# Find the previous fibonacci number

Here given code implementation process.

``````// C program
// Find the previous  fibonacci number
#include <stdio.h>
#include <math.h>

//Find the previous  fibonacci of given number
void previous_fib(int number)
{
if(number <= 0)
{
return;
}

int result = 0;

// Formula
// (number / (1 + sqrt(5)) / 2)
// Assuming that, given number is valid fibonacci number
result = round(number / ((1 + sqrt(5)) / 2));

// Display the calculated result
printf("\n [%d] is previous fibonacci are : %d ",number,result);

}
int main()
{
//Test case
previous_fib(21);
previous_fib(13);
previous_fib(55);
previous_fib(3);
previous_fib(1);
previous_fib(233);
return 0;
}``````

#### Output

`````` [21] is previous fibonacci are : 13
[13] is previous fibonacci are : 8
[55] is previous fibonacci are : 34
[3] is previous fibonacci are : 2
[1] is previous fibonacci are : 1
[233] is previous fibonacci are : 144``````
``````// Java program
// Find the previous fibonacci number
class FibonacciNo
{

//Find the previous fibonacci of given number
public void previous_fib(int number)
{
if (number <= 0)
{
return;
}
long result = 0;
// Formula
// (number / (1 + sqrt(5)) / 2)
// Assuming that, given number is valid fibonacci number
result = Math.round(number / ((1 + Math.sqrt(5)) / 2));
// Display the calculated result
System.out.print("\n [" + number + "] is previous fibonacci are : " + result );
}

public static void main(String[] args)
{
FibonacciNo obj = new FibonacciNo();
//Test case
obj.previous_fib(21);
obj.previous_fib(13);
obj.previous_fib(55);
obj.previous_fib(3);
obj.previous_fib(1);
obj.previous_fib(233);
}
}``````

#### Output

`````` [21] is previous fibonacci are : 13
[13] is previous fibonacci are : 8
[55] is previous fibonacci are : 34
[3] is previous fibonacci are : 2
[1] is previous fibonacci are : 1
[233] is previous fibonacci are : 144``````
``````//Include header file
#include <iostream>

#include<math.h>

using namespace std;
// C++ program
// Find the previous fibonacci number
class FibonacciNo
{
public:
//Find the previous fibonacci of given number
void previous_fib(int number)
{
if (number <= 0)
{
return;
}
long result = 0;
// Formula
// (number / (1 + sqrt(5)) / 2)
// Assuming that, given number is valid fibonacci number
result = round(number / ((1 + sqrt(5)) / 2));
// Display the calculated result
cout << "\n [" << number << "] is previous fibonacci are : " << result;
}
};
int main()
{
FibonacciNo obj = FibonacciNo();
//Test case
obj.previous_fib(21);
obj.previous_fib(13);
obj.previous_fib(55);
obj.previous_fib(3);
obj.previous_fib(1);
obj.previous_fib(233);
return 0;
}``````

#### Output

`````` [21] is previous fibonacci are : 13
[13] is previous fibonacci are : 8
[55] is previous fibonacci are : 34
[3] is previous fibonacci are : 2
[1] is previous fibonacci are : 1
[233] is previous fibonacci are : 144``````
``````//Include namespace system
using System;
// C# program
// Find the previous fibonacci number
class FibonacciNo
{
//Find the previous fibonacci of given number
public void previous_fib(int number)
{
if (number <= 0)
{
return;
}
long result = 0;
// Formula
// (number / (1 + sqrt(5)) / 2)
// Assuming that, given number is valid fibonacci number
result = (long)Math.Round(number / ((1 + Math.Sqrt(5)) / 2));
// Display the calculated result
Console.Write("\n [" + number + "] is previous fibonacci are : " + result);
}
public static void Main(String[] args)
{
FibonacciNo obj = new FibonacciNo();
//Test case
obj.previous_fib(21);
obj.previous_fib(13);
obj.previous_fib(55);
obj.previous_fib(3);
obj.previous_fib(1);
obj.previous_fib(233);
}
}``````

#### Output

`````` [21] is previous fibonacci are : 13
[13] is previous fibonacci are : 8
[55] is previous fibonacci are : 34
[3] is previous fibonacci are : 2
[1] is previous fibonacci are : 1
[233] is previous fibonacci are : 144``````
``````<?php
// Php program
// Find the previous fibonacci number

class FibonacciNo
{
//Find the previous fibonacci of given number
public	function previous_fib(\$number)
{
if (\$number <= 0)
{
return;
}
\$result = 0;
// Formula
// (number / (1 + sqrt(5)) / 2)
// Assuming that, given number is valid fibonacci number
\$result = round(\$number / ((1 + sqrt(5)) / 2));
// Display the calculated result
echo "\n [". \$number ."] is previous fibonacci are : ". \$result;
}
}

function main()
{
\$obj = new FibonacciNo();
//Test case
\$obj->previous_fib(21);
\$obj->previous_fib(13);
\$obj->previous_fib(55);
\$obj->previous_fib(3);
\$obj->previous_fib(1);
\$obj->previous_fib(233);
}
main();``````

#### Output

`````` [21] is previous fibonacci are : 13
[13] is previous fibonacci are : 8
[55] is previous fibonacci are : 34
[3] is previous fibonacci are : 2
[1] is previous fibonacci are : 1
[233] is previous fibonacci are : 144``````
``````// Node Js program
// Find the previous fibonacci number
class FibonacciNo
{
//Find the previous fibonacci of given number
previous_fib(number)
{
if (number <= 0)
{
return;
}
var result = 0;
// Formula
// (number / (1 + sqrt(5)) / 2)
// Assuming that, given number is valid fibonacci number
result = Math.round(number / ((1 + Math.sqrt(5)) / 2));
// Display the calculated result
process.stdout.write("\n [" + number + "] is previous fibonacci are : " + result);
}
}

function main()
{
var obj = new FibonacciNo();
//Test case
obj.previous_fib(21);
obj.previous_fib(13);
obj.previous_fib(55);
obj.previous_fib(3);
obj.previous_fib(1);
obj.previous_fib(233);
}
main();``````

#### Output

`````` [21] is previous fibonacci are : 13
[13] is previous fibonacci are : 8
[55] is previous fibonacci are : 34
[3] is previous fibonacci are : 2
[1] is previous fibonacci are : 1
[233] is previous fibonacci are : 144``````
``````import math
#  Python 3 program
#  Find the previous fibonacci number
class FibonacciNo :
# Find the previous fibonacci of given number
def previous_fib(self, number) :
if (number <= 0) :
return

result = 0
#  Formula
#  (number / (1 + sqrt(5)) / 2)
#  Assuming that, given number is valid fibonacci number
result = round(number / ((1 + math.sqrt(5)) / 2))
#  Display the calculated result
print("\n [", number ,"] is previous fibonacci are : ", result, end = "")

def main() :
obj = FibonacciNo()
# Test case
obj.previous_fib(21)
obj.previous_fib(13)
obj.previous_fib(55)
obj.previous_fib(3)
obj.previous_fib(1)
obj.previous_fib(233)

if __name__ == "__main__": main()``````

#### Output

`````` [ 21 ] is previous fibonacci are :  13
[ 13 ] is previous fibonacci are :  8
[ 55 ] is previous fibonacci are :  34
[ 3 ] is previous fibonacci are :  2
[ 1 ] is previous fibonacci are :  1
[ 233 ] is previous fibonacci are :  144``````
``````#  Ruby program
#  Find the previous fibonacci number
class FibonacciNo
# Find the previous fibonacci of given number
def previous_fib(number)
if (number <= 0)
return
end

result = 0
#  Formula
#  (number / (1 + sqrt(5)) / 2)
#  Assuming that, given number is valid fibonacci number
result = (number / ((1 + Math.sqrt(5)) / 2)).round()
#  Display the calculated result
print("\n [", number ,"] is previous fibonacci are : ", result)
end

end

def main()
obj = FibonacciNo.new()
# Test case
obj.previous_fib(21)
obj.previous_fib(13)
obj.previous_fib(55)
obj.previous_fib(3)
obj.previous_fib(1)
obj.previous_fib(233)
end

main()``````

#### Output

`````` [21] is previous fibonacci are : 13
[13] is previous fibonacci are : 8
[55] is previous fibonacci are : 34
[3] is previous fibonacci are : 2
[1] is previous fibonacci are : 1
[233] is previous fibonacci are : 144``````
``````// Scala program
// Find the previous fibonacci number
class FibonacciNo
{
//Find the previous fibonacci of given number
def previous_fib(number: Int): Unit = {
if (number <= 0)
{
return;
}
var result: Long = 0;
// Formula
// (number / (1 + sqrt(5)) / 2)
// Assuming that, given number is valid fibonacci number
result = Math.round((number / (((1 + Math.sqrt(5)) / 2))));
// Display the calculated result
print("\n [" + number + "] is previous fibonacci are : " + result);
}
}
object Main
{
def main(args: Array[String]): Unit = {
var obj: FibonacciNo = new FibonacciNo();
//Test case
obj.previous_fib(21);
obj.previous_fib(13);
obj.previous_fib(55);
obj.previous_fib(3);
obj.previous_fib(1);
obj.previous_fib(233);
}
}``````

#### Output

`````` [21] is previous fibonacci are : 13
[13] is previous fibonacci are : 8
[55] is previous fibonacci are : 34
[3] is previous fibonacci are : 2
[1] is previous fibonacci are : 1
[233] is previous fibonacci are : 144``````

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