Find smallest pair sum in an array

Here given code implementation process.

``````// C Program
// Find smallest pair sum in an array
#include <stdio.h>

//Function which is display array elements
void display(int arr[], int size)
{
for (int i = 0; i < size; ++i)
{
printf("%d ", arr[i]);
}
printf("\n");
}
//Find the pair of smallest sum in given array
void smallest_pair(int arr[], int size)
{
if (size < 2)
{
//When array contains less than 2 elements
return;
}
//First pair sum
int sum = arr[0] + arr[1];
//Get the first pair indexes
int first = 0;
int second = 1;
for (int i = 0; i < size; ++i)
{
for (int j = i + 1; j < size; ++j)
{
if (arr[i] + arr[j] < sum)
{
//When get a new smallest  element pair
//Get the sum of new small pair
sum = arr[i] + arr[j];
//Get the location of new smallest pair
first = i;
second = j;
}
}
}
printf("\n Array elements : ");
display(arr, size);
//Display result
printf("\n Smallest pair [%d, %d] : %d\n", arr[first], arr[second], sum);
}
int main()
{
int a1[] = {
10 , 15 , -7 , 31 , 33
};
//Get the size of array
int size = sizeof(a1) / sizeof(a1[0]);
smallest_pair(a1, size);
int a2[] = {
9 , 6 , 1 , 5 , 8 , 3
};
//Get the size of array
size = sizeof(a2) / sizeof(a2[0]);
smallest_pair(a2, size);
return 0;
}``````

Output

`````` Array elements : 10 15 -7 31 33

Smallest pair [10, -7] : 3

Array elements : 9 6 1 5 8 3

Smallest pair [1, 3] : 4``````
``````// Java Program
// Find median of two sorted arrays
class MyArray
{
//Function which is display array elements
public void display(int[] arr, int size)
{
for (int i = 0; i < size; ++i)
{
System.out.print(" " + arr[i]);
}
System.out.print("\n");
}
//Find the pair of smallest sum in given array
public void smallest_pair(int[] arr, int size)
{
if (size < 2)
{
//When array contains less than 2 elements
return;
}
//First pair sum
int sum = arr[0] + arr[1];
//Get the first pair indexes
int first = 0;
int second = 1;
for (int i = 0; i < size; ++i)
{
for (int j = i + 1; j < size; ++j)
{
if (arr[i] + arr[j] < sum)
{
//When get a new smallest  element pair
//Get the sum of new small pair
sum = arr[i] + arr[j];
//Get the location of new smallest pair
first = i;
second = j;
}
}
}
System.out.print("\n Array elements : ");
display(arr, size);
System.out.print("\n Smallest pair [" + arr[first] + ", " + arr[second] + "] : " + sum + "\n");
}
public static void main(String[] args)
{
MyArray obj = new MyArray();
int[] a1 = {
10,
15,
-7,
31,
33
};
//Get the size of array
int size = a1.length;
obj.smallest_pair(a1, size);
int[] a2 = {
9,
6,
1,
5,
8,
3
};
//Get the size of array
size = a2.length;
obj.smallest_pair(a2, size);
}
}``````

Output

`````` Array elements :  10 15 -7 31 33

Smallest pair [10, -7] : 3

Array elements :  9 6 1 5 8 3

Smallest pair [1, 3] : 4``````
``````//Include header file
#include <iostream>

using namespace std;
// C++ Program
// Find median of two sorted arrays
class MyArray
{
public:
//Function which is display array elements
void display(int arr[], int size)
{
for (int i = 0; i < size; ++i)
{
cout << " " << arr[i];
}
cout << "\n";
}
//Find the pair of smallest sum in given array
void smallest_pair(int arr[], int size)
{
if (size < 2)
{
//When array contains less than 2 elements
return;
}
//First pair sum
int sum = arr[0] + arr[1];
//Get the first pair indexes
int first = 0;
int second = 1;
for (int i = 0; i < size; ++i)
{
for (int j = i + 1; j < size; ++j)
{
if (arr[i] + arr[j] < sum)
{
//When get a new smallest  element pair
//Get the sum of new small pair
sum = arr[i] + arr[j];
//Get the location of new smallest pair
first = i;
second = j;
}
}
}
cout << "\n Array elements : ";
this->display(arr, size);
cout << "\n Smallest pair [" << arr[first] << ", " << arr[second] << "] : " << sum << "\n";
}
};
int main()
{
MyArray obj = MyArray();
int a1[] = {
10 , 15 , -7 , 31 , 33
};
//Get the size of array
int size = sizeof(a1) / sizeof(a1[0]);
obj.smallest_pair(a1, size);
int a2[] = {
9 , 6 , 1 , 5 , 8 , 3
};
//Get the size of array
size = sizeof(a2) / sizeof(a2[0]);
obj.smallest_pair(a2, size);
return 0;
}``````

Output

`````` Array elements :  10 15 -7 31 33

Smallest pair [10, -7] : 3

Array elements :  9 6 1 5 8 3

Smallest pair [1, 3] : 4``````
``````//Include namespace system
using System;

// C# Program
// Find median of two sorted arrays
class MyArray
{
//Function which is display array elements
public void display(int[] arr, int size)
{
for (int i = 0; i < size; ++i)
{
Console.Write(" " + arr[i]);
}
Console.Write("\n");
}
//Find the pair of smallest sum in given array
public void smallest_pair(int[] arr, int size)
{
if (size < 2)
{
//When array contains less than 2 elements
return;
}
//First pair sum
int sum = arr[0] + arr[1];
//Get the first pair indexes
int first = 0;
int second = 1;
for (int i = 0; i < size; ++i)
{
for (int j = i + 1; j < size; ++j)
{
if (arr[i] + arr[j] < sum)
{
//When get a new smallest  element pair
//Get the sum of new small pair
sum = arr[i] + arr[j];
//Get the location of new smallest pair
first = i;
second = j;
}
}
}
Console.Write("\n Array elements : ");
display(arr, size);
Console.Write("\n Smallest pair [" + arr[first] + ", " + arr[second] + "] : " + sum + "\n");
}
public static void Main(String[] args)
{
MyArray obj = new MyArray();
int[] a1 = {
10 , 15 , -7 , 31 , 33
};
//Get the size of array
int size = a1.Length;
obj.smallest_pair(a1, size);
int[] a2 = {
9 , 6 , 1 , 5 , 8 , 3
};
//Get the size of array
size = a2.Length;
obj.smallest_pair(a2, size);
}
}``````

Output

`````` Array elements :  10 15 -7 31 33

Smallest pair [10, -7] : 3

Array elements :  9 6 1 5 8 3

Smallest pair [1, 3] : 4``````
``````<?php
// Php Program
// Find median of two sorted arrays
class MyArray
{
//Function which is display array elements
public	function display( & \$arr, \$size)
{
for (\$i = 0; \$i < \$size; ++\$i)
{
echo " ". \$arr[\$i];
}
echo "\n";
}
//Find the pair of smallest sum in given array
public	function smallest_pair( & \$arr, \$size)
{
if (\$size < 2)
{
//When array contains less than 2 elements
return;
}
//First pair sum
\$sum = \$arr[0] + \$arr[1];
//Get the first pair indexes
\$first = 0;
\$second = 1;
for (\$i = 0; \$i < \$size; ++\$i)
{
for (\$j = \$i + 1; \$j < \$size; ++\$j)
{
if (\$arr[\$i] + \$arr[\$j] < \$sum)
{
//When get a new smallest  element pair
//Get the sum of new small pair
\$sum = \$arr[\$i] + \$arr[\$j];
//Get the location of new smallest pair
\$first = \$i;
\$second = \$j;
}
}
}
echo "\n Array elements : ";
\$this->display(\$arr, \$size);
echo "\n Smallest pair [". \$arr[\$first] .", ". \$arr[\$second] ."] : ". \$sum ."\n";
}
}

function main()
{
\$obj = new MyArray();
\$a1 = array(10, 15, -7, 31, 33);
//Get the size of array
\$size = count(\$a1);
\$obj->smallest_pair(\$a1, \$size);
\$a2 = array(9, 6, 1, 5, 8, 3);
//Get the size of array
\$size = count(\$a2);
\$obj->smallest_pair(\$a2, \$size);
}
main();``````

Output

`````` Array elements :  10 15 -7 31 33

Smallest pair [10, -7] : 3

Array elements :  9 6 1 5 8 3

Smallest pair [1, 3] : 4``````
``````// Node Js Program
// Find median of two sorted arrays
class MyArray
{
//Function which is display array elements
display(arr, size)
{
for (var i = 0; i < size; ++i)
{
process.stdout.write(" " + arr[i]);
}
process.stdout.write("\n");
}
//Find the pair of smallest sum in given array
smallest_pair(arr, size)
{
if (size < 2)
{
//When array contains less than 2 elements
return;
}
//First pair sum
var sum = arr[0] + arr[1];
//Get the first pair indexes
var first = 0;
var second = 1;
for (var i = 0; i < size; ++i)
{
for (var j = i + 1; j < size; ++j)
{
if (arr[i] + arr[j] < sum)
{
//When get a new smallest  element pair
//Get the sum of new small pair
sum = arr[i] + arr[j];
//Get the location of new smallest pair
first = i;
second = j;
}
}
}
process.stdout.write("\n Array elements : ");
this.display(arr, size);
process.stdout.write("\n Smallest pair [" + arr[first] + ", " + arr[second] + "] : " + sum + "\n");
}
}

function main()
{
var obj = new MyArray();
var a1 = [10, 15, -7, 31, 33];
//Get the size of array
var size = a1.length;
obj.smallest_pair(a1, size);
var a2 = [9, 6, 1, 5, 8, 3];
//Get the size of array
size = a2.length;
obj.smallest_pair(a2, size);
}
main();``````

Output

`````` Array elements :  10 15 -7 31 33

Smallest pair [10, -7] : 3

Array elements :  9 6 1 5 8 3

Smallest pair [1, 3] : 4``````
``````#  Python 3 Program
#  Find median of two sorted arrays
class MyArray :
# Function which is display array elements
def display(self, arr, size) :
i = 0
while (i < size) :
print(" ", arr[i], end = "")
i += 1

print("\n", end = "")

# Find the pair of smallest sum in given array
def smallest_pair(self, arr, size) :
if (size < 2) :
# When array contains less than 2 elements
return

# First pair sum
sum = arr[0] + arr[1]
# Get the first pair indexes
first = 0
second = 1
i = 0
while (i < size) :
j = i + 1
while (j < size) :
if (arr[i] + arr[j] < sum) :
# When get a new smallest  element pair
# Get the sum of new small pair
sum = arr[i] + arr[j]
# Get the location of new smallest pair
first = i
second = j

j += 1

i += 1

print("\n Array elements : ", end = "")
self.display(arr, size)
print("\n Smallest pair [", arr[first] ,", ", arr[second] ,"] : ", sum ,"\n", end = "")

def main() :
obj = MyArray()
a1 = [10, 15, -7, 31, 33]
# Get the size of array
size = len(a1)
obj.smallest_pair(a1, size)
a2 = [9, 6, 1, 5, 8, 3]
# Get the size of array
size = len(a2)
obj.smallest_pair(a2, size)

if __name__ == "__main__": main()``````

Output

`````` Array elements :   10  15  -7  31  33

Smallest pair [ 10 ,  -7 ] :  3

Array elements :   9  6  1  5  8  3

Smallest pair [ 1 ,  3 ] :  4``````
``````#  Ruby Program
#  Find median of two sorted arrays
class MyArray

# Function which is display array elements
def display(arr, size)

i = 0
while (i < size)

print(" ", arr[i])
i += 1
end
print("\n")
end
# Find the pair of smallest sum in given array
def smallest_pair(arr, size)

if (size < 2)

# When array contains less than 2 elements
return
end
# First pair sum
sum = arr[0] + arr[1]
# Get the first pair indexes
first = 0
second = 1
i = 0
while (i < size)

j = i + 1
while (j < size)

if (arr[i] + arr[j] < sum)

# When get a new smallest  element pair
# Get the sum of new small pair
sum = arr[i] + arr[j]
# Get the location of new smallest pair
first = i
second = j
end
j += 1
end
i += 1
end
print("\n Array elements : ")
self.display(arr, size)
print("\n Smallest pair [", arr[first] ,", ", arr[second] ,"] : ", sum ,"\n")
end
end
def main()

obj = MyArray.new()
a1 = [10, 15, -7, 31, 33]
# Get the size of array
size = a1.length
obj.smallest_pair(a1, size)
a2 = [9, 6, 1, 5, 8, 3]
# Get the size of array
size = a2.length
obj.smallest_pair(a2, size)
end
main()``````

Output

`````` Array elements :  10 15 -7 31 33

Smallest pair [10, -7] : 3

Array elements :  9 6 1 5 8 3

Smallest pair [1, 3] : 4
``````
``````// Scala Program
// Find median of two sorted arrays
class MyArray
{
//Function which is display array elements
def display(arr: Array[Int], size: Int): Unit = {
var i: Int = 0;
while (i < size)
{
print(" " + arr(i));
i += 1;
}
print("\n");
}
//Find the pair of smallest sum in given array
def smallest_pair(arr: Array[Int], size: Int): Unit = {
if (size < 2)
{
//When array contains less than 2 elements
return;
}
//First pair sum
var sum: Int = arr(0) + arr(1);
//Get the first pair indexes
var first: Int = 0;
var second: Int = 1;
var i: Int = 0;
while (i < size)
{
var j: Int = i + 1;
while (j < size)
{
if (arr(i) + arr(j) < sum)
{
//When get a new smallest  element pair
//Get the sum of new small pair
sum = arr(i) + arr(j);
//Get the location of new smallest pair
first = i;
second = j;
}
j += 1;
}
i += 1;
}
print("\n Array elements : ");
display(arr, size);
print("\n Smallest pair [" + arr(first) + ", " + arr(second) + "] : " + sum + "\n");
}
}
object Main
{
def main(args: Array[String]): Unit = {
var obj: MyArray = new MyArray();
var a1: Array[Int] = Array(10, 15, -7, 31, 33);
//Get the size of array
var size: Int = a1.length;
obj.smallest_pair(a1, size);
var a2: Array[Int] = Array(9, 6, 1, 5, 8, 3);
//Get the size of array
size = a2.length;
obj.smallest_pair(a2, size);
}
}``````

Output

`````` Array elements :  10 15 -7 31 33

Smallest pair [10, -7] : 3

Array elements :  9 6 1 5 8 3

Smallest pair [1, 3] : 4``````
``````// Swift Program
// Find median of two sorted arrays
class MyArray
{
//Function which is display array elements
func display(_ arr: [Int], _ size: Int)
{
var i: Int = 0;
while (i < size)
{
print(" ", arr[i], terminator: "");
i += 1;
}
print("\n", terminator: "");
}
//Find the pair of smallest sum in given array
func smallest_pair(_ arr: [Int], _ size: Int)
{
if (size < 2)
{
//When array contains less than 2 elements
return;
}
//First pair sum
var sum: Int = arr[0] + arr[1];
//Get the first pair indexes
var first: Int = 0;
var second: Int = 1;
var i: Int = 0;
while (i < size)
{
var j: Int = i + 1;
while (j < size)
{
if (arr[i] + arr[j] < sum)
{
//When get a new smallest  element pair
//Get the sum of new small pair
sum = arr[i] + arr[j];
//Get the location of new smallest pair
first = i;
second = j;
}
j += 1;
}
i += 1;
}
print("\n Array elements : ", terminator: "");
self.display(arr, size);
print("\n Smallest pair [", arr[first] ,", ", arr[second] ,"] : ", sum ,"\n", terminator: "");
}
}
func main()
{
let obj: MyArray = MyArray();
let a1: [Int] = [10, 15, -7, 31, 33];
//Get the size of array
var size: Int = a1.count;
obj.smallest_pair(a1, size);
let a2: [Int] = [9, 6, 1, 5, 8, 3];
//Get the size of array
size = a2.count;
obj.smallest_pair(a2, size);
}
main();``````

Output

`````` Array elements :   10  15  -7  31  33

Smallest pair [ 10 ,  -7 ] :  3

Array elements :   9  6  1  5  8  3

Smallest pair [ 1 ,  3 ] :  4``````

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