# Find the frequency of each element in an array in ruby

Ruby program for Find the frequency of each element in an array. Here problem description and other solutions.

``````class Occurrence
#  Function which is display array elements
def display(arr)
i = 0
while (i < arr.length)
print("   ", arr[i])
i += 1
end
print("\n")
end

#  Count occurrence of given array
def frequency(arr)
#  Display given array
self.display(arr)
#  Create a empty map
map = Hash.new()
i = 0
while (i < arr.length)
if (map.key?(arr[i]))
#  When key exists then update value
map[arr[i]] = map[arr[i]] + 1
else

map[arr[i]] = 1
end

i += 1
end

print("  Occurrence ", "\n")
#   Display calculated result
map.each { | key, value |
print("  ", key ,"  :  ", value, "\n")
}
end

end

def main()
#  Array element
arr = [1, 3, 2, 1, 4, 2, 7, 9, 1, 3, 3, 4, 7]
obj = Occurrence.new()
obj.frequency(arr)
end

main()``````

Output

``````   1   3   2   1   4   2   7   9   1   3   3   4   7
Occurrence
1  :  3
3  :  3
2  :  2
4  :  2
7  :  2
9  :  1
``````

Please share your knowledge to improve code and content standard. Also submit your doubts, and test case. We improve by your feedback. We will try to resolve your query as soon as possible.

### New Comment 