Find the smallest missing number in sorted array
Here given code implementation process.
/*
C program for
Find the smallest missing number in sorted array
*/
#include <stdio.h>
// Find a smallest missing number in distinct sorted array
int smallestMissingNo(int arr[], int low, int high)
{
if (low <= high)
{
// Find middle position of given range
int mid = low + (high - low) / 2;
if (arr[mid] == mid)
{
// When mid index contains same value
// Change range mid+1 to high
return smallestMissingNo(arr, mid + 1, high);
}
// Change range low to mid-1
return smallestMissingNo(arr, low, mid - 1);
}
else
{
// When low value is largest to high
return low;
}
}
int main(int argc, char
const *argv[])
{
int arr1[] = {
0 , 1 , 2 , 3 , 4 , 7 , 11 , 17
};
int arr2[] = {
0 , 1 , 2 , 3
};
int arr3[] = {
1 , 2 , 3
};
// Test A
int n = sizeof(arr1) / sizeof(arr1[0]);
printf("\n %d", smallestMissingNo(arr1, 0, n - 1));
// Test B
n = sizeof(arr2) / sizeof(arr2[0]);
printf("\n %d", smallestMissingNo(arr2, 0, n - 1));
// Test C
n = sizeof(arr3) / sizeof(arr3[0]);
printf("\n %d", smallestMissingNo(arr3, 0, n - 1));
return 0;
}Output
5
4
0/*
Java program for
Find the smallest missing number in sorted array
*/
public class MissingNumber
{
// Find a smallest missing number in distinct sorted array
public int smallestMissingNo(int[] arr, int low, int high)
{
if (low <= high)
{
// Find middle position of given range
int mid = low + (high - low) / 2;
if (arr[mid] == mid)
{
// When mid index contains same value
// Change range mid+1 to high
return smallestMissingNo(arr, mid + 1, high);
}
// Change range low to mid-1
return smallestMissingNo(arr, low, mid - 1);
}
else
{
// When low value is largest to high
return low;
}
}
public static void main(String args[])
{
MissingNumber task = new MissingNumber();
// Array of positive distinct elements
int[] arr1 = {
0 , 1 , 2 , 3 , 4 , 7 , 11 , 17
};
int[] arr2 = {
0 , 1 , 2 , 3
};
int[] arr3 = {
1 , 2 , 3
};
// Test A
int n = arr1.length;
System.out.print("\n " + task.smallestMissingNo(arr1, 0, n - 1));
// Test B
n = arr2.length;
System.out.print("\n " + task.smallestMissingNo(arr2, 0, n - 1));
// Test C
n = arr3.length;
System.out.print("\n " + task.smallestMissingNo(arr3, 0, n - 1));
}
}Output
5
4
0// Include header file
#include <iostream>
using namespace std;
/*
C++ program for
Find the smallest missing number in sorted array
*/
class MissingNumber
{
public:
// Find a smallest missing number in distinct sorted array
int smallestMissingNo(int arr[], int low, int high)
{
if (low <= high)
{
// Find middle position of given range
int mid = low + (high - low) / 2;
if (arr[mid] == mid)
{
// When mid index contains same value
// Change range mid+1 to high
return this->smallestMissingNo(arr, mid + 1, high);
}
// Change range low to mid-1
return this->smallestMissingNo(arr, low, mid - 1);
}
else
{
// When low value is largest to high
return low;
}
}
};
int main()
{
MissingNumber *task = new MissingNumber();
// Array of positive distinct elements
int arr1[] = {
0 , 1 , 2 , 3 , 4 , 7 , 11 , 17
};
int arr2[] = {
0 , 1 , 2 , 3
};
int arr3[] = {
1 , 2 , 3
};
// Test A
int n = sizeof(arr1) / sizeof(arr1[0]);
cout << "\n " << task->smallestMissingNo(arr1, 0, n - 1);
// Test B
n = sizeof(arr2) / sizeof(arr2[0]);
cout << "\n " << task->smallestMissingNo(arr2, 0, n - 1);
// Test C
n = sizeof(arr3) / sizeof(arr3[0]);
cout << "\n " << task->smallestMissingNo(arr3, 0, n - 1);
return 0;
}Output
5
4
0// Include namespace system
using System;
/*
Csharp program for
Find the smallest missing number in sorted array
*/
public class MissingNumber
{
// Find a smallest missing number in distinct sorted array
public int smallestMissingNo(int[] arr, int low, int high)
{
if (low <= high)
{
// Find middle position of given range
int mid = low + (high - low) / 2;
if (arr[mid] == mid)
{
// When mid index contains same value
// Change range mid+1 to high
return this.smallestMissingNo(arr, mid + 1, high);
}
// Change range low to mid-1
return this.smallestMissingNo(arr, low, mid - 1);
}
else
{
// When low value is largest to high
return low;
}
}
public static void Main(String[] args)
{
MissingNumber task = new MissingNumber();
// Array of positive distinct elements
int[] arr1 = {
0 , 1 , 2 , 3 , 4 , 7 , 11 , 17
};
int[] arr2 = {
0 , 1 , 2 , 3
};
int[] arr3 = {
1 , 2 , 3
};
// Test A
int n = arr1.Length;
Console.Write("\n " + task.smallestMissingNo(arr1, 0, n - 1));
// Test B
n = arr2.Length;
Console.Write("\n " + task.smallestMissingNo(arr2, 0, n - 1));
// Test C
n = arr3.Length;
Console.Write("\n " + task.smallestMissingNo(arr3, 0, n - 1));
}
}Output
5
4
0package main
import "fmt"
/*
Go program for
Find the smallest missing number in sorted array
*/
// Find a smallest missing number in distinct sorted array
func smallestMissingNo(arr[] int, low int, high int) int {
if low <= high {
// Find middle position of given range
var mid int = low + (high - low) / 2
if arr[mid] == mid {
// When mid index contains same value
// Change range mid+1 to high
return smallestMissingNo(arr, mid + 1, high)
}
// Change range low to mid-1
return smallestMissingNo(arr, low, mid - 1)
} else {
// When low value is largest to high
return low
}
}
func main() {
// Array of positive distinct elements
var arr1 = [] int {0, 1, 2, 3, 4, 7, 11, 17}
var arr2 = [] int {0, 1, 2, 3}
var arr3 = [] int {1, 2, 3}
// Test A
var n int = len(arr1)
fmt.Print("\n ", smallestMissingNo(arr1, 0, n - 1))
// Test B
n = len(arr2)
fmt.Print("\n ", smallestMissingNo(arr2, 0, n - 1))
// Test C
n = len(arr3)
fmt.Print("\n ", smallestMissingNo(arr3, 0, n - 1))
}Output
5
4
0<?php
/*
Php program for
Find the smallest missing number in sorted array
*/
class MissingNumber
{
// Find a smallest missing number in distinct sorted array
public function smallestMissingNo($arr, $low, $high)
{
if ($low <= $high)
{
// Find middle position of given range
$mid = $low + (int)(($high - $low) / 2);
if ($arr[$mid] == $mid)
{
// When mid index contains same value
// Change range mid+1 to high
return $this->smallestMissingNo($arr, $mid + 1, $high);
}
// Change range low to mid-1
return $this->smallestMissingNo($arr, $low, $mid - 1);
}
else
{
// When low value is largest to high
return $low;
}
}
}
function main()
{
$task = new MissingNumber();
// Array of positive distinct elements
$arr1 = array(0, 1, 2, 3, 4, 7, 11, 17);
$arr2 = array(0, 1, 2, 3);
$arr3 = array(1, 2, 3);
// Test A
$n = count($arr1);
echo("\n ".$task->smallestMissingNo($arr1, 0, $n - 1));
// Test B
$n = count($arr2);
echo("\n ".$task->smallestMissingNo($arr2, 0, $n - 1));
// Test C
$n = count($arr3);
echo("\n ".$task->smallestMissingNo($arr3, 0, $n - 1));
}
main();Output
5
4
0/*
Node JS program for
Find the smallest missing number in sorted array
*/
class MissingNumber
{
// Find a smallest missing number in distinct sorted array
smallestMissingNo(arr, low, high)
{
if (low <= high)
{
// Find middle position of given range
var mid = low + parseInt((high - low) / 2);
if (arr[mid] == mid)
{
// When mid index contains same value
// Change range mid+1 to high
return this.smallestMissingNo(arr, mid + 1, high);
}
// Change range low to mid-1
return this.smallestMissingNo(arr, low, mid - 1);
}
else
{
// When low value is largest to high
return low;
}
}
}
function main()
{
var task = new MissingNumber();
// Array of positive distinct elements
var arr1 = [0, 1, 2, 3, 4, 7, 11, 17];
var arr2 = [0, 1, 2, 3];
var arr3 = [1, 2, 3];
// Test A
var n = arr1.length;
process.stdout.write("\n " + task.smallestMissingNo(arr1, 0, n - 1));
// Test B
n = arr2.length;
process.stdout.write("\n " + task.smallestMissingNo(arr2, 0, n - 1));
// Test C
n = arr3.length;
process.stdout.write("\n " + task.smallestMissingNo(arr3, 0, n - 1));
}
main();Output
5
4
0# Python 3 program for
# Find the smallest missing number in sorted array
class MissingNumber :
# Find a smallest missing number in distinct sorted list
def smallestMissingNo(self, arr, low, high) :
if (low <= high) :
# Find middle position of given range
mid = low + int((high - low) / 2)
if (arr[mid] == mid) :
# When mid index contains same value
# Change range mid+1 to high
return self.smallestMissingNo(arr, mid + 1, high)
# Change range low to mid-1
return self.smallestMissingNo(arr, low, mid - 1)
else :
# When low value is largest to high
return low
def main() :
task = MissingNumber()
# Array of positive distinct elements
arr1 = [0, 1, 2, 3, 4, 7, 11, 17]
arr2 = [0, 1, 2, 3]
arr3 = [1, 2, 3]
# Test A
n = len(arr1)
print("\n ", task.smallestMissingNo(arr1, 0, n - 1), end = "")
# Test B
n = len(arr2)
print("\n ", task.smallestMissingNo(arr2, 0, n - 1), end = "")
# Test C
n = len(arr3)
print("\n ", task.smallestMissingNo(arr3, 0, n - 1), end = "")
if __name__ == "__main__": main()Output
5
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0# Ruby program for
# Find the smallest missing number in sorted array
class MissingNumber
# Find a smallest missing number in distinct sorted array
def smallestMissingNo(arr, low, high)
if (low <= high)
# Find middle position of given range
mid = low + (high - low) / 2
if (arr[mid] == mid)
# When mid index contains same value
# Change range mid+1 to high
return self.smallestMissingNo(arr, mid + 1, high)
end
# Change range low to mid-1
return self.smallestMissingNo(arr, low, mid - 1)
else
# When low value is largest to high
return low
end
end
end
def main()
task = MissingNumber.new()
# Array of positive distinct elements
arr1 = [0, 1, 2, 3, 4, 7, 11, 17]
arr2 = [0, 1, 2, 3]
arr3 = [1, 2, 3]
# Test A
n = arr1.length
print("\n ", task.smallestMissingNo(arr1, 0, n - 1))
# Test B
n = arr2.length
print("\n ", task.smallestMissingNo(arr2, 0, n - 1))
# Test C
n = arr3.length
print("\n ", task.smallestMissingNo(arr3, 0, n - 1))
end
main()Output
5
4
0/*
Scala program for
Find the smallest missing number in sorted array
*/
class MissingNumber()
{
// Find a smallest missing number in distinct sorted array
def smallestMissingNo(arr: Array[Int], low: Int, high: Int): Int = {
if (low <= high)
{
// Find middle position of given range
var mid: Int = low + (high - low) / 2;
if (arr(mid) == mid)
{
// When mid index contains same value
// Change range mid+1 to high
return smallestMissingNo(arr, mid + 1, high);
}
// Change range low to mid-1
return smallestMissingNo(arr, low, mid - 1);
}
else
{
// When low value is largest to high
return low;
}
}
}
object Main
{
def main(args: Array[String]): Unit = {
var task: MissingNumber = new MissingNumber();
// Array of positive distinct elements
var arr1: Array[Int] = Array(0, 1, 2, 3, 4, 7, 11, 17);
var arr2: Array[Int] = Array(0, 1, 2, 3);
var arr3: Array[Int] = Array(1, 2, 3);
// Test A
var n: Int = arr1.length;
print("\n " + task.smallestMissingNo(arr1, 0, n - 1));
// Test B
n = arr2.length;
print("\n " + task.smallestMissingNo(arr2, 0, n - 1));
// Test C
n = arr3.length;
print("\n " + task.smallestMissingNo(arr3, 0, n - 1));
}
}Output
5
4
0import Foundation;
/*
Swift 4 program for
Find the smallest missing number in sorted array
*/
class MissingNumber
{
// Find a smallest missing number in distinct sorted array
func smallestMissingNo(_ arr: [Int], _ low: Int, _ high: Int) -> Int
{
if (low <= high)
{
// Find middle position of given range
let mid: Int = low + (high - low) / 2;
if (arr[mid] == mid)
{
// When mid index contains same value
// Change range mid+1 to high
return self.smallestMissingNo(arr, mid + 1, high);
}
// Change range low to mid-1
return self.smallestMissingNo(arr, low, mid - 1);
}
else
{
// When low value is largest to high
return low;
}
}
}
func main()
{
let task: MissingNumber = MissingNumber();
// Array of positive distinct elements
let arr1: [Int] = [0, 1, 2, 3, 4, 7, 11, 17];
let arr2: [Int] = [0, 1, 2, 3];
let arr3: [Int] = [1, 2, 3];
// Test A
var n: Int = arr1.count;
print("\n ", task.smallestMissingNo(arr1, 0, n - 1), terminator: "");
// Test B
n = arr2.count;
print("\n ", task.smallestMissingNo(arr2, 0, n - 1), terminator: "");
// Test C
n = arr3.count;
print("\n ", task.smallestMissingNo(arr3, 0, n - 1), terminator: "");
}
main();Output
5
4
0/*
Kotlin program for
Find the smallest missing number in sorted array
*/
class MissingNumber
{
// Find a smallest missing number in distinct sorted array
fun smallestMissingNo(arr: Array < Int > , low: Int, high: Int): Int
{
if (low <= high)
{
// Find middle position of given range
val mid: Int = low + (high - low) / 2;
if (arr[mid] == mid)
{
// When mid index contains same value
// Change range mid+1 to high
return this.smallestMissingNo(arr, mid + 1, high);
}
// Change range low to mid-1
return this.smallestMissingNo(arr, low, mid - 1);
}
else
{
// When low value is largest to high
return low;
}
}
}
fun main(args: Array < String > ): Unit
{
val task: MissingNumber = MissingNumber();
// Array of positive distinct elements
val arr1: Array < Int > = arrayOf(0, 1, 2, 3, 4, 7, 11, 17);
val arr2: Array < Int > = arrayOf(0, 1, 2, 3);
val arr3: Array < Int > = arrayOf(1, 2, 3);
// Test A
var n: Int = arr1.count();
print("\n " + task.smallestMissingNo(arr1, 0, n - 1));
// Test B
n = arr2.count();
print("\n " + task.smallestMissingNo(arr2, 0, n - 1));
// Test C
n = arr3.count();
print("\n " + task.smallestMissingNo(arr3, 0, n - 1));
}Output
5
4
0
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