Posted on by Kalkicode
Code Array

# Find a triplet that sum to a given value

Here given code implementation process.

``````/*
C program for
Find a triplet that sum to a given value
*/
#include <stdio.h>

// Display array elements
void printArray(int arr[], int n)
{
for (int i = 0; i < n; ++i)
{
printf("  %d", arr[i]);
}
}
void tripletWithSum(int arr[], int n, int x)
{
if (n > 3)
{
for (int i = 0; i < n; ++i)
{
for (int j = i + 1; j < n; ++j)
{
for (int k = j + 1; k < n; ++k)
{
if (arr[i] + arr[j] + arr[k] == x)
{
printf("\n (%d + %d + %d) = %d",
arr[i], arr[j], arr[k], x);
return;
}
}
}
}
}
printf("\n Triplet of sum are %d not exists", x);
}
int main(int argc, char
const *argv[])
{
int arr[] = {
-2 , 5 , 4 , 8 , 3 , 1 , 7 , -1
};
int n = sizeof(arr) / sizeof(arr[0]);
printArray(arr, n);
// Test A
int x = 5;
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 5
-------------------------------------------
(-2 + 4 + 3) = 5
-----------------------

*/
tripletWithSum(arr, n, x);
// Test B
x = 15;
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 5
-------------------------------------------
(5 + 3 + 7) = 15
-----------------------

*/
tripletWithSum(arr, n, x);
// Test C
x = 19;
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 19
-------------------------------------------
(4 + 8 + 7) = 19
-----------------------

*/
tripletWithSum(arr, n, x);
// Test D
x = 32;
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 32
-------------------------------------------
None
-------------------------------------------
*/
tripletWithSum(arr, n, x);
return 0;
}``````

#### Output

``````  -2  5  4  8  3  1  7  -1
(-2 + 4 + 3) = 5
(5 + 3 + 7) = 15
(4 + 8 + 7) = 19
Triplet of sum are 32 not exists``````
``````// Java program for
// Find a triplet that sum to a given value
public class Triplet
{
// Display array elements
public void printArray(int[] arr, int n)
{
for (int i = 0; i < n; ++i)
{
System.out.print(" " + arr[i]);
}
}
public void tripletWithSum(int[] arr, int n, int x)
{
if (n > 3)
{
for (int i = 0; i < n; ++i)
{
for (int j = i + 1; j < n; ++j)
{
for (int k = j + 1; k < n; ++k)
{
if (arr[i] + arr[j] + arr[k] == x)
{
System.out.print("\n (" +
arr[i] + " + " +
arr[j] + " + " +
arr[k] + ") = " + x);
return;
}
}
}
}
}
System.out.print("\n Triplet of sum are " + x + " not exists");
}
public static void main(String[] args)
{
int[] arr = {
-2 , 5 , 4 , 8 , 3 , 1 , 7 , -1
};
int n = arr.length;
// Test A
int x = 5;
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 5
-------------------------------------------
(-2 + 4 + 3) = 5
-------------------------------------------

*/
// Test B
x = 15;
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 5
-------------------------------------------
(5 + 3 + 7) = 15
-------------------------------------------

*/
// Test C
x = 19;
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 19
-------------------------------------------
(4 + 8 + 7) = 19
-------------------------------------------

*/
// Test D
x = 32;
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 32
-------------------------------------------
None
-------------------------------------------
*/
}
}``````

#### Output

`````` -2 5 4 8 3 1 7 -1
(-2 + 4 + 3) = 5
(5 + 3 + 7) = 15
(4 + 8 + 7) = 19
Triplet of sum are 32 not exists``````
``````// Include header file
#include <iostream>

using namespace std;
// C++ program for
// Find a triplet that sum to a given value
class Triplet
{
public:
// Display array elements
void printArray(int arr[], int n)
{
for (int i = 0; i < n; ++i)
{
cout << " " << arr[i];
}
}
void tripletWithSum(int arr[], int n, int x)
{
if (n > 3)
{
for (int i = 0; i < n; ++i)
{
for (int j = i + 1; j < n; ++j)
{
for (int k = j + 1; k < n; ++k)
{
if (arr[i] + arr[j] + arr[k] == x)
{
cout << "\n ("
<< arr[i]
<< " + "
<< arr[j] << " + "
<< arr[k] << ") = " << x;
return;
}
}
}
}
}
cout << "\n Triplet of sum are " << x << " not exists";
}
};
int main()
{
int arr[] = {
-2 , 5 , 4 , 8 , 3 , 1 , 7 , -1
};
int n = sizeof(arr) / sizeof(arr[0]);
// Test A
int x = 5;
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 5
-------------------------------------------
(-2 + 4 + 3) = 5
-------------------------------------------

*/
// Test B
x = 15;
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 5
-------------------------------------------
(5 + 3 + 7) = 15
-------------------------------------------

*/
// Test C
x = 19;
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 19
-------------------------------------------
(4 + 8 + 7) = 19
-------------------------------------------

*/
// Test D
x = 32;
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 32
-------------------------------------------
None
-------------------------------------------
*/
return 0;
}``````

#### Output

`````` -2 5 4 8 3 1 7 -1
(-2 + 4 + 3) = 5
(5 + 3 + 7) = 15
(4 + 8 + 7) = 19
Triplet of sum are 32 not exists``````
``````// Include namespace system
using System;
// Csharp program for
// Find a triplet that sum to a given value
public class Triplet
{
// Display array elements
public void printArray(int[] arr, int n)
{
for (int i = 0; i < n; ++i)
{
Console.Write(" " + arr[i]);
}
}
public void tripletWithSum(int[] arr, int n, int x)
{
if (n > 3)
{
for (int i = 0; i < n; ++i)
{
for (int j = i + 1; j < n; ++j)
{
for (int k = j + 1; k < n; ++k)
{
if (arr[i] + arr[j] + arr[k] == x)
{
Console.Write("\n (" +
arr[i] + " + " +
arr[j] + " + " +
arr[k] + ") = " + x);
return;
}
}
}
}
}
Console.Write("\n Triplet of sum are " + x + " not exists");
}
public static void Main(String[] args)
{
int[] arr = {
-2 , 5 , 4 , 8 , 3 , 1 , 7 , -1
};
int n = arr.Length;
// Test A
int x = 5;
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 5
-------------------------------------------
(-2 + 4 + 3) = 5
-------------------------------------------

*/
// Test B
x = 15;
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 5
-------------------------------------------
(5 + 3 + 7) = 15
-------------------------------------------

*/
// Test C
x = 19;
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 19
-------------------------------------------
(4 + 8 + 7) = 19
-------------------------------------------

*/
// Test D
x = 32;
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 32
-------------------------------------------
None
-------------------------------------------
*/
}
}``````

#### Output

`````` -2 5 4 8 3 1 7 -1
(-2 + 4 + 3) = 5
(5 + 3 + 7) = 15
(4 + 8 + 7) = 19
Triplet of sum are 32 not exists``````
``````package main
import "fmt"
// Go program for
// Find a triplet that sum to a given value

// Display array elements
func printArray(arr[] int, n int) {
for i := 0 ; i < n ; i++ {
fmt.Print(" ", arr[i])
}
}
func tripletWithSum(arr[] int, n int, x int) {
if n > 3 {
for i := 0 ; i < n ; i++ {
for j := i + 1 ; j < n ; j++ {
for k := j + 1 ; k < n ; k++ {
if arr[i] + arr[j] + arr[k] == x {
fmt.Print("\n (",
arr[i], " + ", arr[j],
" + ", arr[k], ") = ", x)
return
}
}
}
}
}
fmt.Print("\n Triplet of sum are ", x, " not exists")
}
func main() {

var arr = [] int { -2, 5, 4, 8, 3, 1, 7, -1 }
var n int = len(arr)
printArray(arr, n)
// Test A
var x int = 5
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 5
-------------------------------------------
(-2 + 4 + 3) = 5
-------------------------------------------

*/
tripletWithSum(arr, n, x)
// Test B
x = 15
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 5
-------------------------------------------
(5 + 3 + 7) = 15
-------------------------------------------

*/
tripletWithSum(arr, n, x)
// Test C
x = 19
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 19
-------------------------------------------
(4 + 8 + 7) = 19
-------------------------------------------

*/
tripletWithSum(arr, n, x)
// Test D
x = 32
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 32
-------------------------------------------
None
-------------------------------------------
*/
tripletWithSum(arr, n, x)
}``````

#### Output

`````` -2 5 4 8 3 1 7 -1
(-2 + 4 + 3) = 5
(5 + 3 + 7) = 15
(4 + 8 + 7) = 19
Triplet of sum are 32 not exists``````
``````<?php
// Php program for
// Find a triplet that sum to a given value
class Triplet
{
// Display array elements
public	function printArray(\$arr, \$n)
{
for (\$i = 0; \$i < \$n; ++\$i)
{
echo(" ".\$arr[\$i]);
}
}
public	function tripletWithSum(\$arr, \$n, \$x)
{
if (\$n > 3)
{
for (\$i = 0; \$i < \$n; ++\$i)
{
for (\$j = \$i + 1; \$j < \$n; ++\$j)
{
for (\$k = \$j + 1; \$k < \$n; ++\$k)
{
if (\$arr[\$i] + \$arr[\$j] + \$arr[\$k] == \$x)
{
echo("\n (".\$arr[\$i].
" + ".\$arr[\$j].
" + ".\$arr[\$k].
") = ".\$x);
return;
}
}
}
}
}
echo("\n Triplet of sum are ".\$x.
" not exists");
}
}

function main()
{
\$arr = array(-2, 5, 4, 8, 3, 1, 7, -1);
\$n = count(\$arr);
// Test A
\$x = 5;
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 5
-------------------------------------------
(-2 + 4 + 3) = 5
-------------------------------------------

*/
// Test B
\$x = 15;
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 5
-------------------------------------------
(5 + 3 + 7) = 15
-------------------------------------------

*/
// Test C
\$x = 19;
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 19
-------------------------------------------
(4 + 8 + 7) = 19
-------------------------------------------

*/
// Test D
\$x = 32;
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 32
-------------------------------------------
None
-------------------------------------------
*/
}
main();``````

#### Output

`````` -2 5 4 8 3 1 7 -1
(-2 + 4 + 3) = 5
(5 + 3 + 7) = 15
(4 + 8 + 7) = 19
Triplet of sum are 32 not exists``````
``````// Node JS program for
// Find a triplet that sum to a given value
class Triplet
{
// Display array elements
printArray(arr, n)
{
for (var i = 0; i < n; ++i)
{
process.stdout.write(" " + arr[i]);
}
}
tripletWithSum(arr, n, x)
{
if (n > 3)
{
for (var i = 0; i < n; ++i)
{
for (var j = i + 1; j < n; ++j)
{
for (var k = j + 1; k < n; ++k)
{
if (arr[i] + arr[j] + arr[k] == x)
{
process.stdout.write("\n (" +
arr[i] + " + " +
arr[j] + " + " +
arr[k] + ") = " + x);
return;
}
}
}
}
}
process.stdout.write("\n Triplet of sum are " + x + " not exists");
}
}

function main()
{
var arr = [-2, 5, 4, 8, 3, 1, 7, -1];
var n = arr.length;
// Test A
var x = 5;
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 5
-------------------------------------------
(-2 + 4 + 3) = 5
-------------------------------------------

*/
// Test B
x = 15;
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 5
-------------------------------------------
(5 + 3 + 7) = 15
-------------------------------------------

*/
// Test C
x = 19;
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 19
-------------------------------------------
(4 + 8 + 7) = 19
-------------------------------------------

*/
// Test D
x = 32;
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 32
-------------------------------------------
None
-------------------------------------------
*/
}
main();``````

#### Output

`````` -2 5 4 8 3 1 7 -1
(-2 + 4 + 3) = 5
(5 + 3 + 7) = 15
(4 + 8 + 7) = 19
Triplet of sum are 32 not exists``````
``````#  Python 3 program for
#  Find a triplet that sum to a given value
class Triplet :
#  Display list elements
def printArray(self, arr, n) :
i = 0
while (i < n) :
print(" ", arr[i], end = "")
i += 1

def tripletWithSum(self, arr, n, x) :
if (n > 3) :
i = 0
while (i < n) :
j = i + 1
while (j < n) :
k = j + 1
while (k < n) :
if (arr[i] + arr[j] + arr[k] == x) :
print("\n (",
arr[i] ," + ",
arr[j] ," + ",
arr[k] ,") = ", x, end = "")
return

k += 1

j += 1

i += 1

print("\n Triplet of sum are ", x ," not exists", end = "")

def main() :
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
n = len(arr)
#  Test A
x = 5
#    arr = [-2, 5, 4, 8, 3, 1, 7, -1]
#    sum x = 5
#    -------------------------------------------
#    (-2 + 4 + 3) = 5
#    -------------------------------------------
#  Test B
x = 15
#    arr = [-2, 5, 4, 8, 3, 1, 7, -1]
#    sum x = 5
#    -------------------------------------------
#    (5 + 3 + 7) = 15
#    -------------------------------------------
#  Test C
x = 19
#    arr = [-2, 5, 4, 8, 3, 1, 7, -1]
#    sum x = 19
#    -------------------------------------------
#    (4 + 8 + 7) = 19
#    -------------------------------------------
#  Test D
x = 32
#    arr = [-2, 5, 4, 8, 3, 1, 7, -1]
#    sum x = 32
#    -------------------------------------------
#    None
#    -------------------------------------------

if __name__ == "__main__": main()``````

#### Output

``````  -2  5  4  8  3  1  7  -1
( -2  +  4  +  3 ) =  5
( 5  +  3  +  7 ) =  15
( 4  +  8  +  7 ) =  19
Triplet of sum are  32  not exists``````
``````#  Ruby program for
#  Find a triplet that sum to a given value
class Triplet
#  Display array elements
def printArray(arr, n)
i = 0
while (i < n)
print(" ", arr[i])
i += 1
end

end

def tripletWithSum(arr, n, x)
if (n > 3)
i = 0
while (i < n)
j = i + 1
while (j < n)
k = j + 1
while (k < n)
if (arr[i] + arr[j] + arr[k] == x)
print("\n (",
arr[i] ," + ",
arr[j] ," + ",
arr[k] ,") = ", x)
return
end

k += 1
end

j += 1
end

i += 1
end

end

print("\n Triplet of sum are ", x ," not exists")
end

end

def main()
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
n = arr.length
#  Test A
x = 5
#    arr = [-2, 5, 4, 8, 3, 1, 7, -1]
#    sum x = 5
#    -------------------------------------------
#    (-2 + 4 + 3) = 5
#    -------------------------------------------
#  Test B
x = 15
#    arr = [-2, 5, 4, 8, 3, 1, 7, -1]
#    sum x = 5
#    -------------------------------------------
#    (5 + 3 + 7) = 15
#    -------------------------------------------
#  Test C
x = 19
#    arr = [-2, 5, 4, 8, 3, 1, 7, -1]
#    sum x = 19
#    -------------------------------------------
#    (4 + 8 + 7) = 19
#    -------------------------------------------
#  Test D
x = 32
#    arr = [-2, 5, 4, 8, 3, 1, 7, -1]
#    sum x = 32
#    -------------------------------------------
#    None
#    -------------------------------------------
end

main()``````

#### Output

`````` -2 5 4 8 3 1 7 -1
(-2 + 4 + 3) = 5
(5 + 3 + 7) = 15
(4 + 8 + 7) = 19
Triplet of sum are 32 not exists``````
``````// Scala program for
// Find a triplet that sum to a given value
class Triplet()
{
// Display array elements
def printArray(arr: Array[Int], n: Int): Unit = {
var i: Int = 0;
while (i < n)
{
print(" " + arr(i));
i += 1;
}
}
def tripletWithSum(arr: Array[Int], n: Int, x: Int): Unit = {
if (n > 3)
{
var i: Int = 0;
while (i < n)
{
var j: Int = i + 1;
while (j < n)
{
var k: Int = j + 1;
while (k < n)
{
if (arr(i) + arr(j) + arr(k) == x)
{
print("\n (" +
arr(i) + " + " +
arr(j) + " + " +
arr(k) + ") = " + x);
return;
}
k += 1;
}
j += 1;
}
i += 1;
}
}
print("\n Triplet of sum are " + x + " not exists");
}
}
object Main
{
def main(args: Array[String]): Unit = {
var task: Triplet = new Triplet();
var arr: Array[Int] = Array(-2, 5, 4, 8, 3, 1, 7, -1);
var n: Int = arr.length;
// Test A
var x: Int = 5;
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 5
-------------------------------------------
(-2 + 4 + 3) = 5
-------------------------------------------

*/
// Test B
x = 15;
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 5
-------------------------------------------
(5 + 3 + 7) = 15
-------------------------------------------

*/
// Test C
x = 19;
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 19
-------------------------------------------
(4 + 8 + 7) = 19
-------------------------------------------

*/
// Test D
x = 32;
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 32
-------------------------------------------
None
-------------------------------------------
*/
}
}``````

#### Output

`````` -2 5 4 8 3 1 7 -1
(-2 + 4 + 3) = 5
(5 + 3 + 7) = 15
(4 + 8 + 7) = 19
Triplet of sum are 32 not exists``````
``````import Foundation;
// Swift 4 program for
// Find a triplet that sum to a given value
class Triplet
{
// Display array elements
func printArray(_ arr: [Int], _ n: Int)
{
var i: Int = 0;
while (i < n)
{
print(" ", arr[i], terminator: "");
i += 1;
}
}
func tripletWithSum(_ arr: [Int], _ n: Int, _ x: Int)
{
if (n > 3)
{
var i: Int = 0;
while (i < n)
{
var j: Int = i + 1;
while (j < n)
{
var k: Int = j + 1;
while (k < n)
{
if (arr[i] + arr[j] + arr[k] == x)
{
print("\n (",
arr[i] ," + ",
arr[j] ," + ",
arr[k] ,") = ", x, terminator: "");
return;
}
k += 1;
}
j += 1;
}
i += 1;
}
}
print("\n Triplet of sum are ", x ," not exists", terminator: "");
}
}
func main()
{
let arr: [Int] = [-2, 5, 4, 8, 3, 1, 7, -1];
let n: Int = arr.count;
// Test A
var x: Int = 5;
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 5
-------------------------------------------
(-2 + 4 + 3) = 5
-------------------------------------------

*/
// Test B
x = 15;
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 5
-------------------------------------------
(5 + 3 + 7) = 15
-------------------------------------------

*/
// Test C
x = 19;
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 19
-------------------------------------------
(4 + 8 + 7) = 19
-------------------------------------------

*/
// Test D
x = 32;
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 32
-------------------------------------------
None
-------------------------------------------
*/
}
main();``````

#### Output

``````  -2  5  4  8  3  1  7  -1
( -2  +  4  +  3 ) =  5
( 5  +  3  +  7 ) =  15
( 4  +  8  +  7 ) =  19
Triplet of sum are  32  not exists``````
``````// Kotlin program for
// Find a triplet that sum to a given value
class Triplet
{
// Display array elements
fun printArray(arr: Array < Int > , n: Int): Unit
{
var i: Int = 0;
while (i < n)
{
print(" " + arr[i]);
i += 1;
}
}
fun tripletWithSum(arr: Array < Int > , n: Int, x: Int): Unit
{
if (n > 3)
{
var i: Int = 0;
while (i < n)
{
var j: Int = i + 1;
while (j < n)
{
var k: Int = j + 1;
while (k < n)
{
if (arr[i] + arr[j] + arr[k] == x)
{
print("\n (" +
arr[i] + " + " +
arr[j] + " + " +
arr[k] + ") = " + x);
return;
}
k += 1;
}
j += 1;
}
i += 1;
}
}
print("\n Triplet of sum are " + x + " not exists");
}
}
fun main(args: Array < String > ): Unit
{
val arr: Array < Int > = arrayOf(-2, 5, 4, 8, 3, 1, 7, -1);
val n: Int = arr.count();
// Test A
var x: Int = 5;
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 5
-------------------------------------------
(-2 + 4 + 3) = 5
-------------------------------------------

*/
// Test B
x = 15;
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 5
-------------------------------------------
(5 + 3 + 7) = 15
-------------------------------------------

*/
// Test C
x = 19;
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 19
-------------------------------------------
(4 + 8 + 7) = 19
-------------------------------------------

*/
// Test D
x = 32;
/*
arr = [-2, 5, 4, 8, 3, 1, 7, -1]
sum x = 32
-------------------------------------------
None
-------------------------------------------
*/
}``````

#### Output

`````` -2 5 4 8 3 1 7 -1
(-2 + 4 + 3) = 5
(5 + 3 + 7) = 15
(4 + 8 + 7) = 19
Triplet of sum are 32 not exists``````

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