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Find the size of maximum sum subarray

Here given code implementation process.

// C Program
// Find the size of maximum sum subarray
#include <stdio.h>
#include <limits.h>

void printArray(int arr[], int n)
{
	for (int i = 0; i < n; ++i)
	{
		printf("  %d", arr[i]);
	}
	printf("\n");
}
void sizeMaxSumSubarray(int arr[], int n)
{
	// Resultant index
	int s = 0, e = 0;
	// Auxiliary variables
	int temp = 0;
	int result = INT_MIN;
	int sum = 0;
	for (int i = 0; i < n; ++i)
	{
		// Current sum
		sum += arr[i];
		if (result < sum)
		{
			// When sum is greater than result.
			// Get resultant intex.
			s = temp;
			e = i;
			// Change sum
			result = sum;
		}
		if (sum < 0)
		{
			temp = i + 1;
			// Reset sum
			sum = 0;
		}
	}
	result = (e - s + 1);
	printArray(arr, n);
	printf(" Result : %d \n", result);
}
int main()
{
	// Given array elements
	int arr1[] = {
		1 , 2 , -5 , 1 , 2 , -3 , 3 , -2 , 8 , -4
	};
	int arr2[] = {
		-5 , 1 , 2 , -10 , 3 , 1 , 2 , 8 , -2
	};
	// Test A
	// Get the number of elements
	int n = sizeof(arr1) / sizeof(arr1[0]);
	// [1 , 2 , -3 , 3 , -2 , 8]
	// Result : 6
	sizeMaxSumSubarray(arr1, n);
	// Test B
	// Get the number of elements
	n = sizeof(arr2) / sizeof(arr2[0]);
	// [3, 1, 2, 8]
	// Result 4
	sizeMaxSumSubarray(arr2, n);
	return 0;
}

Output

  1  2  -5  1  2  -3  3  -2  8  -4
 Result : 6
  -5  1  2  -10  3  1  2  8  -2
 Result : 4
// Java program for
// Find the size of maximum sum subarray
public class SubArray
{
    public void printArray(int[] arr, int n)
    {
        for (int i = 0; i < n; ++i)
        {
            System.out.print(" " + arr[i] );
        }
        System.out.print("\n");
    }
    public void sizeMaxSumSubarray(int[] arr, int n)
    {
        // Resultant index
        int s = 0, e = 0;
        // Auxiliary variables
        int temp = 0;
        int result = Integer.MIN_VALUE;
        int sum = 0;
        for (int i = 0; i < n; ++i)
        {
            // Current sum
            sum += arr[i];
            if (result < sum)
            {
                // When sum is greater than result.
                // Get resultant intex.
                s = temp;
                e = i;
                // Change sum
                result = sum;
            }
            if (sum < 0)
            {
                temp = i + 1;
                // Reset sum
                sum = 0;
            }
        }
        result = (e - s + 1);
        printArray(arr, n);
        System.out.print(" Result : " + result + " \n");
    }
    public static void main(String[] args)
    {
        SubArray task = new SubArray();
        // Given array elements
        int[] arr1 = {
            1 , 2 , -5 , 1 , 2 , -3 , 3 , -2 , 8 , -4
        };
        int[] arr2 = {
            -5 , 1 , 2 , -10 , 3 , 1 , 2 , 8 , -2
        };
        // Test A
        // Get the number of elements
        int n = arr1.length;
        // [1 , 2 , -3 , 3 , -2 , 8]
        // Result : 6
        task.sizeMaxSumSubarray(arr1, n);
        // Test B
        // Get the number of elements
        n = arr2.length;
        // [3, 1, 2, 8]
        // Result 4
        task.sizeMaxSumSubarray(arr2, n);
    }
}

Output

 1 2 -5 1 2 -3 3 -2 8 -4
 Result : 6
 -5 1 2 -10 3 1 2 8 -2
 Result : 4
// Include header file
#include <iostream>
#include <limits.h>

using namespace std;
// C++ program for
// Find the size of maximum sum subarray
class SubArray
{
	public: void printArray(int arr[], int n)
	{
		for (int i = 0; i < n; ++i)
		{
			cout << " " << arr[i];
		}
		cout << "\n";
	}
	void sizeMaxSumSubarray(int arr[], int n)
	{
		// Resultant index
		int s = 0;
		int e = 0;
		// Auxiliary variables
		int temp = 0;
		int result = INT_MIN;
		int sum = 0;
		for (int i = 0; i < n; ++i)
		{
			// Current sum
			sum += arr[i];
			if (result < sum)
			{
				// When sum is greater than result.
				// Get resultant intex.
				s = temp;
				e = i;
				// Change sum
				result = sum;
			}
			if (sum < 0)
			{
				temp = i + 1;
				// Reset sum
				sum = 0;
			}
		}
		result = (e - s + 1);
		this->printArray(arr, n);
		cout << " Result : " << result << " \n";
	}
};
int main()
{
	SubArray *task = new SubArray();
	// Given array elements
	int arr1[] = {
		1 , 2 , -5 , 1 , 2 , -3 , 3 , -2 , 8 , -4
	};
	int arr2[] = {
		-5 , 1 , 2 , -10 , 3 , 1 , 2 , 8 , -2
	};
	// Test A
	// Get the number of elements
	int n = sizeof(arr1) / sizeof(arr1[0]);
	// [1 , 2 , -3 , 3 , -2 , 8]
	// Result : 6
	task->sizeMaxSumSubarray(arr1, n);
	// Test B
	// Get the number of elements
	n = sizeof(arr2) / sizeof(arr2[0]);
	// [3, 1, 2, 8]
	// Result 4
	task->sizeMaxSumSubarray(arr2, n);
	return 0;
}

Output

 1 2 -5 1 2 -3 3 -2 8 -4
 Result : 6
 -5 1 2 -10 3 1 2 8 -2
 Result : 4
// Include namespace system
using System;
// Csharp program for
// Find the size of maximum sum subarray
public class SubArray
{
	public void printArray(int[] arr, int n)
	{
		for (int i = 0; i < n; ++i)
		{
			Console.Write(" " + arr[i]);
		}
		Console.Write("\n");
	}
	public void sizeMaxSumSubarray(int[] arr, int n)
	{
		// Resultant index
		int s = 0;
		int e = 0;
		// Auxiliary variables
		int temp = 0;
		int result = int.MinValue;
		int sum = 0;
		for (int i = 0; i < n; ++i)
		{
			// Current sum
			sum += arr[i];
			if (result < sum)
			{
				// When sum is greater than result.
				// Get resultant intex.
				s = temp;
				e = i;
				// Change sum
				result = sum;
			}
			if (sum < 0)
			{
				temp = i + 1;
				// Reset sum
				sum = 0;
			}
		}
		result = (e - s + 1);
		this.printArray(arr, n);
		Console.Write(" Result : " + result + " \n");
	}
	public static void Main(String[] args)
	{
		SubArray task = new SubArray();
		// Given array elements
		int[] arr1 = {
			1 , 2 , -5 , 1 , 2 , -3 , 3 , -2 , 8 , -4
		};
		int[] arr2 = {
			-5 , 1 , 2 , -10 , 3 , 1 , 2 , 8 , -2
		};
		// Test A
		// Get the number of elements
		int n = arr1.Length;
		// [1 , 2 , -3 , 3 , -2 , 8]
		// Result : 6
		task.sizeMaxSumSubarray(arr1, n);
		// Test B
		// Get the number of elements
		n = arr2.Length;
		// [3, 1, 2, 8]
		// Result 4
		task.sizeMaxSumSubarray(arr2, n);
	}
}

Output

 1 2 -5 1 2 -3 3 -2 8 -4
 Result : 6
 -5 1 2 -10 3 1 2 8 -2
 Result : 4
package main
import "math"
import "fmt"
// Go program for
// Find the size of maximum sum subarray

func printArray(arr[] int, n int) {
	for i := 0 ; i < n ; i++ {
		fmt.Print(" ", arr[i])
	}
	fmt.Print("\n")
}
func sizeMaxSumSubarray(arr[] int, n int) {
	// Resultant index
	var s int = 0
	var e int = 0
	// Auxiliary variables
	var temp int = 0
	var result int = math.MinInt64
	var sum int = 0
	for i := 0 ; i < n ; i++ {
		// Current sum
		sum += arr[i]
		if result < sum {
			// When sum is greater than result.
			// Get resultant intex.
			s = temp
			e = i
			// Change sum
			result = sum
		}
		if sum < 0 {
			temp = i + 1
			// Reset sum
			sum = 0
		}
	}
	result = (e - s + 1)
	printArray(arr, n)
	fmt.Print(" Result : ", result, " \n")
}
func main() {
	
	// Given array elements
	var arr1 = [] int {1 , 2 , -5 , 1 , 2 , -3 , 3 , -2 , 8, -4}
	var arr2 = [] int {-5, 1, 2, -10, 3, 1, 2, 8, -2}
	// Test A
	// Get the number of elements
	var n int = len(arr1)
	// [1 , 2 , -3 , 3 , -2 , 8]
	// Result : 6
	sizeMaxSumSubarray(arr1, n)
	// Test B
	// Get the number of elements
	n = len(arr2)
	// [3, 1, 2, 8]
	// Result 4
	sizeMaxSumSubarray(arr2, n)
}

Output

 1 2 -5 1 2 -3 3 -2 8 -4
 Result : 6
 -5 1 2 -10 3 1 2 8 -2
 Result : 4
<?php
// Php program for
// Find the size of maximum sum subarray
class SubArray
{
	public	function printArray($arr, $n)
	{
		for ($i = 0; $i < $n; ++$i)
		{
			echo(" ".$arr[$i]);
		}
		echo("\n");
	}
	public	function sizeMaxSumSubarray($arr, $n)
	{
		// Resultant index
		$s = 0;
		$e = 0;
		// Auxiliary variables
		$temp = 0;
		$result = -PHP_INT_MAX;
		$sum = 0;
		for ($i = 0; $i < $n; ++$i)
		{
			// Current sum
			$sum += $arr[$i];
			if ($result < $sum)
			{
				// When sum is greater than result.
				// Get resultant intex.
				$s = $temp;
				$e = $i;
				// Change sum
				$result = $sum;
			}
			if ($sum < 0)
			{
				$temp = $i + 1;
				// Reset sum
				$sum = 0;
			}
		}
		$result = ($e - $s + 1);
		$this->printArray($arr, $n);
		echo(" Result : ".$result." \n");
	}
}

function main()
{
	$task = new SubArray();
	// Given array elements
	$arr1 = array(1, 2, -5, 1, 2, -3, 3, -2, 8, -4);
	$arr2 = array(-5, 1, 2, -10, 3, 1, 2, 8, -2);
	// Test A
	// Get the number of elements
	$n = count($arr1);
	// [1 , 2 , -3 , 3 , -2 , 8]
	// Result : 6
	$task->sizeMaxSumSubarray($arr1, $n);
	// Test B
	// Get the number of elements
	$n = count($arr2);
	// [3, 1, 2, 8]
	// Result 4
	$task->sizeMaxSumSubarray($arr2, $n);
}
main();

Output

 1 2 -5 1 2 -3 3 -2 8 -4
 Result : 6
 -5 1 2 -10 3 1 2 8 -2
 Result : 4
// Node JS program for
// Find the size of maximum sum subarray
class SubArray
{
	printArray(arr, n)
	{
		for (var i = 0; i < n; ++i)
		{
			process.stdout.write(" " + arr[i]);
		}
		process.stdout.write("\n");
	}
	sizeMaxSumSubarray(arr, n)
	{
		// Resultant index
		var s = 0;
		var e = 0;
		// Auxiliary variables
		var temp = 0;
		var result = -Number.MAX_VALUE;
		var sum = 0;
		for (var i = 0; i < n; ++i)
		{
			// Current sum
			sum += arr[i];
			if (result < sum)
			{
				// When sum is greater than result.
				// Get resultant intex.
				s = temp;
				e = i;
				// Change sum
				result = sum;
			}
			if (sum < 0)
			{
				temp = i + 1;
				// Reset sum
				sum = 0;
			}
		}
		result = (e - s + 1);
		this.printArray(arr, n);
		process.stdout.write(" Result : " + result + " \n");
	}
}

function main()
{
	var task = new SubArray();
	// Given array elements
	var arr1 = [1, 2, -5, 1, 2, -3, 3, -2, 8, -4];
	var arr2 = [-5, 1, 2, -10, 3, 1, 2, 8, -2];
	// Test A
	// Get the number of elements
	var n = arr1.length;
	// [1 , 2 , -3 , 3 , -2 , 8]
	// Result : 6
	task.sizeMaxSumSubarray(arr1, n);
	// Test B
	// Get the number of elements
	n = arr2.length;
	// [3, 1, 2, 8]
	// Result 4
	task.sizeMaxSumSubarray(arr2, n);
}
main();

Output

 1 2 -5 1 2 -3 3 -2 8 -4
 Result : 6
 -5 1 2 -10 3 1 2 8 -2
 Result : 4
import sys
#  Python 3 program for
#  Find the size of maximum sum subarray
class SubArray :
	def printArray(self, arr, n) :
		i = 0
		while (i < n) :
			print(" ", arr[i], end = "")
			i += 1
		
		print(end = "\n")
	
	def sizeMaxSumSubarray(self, arr, n) :
		#  Resultant index
		s = 0
		e = 0
		#  Auxiliary variables
		temp = 0
		result = -sys.maxsize
		sum = 0
		i = 0
		while (i < n) :
			#  Current sum
			sum += arr[i]
			if (result < sum) :
				#  When sum is greater than result.
				#  Get resultant intex.
				s = temp
				e = i
				#  Change sum
				result = sum
			
			if (sum < 0) :
				temp = i + 1
				#  Reset sum
				sum = 0
			
			i += 1
		
		result = (e - s + 1)
		self.printArray(arr, n)
		print(" Result : ", result ," ")
	

def main() :
	task = SubArray()
	#  Given list elements
	arr1 = [1, 2, -5, 1, 2, -3, 3, -2, 8, -4]
	arr2 = [-5, 1, 2, -10, 3, 1, 2, 8, -2]
	#  Test A
	#  Get the number of elements
	n = len(arr1)
	#  [1 , 2 , -3 , 3 , -2 , 8]
	#  Result : 6
	task.sizeMaxSumSubarray(arr1, n)
	#  Test B
	#  Get the number of elements
	n = len(arr2)
	#  [3, 1, 2, 8]
	#  Result 4
	task.sizeMaxSumSubarray(arr2, n)

if __name__ == "__main__": main()

Output

  1  2  -5  1  2  -3  3  -2  8  -4
 Result :  6
  -5  1  2  -10  3  1  2  8  -2
 Result :  4
#  Ruby program for
#  Find the size of maximum sum subarray
class SubArray 
	def printArray(arr, n) 
		i = 0
		while (i < n) 
			print(" ", arr[i])
			i += 1
		end

		print("\n")
	end

	def sizeMaxSumSubarray(arr, n) 
		#  Resultant index
		s = 0
		e = 0
		#  Auxiliary variables
		temp = 0
		result = -(2 ** (0. size * 8 - 2))
		sum = 0
		i = 0
		while (i < n) 
			#  Current sum
			sum += arr[i]
			if (result < sum) 
				#  When sum is greater than result.
				#  Get resultant intex.
				s = temp
				e = i
				#  Change sum
				result = sum
			end

			if (sum < 0) 
				temp = i + 1
				#  Reset sum
				sum = 0
			end

			i += 1
		end

		result = (e - s + 1)
		self.printArray(arr, n)
		print(" Result : ", result ," \n")
	end

end

def main() 
	task = SubArray.new()
	#  Given array elements
	arr1 = [1, 2, -5, 1, 2, -3, 3, -2, 8, -4]
	arr2 = [-5, 1, 2, -10, 3, 1, 2, 8, -2]
	#  Test A
	#  Get the number of elements
	n = arr1.length
	#  [1 , 2 , -3 , 3 , -2 , 8]
	#  Result : 6
	task.sizeMaxSumSubarray(arr1, n)
	#  Test B
	#  Get the number of elements
	n = arr2.length
	#  [3, 1, 2, 8]
	#  Result 4
	task.sizeMaxSumSubarray(arr2, n)
end

main()

Output

 1 2 -5 1 2 -3 3 -2 8 -4
 Result : 6 
 -5 1 2 -10 3 1 2 8 -2
 Result : 4 

// Scala program for
// Find the size of maximum sum subarray
class SubArray()
{
	def printArray(arr: Array[Int], n: Int): Unit = {
		var i: Int = 0;
		while (i < n)
		{
			print(" " + arr(i));
			i += 1;
		}
		print("\n");
	}
	def sizeMaxSumSubarray(arr: Array[Int], n: Int): Unit = {
		// Resultant index
		var s: Int = 0;
		var e: Int = 0;
		// Auxiliary variables
		var temp: Int = 0;
		var result: Int = Int.MinValue;
		var sum: Int = 0;
		var i: Int = 0;
		while (i < n)
		{
			// Current sum
			sum += arr(i);
			if (result < sum)
			{
				// When sum is greater than result.
				// Get resultant intex.
				s = temp;
				e = i;
				// Change sum
				result = sum;
			}
			if (sum < 0)
			{
				temp = i + 1;
				// Reset sum
				sum = 0;
			}
			i += 1;
		}
		result = (e - s + 1);
		printArray(arr, n);
		print(" Result : " + result + " \n");
	}
}
object Main
{
	def main(args: Array[String]): Unit = {
		var task: SubArray = new SubArray();
		// Given array elements
		var arr1: Array[Int] = Array(1, 2, -5, 1, 2, -3, 3, -2, 8, -4);
		var arr2: Array[Int] = Array(-5, 1, 2, -10, 3, 1, 2, 8, -2);
		// Test A
		// Get the number of elements
		var n: Int = arr1.length;
		// [1 , 2 , -3 , 3 , -2 , 8]
		// Result : 6
		task.sizeMaxSumSubarray(arr1, n);
		// Test B
		// Get the number of elements
		n = arr2.length;
		// [3, 1, 2, 8]
		// Result 4
		task.sizeMaxSumSubarray(arr2, n);
	}
}

Output

 1 2 -5 1 2 -3 3 -2 8 -4
 Result : 6
 -5 1 2 -10 3 1 2 8 -2
 Result : 4
import Foundation;
// Swift 4 program for
// Find the size of maximum sum subarray
class SubArray
{
	func printArray(_ arr: [Int], _ n: Int)
	{
		var i: Int = 0;
		while (i < n)
		{
			print(" ", arr[i], terminator: "");
			i += 1;
		}
		print(terminator: "\n");
	}
	func sizeMaxSumSubarray(_ arr: [Int], _ n: Int)
	{
		// Resultant index
		var s: Int = 0;
		var e: Int = 0;
		// Auxiliary variables
		var temp: Int = 0;
		var result: Int = Int.min;
		var sum: Int = 0;
		var i: Int = 0;
		while (i < n)
		{
			// Current sum
			sum += arr[i];
			if (result < sum)
			{
				// When sum is greater than result.
				// Get resultant intex.
				s = temp;
				e = i;
				// Change sum
				result = sum;
			}
			if (sum < 0)
			{
				temp = i + 1;
				// Reset sum
				sum = 0;
			}
			i += 1;
		}
		result = (e - s + 1);
		self.printArray(arr, n);
		print(" Result : ", result ," ");
	}
}
func main()
{
	let task: SubArray = SubArray();
	// Given array elements
	let arr1: [Int] = [1, 2, -5, 1, 2, -3, 3, -2, 8, -4];
	let arr2: [Int] = [-5, 1, 2, -10, 3, 1, 2, 8, -2];
	// Test A
	// Get the number of elements
	var n: Int = arr1.count;
	// [1 , 2 , -3 , 3 , -2 , 8]
	// Result : 6
	task.sizeMaxSumSubarray(arr1, n);
	// Test B
	// Get the number of elements
	n = arr2.count;
	// [3, 1, 2, 8]
	// Result 4
	task.sizeMaxSumSubarray(arr2, n);
}
main();

Output

  1  2  -5  1  2  -3  3  -2  8  -4
 Result :  6
  -5  1  2  -10  3  1  2  8  -2
 Result :  4
// Kotlin program for
// Find the size of maximum sum subarray
class SubArray
{
	fun printArray(arr: Array < Int > , n: Int): Unit
	{
		var i: Int = 0;
		while (i < n)
		{
			print(" " + arr[i]);
			i += 1;
		}
		print("\n");
	}
	fun sizeMaxSumSubarray(arr: Array < Int > , n: Int): Unit
	{
		// Resultant index
		var s: Int = 0;
		var e: Int = 0;
		// Auxiliary variables
		var temp: Int = 0;
		var result: Int = Int.MIN_VALUE;
		var sum: Int = 0;
		var i: Int = 0;
		while (i < n)
		{
			// Current sum
			sum += arr[i];
			if (result < sum)
			{
				// When sum is greater than result.
				// Get resultant intex.
				s = temp;
				e = i;
				// Change sum
				result = sum;
			}
			if (sum < 0)
			{
				temp = i + 1;
				// Reset sum
				sum = 0;
			}
			i += 1;
		}
		result = (e - s + 1);
		this.printArray(arr, n);
		print(" Result : " + result + " \n");
	}
}
fun main(args: Array < String > ): Unit
{
	val task: SubArray = SubArray();
	// Given array elements
	val arr1: Array < Int > = arrayOf(1, 2, -5, 1, 2, -3, 3, -2, 8, -4);
	val arr2: Array < Int > = arrayOf(-5, 1, 2, -10, 3, 1, 2, 8, -2);
	// Test A
	// Get the number of elements
	var n: Int = arr1.count();
	// [1 , 2 , -3 , 3 , -2 , 8]
	// Result : 6
	task.sizeMaxSumSubarray(arr1, n);
	// Test B
	// Get the number of elements
	n = arr2.count();
	// [3, 1, 2, 8]
	// Result 4
	task.sizeMaxSumSubarray(arr2, n);
}

Output

 1 2 -5 1 2 -3 3 -2 8 -4
 Result : 6
 -5 1 2 -10 3 1 2 8 -2
 Result : 4
Last updated on by Kalkicode




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