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# Find maximum element in each column of the matrix

The problem to be addressed involves finding the maximum element in each column of a given matrix. A matrix is a two-dimensional array with rows and columns, and the task is to identify and print the largest element in each column.

## Problem Statement

Given a matrix with dimensions ROW x COL, where each element is an integer, the objective is to find the maximum element in each column and display those maximum values.

## Example

Consider the following matrix:

``````1  -1  6  3
4   8  5  4
3   4  5  0
2   3  2  3
0   3  5  7``````

The maximum elements in each column are: 4, 8, 6, and 7.

## Idea to Solve To solve this problem, iterate through each column of the matrix and identify the maximum element in that column. Initialize a variable to store the maximum element for each column and update it while traversing the column.

## Pseudocode

Here's the pseudocode for the algorithm:

``````function colMaxElement(matrix):
for i from 0 to COL-1:
max_element = matrix[i] // Initialize max_element with the first element of the column
for j from 1 to ROW-1:
if matrix[j][i] > max_element:
max_element = matrix[j][i] // Update max_element if a larger element is found
print max_element``````

## Algorithm Explanation

1. Define a function `colMaxElement` that takes a 2D matrix `matrix` as its input.
2. Initialize a loop that iterates through each column of the matrix from 0 to COL-1 (inclusive).
3. Inside the outer loop, initialize a variable `max_element` with the value of the first element in the current column (matrix[i]).
4. Implement an inner loop that starts from 1 and iterates through each row of the current column (from 1 to ROW-1).
5. Within the inner loop, compare the current element (matrix[j][i]) with `max_element`. If the current element is greater than `max_element`, update `max_element` with the value of the current element.
6. After the inner loop completes, print the value of `max_element`, representing the maximum element in the current column.
7. The outer loop proceeds to the next column, and the process repeats until all columns are processed.

## Time Complexity

The time complexity of this algorithm is O(ROW * COL), where ROW is the number of rows in the matrix and COL is the number of columns. The algorithm iterates through each element of the matrix exactly once to find the maximum element in each column. The nested loops contribute to the complexity.

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