# Find maximum sum bitonic sub sequence using dynamic programming

Here given code implementation process.

``````// C Program
// Find maximum sum bitonic sub sequence using dynamic programming
#include <stdio.h>
#include <limits.h>

// Function which is display array elements
void display(int arr[], int n)
{
for (int i = 0; i < n; ++i)
{
printf("%d ", arr[i]);
}
}
// Returns a max value of two integers
int maxValue(int a, int b)
{
if (a > b)
{
return a;
}
return b;
}
void maxSumBitonicSequence(int arr[], int n)
{
// This is collects the sum of bitonic subsequence from left to right.
int sumLeftToRight[n];
// This is collects the sum of bitonic subsequence from right to left.
int sumRightToLeft[n];
// Initial value of result is minimum value.
int result = INT_MIN;
// Set initial value of sum
for (int i = 0; i < n; ++i)
{
sumLeftToRight[i] = arr[i];
sumRightToLeft[i] = arr[i];
}
// Calculate right to left maximum bitonic sum.
// Execute until the its value is not -1.
for (int i = n - 2; i >= 0; --i)
{
// until the its value is greater than [i].
for (int j = n - 1; j > i; --j)
{
if (arr[i] > arr[j] &&
(sumRightToLeft[i] < sumRightToLeft[j] + arr[i]))
{
// Update sum value
sumRightToLeft[i] = sumRightToLeft[j] + arr[i];
}
}
}
// Calculate left to right maximum bitonic sum
for (int i = 1; i < n; ++i)
{
for (int j = 0; j < i; ++j)
{
if (arr[i] > arr[j] &&
(sumLeftToRight[i] < sumLeftToRight[j] + arr[i]))
{
// Update sum value
sumLeftToRight[i] = sumLeftToRight[j] + arr[i];
}
}
}
// Calculate maximum bitonic sum using left and right sum.
for (int i = 0; i < n; ++i)
{
result = maxValue(result ,
(sumRightToLeft[i] + sumLeftToRight[i] - arr[i]));
}
printf("\n Given sequence : ");
display(arr, n);
printf("\n Result : %d", result);
}
int main()
{
// Array of integer elements
int arr1[] = {
4 , 1 , 3 , 9 , 3 , -2 , 2 , 8 , 3 , 1 , 1 , 4 , 5
};
int arr2[] = {
45 , 2 , 1 , 14 , 15 , 18 , 20 , 1 , -12 , 2 , 4
};
// Test A
int n = sizeof(arr1) / sizeof(arr1[0]);
// [1 + 3 + 9 + 8 + 5]
// maximum sum bitonic subsequence
// 26
maxSumBitonicSequence(arr1, n);
// Test B
n = sizeof(arr2) / sizeof(arr2[0]);
// [2 + 14 + 15 + 18 + 20 + 4]
// maximum sum bitonic subsequence
// 73
maxSumBitonicSequence(arr2, n);
return 0;
}``````

#### Output

`````` Given sequence : 4 1 3 9 3 -2 2 8 3 1 1 4 5
Result : 26
Given sequence : 45 2 1 14 15 18 20 1 -12 2 4
Result : 73``````
``````/*
Java Program for
Find maximum sum bitonic sub sequence using dynamic programming
*/

public class BitonicSequence
{
// Function which is display array elements
public void display(int[] arr, int n)
{
for (int i = 0; i < n; ++i)
{
System.out.print("  " + arr[i] );
}
}
// Returns a max value of two integers
public int maxValue(int a, int b)
{
if (a > b)
{
return a;
}
return b;
}
public void maxSumBitonicSequence(int[] arr, int n)
{
// This is collects the sum of bitonic subsequence from left to right.
int[] sumLeftToRight = new int[n];
// This is collects the sum of bitonic subsequence from right to left.
int[] sumRightToLeft = new int[n];
// Initial value of result is minimum value.
int result = Integer.MIN_VALUE;
// Set initial value of sum
for (int i = 0; i < n; ++i)
{
sumLeftToRight[i] = arr[i];
sumRightToLeft[i] = arr[i];
}
// Calculate right to left maximum bitonic sum.
// Execute until the its value is not -1.
for (int i = n - 2; i >= 0; --i)
{
// until the its value is greater than [i].
for (int j = n - 1; j > i; --j)
{
if (arr[i] > arr[j] &&
(sumRightToLeft[i] < sumRightToLeft[j] + arr[i]))
{
// Update sum value
sumRightToLeft[i] = sumRightToLeft[j] + arr[i];
}
}
}
// Calculate left to right maximum bitonic sum
for (int i = 1; i < n; ++i)
{
for (int j = 0; j < i; ++j)
{
if (arr[i] > arr[j] &&
(sumLeftToRight[i] < sumLeftToRight[j] + arr[i]))
{
// Update sum value
sumLeftToRight[i] = sumLeftToRight[j] + arr[i];
}
}
}
// Calculate maximum bitonic sum using left and right sum.
for (int i = 0; i < n; ++i)
{
result = maxValue(result,
(sumRightToLeft[i] + sumLeftToRight[i] - arr[i]));
}
System.out.print("\n Given sequence : ");
display(arr, n);
System.out.print("\n Result : " + result + "");
}
public static void main(String[] args)
{
// Array of integer elements
int[] arr1 = {
4 , 1 , 3 , 9 , 3 , -2 , 2 , 8 , 3 , 1 , 1 , 4 , 5
};
int[] arr2 =  {
45 , 2 , 1 , 14 , 15 , 18 , 20 , 1 , -12 , 2 , 4
};
// Test A
int n = arr1.length;
// [1 + 3 + 9 + 8 + 5]
// maximum sum bitonic subsequence
// 26
// Test B
n = arr2.length;
// [2 + 14 + 15 + 18 + 20 + 4]
// maximum sum bitonic subsequence
// 73
}
}``````

#### Output

`````` Given sequence :   4  1  3  9  3  -2  2  8  3  1  1  4  5
Result : 26
Given sequence :   45  2  1  14  15  18  20  1  -12  2  4
Result : 73``````
``````// Include header file
#include <iostream>
#include <limits.h>

using namespace std;
/*
C++ Program for
Find maximum sum bitonic sub sequence using dynamic programming
*/
class BitonicSequence
{
public:
// Function which is display array elements
void display(int arr[], int n)
{
for (int i = 0; i < n; ++i)
{
cout << "  " << arr[i];
}
}
// Returns a max value of two integers
int maxValue(int a, int b)
{
if (a > b)
{
return a;
}
return b;
}
void maxSumBitonicSequence(int arr[], int n)
{
// This is collects the sum of bitonic subsequence from left to right.
int sumLeftToRight[n];
// This is collects the sum of bitonic subsequence from right to left.
int sumRightToLeft[n];
// Initial value of result is minimum value.
int result = INT_MIN;
// Set initial value of sum
for (int i = 0; i < n; ++i)
{
sumLeftToRight[i] = arr[i];
sumRightToLeft[i] = arr[i];
}
// Calculate right to left maximum bitonic sum.
// Execute until the its value is not -1.
for (int i = n - 2; i >= 0; --i)
{
// until the its value is greater than [i].
for (int j = n - 1; j > i; --j)
{
if (arr[i] > arr[j] &&
(sumRightToLeft[i] < sumRightToLeft[j] + arr[i]))
{
// Update sum value
sumRightToLeft[i] = sumRightToLeft[j] + arr[i];
}
}
}
// Calculate left to right maximum bitonic sum
for (int i = 1; i < n; ++i)
{
for (int j = 0; j < i; ++j)
{
if (arr[i] > arr[j] &&
(sumLeftToRight[i] < sumLeftToRight[j] + arr[i]))
{
// Update sum value
sumLeftToRight[i] = sumLeftToRight[j] + arr[i];
}
}
}
// Calculate maximum bitonic sum using left and right sum.
for (int i = 0; i < n; ++i)
{
result = this->maxValue(result,
(sumRightToLeft[i] + sumLeftToRight[i] - arr[i]));
}
cout << "\n Given sequence : ";
this->display(arr, n);
cout << "\n Result : " << result << "";
}
};
int main()
{
// Array of integer elements
int arr1[] = {
4 , 1 , 3 , 9 , 3 , -2 , 2 , 8 , 3 , 1 , 1 , 4 , 5
};
int arr2[] = {
45 , 2 , 1 , 14 , 15 , 18 , 20 , 1 , -12 , 2 , 4
};
// Test A
int n = sizeof(arr1) / sizeof(arr1[0]);
// [1 + 3 + 9 + 8 + 5]
// maximum sum bitonic subsequence
// 26
// Test B
n = sizeof(arr2) / sizeof(arr2[0]);
// [2 + 14 + 15 + 18 + 20 + 4]
// maximum sum bitonic subsequence
// 73
return 0;
}``````

#### Output

`````` Given sequence :   4  1  3  9  3  -2  2  8  3  1  1  4  5
Result : 26
Given sequence :   45  2  1  14  15  18  20  1  -12  2  4
Result : 73``````
``````// Include namespace system
using System;
/*
Csharp Program for
Find maximum sum bitonic sub sequence using dynamic programming
*/
public class BitonicSequence
{
// Function which is display array elements
public void display(int[] arr, int n)
{
for (int i = 0; i < n; ++i)
{
Console.Write("  " + arr[i]);
}
}
// Returns a max value of two integers
public int maxValue(int a, int b)
{
if (a > b)
{
return a;
}
return b;
}
public void maxSumBitonicSequence(int[] arr, int n)
{
// This is collects the sum of bitonic subsequence from left to right.
int[] sumLeftToRight = new int[n];
// This is collects the sum of bitonic subsequence from right to left.
int[] sumRightToLeft = new int[n];
// Initial value of result is minimum value.
int result = int.MinValue;
// Set initial value of sum
for (int i = 0; i < n; ++i)
{
sumLeftToRight[i] = arr[i];
sumRightToLeft[i] = arr[i];
}
// Calculate right to left maximum bitonic sum.
// Execute until the its value is not -1.
for (int i = n - 2; i >= 0; --i)
{
// until the its value is greater than [i].
for (int j = n - 1; j > i; --j)
{
if (arr[i] > arr[j] &&
(sumRightToLeft[i] < sumRightToLeft[j] + arr[i]))
{
// Update sum value
sumRightToLeft[i] = sumRightToLeft[j] + arr[i];
}
}
}
// Calculate left to right maximum bitonic sum
for (int i = 1; i < n; ++i)
{
for (int j = 0; j < i; ++j)
{
if (arr[i] > arr[j] &&
(sumLeftToRight[i] < sumLeftToRight[j] + arr[i]))
{
// Update sum value
sumLeftToRight[i] = sumLeftToRight[j] + arr[i];
}
}
}
// Calculate maximum bitonic sum using left and right sum.
for (int i = 0; i < n; ++i)
{
result = this.maxValue(result,
(sumRightToLeft[i] + sumLeftToRight[i] - arr[i]));
}
Console.Write("\n Given sequence : ");
this.display(arr, n);
Console.Write("\n Result : " + result + "");
}
public static void Main(String[] args)
{
// Array of integer elements
int[] arr1 = {
4 , 1 , 3 , 9 , 3 , -2 , 2 , 8 , 3 , 1 , 1 , 4 , 5
};
int[] arr2 = {
45 , 2 , 1 , 14 , 15 , 18 , 20 , 1 , -12 , 2 , 4
};
// Test A
int n = arr1.Length;
// [1 + 3 + 9 + 8 + 5]
// maximum sum bitonic subsequence
// 26
// Test B
n = arr2.Length;
// [2 + 14 + 15 + 18 + 20 + 4]
// maximum sum bitonic subsequence
// 73
}
}``````

#### Output

`````` Given sequence :   4  1  3  9  3  -2  2  8  3  1  1  4  5
Result : 26
Given sequence :   45  2  1  14  15  18  20  1  -12  2  4
Result : 73``````
``````package main
import "math"
import "fmt"
/*
Go Program for
Find maximum sum bitonic sub sequence using dynamic programming
*/

// Function which is display array elements
func display(arr[] int, n int) {
for i := 0 ; i < n ; i++ {
fmt.Print("  ", arr[i])
}
}
// Returns a max value of two integers
func maxValue(a, b int) int {
if a > b {
return a
}
return b
}
func maxSumBitonicSequence(arr[] int, n int) {
// This is collects the sum of bitonic subsequence from left to right.
var sumLeftToRight = make([] int, n)
// This is collects the sum of bitonic subsequence from right to left.
var sumRightToLeft = make([] int, n)
// Initial value of result is minimum value.
var result int = math.MinInt64
// Set initial value of sum
for i := 0 ; i < n ; i++ {
sumLeftToRight[i] = arr[i]
sumRightToLeft[i] = arr[i]
}
// Calculate right to left maximum bitonic sum.
// Execute until the its value is not -1.
for i := n - 2 ; i >= 0 ; i-- {
// until the its value is greater than [i].
for j := n - 1 ; j > i ; j-- {
if arr[i] > arr[j] && (sumRightToLeft[i] < sumRightToLeft[j] + arr[i]) {
// Update sum value
sumRightToLeft[i] = sumRightToLeft[j] + arr[i]
}
}
}
// Calculate left to right maximum bitonic sum
for i := 1 ; i < n ; i++ {
for j := 0 ; j < i ; j++ {
if arr[i] > arr[j] && (sumLeftToRight[i] < sumLeftToRight[j] + arr[i]) {
// Update sum value
sumLeftToRight[i] = sumLeftToRight[j] + arr[i]
}
}
}
// Calculate maximum bitonic sum using left and right sum.
for i := 0 ; i < n ; i++ {
result = maxValue(result,
(sumRightToLeft[i] + sumLeftToRight[i] - arr[i]))
}
fmt.Print("\n Given sequence : ")
display(arr, n)
fmt.Print("\n Result : ", result, "")
}
func main() {

// Array of integer elements
var arr1 = [] int {4, 1, 3, 9, 3, -2, 2, 8, 3, 1 , 1, 4, 5}
var arr2 = [] int {45, 2, 1, 14, 15, 18 ,  20, 1, -12, 2, 4}
// Test A
var n int = len(arr1)
// [1 + 3 + 9 + 8 + 5]
// maximum sum bitonic subsequence
// 26
maxSumBitonicSequence(arr1, n)
// Test B
n = len(arr2)
// [2 + 14 + 15 + 18 + 20 + 4]
// maximum sum bitonic subsequence
// 73
maxSumBitonicSequence(arr2, n)
}``````

#### Output

`````` Given sequence :   4  1  3  9  3  -2  2  8  3  1  1  4  5
Result : 26
Given sequence :   45  2  1  14  15  18  20  1  -12  2  4
Result : 73``````
``````<?php
/*
Php Program for
Find maximum sum bitonic sub sequence using dynamic programming
*/
class BitonicSequence
{
// Function which is display array elements
public	function display(\$arr, \$n)
{
for (\$i = 0; \$i < \$n; ++\$i)
{
echo("  ".\$arr[\$i]);
}
}
// Returns a max value of two integers
public	function maxValue(\$a, \$b)
{
if (\$a > \$b)
{
return \$a;
}
return \$b;
}
public	function maxSumBitonicSequence(\$arr, \$n)
{
// This is collects the sum of bitonic subsequence from left to right.
\$sumLeftToRight = array_fill(0, \$n, 0);
// This is collects the sum of bitonic subsequence from right to left.
\$sumRightToLeft = array_fill(0, \$n, 0);
// Initial value of result is minimum value.
\$result = -PHP_INT_MAX;
// Set initial value of sum
for (\$i = 0; \$i < \$n; ++\$i)
{
\$sumLeftToRight[\$i] = \$arr[\$i];
\$sumRightToLeft[\$i] = \$arr[\$i];
}
// Calculate right to left maximum bitonic sum.
// Execute until the its value is not -1.
for (\$i = \$n - 2; \$i >= 0; --\$i)
{
// until the its value is greater than [i].
for (\$j = \$n - 1; \$j > \$i; --\$j)
{
if (\$arr[\$i] > \$arr[\$j] && (\$sumRightToLeft[\$i] < \$sumRightToLeft[\$j] + \$arr[\$i]))
{
// Update sum value
\$sumRightToLeft[\$i] = \$sumRightToLeft[\$j] + \$arr[\$i];
}
}
}
// Calculate left to right maximum bitonic sum
for (\$i = 1; \$i < \$n; ++\$i)
{
for (\$j = 0; \$j < \$i; ++\$j)
{
if (\$arr[\$i] > \$arr[\$j] && (\$sumLeftToRight[\$i] < \$sumLeftToRight[\$j] + \$arr[\$i]))
{
// Update sum value
\$sumLeftToRight[\$i] = \$sumLeftToRight[\$j] + \$arr[\$i];
}
}
}
// Calculate maximum bitonic sum using left and right sum.
for (\$i = 0; \$i < \$n; ++\$i)
{
\$result = \$this->maxValue(\$result, (\$sumRightToLeft[\$i] + \$sumLeftToRight[\$i] - \$arr[\$i]));
}
echo("\n Given sequence : ");
\$this->display(\$arr, \$n);
echo("\n Result : ".\$result.
"");
}
}

function main()
{
// Array of integer elements
\$arr1 = array(4, 1, 3, 9, 3, -2, 2, 8, 3, 1, 1, 4, 5);
\$arr2 = array(45, 2, 1, 14, 15, 18, 20, 1, -12, 2, 4);
// Test A
\$n = count(\$arr1);
// [1 + 3 + 9 + 8 + 5]
// maximum sum bitonic subsequence
// 26
// Test B
\$n = count(\$arr2);
// [2 + 14 + 15 + 18 + 20 + 4]
// maximum sum bitonic subsequence
// 73
}
main();``````

#### Output

`````` Given sequence :   4  1  3  9  3  -2  2  8  3  1  1  4  5
Result : 26
Given sequence :   45  2  1  14  15  18  20  1  -12  2  4
Result : 73``````
``````/*
Node JS Program for
Find maximum sum bitonic sub sequence using dynamic programming
*/
class BitonicSequence
{
// Function which is display array elements
display(arr, n)
{
for (var i = 0; i < n; ++i)
{
process.stdout.write("  " + arr[i]);
}
}
// Returns a max value of two integers
maxValue(a, b)
{
if (a > b)
{
return a;
}
return b;
}
maxSumBitonicSequence(arr, n)
{
// This is collects the sum of bitonic subsequence from left to right.
var sumLeftToRight = Array(n).fill(0);
// This is collects the sum of bitonic subsequence from right to left.
var sumRightToLeft = Array(n).fill(0);
// Initial value of result is minimum value.
var result = -Number.MAX_VALUE;
// Set initial value of sum
for (var i = 0; i < n; ++i)
{
sumLeftToRight[i] = arr[i];
sumRightToLeft[i] = arr[i];
}
// Calculate right to left maximum bitonic sum.
// Execute until the its value is not -1.
for (var i = n - 2; i >= 0; --i)
{
// until the its value is greater than [i].
for (var j = n - 1; j > i; --j)
{
if (arr[i] > arr[j] &&
(sumRightToLeft[i] < sumRightToLeft[j] + arr[i]))
{
// Update sum value
sumRightToLeft[i] = sumRightToLeft[j] + arr[i];
}
}
}
// Calculate left to right maximum bitonic sum
for (var i = 1; i < n; ++i)
{
for (var j = 0; j < i; ++j)
{
if (arr[i] > arr[j] &&
(sumLeftToRight[i] < sumLeftToRight[j] + arr[i]))
{
// Update sum value
sumLeftToRight[i] = sumLeftToRight[j] + arr[i];
}
}
}
// Calculate maximum bitonic sum using left and right sum.
for (var i = 0; i < n; ++i)
{
result = this.maxValue(result,
(sumRightToLeft[i] + sumLeftToRight[i] - arr[i]));
}
process.stdout.write("\n Given sequence : ");
this.display(arr, n);
process.stdout.write("\n Result : " + result + "");
}
}

function main()
{
// Array of integer elements
var arr1 = [4, 1, 3, 9, 3, -2, 2, 8, 3, 1, 1, 4, 5];
var arr2 = [45, 2, 1, 14, 15, 18, 20, 1, -12, 2, 4];
// Test A
var n = arr1.length;
// [1 + 3 + 9 + 8 + 5]
// maximum sum bitonic subsequence
// 26
// Test B
n = arr2.length;
// [2 + 14 + 15 + 18 + 20 + 4]
// maximum sum bitonic subsequence
// 73
}
main();``````

#### Output

`````` Given sequence :   4  1  3  9  3  -2  2  8  3  1  1  4  5
Result : 26
Given sequence :   45  2  1  14  15  18  20  1  -12  2  4
Result : 73``````
``````import sys
#    Python 3 Program for
#    Find maximum sum bitonic sub sequence using dynamic programming
class BitonicSequence :
#  Function which is display list elements
def display(self, arr, n) :
i = 0
while (i < n) :
print(" ", arr[i], end = "")
i += 1

#  Returns a max value of two integers
def maxValue(self, a, b) :
if (a > b) :
return a

return b

def maxSumBitonicSequence(self, arr, n) :
#  This is collects the sum of bitonic subsequence from left to right.
sumLeftToRight = [0] * (n)
#  This is collects the sum of bitonic subsequence from right to left.
sumRightToLeft = [0] * (n)
#  Initial value of result is minimum value.
result = -sys.maxsize
i = 0
#  Set initial value of sum
while (i < n) :
sumLeftToRight[i] = arr[i]
sumRightToLeft[i] = arr[i]
i += 1

i = n - 2
#  Calculate right to left maximum bitonic sum.
#  Execute until the its value is not -1.
while (i >= 0) :
j = n - 1
#  until the its value is greater than [i].
while (j > i) :
if (arr[i] > arr[j] and(sumRightToLeft[i] < sumRightToLeft[j] + arr[i])) :
#  Update sum value
sumRightToLeft[i] = sumRightToLeft[j] + arr[i]

j -= 1

i -= 1

i = 1
#  Calculate left to right maximum bitonic sum
while (i < n) :
j = 0
while (j < i) :
if (arr[i] > arr[j] and(sumLeftToRight[i] < sumLeftToRight[j] + arr[i])) :
#  Update sum value
sumLeftToRight[i] = sumLeftToRight[j] + arr[i]

j += 1

i += 1

i = 0
#  Calculate maximum bitonic sum using left and right sum.
while (i < n) :
result = self.maxValue(result, (sumRightToLeft[i] + sumLeftToRight[i] - arr[i]))
i += 1

print("\n Given sequence : ", end = "")
self.display(arr, n)
print("\n Result : ", result ,"", end = "")

def main() :
#  Array of integer elements
arr1 = [4, 1, 3, 9, 3, -2, 2, 8, 3, 1, 1, 4, 5]
arr2 = [45, 2, 1, 14, 15, 18, 20, 1, -12, 2, 4]
#  Test A
n = len(arr1)
#  [1 + 3 + 9 + 8 + 5]
#  maximum sum bitonic subsequence
#  26
#  Test B
n = len(arr2)
#  [2 + 14 + 15 + 18 + 20 + 4]
#  maximum sum bitonic subsequence
#  73

if __name__ == "__main__": main()``````

#### Output

`````` Given sequence :   4  1  3  9  3  -2  2  8  3  1  1  4  5
Result :  26
Given sequence :   45  2  1  14  15  18  20  1  -12  2  4
Result :  73``````
``````#    Ruby Program for
#    Find maximum sum bitonic sub sequence using dynamic programming
class BitonicSequence
#  Function which is display array elements
def display(arr, n)
i = 0
while (i < n)
print("  ", arr[i])
i += 1
end

end

#  Returns a max value of two integers
def maxValue(a, b)
if (a > b)
return a
end

return b
end

def maxSumBitonicSequence(arr, n)
#  This is collects the sum of bitonic subsequence from left to right.
sumLeftToRight = Array.new(n) {0}
#  This is collects the sum of bitonic subsequence from right to left.
sumRightToLeft = Array.new(n) {0}
#  Initial value of result is minimum value.
result = -(2 ** (0. size * 8 - 2))
i = 0
#  Set initial value of sum
while (i < n)
sumLeftToRight[i] = arr[i]
sumRightToLeft[i] = arr[i]
i += 1
end

i = n - 2
#  Calculate right to left maximum bitonic sum.
#  Execute until the its value is not -1.
while (i >= 0)
j = n - 1
#  until the its value is greater than [i].
while (j > i)
if (arr[i] > arr[j] &&
(sumRightToLeft[i] < sumRightToLeft[j] + arr[i]))
#  Update sum value
sumRightToLeft[i] = sumRightToLeft[j] + arr[i]
end

j -= 1
end

i -= 1
end

i = 1
#  Calculate left to right maximum bitonic sum
while (i < n)
j = 0
while (j < i)
if (arr[i] > arr[j] &&
(sumLeftToRight[i] < sumLeftToRight[j] + arr[i]))
#  Update sum value
sumLeftToRight[i] = sumLeftToRight[j] + arr[i]
end

j += 1
end

i += 1
end

i = 0
#  Calculate maximum bitonic sum using left and right sum.
while (i < n)
result = self.maxValue(result,
(sumRightToLeft[i] + sumLeftToRight[i] - arr[i]))
i += 1
end

print("\n Given sequence : ")
self.display(arr, n)
print("\n Result : ", result ,"")
end

end

def main()
#  Array of integer elements
arr1 = [4, 1, 3, 9, 3, -2, 2, 8, 3, 1, 1, 4, 5]
arr2 = [45, 2, 1, 14, 15, 18, 20, 1, -12, 2, 4]
#  Test A
n = arr1.length
#  [1 + 3 + 9 + 8 + 5]
#  maximum sum bitonic subsequence
#  26
#  Test B
n = arr2.length
#  [2 + 14 + 15 + 18 + 20 + 4]
#  maximum sum bitonic subsequence
#  73
end

main()``````

#### Output

`````` Given sequence :   4  1  3  9  3  -2  2  8  3  1  1  4  5
Result : 26
Given sequence :   45  2  1  14  15  18  20  1  -12  2  4
Result : 73``````
``````/*
Scala Program for
Find maximum sum bitonic sub sequence using dynamic programming
*/
class BitonicSequence()
{
// Function which is display array elements
def display(arr: Array[Int], n: Int): Unit = {
var i: Int = 0;
while (i < n)
{
print("  " + arr(i));
i += 1;
}
}
// Returns a max value of two integers
def maxValue(a: Int, b: Int): Int = {
if (a > b)
{
return a;
}
return b;
}
def maxSumBitonicSequence(arr: Array[Int], n: Int): Unit = {
// This is collects the sum of bitonic subsequence from left to right.
var sumLeftToRight: Array[Int] = Array.fill[Int](n)(0);
// This is collects the sum of bitonic subsequence from right to left.
var sumRightToLeft: Array[Int] = Array.fill[Int](n)(0);
// Initial value of result is minimum value.
var result: Int = Int.MinValue;
var i: Int = 0;
// Set initial value of sum
while (i < n)
{
sumLeftToRight(i) = arr(i);
sumRightToLeft(i) = arr(i);
i += 1;
}
i = n - 2;
// Calculate right to left maximum bitonic sum.
// Execute until the its value is not -1.
while (i >= 0)
{
var j: Int = n - 1;
// until the its value is greater than [i].
while (j > i)
{
if (arr(i) > arr(j) &&
(sumRightToLeft(i) < sumRightToLeft(j) + arr(i)))
{
// Update sum value
sumRightToLeft(i) = sumRightToLeft(j) + arr(i);
}
j -= 1;
}
i -= 1;
}
i = 1;
// Calculate left to right maximum bitonic sum
while (i < n)
{
var j: Int = 0;
while (j < i)
{
if (arr(i) > arr(j) &&
(sumLeftToRight(i) < sumLeftToRight(j) + arr(i)))
{
// Update sum value
sumLeftToRight(i) = sumLeftToRight(j) + arr(i);
}
j += 1;
}
i += 1;
}
i = 0;
// Calculate maximum bitonic sum using left and right sum.
while (i < n)
{
result = maxValue(result,
(sumRightToLeft(i) + sumLeftToRight(i) - arr(i)));
i += 1;
}
print("\n Given sequence : ");
display(arr, n);
print("\n Result : " + result + "");
}
}
object Main
{
def main(args: Array[String]): Unit = {
var task: BitonicSequence = new BitonicSequence();
// Array of integer elements
var arr1: Array[Int] = Array(4, 1, 3, 9, 3, -2, 2, 8, 3, 1, 1, 4, 5);
var arr2: Array[Int] = Array(45, 2, 1, 14, 15, 18, 20, 1, -12, 2, 4);
// Test A
var n: Int = arr1.length;
// [1 + 3 + 9 + 8 + 5]
// maximum sum bitonic subsequence
// 26
// Test B
n = arr2.length;
// [2 + 14 + 15 + 18 + 20 + 4]
// maximum sum bitonic subsequence
// 73
}
}``````

#### Output

`````` Given sequence :   4  1  3  9  3  -2  2  8  3  1  1  4  5
Result : 26
Given sequence :   45  2  1  14  15  18  20  1  -12  2  4
Result : 73``````
``````import Foundation;
/*
Swift 4 Program for
Find maximum sum bitonic sub sequence using dynamic programming
*/
class BitonicSequence
{
// Function which is display array elements
func display(_ arr: [Int], _ n: Int)
{
var i: Int = 0;
while (i < n)
{
print(" ", arr[i], terminator: "");
i += 1;
}
}
// Returns a max value of two integers
func maxValue(_ a: Int, _ b: Int) -> Int
{
if (a > b)
{
return a;
}
return b;
}
func maxSumBitonicSequence(_ arr: [Int], _ n: Int)
{
// This is collects the sum of bitonic subsequence from left to right.
var sumLeftToRight: [Int] = Array(repeating: 0, count: n);
// This is collects the sum of bitonic subsequence from right to left.
var sumRightToLeft: [Int] = Array(repeating: 0, count: n);
// Initial value of result is minimum value.
var result: Int = Int.min;
var i: Int = 0;
// Set initial value of sum
while (i < n)
{
sumLeftToRight[i] = arr[i];
sumRightToLeft[i] = arr[i];
i += 1;
}
i = n - 2;
// Calculate right to left maximum bitonic sum.
// Execute until the its value is not -1.
while (i >= 0)
{
var j: Int = n - 1;
// until the its value is greater than [i].
while (j > i)
{
if (arr[i] > arr[j] &&
(sumRightToLeft[i] < sumRightToLeft[j] + arr[i]))
{
// Update sum value
sumRightToLeft[i] = sumRightToLeft[j] + arr[i];
}
j -= 1;
}
i -= 1;
}
i = 1;
// Calculate left to right maximum bitonic sum
while (i < n)
{
var j: Int = 0;
while (j < i)
{
if (arr[i] > arr[j] &&
(sumLeftToRight[i] < sumLeftToRight[j] + arr[i]))
{
// Update sum value
sumLeftToRight[i] = sumLeftToRight[j] + arr[i];
}
j += 1;
}
i += 1;
}
i = 0;
// Calculate maximum bitonic sum using left and right sum.
while (i < n)
{
result = self.maxValue(result,
(sumRightToLeft[i] + sumLeftToRight[i] - arr[i]));
i += 1;
}
print("\n Given sequence : ", terminator: "");
self.display(arr, n);
print("\n Result : ", result ,"", terminator: "");
}
}
func main()
{
// Array of integer elements
let arr1: [Int] = [4, 1, 3, 9, 3, -2, 2, 8, 3, 1, 1, 4, 5];
let arr2: [Int] = [45, 2, 1, 14, 15, 18, 20, 1, -12, 2, 4];
// Test A
var n: Int = arr1.count;
// [1 + 3 + 9 + 8 + 5]
// maximum sum bitonic subsequence
// 26
// Test B
n = arr2.count;
// [2 + 14 + 15 + 18 + 20 + 4]
// maximum sum bitonic subsequence
// 73
}
main();``````

#### Output

`````` Given sequence :   4  1  3  9  3  -2  2  8  3  1  1  4  5
Result :  26
Given sequence :   45  2  1  14  15  18  20  1  -12  2  4
Result :  73``````
``````/*
Kotlin Program for
Find maximum sum bitonic sub sequence using dynamic programming
*/
class BitonicSequence
{
// Function which is display array elements
fun display(arr: Array < Int > , n: Int): Unit
{
var i: Int = 0;
while (i < n)
{
print("  " + arr[i]);
i += 1;
}
}
// Returns a max value of two integers
fun maxValue(a: Int, b: Int): Int
{
if (a > b)
{
return a;
}
return b;
}
fun maxSumBitonicSequence(arr: Array < Int > , n: Int): Unit
{
// This is collects the sum of bitonic subsequence from left to right.
var sumLeftToRight: Array < Int > = Array(n)
{
0
};
// This is collects the sum of bitonic subsequence from right to left.
var sumRightToLeft: Array < Int > = Array(n)
{
0
};
// Initial value of result is minimum value.
var result: Int = Int.MIN_VALUE;
var i: Int = 0;
// Set initial value of sum
while (i < n)
{
sumLeftToRight[i] = arr[i];
sumRightToLeft[i] = arr[i];
i += 1;
}
i = n - 2;
// Calculate right to left maximum bitonic sum.
// Execute until the its value is not -1.
while (i >= 0)
{
var j: Int = n - 1;
// until the its value is greater than [i].
while (j > i)
{
if (arr[i] > arr[j] &&
(sumRightToLeft[i] < sumRightToLeft[j] + arr[i]))
{
// Update sum value
sumRightToLeft[i] = sumRightToLeft[j] + arr[i];
}
j -= 1;
}
i -= 1;
}
i = 1;
// Calculate left to right maximum bitonic sum
while (i < n)
{
var j: Int = 0;
while (j < i)
{
if (arr[i] > arr[j] &&
(sumLeftToRight[i] < sumLeftToRight[j] + arr[i]))
{
// Update sum value
sumLeftToRight[i] = sumLeftToRight[j] + arr[i];
}
j += 1;
}
i += 1;
}
i = 0;
// Calculate maximum bitonic sum using left and right sum.
while (i < n)
{
result = this.maxValue(result,
(sumRightToLeft[i] + sumLeftToRight[i] - arr[i]));
i += 1;
}
print("\n Given sequence : ");
this.display(arr, n);
print("\n Result : " + result + "");
}
}
fun main(args: Array < String > ): Unit
{
// Array of integer elements
val arr1: Array < Int > = arrayOf(4, 1, 3, 9, 3, -2, 2, 8, 3, 1, 1, 4, 5);
val arr2: Array < Int > = arrayOf(45, 2, 1, 14, 15, 18, 20, 1, -12, 2, 4);
// Test A
var n: Int = arr1.count();
// [1 + 3 + 9 + 8 + 5]
// maximum sum bitonic subsequence
// 26
// Test B
n = arr2.count();
// [2 + 14 + 15 + 18 + 20 + 4]
// maximum sum bitonic subsequence
// 73
}``````

#### Output

`````` Given sequence :   4  1  3  9  3  -2  2  8  3  1  1  4  5
Result : 26
Given sequence :   45  2  1  14  15  18  20  1  -12  2  4
Result : 73``````

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