -1 9 4 3
Given x : -6
None
Array : 9 2 -7 4 1 3 0 7 22 8 -4
Given x : -2
( 2 + -7 + 1 ) = -4
( 2 + -7 + 0 ) = -5
( 2 + -7 + -4 ) = -9
( -7 + 4 + 0 ) = -3
( -7 + 4 + -4 ) = -7
( -7 + 1 + 3 ) = -3
( -7 + 1 + 0 ) = -6
( -7 + 1 + -4 ) = -10
( -7 + 3 + 0 ) = -4
( -7 + 3 + -4 ) = -8
( -7 + 0 + -4 ) = -11
( -7 + 7 + -4 ) = -4
( -7 + 8 + -4 ) = -3
( 1 + 0 + -4 ) = -3/*
Kotlin Program for
Find all triplets which sum less than given value x
*/
class Triplets
{
//Function which is display array elements
fun display(arr: Array < Int > , size: Int): Unit
{
var i: Int = 0;
while (i < size)
{
print(" " + arr[i]);
i += 1;
}
}
// Find all triplets which sum less than x
fun tripletsWithLessThanX(arr: Array < Int > , size: Int, x: Int): Unit
{
if (size < 3)
{
return;
}
print("\n Array : ");
//Display array elements
this.display(arr, size);
print("\n Given x : " + x);
// Result indicator
var status: Boolean = false;
var i: Int = 0;
// Loop which is iterate the first element of result
while (i < size - 2)
{
var j: Int = i + 1;
// Loop which is iterate the second element of result
while (j < size - 1)
{
var k: Int = j + 1;
// Loop which is iterate the third element of result
while (k < size)
{
// Check if whether resultant sum is to zero or not
if (arr[i] + arr[j] + arr[k] < x)
{
status = true;
// Display three elements
print("\n (" + arr[i] + " + " +
arr[j] + " + " + arr[k] + ") = " +
(arr[i] + arr[j] + arr[k]));
}
k += 1;
}
j += 1;
}
i += 1;
}
if (status == false)
{
print(" \n None\n");
}
}
}
fun main(args: Array < String > ): Unit
{
val task: Triplets = Triplets();
// Define array elements
val arr1: Array < Int > = arrayOf(8, 2, 0, 6, -2, 6, -1, 9, 4, 3);
// Define array elements
val arr2: Array < Int > = arrayOf(9, 2, -7, 4, 1, 3, 0, 7, 22, 8, -4);
// Test A
var size: Int = arr1.count();
task.tripletsWithLessThanX(arr1, size, 3);
task.tripletsWithLessThanX(arr1, size, -6);
// Test B
size = arr2.count();
task.tripletsWithLessThanX(arr2, size, -2);
}Output
Array : 8 2 0 6 -2 6 -1 9 4 3
Given x : 3
(2 + 0 + -2) = 0
(2 + 0 + -1) = 1
(2 + -2 + -1) = -1
(0 + -2 + -1) = -3
(0 + -2 + 4) = 2
(0 + -2 + 3) = 1
(0 + -1 + 3) = 2
(-2 + -1 + 4) = 1
(-2 + -1 + 3) = 0
Array : 8 2 0 6 -2 6 -1 9 4 3
Given x : -6
None
Array : 9 2 -7 4 1 3 0 7 22 8 -4
Given x : -2
(2 + -7 + 1) = -4
(2 + -7 + 0) = -5
(2 + -7 + -4) = -9
(-7 + 4 + 0) = -3
(-7 + 4 + -4) = -7
(-7 + 1 + 3) = -3
(-7 + 1 + 0) = -6
(-7 + 1 + -4) = -10
(-7 + 3 + 0) = -4
(-7 + 3 + -4) = -8
(-7 + 0 + -4) = -11
(-7 + 7 + -4) = -4
(-7 + 8 + -4) = -3
(1 + 0 + -4) = -3
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