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Find smallest pair sum in an array

Here given code implementation process.

// C Program 
// Find smallest pair sum in an array
#include <stdio.h>

//Function which is display array elements
void display(int arr[], int size)
{
	for (int i = 0; i < size; ++i)
	{
		printf("%d ", arr[i]);
	}
	printf("\n");
}
//Find the pair of smallest sum in given array
void smallest_pair(int arr[], int size)
{
	if (size < 2)
	{
		//When array contains less than 2 elements
		return;
	}
	//First pair sum
	int sum = arr[0] + arr[1];
	//Get the first pair indexes
	int first = 0;
	int second = 1;
	for (int i = 0; i < size; ++i)
	{
		for (int j = i + 1; j < size; ++j)
		{
			if (arr[i] + arr[j] < sum)
			{
				//When get a new smallest  element pair
				//Get the sum of new small pair
				sum = arr[i] + arr[j];
				//Get the location of new smallest pair
				first = i;
				second = j;
			}
		}
	}
	printf("\n Array elements : ");
	display(arr, size);
	//Display result
	printf("\n Smallest pair [%d, %d] : %d\n", arr[first], arr[second], sum);
}
int main()
{
	int a1[] = {
		10 , 15 , -7 , 31 , 33
	};
	//Get the size of array
	int size = sizeof(a1) / sizeof(a1[0]);
	smallest_pair(a1, size);
	int a2[] = {
		9 , 6 , 1 , 5 , 8 , 3
	};
	//Get the size of array
	size = sizeof(a2) / sizeof(a2[0]);
	smallest_pair(a2, size);
	return 0;
}

Output

 Array elements : 10 15 -7 31 33

 Smallest pair [10, -7] : 3

 Array elements : 9 6 1 5 8 3

 Smallest pair [1, 3] : 4
// Java Program
// Find median of two sorted arrays
class MyArray
{
	//Function which is display array elements
	public void display(int[] arr, int size)
	{
		for (int i = 0; i < size; ++i)
		{
			System.out.print(" " + arr[i]);
		}
		System.out.print("\n");
	}
	//Find the pair of smallest sum in given array
	public void smallest_pair(int[] arr, int size)
	{
		if (size < 2)
		{
			//When array contains less than 2 elements
			return;
		}
		//First pair sum
		int sum = arr[0] + arr[1];
		//Get the first pair indexes
		int first = 0;
		int second = 1;
		for (int i = 0; i < size; ++i)
		{
			for (int j = i + 1; j < size; ++j)
			{
				if (arr[i] + arr[j] < sum)
				{
					//When get a new smallest  element pair
					//Get the sum of new small pair
					sum = arr[i] + arr[j];
					//Get the location of new smallest pair
					first = i;
					second = j;
				}
			}
		}
		System.out.print("\n Array elements : ");
		display(arr, size);
		System.out.print("\n Smallest pair [" + arr[first] + ", " + arr[second] + "] : " + sum + "\n");
	}
	public static void main(String[] args)
	{
		MyArray obj = new MyArray();
		int[] a1 = {
			10,
			15,
			-7,
			31,
			33
		};
		//Get the size of array
		int size = a1.length;
		obj.smallest_pair(a1, size);
		int[] a2 = {
			9,
			6,
			1,
			5,
			8,
			3
		};
		//Get the size of array
		size = a2.length;
		obj.smallest_pair(a2, size);
	}
}

Output

 Array elements :  10 15 -7 31 33

 Smallest pair [10, -7] : 3

 Array elements :  9 6 1 5 8 3

 Smallest pair [1, 3] : 4
//Include header file
#include <iostream>

using namespace std;
// C++ Program
// Find median of two sorted arrays
class MyArray
{
	public:
		//Function which is display array elements
		void display(int arr[], int size)
		{
			for (int i = 0; i < size; ++i)
			{
				cout << " " << arr[i];
			}
			cout << "\n";
		}
	//Find the pair of smallest sum in given array
	void smallest_pair(int arr[], int size)
	{
		if (size < 2)
		{
			//When array contains less than 2 elements
			return;
		}
		//First pair sum
		int sum = arr[0] + arr[1];
		//Get the first pair indexes
		int first = 0;
		int second = 1;
		for (int i = 0; i < size; ++i)
		{
			for (int j = i + 1; j < size; ++j)
			{
				if (arr[i] + arr[j] < sum)
				{
					//When get a new smallest  element pair
					//Get the sum of new small pair
					sum = arr[i] + arr[j];
					//Get the location of new smallest pair
					first = i;
					second = j;
				}
			}
		}
		cout << "\n Array elements : ";
		this->display(arr, size);
		cout << "\n Smallest pair [" << arr[first] << ", " << arr[second] << "] : " << sum << "\n";
	}
};
int main()
{
	MyArray obj = MyArray();
	int a1[] = {
		10 , 15 , -7 , 31 , 33
	};
	//Get the size of array
	int size = sizeof(a1) / sizeof(a1[0]);
	obj.smallest_pair(a1, size);
	int a2[] = {
		9 , 6 , 1 , 5 , 8 , 3
	};
	//Get the size of array
	size = sizeof(a2) / sizeof(a2[0]);
	obj.smallest_pair(a2, size);
	return 0;
}

Output

 Array elements :  10 15 -7 31 33

 Smallest pair [10, -7] : 3

 Array elements :  9 6 1 5 8 3

 Smallest pair [1, 3] : 4
//Include namespace system
using System;

// C# Program
// Find median of two sorted arrays
class MyArray
{
	//Function which is display array elements
	public void display(int[] arr, int size)
	{
		for (int i = 0; i < size; ++i)
		{
			Console.Write(" " + arr[i]);
		}
		Console.Write("\n");
	}
	//Find the pair of smallest sum in given array
	public void smallest_pair(int[] arr, int size)
	{
		if (size < 2)
		{
			//When array contains less than 2 elements
			return;
		}
		//First pair sum
		int sum = arr[0] + arr[1];
		//Get the first pair indexes
		int first = 0;
		int second = 1;
		for (int i = 0; i < size; ++i)
		{
			for (int j = i + 1; j < size; ++j)
			{
				if (arr[i] + arr[j] < sum)
				{
					//When get a new smallest  element pair
					//Get the sum of new small pair
					sum = arr[i] + arr[j];
					//Get the location of new smallest pair
					first = i;
					second = j;
				}
			}
		}
		Console.Write("\n Array elements : ");
		display(arr, size);
		Console.Write("\n Smallest pair [" + arr[first] + ", " + arr[second] + "] : " + sum + "\n");
	}
	public static void Main(String[] args)
	{
		MyArray obj = new MyArray();
		int[] a1 = {
			10 , 15 , -7 , 31 , 33
		};
		//Get the size of array
		int size = a1.Length;
		obj.smallest_pair(a1, size);
		int[] a2 = {
			9 , 6 , 1 , 5 , 8 , 3
		};
		//Get the size of array
		size = a2.Length;
		obj.smallest_pair(a2, size);
	}
}

Output

 Array elements :  10 15 -7 31 33

 Smallest pair [10, -7] : 3

 Array elements :  9 6 1 5 8 3

 Smallest pair [1, 3] : 4
<?php
// Php Program
// Find median of two sorted arrays
class MyArray
{
	//Function which is display array elements
	public	function display( & $arr, $size)
	{
		for ($i = 0; $i < $size; ++$i)
		{
			echo " ". $arr[$i];
		}
		echo "\n";
	}
	//Find the pair of smallest sum in given array
	public	function smallest_pair( & $arr, $size)
	{
		if ($size < 2)
		{
			//When array contains less than 2 elements
			return;
		}
		//First pair sum
		$sum = $arr[0] + $arr[1];
		//Get the first pair indexes
		$first = 0;
		$second = 1;
		for ($i = 0; $i < $size; ++$i)
		{
			for ($j = $i + 1; $j < $size; ++$j)
			{
				if ($arr[$i] + $arr[$j] < $sum)
				{
					//When get a new smallest  element pair
					//Get the sum of new small pair
					$sum = $arr[$i] + $arr[$j];
					//Get the location of new smallest pair
					$first = $i;
					$second = $j;
				}
			}
		}
		echo "\n Array elements : ";
		$this->display($arr, $size);
		echo "\n Smallest pair [". $arr[$first] .", ". $arr[$second] ."] : ". $sum ."\n";
	}
}

function main()
{
	$obj = new MyArray();
	$a1 = array(10, 15, -7, 31, 33);
	//Get the size of array
	$size = count($a1);
	$obj->smallest_pair($a1, $size);
	$a2 = array(9, 6, 1, 5, 8, 3);
	//Get the size of array
	$size = count($a2);
	$obj->smallest_pair($a2, $size);
}
main();

Output

 Array elements :  10 15 -7 31 33

 Smallest pair [10, -7] : 3

 Array elements :  9 6 1 5 8 3

 Smallest pair [1, 3] : 4
// Node Js Program
// Find median of two sorted arrays
class MyArray
{
	//Function which is display array elements
	display(arr, size)
	{
		for (var i = 0; i < size; ++i)
		{
			process.stdout.write(" " + arr[i]);
		}
		process.stdout.write("\n");
	}
	//Find the pair of smallest sum in given array
	smallest_pair(arr, size)
	{
		if (size < 2)
		{
			//When array contains less than 2 elements
			return;
		}
		//First pair sum
		var sum = arr[0] + arr[1];
		//Get the first pair indexes
		var first = 0;
		var second = 1;
		for (var i = 0; i < size; ++i)
		{
			for (var j = i + 1; j < size; ++j)
			{
				if (arr[i] + arr[j] < sum)
				{
					//When get a new smallest  element pair
					//Get the sum of new small pair
					sum = arr[i] + arr[j];
					//Get the location of new smallest pair
					first = i;
					second = j;
				}
			}
		}
		process.stdout.write("\n Array elements : ");
		this.display(arr, size);
		process.stdout.write("\n Smallest pair [" + arr[first] + ", " + arr[second] + "] : " + sum + "\n");
	}
}

function main()
{
	var obj = new MyArray();
	var a1 = [10, 15, -7, 31, 33];
	//Get the size of array
	var size = a1.length;
	obj.smallest_pair(a1, size);
	var a2 = [9, 6, 1, 5, 8, 3];
	//Get the size of array
	size = a2.length;
	obj.smallest_pair(a2, size);
}
main();

Output

 Array elements :  10 15 -7 31 33

 Smallest pair [10, -7] : 3

 Array elements :  9 6 1 5 8 3

 Smallest pair [1, 3] : 4
#  Python 3 Program
#  Find median of two sorted arrays
class MyArray :
	# Function which is display array elements
	def display(self, arr, size) :
		i = 0
		while (i < size) :
			print(" ", arr[i], end = "")
			i += 1
		
		print("\n", end = "")
	
	# Find the pair of smallest sum in given array
	def smallest_pair(self, arr, size) :
		if (size < 2) :
			# When array contains less than 2 elements
			return
		
		# First pair sum
		sum = arr[0] + arr[1]
		# Get the first pair indexes
		first = 0
		second = 1
		i = 0
		while (i < size) :
			j = i + 1
			while (j < size) :
				if (arr[i] + arr[j] < sum) :
					# When get a new smallest  element pair
					# Get the sum of new small pair
					sum = arr[i] + arr[j]
					# Get the location of new smallest pair
					first = i
					second = j
				
				j += 1
			
			i += 1
		
		print("\n Array elements : ", end = "")
		self.display(arr, size)
		print("\n Smallest pair [", arr[first] ,", ", arr[second] ,"] : ", sum ,"\n", end = "")
	

def main() :
	obj = MyArray()
	a1 = [10, 15, -7, 31, 33]
	# Get the size of array
	size = len(a1)
	obj.smallest_pair(a1, size)
	a2 = [9, 6, 1, 5, 8, 3]
	# Get the size of array
	size = len(a2)
	obj.smallest_pair(a2, size)

if __name__ == "__main__": main()

Output

 Array elements :   10  15  -7  31  33

 Smallest pair [ 10 ,  -7 ] :  3

 Array elements :   9  6  1  5  8  3

 Smallest pair [ 1 ,  3 ] :  4
#  Ruby Program
#  Find median of two sorted arrays
class MyArray

	# Function which is display array elements
	def display(arr, size)
	
		i = 0
		while (i < size)
		
			print(" ", arr[i])
			i += 1
		end
		print("\n")
	end
	# Find the pair of smallest sum in given array
	def smallest_pair(arr, size)
	
		if (size < 2)
		
			# When array contains less than 2 elements
			return
		end
		# First pair sum
		sum = arr[0] + arr[1]
		# Get the first pair indexes
		first = 0
		second = 1
		i = 0
		while (i < size)
		
			j = i + 1
			while (j < size)
			
				if (arr[i] + arr[j] < sum)
				
					# When get a new smallest  element pair
					# Get the sum of new small pair
					sum = arr[i] + arr[j]
					# Get the location of new smallest pair
					first = i
					second = j
				end
				j += 1
			end
			i += 1
		end
		print("\n Array elements : ")
		self.display(arr, size)
		print("\n Smallest pair [", arr[first] ,", ", arr[second] ,"] : ", sum ,"\n")
	end
end
def main()

	obj = MyArray.new()
	a1 = [10, 15, -7, 31, 33]
	# Get the size of array
	size = a1.length
	obj.smallest_pair(a1, size)
	a2 = [9, 6, 1, 5, 8, 3]
	# Get the size of array
	size = a2.length
	obj.smallest_pair(a2, size)
end
main()

Output

 Array elements :  10 15 -7 31 33

 Smallest pair [10, -7] : 3

 Array elements :  9 6 1 5 8 3

 Smallest pair [1, 3] : 4

// Scala Program
// Find median of two sorted arrays
class MyArray
{
	//Function which is display array elements
	def display(arr: Array[Int], size: Int): Unit = {
		var i: Int = 0;
		while (i < size)
		{
			print(" " + arr(i));
			i += 1;
		}
		print("\n");
	}
	//Find the pair of smallest sum in given array
	def smallest_pair(arr: Array[Int], size: Int): Unit = {
		if (size < 2)
		{
			//When array contains less than 2 elements
			return;
		}
		//First pair sum
		var sum: Int = arr(0) + arr(1);
		//Get the first pair indexes
		var first: Int = 0;
		var second: Int = 1;
		var i: Int = 0;
		while (i < size)
		{
			var j: Int = i + 1;
			while (j < size)
			{
				if (arr(i) + arr(j) < sum)
				{
					//When get a new smallest  element pair
					//Get the sum of new small pair
					sum = arr(i) + arr(j);
					//Get the location of new smallest pair
					first = i;
					second = j;
				}
				j += 1;
			}
			i += 1;
		}
		print("\n Array elements : ");
		display(arr, size);
		print("\n Smallest pair [" + arr(first) + ", " + arr(second) + "] : " + sum + "\n");
	}
}
object Main
{
	def main(args: Array[String]): Unit = {
		var obj: MyArray = new MyArray();
		var a1: Array[Int] = Array(10, 15, -7, 31, 33);
		//Get the size of array
		var size: Int = a1.length;
		obj.smallest_pair(a1, size);
		var a2: Array[Int] = Array(9, 6, 1, 5, 8, 3);
		//Get the size of array
		size = a2.length;
		obj.smallest_pair(a2, size);
	}
}

Output

 Array elements :  10 15 -7 31 33

 Smallest pair [10, -7] : 3

 Array elements :  9 6 1 5 8 3

 Smallest pair [1, 3] : 4
// Swift Program
// Find median of two sorted arrays
class MyArray
{
	//Function which is display array elements
	func display(_ arr: [Int], _ size: Int)
	{
		var i: Int = 0;
		while (i < size)
		{
			print(" ", arr[i], terminator: "");
			i += 1;
		}
		print("\n", terminator: "");
	}
	//Find the pair of smallest sum in given array
	func smallest_pair(_ arr: [Int], _ size: Int)
	{
		if (size < 2)
		{
			//When array contains less than 2 elements
			return;
		}
		//First pair sum
		var sum: Int = arr[0] + arr[1];
		//Get the first pair indexes
		var first: Int = 0;
		var second: Int = 1;
		var i: Int = 0;
		while (i < size)
		{
			var j: Int = i + 1;
			while (j < size)
			{
				if (arr[i] + arr[j] < sum)
				{
					//When get a new smallest  element pair
					//Get the sum of new small pair
					sum = arr[i] + arr[j];
					//Get the location of new smallest pair
					first = i;
					second = j;
				}
				j += 1;
			}
			i += 1;
		}
		print("\n Array elements : ", terminator: "");
		self.display(arr, size);
		print("\n Smallest pair [", arr[first] ,", ", arr[second] ,"] : ", sum ,"\n", terminator: "");
	}
}
func main()
{
	let obj: MyArray = MyArray();
	let a1: [Int] = [10, 15, -7, 31, 33];
	//Get the size of array
	var size: Int = a1.count;
	obj.smallest_pair(a1, size);
	let a2: [Int] = [9, 6, 1, 5, 8, 3];
	//Get the size of array
	size = a2.count;
	obj.smallest_pair(a2, size);
}
main();

Output

 Array elements :   10  15  -7  31  33

 Smallest pair [ 10 ,  -7 ] :  3

 Array elements :   9  6  1  5  8  3

 Smallest pair [ 1 ,  3 ] :  4
Last updated on by Kalkicode




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