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Find the previous fibonacci number

Here given code implementation process.

// C program
// Find the previous  fibonacci number
#include <stdio.h>
#include <math.h>

//Find the previous  fibonacci of given number
void previous_fib(int number)
{
    if(number <= 0)
    {
        return;
    }

    int result = 0;

    // Formula
    // (number / (1 + sqrt(5)) / 2)
    // Assuming that, given number is valid fibonacci number
    result = round(number / ((1 + sqrt(5)) / 2)); 
    

    // Display the calculated result 
    printf("\n [%d] is previous fibonacci are : %d ",number,result);

}
int main()
{
    //Test case
    previous_fib(21);
    previous_fib(13);
    previous_fib(55);
    previous_fib(3);
    previous_fib(1);
    previous_fib(233);
    return 0;
}

Output

 [21] is previous fibonacci are : 13
 [13] is previous fibonacci are : 8
 [55] is previous fibonacci are : 34
 [3] is previous fibonacci are : 2
 [1] is previous fibonacci are : 1
 [233] is previous fibonacci are : 144
// Java program 
// Find the previous fibonacci number
class FibonacciNo
{
    
    //Find the previous fibonacci of given number
    public void previous_fib(int number)
    {
        if (number <= 0)
        {
            return;
        }
        long result = 0;
        // Formula
        // (number / (1 + sqrt(5)) / 2)
        // Assuming that, given number is valid fibonacci number
        result = Math.round(number / ((1 + Math.sqrt(5)) / 2));
        // Display the calculated result 
        System.out.print("\n [" + number + "] is previous fibonacci are : " + result );
    }


    public static void main(String[] args)
    {
        FibonacciNo obj = new FibonacciNo();
        //Test case
        obj.previous_fib(21);
        obj.previous_fib(13);
        obj.previous_fib(55);
        obj.previous_fib(3);
        obj.previous_fib(1);
        obj.previous_fib(233);
    }
}

Output

 [21] is previous fibonacci are : 13
 [13] is previous fibonacci are : 8
 [55] is previous fibonacci are : 34
 [3] is previous fibonacci are : 2
 [1] is previous fibonacci are : 1
 [233] is previous fibonacci are : 144
//Include header file
#include <iostream>

#include<math.h>

using namespace std;
// C++ program 
// Find the previous fibonacci number
class FibonacciNo
{
	public:
		//Find the previous fibonacci of given number
		void previous_fib(int number)
		{
			if (number <= 0)
			{
				return;
			}
			long result = 0;
			// Formula
			// (number / (1 + sqrt(5)) / 2)
			// Assuming that, given number is valid fibonacci number
			result = round(number / ((1 + sqrt(5)) / 2));
			// Display the calculated result 
			cout << "\n [" << number << "] is previous fibonacci are : " << result;
		}
};
int main()
{
	FibonacciNo obj = FibonacciNo();
	//Test case
	obj.previous_fib(21);
	obj.previous_fib(13);
	obj.previous_fib(55);
	obj.previous_fib(3);
	obj.previous_fib(1);
	obj.previous_fib(233);
	return 0;
}

Output

 [21] is previous fibonacci are : 13
 [13] is previous fibonacci are : 8
 [55] is previous fibonacci are : 34
 [3] is previous fibonacci are : 2
 [1] is previous fibonacci are : 1
 [233] is previous fibonacci are : 144
//Include namespace system
using System;
// C# program 
// Find the previous fibonacci number
class FibonacciNo
{
	//Find the previous fibonacci of given number
	public void previous_fib(int number)
	{
		if (number <= 0)
		{
			return;
		}
		long result = 0;
		// Formula
		// (number / (1 + sqrt(5)) / 2)
		// Assuming that, given number is valid fibonacci number
		result = (long)Math.Round(number / ((1 + Math.Sqrt(5)) / 2));
		// Display the calculated result 
		Console.Write("\n [" + number + "] is previous fibonacci are : " + result);
	}
	public static void Main(String[] args)
	{
		FibonacciNo obj = new FibonacciNo();
		//Test case
		obj.previous_fib(21);
		obj.previous_fib(13);
		obj.previous_fib(55);
		obj.previous_fib(3);
		obj.previous_fib(1);
		obj.previous_fib(233);
	}
}

Output

 [21] is previous fibonacci are : 13
 [13] is previous fibonacci are : 8
 [55] is previous fibonacci are : 34
 [3] is previous fibonacci are : 2
 [1] is previous fibonacci are : 1
 [233] is previous fibonacci are : 144
<?php
// Php program 
// Find the previous fibonacci number

class FibonacciNo
{
	//Find the previous fibonacci of given number
	public	function previous_fib($number)
	{
		if ($number <= 0)
		{
			return;
		}
		$result = 0;
		// Formula
		// (number / (1 + sqrt(5)) / 2)
		// Assuming that, given number is valid fibonacci number
		$result = round($number / ((1 + sqrt(5)) / 2));
		// Display the calculated result 
		echo "\n [". $number ."] is previous fibonacci are : ". $result;
	}
}

function main()
{
	$obj = new FibonacciNo();
	//Test case
	$obj->previous_fib(21);
	$obj->previous_fib(13);
	$obj->previous_fib(55);
	$obj->previous_fib(3);
	$obj->previous_fib(1);
	$obj->previous_fib(233);
}
main();

Output

 [21] is previous fibonacci are : 13
 [13] is previous fibonacci are : 8
 [55] is previous fibonacci are : 34
 [3] is previous fibonacci are : 2
 [1] is previous fibonacci are : 1
 [233] is previous fibonacci are : 144
// Node Js program 
// Find the previous fibonacci number
class FibonacciNo
{
	//Find the previous fibonacci of given number
	previous_fib(number)
	{
		if (number <= 0)
		{
			return;
		}
		var result = 0;
		// Formula
		// (number / (1 + sqrt(5)) / 2)
		// Assuming that, given number is valid fibonacci number
		result = Math.round(number / ((1 + Math.sqrt(5)) / 2));
		// Display the calculated result 
		process.stdout.write("\n [" + number + "] is previous fibonacci are : " + result);
	}
}

function main()
{
	var obj = new FibonacciNo();
	//Test case
	obj.previous_fib(21);
	obj.previous_fib(13);
	obj.previous_fib(55);
	obj.previous_fib(3);
	obj.previous_fib(1);
	obj.previous_fib(233);
}
main();

Output

 [21] is previous fibonacci are : 13
 [13] is previous fibonacci are : 8
 [55] is previous fibonacci are : 34
 [3] is previous fibonacci are : 2
 [1] is previous fibonacci are : 1
 [233] is previous fibonacci are : 144
import math
#  Python 3 program 
#  Find the previous fibonacci number
class FibonacciNo :
	# Find the previous fibonacci of given number
	def previous_fib(self, number) :
		if (number <= 0) :
			return
		
		result = 0
		#  Formula
		#  (number / (1 + sqrt(5)) / 2)
		#  Assuming that, given number is valid fibonacci number
		result = round(number / ((1 + math.sqrt(5)) / 2))
		#  Display the calculated result 
		print("\n [", number ,"] is previous fibonacci are : ", result, end = "")
	

def main() :
	obj = FibonacciNo()
	# Test case
	obj.previous_fib(21)
	obj.previous_fib(13)
	obj.previous_fib(55)
	obj.previous_fib(3)
	obj.previous_fib(1)
	obj.previous_fib(233)

if __name__ == "__main__": main()

Output

 [ 21 ] is previous fibonacci are :  13
 [ 13 ] is previous fibonacci are :  8
 [ 55 ] is previous fibonacci are :  34
 [ 3 ] is previous fibonacci are :  2
 [ 1 ] is previous fibonacci are :  1
 [ 233 ] is previous fibonacci are :  144
#  Ruby program 
#  Find the previous fibonacci number
class FibonacciNo 
	# Find the previous fibonacci of given number
	def previous_fib(number) 
		if (number <= 0) 
			return
		end

		result = 0
		#  Formula
		#  (number / (1 + sqrt(5)) / 2)
		#  Assuming that, given number is valid fibonacci number
		result = (number / ((1 + Math.sqrt(5)) / 2)).round()
		#  Display the calculated result 
		print("\n [", number ,"] is previous fibonacci are : ", result)
	end

end

def main() 
	obj = FibonacciNo.new()
	# Test case
	obj.previous_fib(21)
	obj.previous_fib(13)
	obj.previous_fib(55)
	obj.previous_fib(3)
	obj.previous_fib(1)
	obj.previous_fib(233)
end

main()

Output

 [21] is previous fibonacci are : 13
 [13] is previous fibonacci are : 8
 [55] is previous fibonacci are : 34
 [3] is previous fibonacci are : 2
 [1] is previous fibonacci are : 1
 [233] is previous fibonacci are : 144
// Scala program 
// Find the previous fibonacci number
class FibonacciNo
{
	//Find the previous fibonacci of given number
	def previous_fib(number: Int): Unit = {
		if (number <= 0)
		{
			return;
		}
		var result: Long = 0;
		// Formula
		// (number / (1 + sqrt(5)) / 2)
		// Assuming that, given number is valid fibonacci number
		result = Math.round((number / (((1 + Math.sqrt(5)) / 2))));
		// Display the calculated result 
		print("\n [" + number + "] is previous fibonacci are : " + result);
	}
}
object Main
{
	def main(args: Array[String]): Unit = {
		var obj: FibonacciNo = new FibonacciNo();
		//Test case
		obj.previous_fib(21);
		obj.previous_fib(13);
		obj.previous_fib(55);
		obj.previous_fib(3);
		obj.previous_fib(1);
		obj.previous_fib(233);
	}
}

Output

 [21] is previous fibonacci are : 13
 [13] is previous fibonacci are : 8
 [55] is previous fibonacci are : 34
 [3] is previous fibonacci are : 2
 [1] is previous fibonacci are : 1
 [233] is previous fibonacci are : 144
Last updated on by Kalkicode




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