Find the frequency of each element in an list in python
Python program for Find the frequency of each element in an list. Here problem description and other solutions.
class Occurrence :
# Function which is display array elements
def display(self, arr) :
i = 0
while (i < len(arr)) :
print( arr[i], end = " ")
i += 1
print(end = "\n")
# Count occurrence of given list
def frequency(self, arr) :
# Display given list
self.display(arr)
# Create a empty map
map = dict()
i = 0
while (i < len(arr)) :
if ((arr[i] in map.keys())) :
# When key exists then update value
map[arr[i]] = map.get(arr[i]) + 1
else :
# Add new element
map[arr[i]] = 1
i += 1
print(" Occurrence ")
for key, value in map.items() :
print(" ", key ," : ", value)
def main() :
# Array element
arr = [1, 3, 2, 1, 4, 2, 7, 9, 1, 3, 3, 4, 7]
task = Occurrence()
task.frequency(arr)
if __name__ == "__main__": main()
Output
1 3 2 1 4 2 7 9 1 3 3 4 7
Occurrence
1 : 3
2 : 2
3 : 3
4 : 2
7 : 2
9 : 1
Please share your knowledge to improve code and content standard. Also submit your doubts, and test case. We improve by your feedback. We will try to resolve your query as soon as possible.
New Comment