Find min and max element in a binary tree

Here given code implementation process.
// C program for
// Find min and max element in a binary tree
#include <stdio.h>
#include <stdlib.h>
// Tree Node
struct TreeNode
{
int data;
struct TreeNode *left;
struct TreeNode *right;
};
// Binary Tree
struct BinaryTree
{
struct TreeNode *root;
};
// Create new tree
struct BinaryTree *newTree()
{
// Create dynamic node
struct BinaryTree *tree =
(struct BinaryTree *) malloc(sizeof(struct BinaryTree));
if (tree != NULL)
{
tree->root = NULL;
}
else
{
printf("Memory Overflow to Create tree Tree\n");
}
//return new tree
return tree;
}
// This is creates and returns the new binary tree node
struct TreeNode *newNode(int data)
{
// Create dynamic node
struct TreeNode *new_node =
(struct TreeNode *) malloc(sizeof(struct TreeNode));
if (new_node != NULL)
{
//Set data and pointer values
new_node->data = data;
new_node->left = NULL;
new_node->right = NULL;
}
else
{
//This is indicates, segmentation fault or memory overflow problem
printf("Memory Overflow\n");
}
//return new node
return new_node;
}
// Find the value of min and max node recursively
void findNode(struct TreeNode *node,
struct TreeNode **min,
struct TreeNode **max)
{
if (node == NULL)
{
return;
}
if (( *min)->data > node->data)
{
// Change
*min = node;
}
if (( *max)->data < node->data)
{
*max = node;
}
// Visit left and right subtree
findNode(node->left, min, max);
findNode(node->right, min, max);
}
void minAndMax(struct TreeNode *root)
{
if (root == NULL)
{
return;
}
// Assign first root of tree
struct TreeNode *min = root;
struct TreeNode *max = root;
// Find node value
findNode(root, & min, & max);
// Display min and max node value
printf(" Minimum : %d", min->data);
printf("\n Maximum : %d\n", max->data);
// Note that in case only one node then both
// printing the value of root node
}
int main(int argc, char
const *argv[])
{
struct BinaryTree *tree = newTree();
/*
4
/ \
-4 7
/ \ \
2 3 12
/ / \ /
1 10 8 15
/ / \
3 9 13
-----------------
Binary tree
*/
tree->root = newNode(4);
tree->root->left = newNode(-4);
tree->root->left->right = newNode(3);
tree->root->left->right->left = newNode(10);
tree->root->left->right->left->left = newNode(9);
tree->root->left->right->right = newNode(8);
tree->root->left->left = newNode(2);
tree->root->left->left->left = newNode(1);
tree->root->left->left->left->left = newNode(3);
tree->root->right = newNode(7);
tree->root->right->right = newNode(12);
tree->root->right->right->left = newNode(15);
tree->root->right->right->left->right = newNode(13);
minAndMax(tree->root);
return 0;
}
Output
Minimum : -4
Maximum : 15
/*
Java program for
Find min and max element in a binary tree
*/
// Binary Tree node
class TreeNode
{
public int data;
public TreeNode left;
public TreeNode right;
public TreeNode(int data)
{
// Set node value
this.data = data;
this.left = null;
this.right = null;
}
}
public class BinaryTree
{
public TreeNode root;
public int min;
public int max;
public BinaryTree()
{
// Set initial tree root to null
this.root = null;
this.min = 0;
this.max = 0;
}
// Find the value of min and max node recursively
public void findNode(TreeNode node)
{
if (node == null)
{
return;
}
if (this.min > node.data)
{
// Change
this.min = node.data;
}
if (this.max < node.data)
{
max = node.data;
}
// Visit left and right subtree
this.findNode(node.left);
this.findNode(node.right);
}
public void minAndMax()
{
if (this.root == null)
{
return;
}
// Assign root value to min max
this.min = this.root.data;
this.max = this.root.data;
// Find node value
this.findNode(this.root);
// Display min and max node value
System.out.print(" Minimum : " + this.min);
System.out.print("\n Maximum : " + this.max + "\n");
}
public static void main(String[] args)
{
BinaryTree tree = new BinaryTree();
/*
4
/ \
-4 7
/ \ \
2 3 12
/ / \ /
1 10 8 15
/ / \
3 9 13
-----------------
Binary tree
*/
tree.root = new TreeNode(4);
tree.root.left = new TreeNode(-4);
tree.root.left.right = new TreeNode(3);
tree.root.left.right.left = new TreeNode(10);
tree.root.left.right.left.left = new TreeNode(9);
tree.root.left.right.right = new TreeNode(8);
tree.root.left.left = new TreeNode(2);
tree.root.left.left.left = new TreeNode(1);
tree.root.left.left.left.left = new TreeNode(3);
tree.root.right = new TreeNode(7);
tree.root.right.right = new TreeNode(12);
tree.root.right.right.left = new TreeNode(15);
tree.root.right.right.left.right = new TreeNode(13);
tree.minAndMax();
}
}
Output
Minimum : -4
Maximum : 15
// Include header file
#include <iostream>
using namespace std;
/*
C++ program for
Find min and max element in a binary tree
*/
// Binary Tree node
class TreeNode
{
public:
int data;
TreeNode *left;
TreeNode *right;
TreeNode(int data)
{
// Set node value
this->data = data;
this->left = NULL;
this->right = NULL;
}
};
class BinaryTree
{
public:
TreeNode *root;
int min;
int max;
BinaryTree()
{
this->root = NULL;
this->min = 0;
this->max = 0;
}
// Find the value of min and max node recursively
void findNode(TreeNode *node)
{
if (node == NULL)
{
return;
}
if (this->min > node->data)
{
// Change
this->min = node->data;
}
if (this->max < node->data)
{
this->max = node->data;
}
// Visit left and right subtree
this->findNode(node->left);
this->findNode(node->right);
}
void minAndMax()
{
if (this->root == NULL)
{
return;
}
// Assign root value to min max
this->min = this->root->data;
this->max = this->root->data;
// Find node value
this->findNode(this->root);
// Display min and max node value
cout << " Minimum : " << this->min;
cout << "\n Maximum : " << this->max << "\n";
}
};
int main()
{
BinaryTree *tree = new BinaryTree();
/*
4
/ \
-4 7
/ \ \
2 3 12
/ / \ /
1 10 8 15
/ / \
3 9 13
-----------------
Binary tree
*/
tree->root = new TreeNode(4);
tree->root->left = new TreeNode(-4);
tree->root->left->right = new TreeNode(3);
tree->root->left->right->left = new TreeNode(10);
tree->root->left->right->left->left = new TreeNode(9);
tree->root->left->right->right = new TreeNode(8);
tree->root->left->left = new TreeNode(2);
tree->root->left->left->left = new TreeNode(1);
tree->root->left->left->left->left = new TreeNode(3);
tree->root->right = new TreeNode(7);
tree->root->right->right = new TreeNode(12);
tree->root->right->right->left = new TreeNode(15);
tree->root->right->right->left->right = new TreeNode(13);
tree->minAndMax();
return 0;
}
Output
Minimum : -4
Maximum : 15
// Include namespace system
using System;
/*
Csharp program for
Find min and max element in a binary tree
*/
// Binary Tree node
public class TreeNode
{
public int data;
public TreeNode left;
public TreeNode right;
public TreeNode(int data)
{
// Set node value
this.data = data;
this.left = null;
this.right = null;
}
}
public class BinaryTree
{
public TreeNode root;
public int min;
public int max;
public BinaryTree()
{
// Set initial tree root to null
this.root = null;
this.min = 0;
this.max = 0;
}
// Find the value of min and max node recursively
public void findNode(TreeNode node)
{
if (node == null)
{
return;
}
if (this.min > node.data)
{
// Change
this.min = node.data;
}
if (this.max < node.data)
{
this.max = node.data;
}
// Visit left and right subtree
this.findNode(node.left);
this.findNode(node.right);
}
public void minAndMax()
{
if (this.root == null)
{
return;
}
// Assign root value to min max
this.min = this.root.data;
this.max = this.root.data;
// Find node value
this.findNode(this.root);
// Display min and max node value
Console.Write(" Minimum : " + this.min);
Console.Write("\n Maximum : " + this.max + "\n");
}
public static void Main(String[] args)
{
BinaryTree tree = new BinaryTree();
/*
4
/ \
-4 7
/ \ \
2 3 12
/ / \ /
1 10 8 15
/ / \
3 9 13
-----------------
Binary tree
*/
tree.root = new TreeNode(4);
tree.root.left = new TreeNode(-4);
tree.root.left.right = new TreeNode(3);
tree.root.left.right.left = new TreeNode(10);
tree.root.left.right.left.left = new TreeNode(9);
tree.root.left.right.right = new TreeNode(8);
tree.root.left.left = new TreeNode(2);
tree.root.left.left.left = new TreeNode(1);
tree.root.left.left.left.left = new TreeNode(3);
tree.root.right = new TreeNode(7);
tree.root.right.right = new TreeNode(12);
tree.root.right.right.left = new TreeNode(15);
tree.root.right.right.left.right = new TreeNode(13);
tree.minAndMax();
}
}
Output
Minimum : -4
Maximum : 15
package main
import "fmt"
/*
Go program for
Find min and max element in a binary tree
*/
// Binary Tree node
type TreeNode struct {
data int
left * TreeNode
right * TreeNode
}
func getTreeNode(data int) * TreeNode {
var me *TreeNode = &TreeNode {}
// Set node value
me.data = data
me.left = nil
me.right = nil
return me
}
type BinaryTree struct {
root * TreeNode
min int
max int
}
func getBinaryTree() * BinaryTree {
var me *BinaryTree = &BinaryTree {}
// Set initial tree root to null
me.root = nil
me.min = 0
me.max = 0
return me
}
// Find the value of min and max node recursively
func(this *BinaryTree) findNode(node * TreeNode) {
if node == nil {
return
}
if this.min > node.data {
// Change
this.min = node.data
}
if this.max < node.data {
this.max = node.data
}
// Visit left and right subtree
this.findNode(node.left)
this.findNode(node.right)
}
func(this BinaryTree) minAndMax() {
if this.root == nil {
return
}
// Assign root value to min max
this.min = this.root.data
this.max = this.root.data
// Find node value
this.findNode(this.root)
// Display min and max node value
fmt.Print(" Minimum : ", this.min)
fmt.Print("\n Maximum : ", this.max, "\n")
}
func main() {
var tree * BinaryTree = getBinaryTree()
/*
4
/ \
-4 7
/ \ \
2 3 12
/ / \ /
1 10 8 15
/ / \
3 9 13
-----------------
Binary tree
*/
tree.root = getTreeNode(4)
tree.root.left = getTreeNode(-4)
tree.root.left.right = getTreeNode(3)
tree.root.left.right.left = getTreeNode(10)
tree.root.left.right.left.left = getTreeNode(9)
tree.root.left.right.right = getTreeNode(8)
tree.root.left.left = getTreeNode(2)
tree.root.left.left.left = getTreeNode(1)
tree.root.left.left.left.left = getTreeNode(3)
tree.root.right = getTreeNode(7)
tree.root.right.right = getTreeNode(12)
tree.root.right.right.left = getTreeNode(15)
tree.root.right.right.left.right = getTreeNode(13)
tree.minAndMax()
}
Output
Minimum : -4
Maximum : 15
<?php
/*
Php program for
Find min and max element in a binary tree
*/
// Binary Tree node
class TreeNode
{
public $data;
public $left;
public $right;
public function __construct($data)
{
// Set node value
$this->data = $data;
$this->left = NULL;
$this->right = NULL;
}
}
class BinaryTree
{
public $root;
public $min;
public $max;
public function __construct()
{
$this->root = NULL;
$this->min = 0;
$this->max = 0;
}
// Find the value of min and max node recursively
public function findNode($node)
{
if ($node == NULL)
{
return;
}
if ($this->min > $node->data)
{
// Change
$this->min = $node->data;
}
if ($this->max < $node->data)
{
$this->max = $node->data;
}
// Visit left and right subtree
$this->findNode($node->left);
$this->findNode($node->right);
}
public function minAndMax()
{
if ($this->root == NULL)
{
return;
}
// Assign root value to min max
$this->min = $this->root->data;
$this->max = $this->root->data;
// Find node value
$this->findNode($this->root);
// Display min and max node value
echo(" Minimum : ".$this->min);
echo("\n Maximum : ".$this->max."\n");
}
}
function main()
{
$tree = new BinaryTree();
/*
4
/ \
-4 7
/ \ \
2 3 12
/ / \ /
1 10 8 15
/ / \
3 9 13
-----------------
Binary tree
*/
$tree->root = new TreeNode(4);
$tree->root->left = new TreeNode(-4);
$tree->root->left->right = new TreeNode(3);
$tree->root->left->right->left = new TreeNode(10);
$tree->root->left->right->left->left = new TreeNode(9);
$tree->root->left->right->right = new TreeNode(8);
$tree->root->left->left = new TreeNode(2);
$tree->root->left->left->left = new TreeNode(1);
$tree->root->left->left->left->left = new TreeNode(3);
$tree->root->right = new TreeNode(7);
$tree->root->right->right = new TreeNode(12);
$tree->root->right->right->left = new TreeNode(15);
$tree->root->right->right->left->right = new TreeNode(13);
$tree->minAndMax();
}
main();
Output
Minimum : -4
Maximum : 15
/*
Node JS program for
Find min and max element in a binary tree
*/
// Binary Tree node
class TreeNode
{
constructor(data)
{
// Set node value
this.data = data;
this.left = null;
this.right = null;
}
}
class BinaryTree
{
constructor()
{
this.root = null;
this.min = 0;
this.max = 0;
}
// Find the value of min and max node recursively
findNode(node)
{
if (node == null)
{
return;
}
if (this.min > node.data)
{
// Change
this.min = node.data;
}
if (this.max < node.data)
{
this.max = node.data;
}
// Visit left and right subtree
this.findNode(node.left);
this.findNode(node.right);
}
minAndMax()
{
if (this.root == null)
{
return;
}
// Assign root value to min max
this.min = this.root.data;
this.max = this.root.data;
// Find node value
this.findNode(this.root);
// Display min and max node value
process.stdout.write(" Minimum : " + this.min);
process.stdout.write("\n Maximum : " + this.max + "\n");
}
}
function main()
{
var tree = new BinaryTree();
/*
4
/ \
-4 7
/ \ \
2 3 12
/ / \ /
1 10 8 15
/ / \
3 9 13
-----------------
Binary tree
*/
tree.root = new TreeNode(4);
tree.root.left = new TreeNode(-4);
tree.root.left.right = new TreeNode(3);
tree.root.left.right.left = new TreeNode(10);
tree.root.left.right.left.left = new TreeNode(9);
tree.root.left.right.right = new TreeNode(8);
tree.root.left.left = new TreeNode(2);
tree.root.left.left.left = new TreeNode(1);
tree.root.left.left.left.left = new TreeNode(3);
tree.root.right = new TreeNode(7);
tree.root.right.right = new TreeNode(12);
tree.root.right.right.left = new TreeNode(15);
tree.root.right.right.left.right = new TreeNode(13);
tree.minAndMax();
}
main();
Output
Minimum : -4
Maximum : 15
# Python 3 program for
# Find min and max element in a binary tree
# Binary Tree node
class TreeNode :
def __init__(self, data) :
# Set node value
self.data = data
self.left = None
self.right = None
class BinaryTree :
def __init__(self) :
self.root = None
self.min = 0
self.max = 0
# Find the value of min and max node recursively
def findNode(self, node) :
if (node == None) :
return
if (self.min > node.data) :
# Change
self.min = node.data
if (self.max < node.data) :
self.max = node.data
# Visit left and right subtree
self.findNode(node.left)
self.findNode(node.right)
def minAndMax(self) :
if (self.root == None) :
return
# Assign root value to min max
self.min = self.root.data
self.max = self.root.data
# Find node value
self.findNode(self.root)
# Display min and max node value
print(" Minimum : ", self.min, end = "")
print("\n Maximum : ", self.max )
def main() :
tree = BinaryTree()
# 4
# / \
# -4 7
# / \ \
# 2 3 12
# / / \ /
# 1 10 8 15
# / / \
# 3 9 13
# -----------------
# Binary tree
tree.root = TreeNode(4)
tree.root.left = TreeNode(-4)
tree.root.left.right = TreeNode(3)
tree.root.left.right.left = TreeNode(10)
tree.root.left.right.left.left = TreeNode(9)
tree.root.left.right.right = TreeNode(8)
tree.root.left.left = TreeNode(2)
tree.root.left.left.left = TreeNode(1)
tree.root.left.left.left.left = TreeNode(3)
tree.root.right = TreeNode(7)
tree.root.right.right = TreeNode(12)
tree.root.right.right.left = TreeNode(15)
tree.root.right.right.left.right = TreeNode(13)
tree.minAndMax()
if __name__ == "__main__": main()
Output
Minimum : -4
Maximum : 15
# Ruby program for
# Find min and max element in a binary tree
# Binary Tree node
class TreeNode
# Define the accessor and reader of class TreeNode
attr_reader :data, :left, :right
attr_accessor :data, :left, :right
def initialize(data)
# Set node value
self.data = data
self.left = nil
self.right = nil
end
end
class BinaryTree
# Define the accessor and reader of class BinaryTree
attr_reader :root, :min, :max
attr_accessor :root, :min, :max
def initialize()
self.root = nil
self.min = 0
self.max = 0
end
# Find the value of min and max node recursively
def findNode(node)
if (node == nil)
return
end
if (self.min > node.data)
# Change
self.min = node.data
end
if (self.max < node.data)
self.max = node.data
end
# Visit left and right subtree
self.findNode(node.left)
self.findNode(node.right)
end
def minAndMax()
if (self.root == nil)
return
end
# Assign root value to min max
self.min = self.root.data
self.max = self.root.data
# Find node value
self.findNode(self.root)
# Display min and max node value
print(" Minimum : ", self.min)
print("\n Maximum : ", self.max ,"\n")
end
end
def main()
tree = BinaryTree.new()
# 4
# / \
# -4 7
# / \ \
# 2 3 12
# / / \ /
# 1 10 8 15
# / / \
# 3 9 13
# -----------------
# Binary tree
tree.root = TreeNode.new(4)
tree.root.left = TreeNode.new(-4)
tree.root.left.right = TreeNode.new(3)
tree.root.left.right.left = TreeNode.new(10)
tree.root.left.right.left.left = TreeNode.new(9)
tree.root.left.right.right = TreeNode.new(8)
tree.root.left.left = TreeNode.new(2)
tree.root.left.left.left = TreeNode.new(1)
tree.root.left.left.left.left = TreeNode.new(3)
tree.root.right = TreeNode.new(7)
tree.root.right.right = TreeNode.new(12)
tree.root.right.right.left = TreeNode.new(15)
tree.root.right.right.left.right = TreeNode.new(13)
tree.minAndMax()
end
main()
Output
Minimum : -4
Maximum : 15
/*
Scala program for
Find min and max element in a binary tree
*/
// Binary Tree node
class TreeNode(var data: Int,
var left: TreeNode,
var right: TreeNode)
{
def this(data: Int)
{
// Set node value
this(data,null,null);
}
}
class BinaryTree(var root: TreeNode,
var min: Int,
var max: Int)
{
def this()
{
this(null,0,0);
}
// Find the value of min and max node recursively
def findNode(node: TreeNode): Unit = {
if (node == null)
{
return;
}
if (this.min > node.data)
{
// Change
this.min = node.data;
}
if (this.max < node.data)
{
max = node.data;
}
// Visit left and right subtree
this.findNode(node.left);
this.findNode(node.right);
}
def minAndMax(): Unit = {
if (this.root == null)
{
return;
}
// Assign root value to min max
this.min = this.root.data;
this.max = this.root.data;
// Find node value
this.findNode(this.root);
// Display min and max node value
print(" Minimum : " + this.min);
print("\n Maximum : " + this.max + "\n");
}
}
object Main
{
def main(args: Array[String]): Unit = {
var tree: BinaryTree = new BinaryTree();
/*
4
/ \
-4 7
/ \ \
2 3 12
/ / \ /
1 10 8 15
/ / \
3 9 13
-----------------
Binary tree
*/
tree.root = new TreeNode(4);
tree.root.left = new TreeNode(-4);
tree.root.left.right = new TreeNode(3);
tree.root.left.right.left = new TreeNode(10);
tree.root.left.right.left.left = new TreeNode(9);
tree.root.left.right.right = new TreeNode(8);
tree.root.left.left = new TreeNode(2);
tree.root.left.left.left = new TreeNode(1);
tree.root.left.left.left.left = new TreeNode(3);
tree.root.right = new TreeNode(7);
tree.root.right.right = new TreeNode(12);
tree.root.right.right.left = new TreeNode(15);
tree.root.right.right.left.right = new TreeNode(13);
tree.minAndMax();
}
}
Output
Minimum : -4
Maximum : 15
/*
Swift 4 program for
Find min and max element in a binary tree
*/
// Binary Tree node
class TreeNode
{
var data: Int;
var left: TreeNode? ;
var right: TreeNode? ;
init(_ data: Int)
{
// Set node value
self.data = data;
self.left = nil;
self.right = nil;
}
}
class BinaryTree
{
var root: TreeNode? ;
var min: Int;
var max: Int;
init()
{
self.root = nil;
self.min = 0;
self.max = 0;
}
// Find the value of min and max node recursively
func findNode(_ node: TreeNode? )
{
if (node == nil)
{
return;
}
if (self.min > node!.data)
{
// Change
self.min = node!.data;
}
if (self.max < node!.data)
{
self.max = node!.data;
}
// Visit left and right subtree
self.findNode(node!.left);
self.findNode(node!.right);
}
func minAndMax()
{
if (self.root == nil)
{
return;
}
// Assign root value to min max
self.min = self.root!.data;
self.max = self.root!.data;
// Find node value
self.findNode(self.root);
// Display min and max node value
print(" Minimum : ", self.min, terminator: "");
print("\n Maximum : ", self.max );
}
}
func main()
{
let tree: BinaryTree = BinaryTree();
/*
4
/ \
-4 7
/ \ \
2 3 12
/ / \ /
1 10 8 15
/ / \
3 9 13
-----------------
Binary tree
*/
tree.root = TreeNode(4);
tree.root!.left = TreeNode(-4);
tree.root!.left!.right = TreeNode(3);
tree.root!.left!.right!.left = TreeNode(10);
tree.root!.left!.right!.left!.left = TreeNode(9);
tree.root!.left!.right!.right = TreeNode(8);
tree.root!.left!.left = TreeNode(2);
tree.root!.left!.left!.left = TreeNode(1);
tree.root!.left!.left!.left!.left = TreeNode(3);
tree.root!.right = TreeNode(7);
tree.root!.right!.right = TreeNode(12);
tree.root!.right!.right!.left = TreeNode(15);
tree.root!.right!.right!.left!.right = TreeNode(13);
tree.minAndMax();
}
main();
Output
Minimum : -4
Maximum : 15
/*
Kotlin program for
Find min and max element in a binary tree
*/
// Binary Tree node
class TreeNode
{
var data: Int;
var left: TreeNode ? ;
var right: TreeNode ? ;
constructor(data: Int)
{
// Set node value
this.data = data;
this.left = null;
this.right = null;
}
}
class BinaryTree
{
var root: TreeNode ? ;
var min: Int;
var max: Int;
constructor()
{
this.root = null;
this.min = 0;
this.max = 0;
}
// Find the value of min and max node recursively
fun findNode(node: TreeNode?): Unit
{
if (node == null)
{
return;
}
if (this.min > node.data)
{
// Change
this.min = node.data;
}
if (this.max < node.data)
{
this.max = node.data;
}
// Visit left and right subtree
this.findNode(node.left);
this.findNode(node.right);
}
fun minAndMax(): Unit
{
if (this.root == null)
{
return;
}
// Assign root value to min max
this.min = this.root!!.data;
this.max = this.root!!.data;
// Find node value
this.findNode(this.root);
// Display min and max node value
print(" Minimum : " + this.min);
print("\n Maximum : " + this.max + "\n");
}
}
fun main(args: Array < String > ): Unit
{
val tree: BinaryTree = BinaryTree();
/*
4
/ \
-4 7
/ \ \
2 3 12
/ / \ /
1 10 8 15
/ / \
3 9 13
-----------------
Binary tree
*/
tree.root = TreeNode(4);
tree.root?.left = TreeNode(-4);
tree.root?.left?.right = TreeNode(3);
tree.root?.left?.right?.left = TreeNode(10);
tree.root?.left?.right?.left?.left = TreeNode(9);
tree.root?.left?.right?.right = TreeNode(8);
tree.root?.left?.left = TreeNode(2);
tree.root?.left?.left?.left = TreeNode(1);
tree.root?.left?.left?.left?.left = TreeNode(3);
tree.root?.right = TreeNode(7);
tree.root?.right?.right = TreeNode(12);
tree.root?.right?.right?.left = TreeNode(15);
tree.root?.right?.right?.left?.right = TreeNode(13);
tree.minAndMax();
}
Output
Minimum : -4
Maximum : 15
Please share your knowledge to improve code and content standard. Also submit your doubts, and test case. We improve by your feedback. We will try to resolve your query as soon as possible.
New Comment