Find the numbers occurring odd number of times

Here given code implementation process.

// C program 
// Find the numbers occurring odd number of times 
#include <iostream>
#include <map>
using namespace std;

void oddOccurrences(int num[], int n)
{
    // Create a map
    map < int, int > mp;
    int result = 0;

    // Execute loop through by size
    for (int i = 0; i < n; ++i)
    {
        // Counting occurrences of array elements
        mp[num[i]]++;
    }
    cout << "\n Odd occurring element : " << endl;

    // iterating map elements
    for (auto it: mp)
    {
        if (it.second % 2 != 0)
        {
            cout << "  " << it.first;
            result++;
        }
    }
    if (result == 0)
    {
        cout << " None " << endl;
    }
}
int main(int argc, char
    const *argv[])
{
    int num[] = {
        1 , 8 , 2 , 8 , 6 , 2 , 11 , 1 , 11 , 2 , 1 , 3
    };
    int n = sizeof(num) / sizeof(num[0]);
    oddOccurrences(num, n);
    return 0;
}

Output

 Odd occurring element :
  1  2  3  6
/*
  Java program
  Find the numbers occurring odd number of times 
*/
import java.util.HashMap;
import java.util.Map;
public class Occurrence
{

    // Find all elements in given array which is occurs 
    // odd number of times
    public void oddOccurrences(int[] num, int n)
    {
       
        // Create a empty map
        Map < Integer, Integer > map = new HashMap <Integer,Integer> ();
        // Execute loop through by array size
        for (int i = 0; i < n; i++)
        {
            if (map.containsKey(num[i]))
            {
                // When key exists then update value
                map.put(num[i], map.get(num[i]) + 1);
            }
            else
            {
                map.put(num[i], 1);
            }
        }
        System.out.print(" Odd occurring element : \n");
        // iterating map elements
        for (int key: map.keySet())
        {
            if( (map.get(key) % 2) != 0)
            {
                System.out.print("  "+key );
            }
            
        }
    }
    public static void main(String[] args)
    {
        Occurrence task = new Occurrence();

        // Define array of integer elements
        int []num = 
        {
            1 , 8 , 2 , 8 , 6 , 2 , 11 , 1 , 11 , 2 , 1 , 3
        };
        // Get number of elements
        int n = num.length;

        task.oddOccurrences(num, n);
    }
}

Output

 Odd occurring element :
  1  2  3  6
// Include namespace system
using System;
using System.Collections.Generic;
public class Occurrence
{
	// Find all elements in given array which is occurs
	// odd number of times
	public void oddOccurrences(int[] num, int n)
	{
		// Create a empty map
		Dictionary < int, int > dict = new Dictionary < int, int > ();
		// Execute loop through by array size
		for (int i = 0; i < n; i++)
		{
			if (dict.ContainsKey(num[i]))
			{
				dict[num[i]] = dict[num[i]] + 1;
			}
			else
			{
				dict.Add(num[i], 1);
			}
		}
		Console.Write(" Odd occurring element : \n");
		foreach(KeyValuePair < int, int > entry in dict)
		{
			if ((dict[entry.Key] % 2) != 0)
			{
				Console.Write("  " + entry.Key);
			}
		}
	}
	public static void Main(String[] args)
	{
		Occurrence task = new Occurrence();
		// Define array of integer elements
		int[] num = {
			1 , 8 , 2 , 8 , 6 , 2 , 11 , 1 , 11 , 2 , 1 , 3
		};
		// Get number of elements
		int n = num.Length;
		task.oddOccurrences(num, n);
	}
}

Output

 Odd occurring element :
  1  2  6  3
<?php
/*
  Php program
  Find the numbers occurring odd number of times 
*/
class Occurrence
{
	// Find all elements in given array which is occurs
	// odd number of times
	public	function oddOccurrences($num, $n)
	{
		// Create a empty array
		$map = array();
		// Execute loop through by array size
		for ($i = 0; $i < $n; $i++)
		{
			if (array_key_exists($num[$i], $map))
			{
				$map[$num[$i]] = $map[$num[$i]] + 1;
			}
			else
			{
				$map[$num[$i]] = 1;
			}
		}
		echo " Odd occurring element : \n";
		foreach($map as $key => $value)
		{
			if (($value % 2) != 0)
			{
				echo "  ". $key;
			}
		}
	}
}

function main()
{
	$task = new Occurrence();
	// Define array of integer elements
	$num = array(1, 8, 2, 8, 6, 2, 11, 1, 11, 2, 1, 3);
	// Get number of elements
	$n = count($num);
	$task->oddOccurrences($num, $n);
}
main();

Output

 Odd occurring element :
  1  2  6  3
/*
  Node Js program
  Find the numbers occurring odd number of times 
*/
class Occurrence
{
	// Find all elements in given array which is occurs
	// odd number of times
	oddOccurrences(num, n)
	{
		// Create a empty map
		var map = new Map();
		// Execute loop through by array size
		for (var i = 0; i < n; i++)
		{
			if (map.has(num[i]))
			{
				map.set(num[i], map.get(num[i]) + 1);
			}
			else
			{
				map.set(num[i], 1);
			}
		}
		process.stdout.write(" Odd occurring element : \n");
		for (let [key, value] of map)
		{
			if ((value % 2) != 0)
			{
				process.stdout.write("  " + key);
			}
		}
	}
}

function main()
{
	var task = new Occurrence();
	// Define array of integer elements
	var num = [1, 8, 2, 8, 6, 2, 11, 1, 11, 2, 1, 3];
	// Get number of elements
	var n = num.length;
	task.oddOccurrences(num, n);
}
main();

Output

 Odd occurring element :
  1  2  6  3
#   Python 3 program
#   Find the numbers occurring odd number of times 

class Occurrence :
	#  Find all elements in given list which is occurs
	#  odd number of times
	def oddOccurrences(self, num, n) :
		#  Create a empty dict
		map = dict()
		#  Execute loop through by list size
		i = 0
		while (i < n) :
			if (num[i] in map.keys()) :
				map[num[i]] = map.get(num[i]) + 1
			else :
				map[num[i]] = 1
			
			i += 1
		
		print(" Odd occurring element : ")
		for key, value in map.items() :
			if ((value % 2) != 0) :
				print("  ", key, end = "")
			
		
	

def main() :
	task = Occurrence()
	#  Define list of integer elements
	num = [1, 8, 2, 8, 6, 2, 11, 1, 11, 2, 1, 3]
	#  Get number of elements
	n = len(num)
	task.oddOccurrences(num, n)

if __name__ == "__main__": main()

Output

 Odd occurring element :
   1   2   3   6
#   Ruby program
#   Find the numbers occurring odd number of times 

class Occurrence 
	#  Find all elements in given array which is occurs
	#  odd number of times
	def oddOccurrences(num, n) 
		#  Create a empty hash
		map = Hash.new 
		#  Execute loop through by array size
		i = 0
		while (i < n) 
			if (map.key?(num[i])) 
				map[num[i]] = map[num[i]] + 1
			else 
				map[num[i]] = 1
			end

			i += 1
		end

		print(" Odd occurring element : \n")
		map.each { | key, value | 
			if ((map[key] % 2) != 0) 
				print("  ", key)
			end

		}
	end

end

def main() 
	task = Occurrence.new()
	#  Define array of integer elements
	num = [1, 8, 2, 8, 6, 2, 11, 1, 11, 2, 1, 3]
	#  Get number of elements
	n = num.length
	task.oddOccurrences(num, n)
end

main()

Output

 Odd occurring element : 
  1  2  6  3
import scala.collection.mutable._;
/*
  Scala program
  Find the numbers occurring odd number of times 
*/
class Occurrence
{
	// Find all elements in given array which is occurs
	// odd number of times
	def oddOccurrences(num: Array[Int], n: Int): Unit = {
		// Create a empty map
		var map: Map[Int, Int] = Map();
		// Execute loop through by array size
		var i: Int = 0;
		while (i < n)
		{
			if (map.contains(num(i)))
			{
				map(num(i)) = map.get(num(i)).get + 1;
			}
			else
			{
				map += (num(i) -> 1);
			}
			i += 1;
		}
		print(" Odd occurring element : \n");
		map.keys.foreach
		{	key  => 
			if ((map.get(key).get % 2) != 0)
			{
				print("  " + key);
			}
		}
	}
}
object Main
{
	def main(args: Array[String]): Unit = {
		var task: Occurrence = new Occurrence();
		// Define array of integer elements
		var num: Array[Int] = Array(1, 8, 2, 8, 6, 2, 11, 1, 11, 2, 1, 3);
		// Get number of elements
		var n: Int = num.length;
		task.oddOccurrences(num, n);
	}
}

Output

 Odd occurring element :
  1  2  3  6
/*
  Swift 4 program
  Find the numbers occurring odd number of times 
*/
class Occurrence
{
	// Find all elements in given array which is occurs
	// odd number of times
	func oddOccurrences(_ num: [Int], _ n: Int)
	{
		// Create a empty dict
		var map = [Int: Int]();
		
		var i: Int = 0;
      	// Execute loop through by array size
		while (i < n)
		{
			if (map.keys.contains(num[i]))
			{
				map[num[i]] = map[num[i]]! + 1;
			}
			else
			{
				map[num[i]] = 1;
			}
			i += 1;
		}
		print(" Odd occurring element : ");
		for (key, value) in map
		{
			if ((value % 2)  != 0)
			{
				print("  ", key, terminator: "");
			}
		}
	}
}
func main()
{
	let task: Occurrence = Occurrence();
	// Define array of integer elements
	let num: [Int] = [1, 8, 2, 8, 6, 2, 11, 1, 11, 2, 1, 3];
	// Get number of elements
	let n: Int = num.count;
	task.oddOccurrences(num, n);
}
main();

Output

 Odd occurring element :
   6   2   3   1
/*
  Kotlin program
  Find the numbers occurring odd number of times 
*/
class Occurrence
{
	// Find all elements in given array which is occurs
	// odd number of times
	fun oddOccurrences(num: Array < Int > , n: Int): Unit
	{
		// Create a empty map

		var map = mutableMapOf<Int, Int>();
		var i: Int = 0;
		// Execute loop through by array size
		while (i < n)
		{
			if (map.containsKey(num[i]))
			{
				map.put(num[i], map.getValue(num[i]) + 1);
			}
			else
			{
				map.put(num[i], 1);
			}
			i += 1;
		}
		print(" Odd occurring element : \n");
		// iterating map elements
		for (key in map.keys)
		{
			if ((map.getValue(key) % 2) != 0)
			{
				print("  " + key);
			}
		}
	}
}
fun main(args: Array <String> ): Unit
{
	var task: Occurrence = Occurrence();
	// Define array of integer elements
	var num: Array <Int> = arrayOf(1, 8, 2, 8, 6, 2, 11, 1, 11, 2, 1, 3);
	// Get number of elements
	var n: Int = num.count();
	task.oddOccurrences(num, n);
}

Output

 Odd occurring element :
  1  2  6  3


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