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Find maximum sum bitonic sub sequence using dynamic programming

Here given code implementation process.

// C Program
// Find maximum sum bitonic sub sequence using dynamic programming
#include <stdio.h>
#include <limits.h>

 // Function which is display array elements
void display(int arr[], int n)
{
	for (int i = 0; i < n; ++i)
	{
		printf("%d ", arr[i]);
	}
}
// Returns a max value of two integers
int maxValue(int a, int b)
{
	if (a > b)
	{
		return a;
	}
	return b;
}
void maxSumBitonicSequence(int arr[], int n)
{
	// This is collects the sum of bitonic subsequence from left to right.
	int sumLeftToRight[n];
	// This is collects the sum of bitonic subsequence from right to left.
	int sumRightToLeft[n];
	// Initial value of result is minimum value.
	int result = INT_MIN;
	// Set initial value of sum
	for (int i = 0; i < n; ++i)
	{
		sumLeftToRight[i] = arr[i];
		sumRightToLeft[i] = arr[i];
	}
	// Calculate right to left maximum bitonic sum.
	// This loop start with second last element and 
	// Execute until the its value is not -1.
	for (int i = n - 2; i >= 0; --i)
	{
		// This loop start with last element and execute 
		// until the its value is greater than [i].
		for (int j = n - 1; j > i; --j)
		{
			if (arr[i] > arr[j] && 
                (sumRightToLeft[i] < sumRightToLeft[j] + arr[i]))
			{
				// Update sum value
				sumRightToLeft[i] = sumRightToLeft[j] + arr[i];
			}
		}
	}
	// Calculate left to right maximum bitonic sum
	for (int i = 1; i < n; ++i)
	{
		for (int j = 0; j < i; ++j)
		{
			if (arr[i] > arr[j] && 
                (sumLeftToRight[i] < sumLeftToRight[j] + arr[i]))
			{
				// Update sum value
				sumLeftToRight[i] = sumLeftToRight[j] + arr[i];
			}
		}
	}
	// Calculate maximum bitonic sum using left and right sum.
	for (int i = 0; i < n; ++i)
	{
		result = maxValue(result , 
                          (sumRightToLeft[i] + sumLeftToRight[i] - arr[i]));
	}
	printf("\n Given sequence : ");
	display(arr, n);
	printf("\n Result : %d", result);
}
int main()
{
	// Array of integer elements
	int arr1[] = {
		4 , 1 , 3 , 9 , 3 , -2 , 2 , 8 , 3 , 1 , 1 , 4 , 5
	};
	int arr2[] = {
		45 , 2 , 1 , 14 , 15 , 18 , 20 , 1 , -12 , 2 , 4
	};
	// Test A
	int n = sizeof(arr1) / sizeof(arr1[0]);
	// [1 + 3 + 9 + 8 + 5] 
	// maximum sum bitonic subsequence 
	// 26
	maxSumBitonicSequence(arr1, n);
	// Test B
	n = sizeof(arr2) / sizeof(arr2[0]);
	// [2 + 14 + 15 + 18 + 20 + 4] 
	// maximum sum bitonic subsequence 
	// 73
	maxSumBitonicSequence(arr2, n);
	return 0;
}

Output

 Given sequence : 4 1 3 9 3 -2 2 8 3 1 1 4 5
 Result : 26
 Given sequence : 45 2 1 14 15 18 20 1 -12 2 4
 Result : 73
/*
    Java Program for
    Find maximum sum bitonic sub sequence using dynamic programming
*/

public class BitonicSequence
{
    // Function which is display array elements
    public void display(int[] arr, int n)
    {
        for (int i = 0; i < n; ++i)
        {
            System.out.print("  " + arr[i] );
        }
    }
    // Returns a max value of two integers
    public int maxValue(int a, int b)
    {
        if (a > b)
        {
            return a;
        }
        return b;
    }
    public void maxSumBitonicSequence(int[] arr, int n)
    {
        // This is collects the sum of bitonic subsequence from left to right.
        int[] sumLeftToRight = new int[n];
        // This is collects the sum of bitonic subsequence from right to left.
        int[] sumRightToLeft = new int[n];
        // Initial value of result is minimum value.
        int result = Integer.MIN_VALUE;
        // Set initial value of sum
        for (int i = 0; i < n; ++i)
        {
            sumLeftToRight[i] = arr[i];
            sumRightToLeft[i] = arr[i];
        }
        // Calculate right to left maximum bitonic sum.
        // This loop start with second last element and 
        // Execute until the its value is not -1.
        for (int i = n - 2; i >= 0; --i)
        {
            // This loop start with last element and execute 
            // until the its value is greater than [i].
            for (int j = n - 1; j > i; --j)
            {
                if (arr[i] > arr[j] && 
                    (sumRightToLeft[i] < sumRightToLeft[j] + arr[i]))
                {
                    // Update sum value
                    sumRightToLeft[i] = sumRightToLeft[j] + arr[i];
                }
            }
        }
        // Calculate left to right maximum bitonic sum
        for (int i = 1; i < n; ++i)
        {
            for (int j = 0; j < i; ++j)
            {
                if (arr[i] > arr[j] && 
                    (sumLeftToRight[i] < sumLeftToRight[j] + arr[i]))
                {
                    // Update sum value
                    sumLeftToRight[i] = sumLeftToRight[j] + arr[i];
                }
            }
        }
        // Calculate maximum bitonic sum using left and right sum.
        for (int i = 0; i < n; ++i)
        {
            result = maxValue(result, 
                              (sumRightToLeft[i] + sumLeftToRight[i] - arr[i]));
        }
        System.out.print("\n Given sequence : ");
        display(arr, n);
        System.out.print("\n Result : " + result + "");
    }
    public static void main(String[] args)
    {
        BitonicSequence task = new BitonicSequence();
        // Array of integer elements
        int[] arr1 = {
            4 , 1 , 3 , 9 , 3 , -2 , 2 , 8 , 3 , 1 , 1 , 4 , 5
        };
        int[] arr2 =  {
            45 , 2 , 1 , 14 , 15 , 18 , 20 , 1 , -12 , 2 , 4
        };
        // Test A
        int n = arr1.length;
        // [1 + 3 + 9 + 8 + 5] 
        // maximum sum bitonic subsequence 
        // 26
        task.maxSumBitonicSequence(arr1, n);
        // Test B
        n = arr2.length;
        // [2 + 14 + 15 + 18 + 20 + 4] 
        // maximum sum bitonic subsequence 
        // 73
        task.maxSumBitonicSequence(arr2, n);
    }
}

Output

 Given sequence :   4  1  3  9  3  -2  2  8  3  1  1  4  5
 Result : 26
 Given sequence :   45  2  1  14  15  18  20  1  -12  2  4
 Result : 73
// Include header file
#include <iostream>
#include <limits.h>

using namespace std;
/*
    C++ Program for
    Find maximum sum bitonic sub sequence using dynamic programming
*/
class BitonicSequence
{
	public:
		// Function which is display array elements
		void display(int arr[], int n)
		{
			for (int i = 0; i < n; ++i)
			{
				cout << "  " << arr[i];
			}
		}
	// Returns a max value of two integers
	int maxValue(int a, int b)
	{
		if (a > b)
		{
			return a;
		}
		return b;
	}
	void maxSumBitonicSequence(int arr[], int n)
	{
		// This is collects the sum of bitonic subsequence from left to right.
		int sumLeftToRight[n];
		// This is collects the sum of bitonic subsequence from right to left.
		int sumRightToLeft[n];
		// Initial value of result is minimum value.
		int result = INT_MIN;
		// Set initial value of sum
		for (int i = 0; i < n; ++i)
		{
			sumLeftToRight[i] = arr[i];
			sumRightToLeft[i] = arr[i];
		}
		// Calculate right to left maximum bitonic sum.
		// This loop start with second last element and 
		// Execute until the its value is not -1.
		for (int i = n - 2; i >= 0; --i)
		{
			// This loop start with last element and execute 
			// until the its value is greater than [i].
			for (int j = n - 1; j > i; --j)
			{
				if (arr[i] > arr[j] && 
                    (sumRightToLeft[i] < sumRightToLeft[j] + arr[i]))
				{
					// Update sum value
					sumRightToLeft[i] = sumRightToLeft[j] + arr[i];
				}
			}
		}
		// Calculate left to right maximum bitonic sum
		for (int i = 1; i < n; ++i)
		{
			for (int j = 0; j < i; ++j)
			{
				if (arr[i] > arr[j] && 
                    (sumLeftToRight[i] < sumLeftToRight[j] + arr[i]))
				{
					// Update sum value
					sumLeftToRight[i] = sumLeftToRight[j] + arr[i];
				}
			}
		}
		// Calculate maximum bitonic sum using left and right sum.
		for (int i = 0; i < n; ++i)
		{
			result = this->maxValue(result, 
                    (sumRightToLeft[i] + sumLeftToRight[i] - arr[i]));
		}
		cout << "\n Given sequence : ";
		this->display(arr, n);
		cout << "\n Result : " << result << "";
	}
};
int main()
{
	BitonicSequence *task = new BitonicSequence();
	// Array of integer elements
	int arr1[] = {
		4 , 1 , 3 , 9 , 3 , -2 , 2 , 8 , 3 , 1 , 1 , 4 , 5
	};
	int arr2[] = {
		45 , 2 , 1 , 14 , 15 , 18 , 20 , 1 , -12 , 2 , 4
	};
	// Test A
	int n = sizeof(arr1) / sizeof(arr1[0]);
	// [1 + 3 + 9 + 8 + 5] 
	// maximum sum bitonic subsequence 
	// 26
	task->maxSumBitonicSequence(arr1, n);
	// Test B
	n = sizeof(arr2) / sizeof(arr2[0]);
	// [2 + 14 + 15 + 18 + 20 + 4] 
	// maximum sum bitonic subsequence 
	// 73
	task->maxSumBitonicSequence(arr2, n);
	return 0;
}

Output

 Given sequence :   4  1  3  9  3  -2  2  8  3  1  1  4  5
 Result : 26
 Given sequence :   45  2  1  14  15  18  20  1  -12  2  4
 Result : 73
// Include namespace system
using System;
/*
    Csharp Program for
    Find maximum sum bitonic sub sequence using dynamic programming
*/
public class BitonicSequence
{
	// Function which is display array elements
	public void display(int[] arr, int n)
	{
		for (int i = 0; i < n; ++i)
		{
			Console.Write("  " + arr[i]);
		}
	}
	// Returns a max value of two integers
	public int maxValue(int a, int b)
	{
		if (a > b)
		{
			return a;
		}
		return b;
	}
	public void maxSumBitonicSequence(int[] arr, int n)
	{
		// This is collects the sum of bitonic subsequence from left to right.
		int[] sumLeftToRight = new int[n];
		// This is collects the sum of bitonic subsequence from right to left.
		int[] sumRightToLeft = new int[n];
		// Initial value of result is minimum value.
		int result = int.MinValue;
		// Set initial value of sum
		for (int i = 0; i < n; ++i)
		{
			sumLeftToRight[i] = arr[i];
			sumRightToLeft[i] = arr[i];
		}
		// Calculate right to left maximum bitonic sum.
		// This loop start with second last element and 
		// Execute until the its value is not -1.
		for (int i = n - 2; i >= 0; --i)
		{
			// This loop start with last element and execute 
			// until the its value is greater than [i].
			for (int j = n - 1; j > i; --j)
			{
				if (arr[i] > arr[j] && 
                    (sumRightToLeft[i] < sumRightToLeft[j] + arr[i]))
				{
					// Update sum value
					sumRightToLeft[i] = sumRightToLeft[j] + arr[i];
				}
			}
		}
		// Calculate left to right maximum bitonic sum
		for (int i = 1; i < n; ++i)
		{
			for (int j = 0; j < i; ++j)
			{
				if (arr[i] > arr[j] && 
                    (sumLeftToRight[i] < sumLeftToRight[j] + arr[i]))
				{
					// Update sum value
					sumLeftToRight[i] = sumLeftToRight[j] + arr[i];
				}
			}
		}
		// Calculate maximum bitonic sum using left and right sum.
		for (int i = 0; i < n; ++i)
		{
			result = this.maxValue(result, 
                       (sumRightToLeft[i] + sumLeftToRight[i] - arr[i]));
		}
		Console.Write("\n Given sequence : ");
		this.display(arr, n);
		Console.Write("\n Result : " + result + "");
	}
	public static void Main(String[] args)
	{
		BitonicSequence task = new BitonicSequence();
		// Array of integer elements
		int[] arr1 = {
			4 , 1 , 3 , 9 , 3 , -2 , 2 , 8 , 3 , 1 , 1 , 4 , 5
		};
		int[] arr2 = {
			45 , 2 , 1 , 14 , 15 , 18 , 20 , 1 , -12 , 2 , 4
		};
		// Test A
		int n = arr1.Length;
		// [1 + 3 + 9 + 8 + 5] 
		// maximum sum bitonic subsequence 
		// 26
		task.maxSumBitonicSequence(arr1, n);
		// Test B
		n = arr2.Length;
		// [2 + 14 + 15 + 18 + 20 + 4] 
		// maximum sum bitonic subsequence 
		// 73
		task.maxSumBitonicSequence(arr2, n);
	}
}

Output

 Given sequence :   4  1  3  9  3  -2  2  8  3  1  1  4  5
 Result : 26
 Given sequence :   45  2  1  14  15  18  20  1  -12  2  4
 Result : 73
package main
import "math"
import "fmt"
/*
    Go Program for
    Find maximum sum bitonic sub sequence using dynamic programming
*/

// Function which is display array elements
func display(arr[] int, n int) {
	for i := 0 ; i < n ; i++ {
		fmt.Print("  ", arr[i])
	}
}
// Returns a max value of two integers
func maxValue(a, b int) int {
	if a > b {
		return a
	}
	return b
}
func maxSumBitonicSequence(arr[] int, n int) {
	// This is collects the sum of bitonic subsequence from left to right.
	var sumLeftToRight = make([] int, n)
	// This is collects the sum of bitonic subsequence from right to left.
	var sumRightToLeft = make([] int, n)
	// Initial value of result is minimum value.
	var result int = math.MinInt64
	// Set initial value of sum
	for i := 0 ; i < n ; i++ {
		sumLeftToRight[i] = arr[i]
		sumRightToLeft[i] = arr[i]
	}
	// Calculate right to left maximum bitonic sum.
	// This loop start with second last element and 
	// Execute until the its value is not -1.
	for i := n - 2 ; i >= 0 ; i-- {
		// This loop start with last element and execute 
		// until the its value is greater than [i].
		for j := n - 1 ; j > i ; j-- {
			if arr[i] > arr[j] && (sumRightToLeft[i] < sumRightToLeft[j] + arr[i]) {
				// Update sum value
				sumRightToLeft[i] = sumRightToLeft[j] + arr[i]
			}
		}
	}
	// Calculate left to right maximum bitonic sum
	for i := 1 ; i < n ; i++ {
		for j := 0 ; j < i ; j++ {
			if arr[i] > arr[j] && (sumLeftToRight[i] < sumLeftToRight[j] + arr[i]) {
				// Update sum value
				sumLeftToRight[i] = sumLeftToRight[j] + arr[i]
			}
		}
	}
	// Calculate maximum bitonic sum using left and right sum.
	for i := 0 ; i < n ; i++ {
		result = maxValue(result, 
			(sumRightToLeft[i] + sumLeftToRight[i] - arr[i]))
	}
	fmt.Print("\n Given sequence : ")
	display(arr, n)
	fmt.Print("\n Result : ", result, "")
}
func main() {
	
	// Array of integer elements
	var arr1 = [] int {4, 1, 3, 9, 3, -2, 2, 8, 3, 1 , 1, 4, 5}
	var arr2 = [] int {45, 2, 1, 14, 15, 18 ,  20, 1, -12, 2, 4}
	// Test A
	var n int = len(arr1)
	// [1 + 3 + 9 + 8 + 5] 
	// maximum sum bitonic subsequence 
	// 26
	maxSumBitonicSequence(arr1, n)
	// Test B
	n = len(arr2)
	// [2 + 14 + 15 + 18 + 20 + 4] 
	// maximum sum bitonic subsequence 
	// 73
	maxSumBitonicSequence(arr2, n)
}

Output

 Given sequence :   4  1  3  9  3  -2  2  8  3  1  1  4  5
 Result : 26
 Given sequence :   45  2  1  14  15  18  20  1  -12  2  4
 Result : 73
<?php
/*
    Php Program for
    Find maximum sum bitonic sub sequence using dynamic programming
*/
class BitonicSequence
{
	// Function which is display array elements
	public	function display($arr, $n)
	{
		for ($i = 0; $i < $n; ++$i)
		{
			echo("  ".$arr[$i]);
		}
	}
	// Returns a max value of two integers
	public	function maxValue($a, $b)
	{
		if ($a > $b)
		{
			return $a;
		}
		return $b;
	}
	public	function maxSumBitonicSequence($arr, $n)
	{
		// This is collects the sum of bitonic subsequence from left to right.
		$sumLeftToRight = array_fill(0, $n, 0);
		// This is collects the sum of bitonic subsequence from right to left.
		$sumRightToLeft = array_fill(0, $n, 0);
		// Initial value of result is minimum value.
		$result = -PHP_INT_MAX;
		// Set initial value of sum
		for ($i = 0; $i < $n; ++$i)
		{
			$sumLeftToRight[$i] = $arr[$i];
			$sumRightToLeft[$i] = $arr[$i];
		}
		// Calculate right to left maximum bitonic sum.
		// This loop start with second last element and 
		// Execute until the its value is not -1.
		for ($i = $n - 2; $i >= 0; --$i)
		{
			// This loop start with last element and execute 
			// until the its value is greater than [i].
			for ($j = $n - 1; $j > $i; --$j)
			{
				if ($arr[$i] > $arr[$j] && ($sumRightToLeft[$i] < $sumRightToLeft[$j] + $arr[$i]))
				{
					// Update sum value
					$sumRightToLeft[$i] = $sumRightToLeft[$j] + $arr[$i];
				}
			}
		}
		// Calculate left to right maximum bitonic sum
		for ($i = 1; $i < $n; ++$i)
		{
			for ($j = 0; $j < $i; ++$j)
			{
				if ($arr[$i] > $arr[$j] && ($sumLeftToRight[$i] < $sumLeftToRight[$j] + $arr[$i]))
				{
					// Update sum value
					$sumLeftToRight[$i] = $sumLeftToRight[$j] + $arr[$i];
				}
			}
		}
		// Calculate maximum bitonic sum using left and right sum.
		for ($i = 0; $i < $n; ++$i)
		{
			$result = $this->maxValue($result, ($sumRightToLeft[$i] + $sumLeftToRight[$i] - $arr[$i]));
		}
		echo("\n Given sequence : ");
		$this->display($arr, $n);
		echo("\n Result : ".$result.
			"");
	}
}

function main()
{
	$task = new BitonicSequence();
	// Array of integer elements
	$arr1 = array(4, 1, 3, 9, 3, -2, 2, 8, 3, 1, 1, 4, 5);
	$arr2 = array(45, 2, 1, 14, 15, 18, 20, 1, -12, 2, 4);
	// Test A
	$n = count($arr1);
	// [1 + 3 + 9 + 8 + 5] 
	// maximum sum bitonic subsequence 
	// 26
	$task->maxSumBitonicSequence($arr1, $n);
	// Test B
	$n = count($arr2);
	// [2 + 14 + 15 + 18 + 20 + 4] 
	// maximum sum bitonic subsequence 
	// 73
	$task->maxSumBitonicSequence($arr2, $n);
}
main();

Output

 Given sequence :   4  1  3  9  3  -2  2  8  3  1  1  4  5
 Result : 26
 Given sequence :   45  2  1  14  15  18  20  1  -12  2  4
 Result : 73
/*
    Node JS Program for
    Find maximum sum bitonic sub sequence using dynamic programming
*/
class BitonicSequence
{
	// Function which is display array elements
	display(arr, n)
	{
		for (var i = 0; i < n; ++i)
		{
			process.stdout.write("  " + arr[i]);
		}
	}
	// Returns a max value of two integers
	maxValue(a, b)
	{
		if (a > b)
		{
			return a;
		}
		return b;
	}
	maxSumBitonicSequence(arr, n)
	{
		// This is collects the sum of bitonic subsequence from left to right.
		var sumLeftToRight = Array(n).fill(0);
		// This is collects the sum of bitonic subsequence from right to left.
		var sumRightToLeft = Array(n).fill(0);
		// Initial value of result is minimum value.
		var result = -Number.MAX_VALUE;
		// Set initial value of sum
		for (var i = 0; i < n; ++i)
		{
			sumLeftToRight[i] = arr[i];
			sumRightToLeft[i] = arr[i];
		}
		// Calculate right to left maximum bitonic sum.
		// This loop start with second last element and 
		// Execute until the its value is not -1.
		for (var i = n - 2; i >= 0; --i)
		{
			// This loop start with last element and execute 
			// until the its value is greater than [i].
			for (var j = n - 1; j > i; --j)
			{
				if (arr[i] > arr[j] && 
                    (sumRightToLeft[i] < sumRightToLeft[j] + arr[i]))
				{
					// Update sum value
					sumRightToLeft[i] = sumRightToLeft[j] + arr[i];
				}
			}
		}
		// Calculate left to right maximum bitonic sum
		for (var i = 1; i < n; ++i)
		{
			for (var j = 0; j < i; ++j)
			{
				if (arr[i] > arr[j] && 
                    (sumLeftToRight[i] < sumLeftToRight[j] + arr[i]))
				{
					// Update sum value
					sumLeftToRight[i] = sumLeftToRight[j] + arr[i];
				}
			}
		}
		// Calculate maximum bitonic sum using left and right sum.
		for (var i = 0; i < n; ++i)
		{
			result = this.maxValue(result, 
                      (sumRightToLeft[i] + sumLeftToRight[i] - arr[i]));
		}
		process.stdout.write("\n Given sequence : ");
		this.display(arr, n);
		process.stdout.write("\n Result : " + result + "");
	}
}

function main()
{
	var task = new BitonicSequence();
	// Array of integer elements
	var arr1 = [4, 1, 3, 9, 3, -2, 2, 8, 3, 1, 1, 4, 5];
	var arr2 = [45, 2, 1, 14, 15, 18, 20, 1, -12, 2, 4];
	// Test A
	var n = arr1.length;
	// [1 + 3 + 9 + 8 + 5] 
	// maximum sum bitonic subsequence 
	// 26
	task.maxSumBitonicSequence(arr1, n);
	// Test B
	n = arr2.length;
	// [2 + 14 + 15 + 18 + 20 + 4] 
	// maximum sum bitonic subsequence 
	// 73
	task.maxSumBitonicSequence(arr2, n);
}
main();

Output

 Given sequence :   4  1  3  9  3  -2  2  8  3  1  1  4  5
 Result : 26
 Given sequence :   45  2  1  14  15  18  20  1  -12  2  4
 Result : 73
import sys
#    Python 3 Program for
#    Find maximum sum bitonic sub sequence using dynamic programming
class BitonicSequence :
	#  Function which is display list elements
	def display(self, arr, n) :
		i = 0
		while (i < n) :
			print(" ", arr[i], end = "")
			i += 1
		
	
	#  Returns a max value of two integers
	def maxValue(self, a, b) :
		if (a > b) :
			return a
		
		return b
	
	def maxSumBitonicSequence(self, arr, n) :
		#  This is collects the sum of bitonic subsequence from left to right.
		sumLeftToRight = [0] * (n)
		#  This is collects the sum of bitonic subsequence from right to left.
		sumRightToLeft = [0] * (n)
		#  Initial value of result is minimum value.
		result = -sys.maxsize
		i = 0
		#  Set initial value of sum
		while (i < n) :
			sumLeftToRight[i] = arr[i]
			sumRightToLeft[i] = arr[i]
			i += 1
		
		i = n - 2
		#  Calculate right to left maximum bitonic sum.
		#  This loop start with second last element and 
		#  Execute until the its value is not -1.
		while (i >= 0) :
			j = n - 1
			#  This loop start with last element and execute 
			#  until the its value is greater than [i].
			while (j > i) :
				if (arr[i] > arr[j] and(sumRightToLeft[i] < sumRightToLeft[j] + arr[i])) :
					#  Update sum value
					sumRightToLeft[i] = sumRightToLeft[j] + arr[i]
				
				j -= 1
			
			i -= 1
		
		i = 1
		#  Calculate left to right maximum bitonic sum
		while (i < n) :
			j = 0
			while (j < i) :
				if (arr[i] > arr[j] and(sumLeftToRight[i] < sumLeftToRight[j] + arr[i])) :
					#  Update sum value
					sumLeftToRight[i] = sumLeftToRight[j] + arr[i]
				
				j += 1
			
			i += 1
		
		i = 0
		#  Calculate maximum bitonic sum using left and right sum.
		while (i < n) :
			result = self.maxValue(result, (sumRightToLeft[i] + sumLeftToRight[i] - arr[i]))
			i += 1
		
		print("\n Given sequence : ", end = "")
		self.display(arr, n)
		print("\n Result : ", result ,"", end = "")
	

def main() :
	task = BitonicSequence()
	#  Array of integer elements
	arr1 = [4, 1, 3, 9, 3, -2, 2, 8, 3, 1, 1, 4, 5]
	arr2 = [45, 2, 1, 14, 15, 18, 20, 1, -12, 2, 4]
	#  Test A
	n = len(arr1)
	#  [1 + 3 + 9 + 8 + 5] 
	#  maximum sum bitonic subsequence 
	#  26
	task.maxSumBitonicSequence(arr1, n)
	#  Test B
	n = len(arr2)
	#  [2 + 14 + 15 + 18 + 20 + 4] 
	#  maximum sum bitonic subsequence 
	#  73
	task.maxSumBitonicSequence(arr2, n)

if __name__ == "__main__": main()

Output

 Given sequence :   4  1  3  9  3  -2  2  8  3  1  1  4  5
 Result :  26
 Given sequence :   45  2  1  14  15  18  20  1  -12  2  4
 Result :  73
#    Ruby Program for
#    Find maximum sum bitonic sub sequence using dynamic programming
class BitonicSequence 
	#  Function which is display array elements
	def display(arr, n) 
		i = 0
		while (i < n) 
			print("  ", arr[i])
			i += 1
		end

	end

	#  Returns a max value of two integers
	def maxValue(a, b) 
		if (a > b) 
			return a
		end

		return b
	end

	def maxSumBitonicSequence(arr, n) 
		#  This is collects the sum of bitonic subsequence from left to right.
		sumLeftToRight = Array.new(n) {0}
		#  This is collects the sum of bitonic subsequence from right to left.
		sumRightToLeft = Array.new(n) {0}
		#  Initial value of result is minimum value.
		result = -(2 ** (0. size * 8 - 2))
		i = 0
		#  Set initial value of sum
		while (i < n) 
			sumLeftToRight[i] = arr[i]
			sumRightToLeft[i] = arr[i]
			i += 1
		end

		i = n - 2
		#  Calculate right to left maximum bitonic sum.
		#  This loop start with second last element and 
		#  Execute until the its value is not -1.
		while (i >= 0) 
			j = n - 1
			#  This loop start with last element and execute 
			#  until the its value is greater than [i].
			while (j > i) 
				if (arr[i] > arr[j] && 
                    (sumRightToLeft[i] < sumRightToLeft[j] + arr[i])) 
					#  Update sum value
					sumRightToLeft[i] = sumRightToLeft[j] + arr[i]
				end

				j -= 1
			end

			i -= 1
		end

		i = 1
		#  Calculate left to right maximum bitonic sum
		while (i < n) 
			j = 0
			while (j < i) 
				if (arr[i] > arr[j] && 
                    (sumLeftToRight[i] < sumLeftToRight[j] + arr[i])) 
					#  Update sum value
					sumLeftToRight[i] = sumLeftToRight[j] + arr[i]
				end

				j += 1
			end

			i += 1
		end

		i = 0
		#  Calculate maximum bitonic sum using left and right sum.
		while (i < n) 
			result = self.maxValue(result, 
                    (sumRightToLeft[i] + sumLeftToRight[i] - arr[i]))
			i += 1
		end

		print("\n Given sequence : ")
		self.display(arr, n)
		print("\n Result : ", result ,"")
	end

end

def main() 
	task = BitonicSequence.new()
	#  Array of integer elements
	arr1 = [4, 1, 3, 9, 3, -2, 2, 8, 3, 1, 1, 4, 5]
	arr2 = [45, 2, 1, 14, 15, 18, 20, 1, -12, 2, 4]
	#  Test A
	n = arr1.length
	#  [1 + 3 + 9 + 8 + 5] 
	#  maximum sum bitonic subsequence 
	#  26
	task.maxSumBitonicSequence(arr1, n)
	#  Test B
	n = arr2.length
	#  [2 + 14 + 15 + 18 + 20 + 4] 
	#  maximum sum bitonic subsequence 
	#  73
	task.maxSumBitonicSequence(arr2, n)
end

main()

Output

 Given sequence :   4  1  3  9  3  -2  2  8  3  1  1  4  5
 Result : 26
 Given sequence :   45  2  1  14  15  18  20  1  -12  2  4
 Result : 73
/*
    Scala Program for
    Find maximum sum bitonic sub sequence using dynamic programming
*/
class BitonicSequence()
{
	// Function which is display array elements
	def display(arr: Array[Int], n: Int): Unit = {
		var i: Int = 0;
		while (i < n)
		{
			print("  " + arr(i));
			i += 1;
		}
	}
	// Returns a max value of two integers
	def maxValue(a: Int, b: Int): Int = {
		if (a > b)
		{
			return a;
		}
		return b;
	}
	def maxSumBitonicSequence(arr: Array[Int], n: Int): Unit = {
		// This is collects the sum of bitonic subsequence from left to right.
		var sumLeftToRight: Array[Int] = Array.fill[Int](n)(0);
		// This is collects the sum of bitonic subsequence from right to left.
		var sumRightToLeft: Array[Int] = Array.fill[Int](n)(0);
		// Initial value of result is minimum value.
		var result: Int = Int.MinValue;
		var i: Int = 0;
		// Set initial value of sum
		while (i < n)
		{
			sumLeftToRight(i) = arr(i);
			sumRightToLeft(i) = arr(i);
			i += 1;
		}
		i = n - 2;
		// Calculate right to left maximum bitonic sum.
		// This loop start with second last element and 
		// Execute until the its value is not -1.
		while (i >= 0)
		{
			var j: Int = n - 1;
			// This loop start with last element and execute 
			// until the its value is greater than [i].
			while (j > i)
			{
				if (arr(i) > arr(j) && 
                    (sumRightToLeft(i) < sumRightToLeft(j) + arr(i)))
				{
					// Update sum value
					sumRightToLeft(i) = sumRightToLeft(j) + arr(i);
				}
				j -= 1;
			}
			i -= 1;
		}
		i = 1;
		// Calculate left to right maximum bitonic sum
		while (i < n)
		{
			var j: Int = 0;
			while (j < i)
			{
				if (arr(i) > arr(j) && 
                    (sumLeftToRight(i) < sumLeftToRight(j) + arr(i)))
				{
					// Update sum value
					sumLeftToRight(i) = sumLeftToRight(j) + arr(i);
				}
				j += 1;
			}
			i += 1;
		}
		i = 0;
		// Calculate maximum bitonic sum using left and right sum.
		while (i < n)
		{
			result = maxValue(result, 
                    (sumRightToLeft(i) + sumLeftToRight(i) - arr(i)));
			i += 1;
		}
		print("\n Given sequence : ");
		display(arr, n);
		print("\n Result : " + result + "");
	}
}
object Main
{
	def main(args: Array[String]): Unit = {
		var task: BitonicSequence = new BitonicSequence();
		// Array of integer elements
		var arr1: Array[Int] = Array(4, 1, 3, 9, 3, -2, 2, 8, 3, 1, 1, 4, 5);
		var arr2: Array[Int] = Array(45, 2, 1, 14, 15, 18, 20, 1, -12, 2, 4);
		// Test A
		var n: Int = arr1.length;
		// [1 + 3 + 9 + 8 + 5] 
		// maximum sum bitonic subsequence 
		// 26
		task.maxSumBitonicSequence(arr1, n);
		// Test B
		n = arr2.length;
		// [2 + 14 + 15 + 18 + 20 + 4] 
		// maximum sum bitonic subsequence 
		// 73
		task.maxSumBitonicSequence(arr2, n);
	}
}

Output

 Given sequence :   4  1  3  9  3  -2  2  8  3  1  1  4  5
 Result : 26
 Given sequence :   45  2  1  14  15  18  20  1  -12  2  4
 Result : 73
import Foundation;
/*
    Swift 4 Program for
    Find maximum sum bitonic sub sequence using dynamic programming
*/
class BitonicSequence
{
	// Function which is display array elements
	func display(_ arr: [Int], _ n: Int)
	{
		var i: Int = 0;
		while (i < n)
		{
			print(" ", arr[i], terminator: "");
			i += 1;
		}
	}
	// Returns a max value of two integers
	func maxValue(_ a: Int, _ b: Int) -> Int
	{
		if (a > b)
		{
			return a;
		}
		return b;
	}
	func maxSumBitonicSequence(_ arr: [Int], _ n: Int)
	{
		// This is collects the sum of bitonic subsequence from left to right.
		var sumLeftToRight: [Int] = Array(repeating: 0, count: n);
		// This is collects the sum of bitonic subsequence from right to left.
		var sumRightToLeft: [Int] = Array(repeating: 0, count: n);
		// Initial value of result is minimum value.
		var result: Int = Int.min;
		var i: Int = 0;
		// Set initial value of sum
		while (i < n)
		{
			sumLeftToRight[i] = arr[i];
			sumRightToLeft[i] = arr[i];
			i += 1;
		}
		i = n - 2;
		// Calculate right to left maximum bitonic sum.
		// This loop start with second last element and 
		// Execute until the its value is not -1.
		while (i >= 0)
		{
			var j: Int = n - 1;
			// This loop start with last element and execute 
			// until the its value is greater than [i].
			while (j > i)
			{
				if (arr[i] > arr[j] && 
                    (sumRightToLeft[i] < sumRightToLeft[j] + arr[i]))
				{
					// Update sum value
					sumRightToLeft[i] = sumRightToLeft[j] + arr[i];
				}
				j -= 1;
			}
			i -= 1;
		}
		i = 1;
		// Calculate left to right maximum bitonic sum
		while (i < n)
		{
			var j: Int = 0;
			while (j < i)
			{
				if (arr[i] > arr[j] && 
                    (sumLeftToRight[i] < sumLeftToRight[j] + arr[i]))
				{
					// Update sum value
					sumLeftToRight[i] = sumLeftToRight[j] + arr[i];
				}
				j += 1;
			}
			i += 1;
		}
		i = 0;
		// Calculate maximum bitonic sum using left and right sum.
		while (i < n)
		{
			result = self.maxValue(result, 
                     (sumRightToLeft[i] + sumLeftToRight[i] - arr[i]));
			i += 1;
		}
		print("\n Given sequence : ", terminator: "");
		self.display(arr, n);
		print("\n Result : ", result ,"", terminator: "");
	}
}
func main()
{
	let task: BitonicSequence = BitonicSequence();
	// Array of integer elements
	let arr1: [Int] = [4, 1, 3, 9, 3, -2, 2, 8, 3, 1, 1, 4, 5];
	let arr2: [Int] = [45, 2, 1, 14, 15, 18, 20, 1, -12, 2, 4];
	// Test A
	var n: Int = arr1.count;
	// [1 + 3 + 9 + 8 + 5] 
	// maximum sum bitonic subsequence 
	// 26
	task.maxSumBitonicSequence(arr1, n);
	// Test B
	n = arr2.count;
	// [2 + 14 + 15 + 18 + 20 + 4] 
	// maximum sum bitonic subsequence 
	// 73
	task.maxSumBitonicSequence(arr2, n);
}
main();

Output

 Given sequence :   4  1  3  9  3  -2  2  8  3  1  1  4  5
 Result :  26
 Given sequence :   45  2  1  14  15  18  20  1  -12  2  4
 Result :  73
/*
    Kotlin Program for
    Find maximum sum bitonic sub sequence using dynamic programming
*/
class BitonicSequence
{
	// Function which is display array elements
	fun display(arr: Array < Int > , n: Int): Unit
	{
		var i: Int = 0;
		while (i < n)
		{
			print("  " + arr[i]);
			i += 1;
		}
	}
	// Returns a max value of two integers
	fun maxValue(a: Int, b: Int): Int
	{
		if (a > b)
		{
			return a;
		}
		return b;
	}
	fun maxSumBitonicSequence(arr: Array < Int > , n: Int): Unit
	{
		// This is collects the sum of bitonic subsequence from left to right.
		var sumLeftToRight: Array < Int > = Array(n)
		{
			0
		};
		// This is collects the sum of bitonic subsequence from right to left.
		var sumRightToLeft: Array < Int > = Array(n)
		{
			0
		};
		// Initial value of result is minimum value.
		var result: Int = Int.MIN_VALUE;
		var i: Int = 0;
		// Set initial value of sum
		while (i < n)
		{
			sumLeftToRight[i] = arr[i];
			sumRightToLeft[i] = arr[i];
			i += 1;
		}
		i = n - 2;
		// Calculate right to left maximum bitonic sum.
		// This loop start with second last element and 
		// Execute until the its value is not -1.
		while (i >= 0)
		{
			var j: Int = n - 1;
			// This loop start with last element and execute 
			// until the its value is greater than [i].
			while (j > i)
			{
				if (arr[i] > arr[j] && 
                    (sumRightToLeft[i] < sumRightToLeft[j] + arr[i]))
				{
					// Update sum value
					sumRightToLeft[i] = sumRightToLeft[j] + arr[i];
				}
				j -= 1;
			}
			i -= 1;
		}
		i = 1;
		// Calculate left to right maximum bitonic sum
		while (i < n)
		{
			var j: Int = 0;
			while (j < i)
			{
				if (arr[i] > arr[j] && 
                    (sumLeftToRight[i] < sumLeftToRight[j] + arr[i]))
				{
					// Update sum value
					sumLeftToRight[i] = sumLeftToRight[j] + arr[i];
				}
				j += 1;
			}
			i += 1;
		}
		i = 0;
		// Calculate maximum bitonic sum using left and right sum.
		while (i < n)
		{
			result = this.maxValue(result, 
                     (sumRightToLeft[i] + sumLeftToRight[i] - arr[i]));
			i += 1;
		}
		print("\n Given sequence : ");
		this.display(arr, n);
		print("\n Result : " + result + "");
	}
}
fun main(args: Array < String > ): Unit
{
	val task: BitonicSequence = BitonicSequence();
	// Array of integer elements
	val arr1: Array < Int > = arrayOf(4, 1, 3, 9, 3, -2, 2, 8, 3, 1, 1, 4, 5);
	val arr2: Array < Int > = arrayOf(45, 2, 1, 14, 15, 18, 20, 1, -12, 2, 4);
	// Test A
	var n: Int = arr1.count();
	// [1 + 3 + 9 + 8 + 5] 
	// maximum sum bitonic subsequence 
	// 26
	task.maxSumBitonicSequence(arr1, n);
	// Test B
	n = arr2.count();
	// [2 + 14 + 15 + 18 + 20 + 4] 
	// maximum sum bitonic subsequence 
	// 73
	task.maxSumBitonicSequence(arr2, n);
}

Output

 Given sequence :   4  1  3  9  3  -2  2  8  3  1  1  4  5
 Result : 26
 Given sequence :   45  2  1  14  15  18  20  1  -12  2  4
 Result : 73
Last updated on by Kalkicode




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