Find maximum element in each column of the matrix
The problem to be addressed involves finding the maximum element in each column of a given matrix. A matrix is a twodimensional array with rows and columns, and the task is to identify and print the largest element in each column.
Problem Statement
Given a matrix with dimensions ROW x COL, where each element is an integer, the objective is to find the maximum element in each column and display those maximum values.
Example
Consider the following matrix:
1 1 6 3
4 8 5 4
3 4 5 0
2 3 2 3
0 3 5 7
The maximum elements in each column are: 4, 8, 6, and 7.
Idea to Solve
To solve this problem, iterate through each column of the matrix and identify the maximum element in that column. Initialize a variable to store the maximum element for each column and update it while traversing the column.
Pseudocode
Here's the pseudocode for the algorithm:
function colMaxElement(matrix):
for i from 0 to COL1:
max_element = matrix[0][i] // Initialize max_element with the first element of the column
for j from 1 to ROW1:
if matrix[j][i] > max_element:
max_element = matrix[j][i] // Update max_element if a larger element is found
print max_element
Algorithm Explanation
 Define a function
colMaxElement
that takes a 2D matrixmatrix
as its input.  Initialize a loop that iterates through each column of the matrix from 0 to COL1 (inclusive).
 Inside the outer loop, initialize a variable
max_element
with the value of the first element in the current column (matrix[0][i]).  Implement an inner loop that starts from 1 and iterates through each row of the current column (from 1 to ROW1).
 Within the inner loop, compare the current element (matrix[j][i]) with
max_element
. If the current element is greater thanmax_element
, updatemax_element
with the value of the current element.  After the inner loop completes, print the value of
max_element
, representing the maximum element in the current column.  The outer loop proceeds to the next column, and the process repeats until all columns are processed.
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Time Complexity
The time complexity of this algorithm is O(ROW * COL), where ROW is the number of rows in the matrix and COL is the number of columns. The algorithm iterates through each element of the matrix exactly once to find the maximum element in each column. The nested loops contribute to the complexity.
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